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Mixed-Signal VLSI Design Course Code: EE719 Department: Electrical Engineering Lecture 18: February 13, 2018
Instructor Name: M. Shojaei Baghini E-Mail ID: mshojaei@ee.iitb.ac.in
Mixed-Signal VLSI Design Course Code: EE719 Department: Electrical - - PowerPoint PPT Presentation
Mixed-Signal VLSI Design Course Code: EE719 Department: Electrical Engineering Lecture 18: February 13, 2018 Instructor Name: M. Shojaei Baghini E-Mail ID: mshojaei@ee.iitb.ac.in 1 2 2 Module 23 Performance Parameters of Data Converters
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Instructor Name: M. Shojaei Baghini E-Mail ID: mshojaei@ee.iitb.ac.in
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IIT-Bombay Lecture 18 M. Shojaei Baghini
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IIT-Bombay Lecture 18 M. Shojaei Baghini
Analog Domain Digital Domain Conditioning A/D Conversion D/A Conversion Smoothing and Equalization
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IIT-Bombay Lecture 18 M. Shojaei Baghini
l Full Scale Range l Resolution: Effective Number of Bits (ENOB) l Introduced Noise and Distortion: Signal to
l Signal Bandwidth l Sampling Frequency
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IIT-Bombay Lecture 18 M. Shojaei Baghini
Assume N-point FFT of a sine wave test. If the fundamental frequency is in bin m and has amplitude Am then SNDR is given by the following relation.
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IIT-Bombay Lecture 18 M. Shojaei Baghini
Source: Nicolas Gray, National Semiconductor, 2006 Noise floor
Note: The average value of the noise contained in each frequency bin of M-point FFT is 10 Β΄ log (M/2) dB below the total noise power.
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IIT-Bombay Lecture 18 M. Shojaei Baghini
l In general dynamic range is the ratio of
l Spurious-free dynamic range (SFDR) is
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IIT-Bombay Lecture 18 M. Shojaei Baghini
l Most of signals contain many frequency components. l Non-linearity causes two or more signal frequencies to
produce intermodulation products.
Source: Analog Devices tutorial MT-053, 2009
Single tone SFDR Multi tone SFDR
Frequency Frequency
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IIT-Bombay Lecture 18 M. Shojaei Baghini
1 LSB Center point ADC (II) DAC (I)
D: LSB size
May be [-VFS/2,VFS/2].
may be used. Starting from DAC
Type equation here.
π
123_567 = β : π<Γ2< ?@A <BC
bi: bit # i
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IIT-Bombay Lecture 18 M. Shojaei Baghini
D πFπ π, π’ ππ =
K @K
D πF 1 β ππ = βF 12
β/F @β/F
dB N q x SQNR V x V q
e rms FS rms N FS e
76 . 1 02 . 6 log 10 2 2 12 2 12
2 2 2 2 2 2
+ = Γ· Γ· ΓΈ ΓΆ Γ§ Γ§ Γ¨ Γ¦ = = Β΄ = D =
For a sinusoidal signal x(t) and approximate uniform distribution of qe.
Example: N=6 bits Γ SNR=37.9dB N=10 bits Γ SNR=62.0dB
t qe(t)
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IIT-Bombay Lecture 18 M. Shojaei Baghini