RC Circuits RC Circuits Charging At t=0, capacitance is uncharged - - PDF document

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RC Circuits RC Circuits Charging At t=0, capacitance is uncharged - - PDF document

RC Circuits RC Circuits Charging At t=0, capacitance is uncharged and C Q=0 (initial condition). At t=0, switched is closed, it the capacitor has no charge, it behaves like a conductor and I= /R. R After the capacitor is


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SLIDE 1

RC Circuits

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SLIDE 2

RC Circuits – Charging

 C R

At t=0, capacitance is uncharged and Q=0 (initial condition). At t=0, switched is closed, it the capacitor has no charge, it behaves like a conductor and I=/R. After the capacitor is completely charged, Q=C , VC=  and VR=0. I=0 and the capacitors behave like an insulator.

slide-3
SLIDE 3

RC Circuits – Charging

 C R

) e 1 ( C q C

  • K

K C q 0, At t e K C q ) e (K Ke C

  • q

K' CR t

  • )

C

  • q

n( dt CR 1

  • C
  • q

dq dt q)

  • (C

dq CR t d q d R C q IR C q

CR t

  • CR

t

  • K'

CR t

                                      ) e

  • (1

C q V e IR V e R e CR C t d dq I

CR t

  • C

CR t

  • R

CR t

  • CR

t

           

Integration constant VR + VC = 

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SLIDE 4

RC time constant

=RC is known as the RC time constant. It indicates the response time (how fast you can charge up the capacitor) of the RC circuit.

e R I

CR t

 R I  

t

R 37 . ~ R e I

1

 

t=RC

) e 1 ( C q

CR t

   C q 

t

  C 63 . ~ C ) e 1 ( q

  • 1

 

t=RC

37 . e 2.72 e

1

 707 . 2 1 1.414 2  

Nothing to do with RC circuits

slide-5
SLIDE 5

RC Circuits – Discharging

C R

At t=0, capacitance is charged with a charge Q (initial condition). At t=0, switched is closed, the capacitor starts to discharge. After the capacitor is completely discharged, Q=0, VC= 0, VR=0 and I=0.

slide-6
SLIDE 6

RC Circuits – Discharging

CR t

  • CR

t

  • K'

CR t

  • Qe

q K Q Q q 0, At t e K q ) e (K Ke q K' CR t

  • q

n dt CR 1

  • q

dq dt q

  • dq

CR ) t d q d

  • (I

t d q d R C q IR C q                         

CR t

  • C

CR t

  • R

CR t

  • e

C Q C q V e C Q IR V e RC Q t d dq I          

Integration constant VR + VC = 0

C R

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SLIDE 7

In Summary

For both charge and discharge, Q, I, VC, and VR must be one of the following two cases:

t t

RC t

  • 0e

y y 

y can be Q, I, VC, or VR y y0 y y

) e

  • (1

y y

RC t

slide-8
SLIDE 8

Class 26: Magnetic force acting on a moving point charge

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SLIDE 9

Magnetic Field

  • 1. All single magnets have two poles, N and S.
  • 2. Externally, magnetic field lines come out from the N pole and getting into the S pole.
  • 3. Between two magnets, like poles repel and unlike poles attract.
  • 4. The geographical north pole of earth is actually the S pole of a bar magnet.
  • 5. We will explain why there is magnetic field later.
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SLIDE 10

cross product between two vectors

bc

  • ad

d c b a B B A A k ˆ B B A A j ˆ B B A A i ˆ B B B A A A k ˆ j ˆ i ˆ B A

y x y x z x z x z y z y z y x z y x

        B A    A  B 

Direction: Magnitude:

 sin | B || A | B A      

From class 3

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SLIDE 11

A common symbol

  • r
  • r

A vector perpendicular and pointing into the screen /paper. A vector perpendicular and pointing out of the screen /paper.

From class 3

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SLIDE 12

Magnetic Force Acting on a Moving Charge

  • 1. Unit of magnetic field is Tesla (T).
  • 2. If there is magnetic field, only under two conditions the magnetic force
  • n the charge particle will be zero: (i) the particle is not moving (v=0), or

(ii) it is moving in parallel or antiparallel to the magnetic field (sin=0).

  • 3. The magnetic force is always perpendicular to the magnetic field and the

velocity.

  • 4. The magnetic force does no work because .
  • 5. If you want to determine the direction acting on a negative charge

particle, treat it like a positive charge first, then reverse the force direction at the end.

When a charge particle moves in a magnetic field B, there will be magnetic force acting on the particle: B v F `

B v q FB     

v FB    