Fundamental butting ::i::::: Galois ness ) intermediate Chandu - - PowerPoint PPT Presentation

fundamental
SMART_READER_LITE
LIVE PREVIEW

Fundamental butting ::i::::: Galois ness ) intermediate Chandu - - PowerPoint PPT Presentation

Theorem Fundamental butting ::i::::: Galois ness ) intermediate Chandu Eakins of Thur ( Equivalent ( iii ) Gal ( Elk ) A Gal ( EIF ) ( iv ) Khs Galois . is Leatherback HH et Aut ( E ) sub extensions of E


slide-1
SLIDE 1

Fundamental

Theorem

slide-2
SLIDE 2

butting

Thur ( Equivalent

ChanduEakins of

intermediate Galois ness)

¥

::÷÷÷÷÷÷÷÷i÷÷÷÷:÷::::

(iii) Gal (Elk) A Gal ( EIF)

(iv ) Khs

is

Galois .

slide-3
SLIDE 3

Leatherback

HH et Aut ( E)

subextensions of E

subgroups

Properties

. contravariance
  • preserves
" bigness "

injective

NcwSt

Are

these

universes

"the

same

" ?
slide-4
SLIDE 4

Nn/BasicAenl

let

E) F

be

Galois ,

and

let

G

  • Gal (E IF)

let

sub (G)

be the

set of

subgroups of G

.

Let

hat (Elf)

be The set

  • f

intermediate fields in EIF

.

Define

F :

Sub (G) → Lat LEIF)

be

FIH)

  • E 't

and

A

: lat LEIF) → Sub(G)

be

ACK)

  • Gul (Elk)

F

s ←O

G

Lat IE IFI

slide-5
SLIDE 5

Thin

( Fundamental Theorem of

Galois theory)

The

functions

F

and I

satisfy

  • A. F
  • ids.ba,

and

  • F. H
  • ideate , e)
, and are

both

contravariant .

Furthermore,

we

have

" for all

HESUBCG) , then

[ FIH)

: F)
  • 1¥,

Iii) for all

KELAHEIF) , then ¥aI,

E Ck : F)

Ciii) KIF

is

Galois ift

Alk) of

Civ)

HOG

iff

FIH) Ip

is

Galois .

slide-6
SLIDE 6

If we've

already

seen

F

is

contravariant ,

and

by

hwk 9

,

problem

4

we

get A

is

contravariant

.

New ,

let's show

fo F

  • id sides
.

let

HEG

be

given ,

and

we'll

show

(I. FXH) = H

.

Nate

(

do FXH) =L ( FCH))

: GI E

" )

  • Gul ( ELE
't) .

Its

certainly true that

any

TEH

has

re Gul LE IE 't)

since

TEH implies

re Aut LE )

, and

since

EH

= { et E : h ( e)
  • e

for

all

he H)

we got
  • fixes EH .

So

we

get

HE

Gal ( E IE

't )

.
slide-7
SLIDE 7

On the

  • ther

hand ,

I Gal LEIE

") I

= [ E : E ") = IHI

1

since

EIEH is Galois

Since

( Gal ( EIEH ) I

is

finite ,

we get

H

  • GAKEIEH)
'
  • (A. F) CH)

Now, let's

show

F 'S

  • idiot CEIF)
.

let

FEKEE

.

Then

(Fo A) ( K)

= FLICK))
  • F ( GulfElk))
= E' ⇐"Elk)

Since Elk is Galois

, we get

EGAKEIK)

.
  • K
.
slide-8
SLIDE 8

Now

for [

since G - GallElf)

and Elf

Galois

"

,

  • .
.
  • "
.
  • hit:b
  • [FIH) ? F)
.

Ci"

,

  • .
=
  • Ck :b
.

(iii) & Civ)

are

the

content of

"

Equivalent

characterizations

  • f

intermediate

Guleismts

"
  • INGI