Learning dynamical systems with particle stochastic approximation EM
Fredrik Lindsten, Link¨
- ping University
2019-04-11
Joint work with Andreas Lindholm, Uppsala University
Learning dynamical systems with particle stochastic approximation EM - - PowerPoint PPT Presentation
Learning dynamical systems with particle stochastic approximation EM Fredrik Lindsten, Link oping University 2019-04-11 Joint work with Andreas Lindholm, Uppsala University Parametric state-space models Dynamical system on state-space form,
Joint work with Andreas Lindholm, Uppsala University
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θ
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tem Identification. 20th World Congress of the International Federation of Automatic Control, Toulouse, France, July 2017.
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Computational time (seconds) Average relative error PSAEM,N=15 PSEM, N=15 PSEM, N=50 PSEM, N=100 PSEM, N=500 4/35
Stochastic approximation SAEM
PMCMC MCMC Particle filters Expectation Maximization 5/35
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Stochastic approximation SAEM
PMCMC MCMC Particle filters Expectation Maximization Will focus on this 7/35
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θ
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def
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def
k γk = ∞, k γ2 k < ∞, and
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j=1 αjk log pθ(
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Stochastic approximation SAEM Expectation Maximization
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K→∞
K
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Stochastic approximation SAEM MCMC Expectation Maximization Markovian SAEM
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def
N
Tδxi
0:T (x0:T).
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N
Tδxi
0:T (x0:T).
5 10 15 20 25 −4 −3.5 −3 −2.5 −2 −1.5 −1 −0.5 0.5 1 Time State
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t = xt.
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5 10 15 20 25 30 35 40 45 50 −3 −2 −1 1 2 3 Time State
5 10 15 20 25 30 35 40 45 50 −3 −2 −1 1 2 3 Time State
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Stochastic approximation SAEM
PMCMC MCMC Particle filters Expectation Maximization
tion EM. Submitted, 2019.
filters. Proceedings of the 38th International Conference on Acoustics, Speech, and Signal Processing (ICASSP), Vancouver, Canada, May 2013. 28/35
v),
2 + et,
e).
v, σ2 e)
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Computational time (seconds) Average relative error PSAEM,N=15 PSEM, N=15 PSEM, N=50 PSEM, N=100 PSEM, N=500 30/35
tem Identification. 20th World Congress of the International Federation of Automatic Control, Toulouse, France, July 2017.
t+1 =10 ∧ xu t + Ts(−k1
t − k2{10 ∧ xu t } + k5ut) + v u t
t+1 =10 ∧ xl t + Ts(k1
t + k2{10 ∧ xu t } − k3
t
t} + k6{(xu t − 10) ∨ 0}) + v l t
t + et,
v, σ2 e, x0}. 31/35
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