SLIDE 34 34/35 Faculteit Wiskunde & Informatica
Proof
We may assume that C has a generator matrix of the form G = (Ik|B) Let x = (x1, . . . , xk) be an k-tuple of nonzero elements of Fq Let D(x) be the diagonal matrix with x on its diagonal Let Gx = (D(x)|B) be the generator matrix of the code Cx Then Cx is monomial equivalent with C Now det(GxG T
x ) = det(D(x2 1, . . . , x2 k ) + BB T)
is a polynomial in x1, . . . , xk Its degree with respect to xi is 2 for all i which is at most q − 2, since q ≥ 4 Hence there exists a x ∈ Fn
q with nonzero entries
such that det GxG T
x = 0
So GxG T
x is invertible
Therefore Cx is LCD