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Two-body Momentum Distributions in 2 ≤ A ≤ 40 nuclei
- M. Alvioli
National Research Council Research Institute for Geo-Hydrological Hazards Perugia, Italy
- M. Alvioli
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Two-body Momentum Distributions in 2 A 40 nuclei M. Alvioli - - PowerPoint PPT Presentation
Two-body Momentum Distributions in 2 A 40 nuclei M. Alvioli National Research Council Research Institute for Geo-Hydrological Hazards Perugia, Italy M. Alvioli MIT 2016 1 CONTENTS 0. Introduction &
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10 20 30 40
p p
0.2 0.4 0.6 0.8 1 0.05 0.1 0.15 0.2 0.25 0.3 0.35 0.4 0.45 0.5 0.55
0.2 0.4 0.6 0.8 1 0.05 0.1 0.15 0.2 0.25 0.3 0.35 0.4 0.45 0.5 0.55
0.2 0.4 0.6 0.8 1 0.05 0.1 0.15 0.2 0.25 0.3 0.35 0.4 0.45 0.5 0.55
0.2 0.4 0.6 0.8 1 0.05 0.1 0.15 0.2 0.25 0.3 0.35 0.4 0.45 0.5 0.55
pn(GeV/c) cosγ 5.9 GeV/c, 98 8.0 GeV/c, 98 9.0 GeV/c, 98 5.9 GeV/c, 94 7.5 GeV/c, 94
0.2 0.4 0.6 0.8 1 0.05 0.1 0.15 0.2 0.25 0.3 0.35 0.4 0.45 0.5 0.55
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H (r1, r′ 1) =
1) ρo(r2) − HE(r12, r1′2) ρ(1)
1)
S (r1, r′ 1) = −
1)ρo(r3) − HE(r23)ρ(1)
1)
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1, r′ 2) = ρ(2) SM(r1, r2; r′ 1, r′ 2) + ρ(2) 2b(r1, r2; r′ 1, r′ 2) + ρ(2) 3b(r1, r2; r′ 1, r′ 2) + ρ(2) 4b(r1, r2; r′ 1, r′ 2)
SM(r1, r2; r′ 1, r′ 2) = CD ρo(r1, r′ 1) ρo(r2, r′ 2) − CE ρo(r1, r′ 2) ρo(r2, r′ 1)
2b(r1, r2; r′ 1, r′ 2) = 1
1) ρo(r2, r′ 2) − 1
2) ρo(r2, r′ 1)
3b(r1, r2; r′ 1, r′ 2) =
1) ρo(r2, r′ 2) ρo(r3, r3) +
1) ρo(r2, r3) ρo(r3, r′ 2) +
1) ρo(r3, r′ 2) +
2) ρo(r3, r′ 1) +
2) ρo(r2, r3) ρo(r3, r′ 1) +
2) ρo(r2, r′ 1) ρo(r3, r3) ]
4b(r1, r2; r′ 1, r′ 2) = 1
P∈C
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1 1’
1 1’ 2
2 1’ 1 1’ 1 2 3 3 2 1 1’
a
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pn
K c.m . = 0.0 K c.m . = 0.5 K c.m . = 1.0 K c.m . = 1.5 3He
pp
1 2 3 4 5 10He
n pN (k rel ,K c.m. , ) [fm 6 ]pn pp
K c.m . = 0.0 K c.m . = 0.5 K c.m . = 1.019
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pn
n pN A (k rel ,K c.m. , ) [fm 6 ] K c.m . = 0.0 K c.m . = 0.5 K c.m . = 1.0 K c.m . = 1.5 3He
pp
1 2 3 4 5 10He
n pN (k rel ,K c.m. , ) [fm 6 ]pn pp
K c.m . = 0.0 K c.m . = 0.5 K c.m . = 1.020
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pn
n pN A (k rel ,K c.m. , ) [fm 6 ] K c.m . = 0.0 K c.m . = 0.5 K c.m . = 1.0 K c.m . = 1.5 K c.m . = 3.0 3He
pp
1 2 3 4 5 10He
n pN (k rel ,K c.m. , ) [fm 6 ]pn pp
K c.m . = 0.0 K c.m . = 0.5 K c.m . = 1.0 K c.m . = 3.021
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pn
1 2 3 4 5 10pn
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pn
1 2 3 4 5 10pn
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2H 3He 4He 6Li 8Be 12C 16O 40Ca
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pn A (krel,Kcm=0) /(C pn A n pn cm(Kcm=0)) [fm 3] 2H 12C 3He 16O 4He 40Ca
k rel [fm2
(b)pn A (krel)/C pn A [fm 3]
2H 12C 3He 16O 4He 40Ca
1 2 3 4 5 1029
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He
12C
cos COUNTS K c.m. [fm33
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