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The Himalaya of Bhutan Intro to Quantitative Geology - - PowerPoint PPT Presentation

Introduction to Quantitative Geology Overview of Exercises 6 and 7 Quantitative t hermochronology Instructor: David Whipp david.whipp@helsinki.fi 2.12.19 Intro to Quantitative Geology www.helsinki.fi/yliopisto 1 The Himalaya of Bhutan Intro


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Intro to Quantitative Geology www.helsinki.fi/yliopisto

Introduction to Quantitative Geology

Overview of Exercises 6 and 7 Quantitative thermochronology

Instructor: David Whipp david.whipp@helsinki.fi 2.12.19

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www.helsinki.fi/yliopisto Intro to Quantitative Geology

The Himalaya of Bhutan

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http://commons.wikimedia.org

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www.helsinki.fi/yliopisto Intro to Quantitative Geology

Thermochronometer ages in western Bhutan

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Coutand et al., 2014

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www.helsinki.fi/yliopisto Intro to Quantitative Geology

Linking ages to geological processes

  • Thermochronometer ages contain valuable information about

past geological processes, but age interpretation is difficult

4 1 1 2 3 4 5 6 7 8 9 2 3 4 5 6 7 8 9 10 11 12 13 14

Age (Ma) Western Transect (89.1-89.82°E)

I-STD MCT MBT MFT

Elevation asl (km)

a) b)

100 150 50 200 28.25 28.5 26.5 26.75 27 27.25 27.5 27.75 28

Latitude (°N) Distance along swath (km) Elevation (± 1σ) )

Coutand et al., 2014

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Estimating rock exhumation rates

  • In mountainous settings, rock exhumation is the result of a

erosional (surface) and/or tectonic processes

  • Exhumation: The unroofing history of a rock, as caused by

tectonic and/or surficial processes (Ring et al., 1999)

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Grand Teton National Park, Wyoming, USA

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www.helsinki.fi/yliopisto Intro to Quantitative Geology

Estimating exhumation rates from ages

  • The simplest way to estimate a long-term average exhumation

rate from a thermochronometer age is to assume a constant geothermal gradient and determine the depth from which the sample was exhumed

  • For example, assume we measure an apatite (U-Th)/He age
  • f 12.3±0.9 Ma in a sample
  • Assume a nominal closure temperature 𝑈c of 75±5°C and a

“typical” geothermal gradient of 20°C/km

  • How would you find the exhumation rate?
  • The simple approach is to find the depth of 𝑈c and divide

that depth by the age

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www.helsinki.fi/yliopisto Intro to Quantitative Geology

Estimating exhumation rates from ages

  • The simplest way to estimate a long-term average exhumation

rate from a thermochronometer age is to assume a constant geothermal gradient and determine the depth from which the sample was exhumed

  • For example, assume we measure an apatite (U-Th)/He age
  • f 12.3±0.9 Ma in a sample
  • Assume a nominal closure temperature 𝑈c of 75±5°C and a

“typical” geothermal gradient of 20°C/km

  • How would you find the exhumation rate?
  • The simple approach is to find the depth of 𝑈c and divide

that depth by the age

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www.helsinki.fi/yliopisto Intro to Quantitative Geology

Exhumation rate example

  • If we assume the surface temperature is 0°C, the depth 𝑨c of

𝑈c is simply 𝑈c divided by the geothermal gradient

  • 𝑨c = 75°C / (20°C/km) = 3.75 km
  • An exhumation rate ė can be estimated by dividing that

depth by the measured age

  • ė = 3.75 km / 12.3 Ma = ~0.3 km/Ma = ~0.3 mm/a

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A constant thermal gradient is a bad idea

  • This approach works, but it neglects many known thermal

factors including ‘bending’ of the geotherm as a result of thermal advection

  • A more reasonable approach would be to utilize a 1-D thermal

model to simulate heat transfer processes during rock cooling, which will be our approach in the final two lab exercises

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www.helsinki.fi/yliopisto Intro to Quantitative Geology

T(z) = TL ✓ 1 − e−(vzz/κ) 1 − e−(vzL/κ) ◆

1-D steady-state geotherms

  • Advection is often the

main thermal influence

  • n thermochronometer

ages in mountainous regions

  • Thus, advection must be

considered by using an appropriate equation
 
 


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Now what?

  • With a predicted 1-D thermal field, the next step is to

determine the cooling history for a rock sample

  • We know the sample is at the surface (𝑨 = 0) today, and we

can use the advection velocity 𝑤𝑨 to determine the cooling history

  • How?
  • We can calculate the past depth of a rock sample by using

time steps back to some time in the past

  • Each time step, the rock will be displaced by 𝑤𝑨 ⨉ 𝑒𝑢

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www.helsinki.fi/yliopisto Intro to Quantitative Geology

Now what?

  • With a predicted 1-D thermal field, the next step is to

determine the cooling history for a rock sample

  • We know the sample is at the surface (𝑨 = 0) today, and we

can use the advection velocity 𝑤𝑨 to determine the cooling history

  • How?
  • We can calculate the past depth of a rock sample by using

time steps back to some time in the past

  • Each time step, the rock will be displaced by 𝑤𝑨 ⨉ 𝑒𝑢

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www.helsinki.fi/yliopisto Intro to Quantitative Geology

Generating a thermal history

  • At each time, record the

depth and temperature, then move the particle upward by 𝑤𝑨 ⨉ 𝑒𝑢

  • The result is a thermal

history for a given exhumation (advection) rate that can now be linked to an estimated closure temperature to predict a cooling age and compare to data

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𝑈1(𝑨,𝑢) 𝑈2(𝑨,𝑢) 𝑈3(𝑨,𝑢) 𝑈4(𝑨,𝑢) 𝑈5(𝑨,𝑢)

𝑈c

Predicted age

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General concept for age prediction

  • 1. Calculate thermal solution
  • 2. Generate thermal history based on thermal solution and

advection velocity

  • 3. Use thermal history to calculate 𝑈c
  • 4. Record time at which sample cools below 𝑈c (predicted age)
  • 5. Compare predicted age to measured age
  • 6. Repeat steps 1-5 as needed until a good fit is observed

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Age

Measured age Predicted ages