ME 474-674 Winter 2008 Slides 6 -1
More info: “Materials Selection in Mechanical Design”, Chapters 5 and 6
Material for a pressure vessel Short term thermal insulation - - PowerPoint PPT Presentation
More Case Studies in Materials Selection Material for a pressure vessel Short term thermal insulation Energy efficient kilns More info: Materials Selection in Mechanical Design , Chapters 5 and 6 ME 474-674 Winter 2008 Slides 6
ME 474-674 Winter 2008 Slides 6 -1
More info: “Materials Selection in Mechanical Design”, Chapters 5 and 6
ME 474-674 Winter 2008 Slides 6 -2
Cylindrical pressure vessels are containers for a fluid under pressure A safe design will be based on one of two factors
The maximum principal stress is the hoop stress
2a
ME 474-674 Winter 2008 Slides 6 -3
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c”
c
c are present
c is
* 1 c C
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* 1 c C
C
1 1 =
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2 1 2
f C c
f C
1 2 =
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f C f C
K C R p
t pR K C t σ π σ σ π
2 1 2 2 1 2
2 2 ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ = = ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ =
f C
2 1 3 =
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f C
2 1 f C
1
C
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Yield strength (elastic limit) (MPa)
0.01 0.1 1 10 100 1000
Fracture toughness (MPa.m^ 1/2)
0.01 0.1 1 10 100
ME 474-674 Winter 2008 Slides 6 -11
Lead Polymer Foam Metal Foam Leather
Yield strength (elastic limit) (MPa)
0.01 0.1 1 10 100 1000
Fracture toughness (MPa.m^ 1/2)
0.01 0.1 1 10 100
Metal foam Flexible Polymer Foam (MD) Commercially pure lead Leather Copper Stainless steel Non age-hardening wrought Al-alloys Nickel
ME 474-674 Winter 2008 Slides 6 -12
Yield strength (elastic limit) (MPa)
0.01 0.1 1 10 100 1000
Fracture toughness (MPa.m^ 1/2)
0.01 0.1 1 10 100
Metal foam Commercially pure lead Lead alloys Copper Nickel Leather Flexible Polymer Foam (MD)
ME 474-674 Winter 2008 Slides 6 -13
Yield strength (elastic limit) (MPa)
0.01 0.1 1 10 100 1000
Fracture toughness (MPa.m^ 1/2)
0.01 0.1 1 10 100
Copper Nickel Tungsten carbides Silicon Silicon nitride Aluminum nitride Low alloy steel Medium carbon steel CFRP, epoxy matrix (isotropic)
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Yield strength (elastic limit) (MPa)
0.01 0.1 1 10 100 1000
Fracture toughness (MPa.m^ 1/2)
0.01 0.1 1 10 100
Copper Non age-hardening wrought Al-alloys Zinc die-casting alloys Nickel Stainless steel Zinc die-casting alloys Cast Al-alloys Bronze
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Select Materials - All Stages
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An application for short term thermal insulation is the rescue beacons for
These electronic devices do not function if the temperature drops below a
Therefore, to give the rescue operation the greatest chance of being effective,
The electronics have to be wrapped in an insulating blanket
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Thermal conductivity (W/m.K) 0.1 1 10 100
Rigid Polymer Foam (LD) Rigid Polymer Foam (MD) Flexible Polymer Foam (MD) Rigid Polymer Foam (HD)
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But is this the answer we are looking for? The answer is no! The problem requires that the time that it takes for the electronic package to cool
This is not a steady state problem. Therefore use 2nd law of heat conduction If the temperature at the surface is decreased suddenly, as in dropping the pilot
Where a is the thermal diffusivity
p
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2
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Thermal Diffusivity 1e-7 1e-6 1e-5 1e-4 Thermal conductivity (W/m.K) 0.1 1 10 100
Butyl Rubber Isoprene (IR) Isoprene (IR) Polychloroprene (Neoprene, CR)
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Kilns used for firing pottery are heated up from room temperature to the firing
There are two major factors that consume energy
The first can be minimized by reducing the thermal mass of the system, i.e.
The second can be minimized by reducing the heat loss through the wall by
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How can these apparently contradictory requirements be reconciled? Is there a material index that can capture both requirements?
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There are two sources of heat loss
1
2
p
2 1
p
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To minimize total heat loss, differentiate the above equation and set equal to zero
Substituting back into the equation for Q gives The material index to be maximized is
2 / 1 2 / 1
p
2 / 1 2 / 1
p
2 / 1 ) 2 / 1 (
p
−
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Select Materials - Stage 1 – limit stage
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Thermal diffusivity
1e-7 1e-6 1e-5 1e-4
Thermal conductivity (W/m.K)
0.1 1 10 100
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Thermal diffusivity
1e-7 1e-6 1e-5 1e-4
Thermal conductivity (W/m.K)
0.1 1 10 100
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Select Materials - All Stages 5 materials
Switching to the larger database gives over 60 materials.
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Thermal Diffusivity = Thermal conductivity / Specific heat / Density 1e-7 1e-6 1e-5 1e-4 Thermal conductivity (W/m.K) 0.1 1 10 100
Graphite (perpendicular to plane) Mullite (Al2O3-SiO2 alloys) Carbon (Vitreous) Graphite Foam (0.12) Alumina Foam (99.8% )(0.4) Carbon Foam (Reticulated, Vitreous)(0.05) Glass Ceramic (N11) Glass Ceramic - Slipcast Plaster of Paris Carbon Fiber Reinforced Carbon Matrix Composite (Vf:50% )
Additional criteria can be imposed