lyapunov exponent and integrated density of states for
play

Lyapunov exponent and integrated density of states for slowly - PowerPoint PPT Presentation

The Model First result Second result Thank you ! Lyapunov exponent and integrated density of states for slowly oscillating perturbations of periodic Schrdinger operators Asya M ETELKINA FernUniversitt in Hagen Saint-Petersburg July 2010


  1. The Model First result Second result Thank you ! Lyapunov exponent and integrated density of states for slowly oscillating perturbations of periodic Schrödinger operators Asya M ETELKINA FernUniversität in Hagen Saint-Petersburg July 2010 1 / 8

  2. The Model First result Second result Thank you ! The Model Operator H ( θ ) in L 2 ( R + ) associated to θ ∈ [ 0 , π ) : H ( θ ) = − d 2 dx 2 +[ V ( x )+ W ( x α )] (1) on D ( H ( θ )) = { f ∈ H 2 ( R + ) | f ( 0 ) cos θ + f ′ ( 0 ) sin θ = 0 } . Basic assumptions : ( V ) V ∈ L 2 , loc ( R ) and periodic V ( x + 1 ) = V ( x ) , ( W ) W is smooth and periodic function with W ( x + 2 π ) = W ( x ) . ( α ) α ∈ ( 0 , 1 ) . Remark : For α ∈ ( 0 , 1 ) the function W ( x α ) oscillates slowly at infinity : d dx ( W ( x α )) = lim x → ∞ ( x α − 1 W ′ ( x α )) = 0 . lim x → ∞ Additional assumptions : α ∈ ( 1 2 , 1 ) and W is analytic in S Y = {| ℑ z | < Y } . 2 / 8

  3. The Model First result Second result Thank you ! Resolvent matrix Schrödinger equation : H ( θ ) f ( x , E ) = Ef ( x , E ) is equivalent to matrix equation on resolvent matrix T ( x , y , E ) : d dxT ( x , y , E ) = A ( x , E ) T ( x , y , E ) with T ( y , y , E ) = I (2) � � 0 1 A ( x , E ) = and (3) V ( x )+ W ( x α ) − E 0 Consider a quasi-periodic (periodic) matrix equation depending on z and ε : d dxT z , ε ( x , y , E ) = A z , ε ( x , E ) T z , ε ( x , y , E ) with T z , ε ( y , y , E ) = I (4) � � 0 1 A z , ε ( x , E ) = and (5) V ( x )+ W ( ε x + z ) − E 0 3 / 8

  4. The Model First result Second result Thank you ! Approximation of the resolvent matrix 1 1 α . Pose x n = ( 2 π n ) Claim : There exist C and n 0 such that ∀ n > n 0 one can find ( z n , ε n ) such that : | W ( x α ) − W ( ε n x + z n ) | < C 1 sup (6) n x ∈ [ x n , x n + 1 ] Lemma (A. Metelkina) Suppose basic and additional assumptions are satisfied. ∃ ( z n , ε n ) such that for n big enough the resolvent matrix T ( x n + 1 , x n , E ) of (2) can be approched by the resolvent matrix T z n , ε n ( x n + 1 , x n , E ) of (4) 4 / 8

  5. The Model First result Second result Thank you ! Approximations of the resolvent matrix 2 Symmetries in A z , ε . V ( x ) = V ( x + 1 ) ⇒ [ V ( x + 1 )+ W ( ε ( x + 1 )+( z − ε ))] = [ V ( x )+ W ( ε z + x )] Consistancy condition : T z , ε ( x + 1 , E ) = T z − ε , ε ( x , E ) W ( ε x +( z + 2 π )) = W ( ε x + z ) ⇒ T z + 2 π , ε ( x , E ) satisfies (4) if T z , ε ( x , E ) does. Monodromy matrix M ( z , ε ) : T z + 2 π , ε ( x , E ) = T z , ε ( x , E ) M T ( z , ε , E ) (7) Theorem (A. Metelkina) Suppose basic and additional assumptions are satisfied. ∃ ( z n , ε n ) such that for n big enough the resolvent matrix T ( x n + 1 , x n , E ) of (2) can be approched by the transposed monodromy matrix M T ( z n , ε n , E ) associated to T z n , ε n ( x n + 1 , x n , E ) and defined in (7) 5 / 8

  6. The Model First result Second result Thank you ! Definitions of IDS and LE Let N D ( H l , E ) be the number of Dirichlet eigenvalues H in L 2 ( 0 , l ) . Definition (IDS) We call integrated density of states the following limit when it exists : N D ( H l , E ) k ( E ) = lim l l → ∞ T ( x , 0 , E ) be the resolvent matrix, solution of (2). Definition (LE) We call Lyapunov exponent the following limit when it exists : ln � T ( x , 0 , E ) � γ ( E ) = lim x → ∞ x 6 / 8

  7. The Model First result Second result Thank you ! Theorem : IDS and LE For E ∈ C + lets k p ( E ) be a principal branch of Bloch quasimomentum. For E ∈ R denote k p ( E ) its boudary values. Theorem (A. Metelkina) Suppose only basic assumptions are satisfied. For all energies E ∈ R the integrated density of states for H ( θ ) exists and is given by : � 2 π 1 k ( E ) = ℜ k p ( E − W ( x )) dx 2 π 2 0 For almost all E ∈ R the Lyapunov exponent for H ( θ ) exists and is given by : � 2 π γ ( E ) = 1 ℑ k p ( E − W ( x )) dx 2 π 0 7 / 8

  8. The Model First result Second result Thank you ! Thank you for your attention ! 8 / 8

Download Presentation
Download Policy: The content available on the website is offered to you 'AS IS' for your personal information and use only. It cannot be commercialized, licensed, or distributed on other websites without prior consent from the author. To download a presentation, simply click this link. If you encounter any difficulties during the download process, it's possible that the publisher has removed the file from their server.

Recommend


More recommend