Hyperbolic surfaces, cutting sequences, and continued fractions - - PowerPoint PPT Presentation

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Hyperbolic surfaces, cutting sequences, and continued fractions - - PowerPoint PPT Presentation

Hyperbolic surfaces, cutting sequences, and continued fractions Claire Merriman October 21, 2019 The Ohio State University merriman.72@osu.edu OCF Animation First frame of the animiation. Regular Continued Fractions Way to represent x >


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SLIDE 1

Hyperbolic surfaces, cutting sequences, and continued fractions

Claire Merriman October 21, 2019

The Ohio State University merriman.72@osu.edu

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SLIDE 2

OCF Animation

First frame of the animiation.

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SLIDE 3

Regular Continued Fractions

Way to represent x > 0 as

  • x = a0 +

1 a1 + 1 a2 + . . .

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SLIDE 4

Regular Continued Fractions

Way to represent x > 0 as

  • x = a0 +

1 a1 + 1 a2 + . . .

  • π = 3 +

1 7 + 1 15 + 1 1 + 1 292 + . . .

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SLIDE 5

Dynamics

Define T : [0, 1] → [0, 1] by T(x) =   

1 x −

  • 1

x

  • if x = 0

if x = 0 =   

1 x − k

for x ∈

  • 1

k+1, 1 k

  • if x = 0

. 1 a1 + 1 a2 + 1 a3 + . . . → 1 a2 + 1 a3 + 1 a4 + . . .

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SLIDE 6

Gauss map ...

1 9 1 8 1 7 1 6 1 5 1 4 1 3 1 2

1 1

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SLIDE 7

Natural Extension

Define ¯ T : [0, 1)2 → [0, 1)2 by ¯ T(x, y) =   

  • 1

x − k, 1 y+k

  • for x ∈
  • 1

k+1, 1 k

  • (0, y)

if x = 0 .

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SLIDE 8

Natural Extension

Define ¯ T : [0, 1)2 → [0, 1)2 by ¯ T(x, y) =   

  • 1

x − k, 1 y+k

  • for x ∈
  • 1

k+1, 1 k

  • (0, y)

if x = 0 .      1 a0 + 1 a1 + . . . , 1 a−1 + 1 a2 + . . .      →      1 a1 + 1 a2 + . . . , 1 a0 + 1 a1 + . . .     

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Natural extension domain

Plot of ¯ T n(x, 0) for 1500 values of x, 1 ≤ n ≤ 200

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SLIDE 10

Nakada α-continued fractions

Nakada (1981) introduced the α-continued fractions. Define Tα on [α − 1, α]: Tα(x) = 1 |x| − 1 |x| + 1 − α

  • = ǫ

x − a1 for ǫx ∈

  • 1

a1 − 1 + α, 1 a1 + α

  • x =

ǫ1 a1 + ǫ2 a2 + . . . .

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SLIDE 11

Nakada α-continued fractions

Nakada (1981) introduced the α-continued fractions. Define Tα on [α − 1, α]: Tα(x) = 1 |x| − 1 |x| + 1 − α

  • = ǫ

x − a1 for ǫx ∈

  • 1

a1 − 1 + α, 1 a1 + α

  • x =

ǫ1 a1 + ǫ2 a2 + . . . . When α = 1

2, π = 3 +

1 7 + 1 16 − 1 293 + . . .

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SLIDE 12

Gauss map

' ' ' ' ' '

α 1 α + 1

(1,+1)

1 α + 2

(2,+1)

1 α + 3

(3,+1)

α-1

(2,-1)

  • 1

α + 3

(3,-1)

... ...

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SLIDE 13

Natural extension

Natural extension defined on [α − 1, α) × Rα. (x, y) → ǫ x − a1, 1 a1 + ǫy

  • for ǫx ∈
  • 1

a1 − 1 + α, 1 a1 + α

    ǫ0 a0 + ǫ1 a1 + . . . , 1 a−1 + ǫ−1 a2 + . . .      →      ǫ1 a1 + ǫ2 a3 + . . . , 1 a0 + ǫ0 a1 + . . .     

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RCF Animation

Frame of the animation of the natural extension domain where α = .5.

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α-odd continued fractions

Boca-M (2019) introduced the α-odd continued fractions. Define ϕα on [α − 2, α] ϕα(x) = ǫ x − 2a1 + 1 for ǫx ∈

  • 1

2a1 + 1 + α, 1 2a1 − 1 + α

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SLIDE 16

α-odd continued fractions

' ' ' '

α 1 α + 1

(1,+1)

1 α + 3

(3,+1)

α-2

(1,-1)

  • 1

α + 3

(3,-1)

... ...

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SLIDE 17

OCF Animation

First frame of the animation of the natural extension domain with α = 1+

√ 5.

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SLIDE 18

Two stills from the animationof the natural extension domain,

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SLIDE 19

Farey Tessellation

H := {x + iy | y > 0} Connect two rational numbers p

q, p′ q′ iff pq′ − p′q = ±1.

1/2 2/3 1/3 3/2 5/3 4/3

  • 1/2
  • 2/3
  • 1/3
  • 3/2
  • 5/3
  • 4/3
  • 1

1 2

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SLIDE 20

Geodesics

Let S be the set of geodesics γ with endpoints

  • γ−∞ ∈ (−1, 0), γ∞ ≥ 1
  • γ−∞ ∈ (0, 1), γ∞ ≤ −1
  • 1/2
  • 2/3

1/2 2/3 1/3 3/2 5/3 4/3 5/2 7/3

  • 1

1 2 3

ξγ ηγ

γ- γ+

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SLIDE 21

Some segments of type L Some segments of type R

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SLIDE 22

Example

  • 1/2
  • 2/3

1/2 2/3 1/3 3/2 5/3 4/3 5/2 7/3

  • 1

1 2 3

ξγ ηγ

γ- γ+ R R L L R L

Cutting sequence . . . RRξγL2R1L3 . . .

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SLIDE 23

Theorem (Series, ’85) A geodesic from γ−∞ to γ∞ has two options:

  • γ−∞ ∈ (−1, 0), γ∞ ∈ (1, ∞). This geodesic has the coding

. . . Ln−2Rn−1ξγLn0Rn1Ln2 . . . γ−∞ = −[n−1, n−2, . . . ] and γ∞ = n0 + [n1, n2, . . . ]

  • γ−∞ ∈ (0, 1), γ∞ ∈ (−∞, −1). This geodesic has the coding

. . . Ln−2Ln−1ξγRn0Ln1Rn2 . . . γ−∞ = [n−1, n−2, . . . ] and γ∞ = −

  • n0 + [n1, n2, . . . ]
  • .
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SLIDE 24

Action on Upper Half Plane

Case 1, γ∞ > 1. Define ρ on S by (x, y) → (

1 a1−x , 1 a1−y ).

  • 1/2
  • 2/3
  • 3/2

1/2 2/3 1/3

  • 5/3
  • 1
  • 2

1

ξρ (γ) ηρ (γ) ρ(γ+) ρ(γ-) L L R L L R

. . . L1R2ξγL2ηγR1L3 · · · → L1R2L2ξρ(γ)R1ηρ(γ)L3 . . .

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SLIDE 25

Lehner expansions

Lehner (1994) defined continued fractions x ∈ [1, 2] x = a0 + eo a1 + e1 a2 + . . . (ai, ei) = (1, +1), (2, −1).

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Lehner expansions

Lehner (1994) defined continued fractions x ∈ [1, 2] x = a0 + eo a1 + e1 a2 + . . . (ai, ei) = (1, +1), (2, −1). Define L : [1, 2] → [1, 2] by L(x) =     

1 2−x

if x ∈

  • 1, 3

2

  • 1

x−1

if x ∈

  • 3

2, 2

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SLIDE 27

Tent map

(1,+1) (2,-1)

3 2

2 2

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SLIDE 28

Dajani and Kraaikamp (2000) introduced the Farey expansions for y ∈ [−1, ∞) y = f0 b0 + f1 b1 + . . . = (f0/b0)(f1/b1)(f2/b2) . . .

  • (fi/bi) = (+1/1), (−1/2).

π = (1/1)(−1/2)3(1/1)(−1/2)6(1/1)(−1/2)14 . . .

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SLIDE 29

Natural extension

L : [1, 2) × [−1, ∞) → [1, 2) × [−1, ∞) by

  • e0

x − a0 , e0 y + a0

  • =

    

  • −1

x−2, −1 y+2

  • x ∈
  • 1, 3

2

  • 1

x−1, 1 y+1

  • x ∈
  • 3

2, 2

  • .

     a0 + ǫ1 a1 + ǫ2 a2 + . . . , 1 a−1 + ǫ−1 a2 + . . .      →      a1 + ǫ2 a3 + . . ., 1 a0 + ǫ0 a1 + . . .     

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Geodesics

Connect backwards endpoint γ−∞ to forward endpoint γ∞ with γ Either

  • γ−∞ < 1, 1 < γ∞ < 2
  • γ−∞ − 1, −2 < γ∞ < −1
  • 2
  • 1

1 3/2 2 γ∞ γ-∞ ξγ ηγ

  R L L R L L

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SLIDE 31

Example

  • 2
  • 1

1 3/2 2 γ∞ γ-∞ ξγ ηγ

  R L L R L L

Cutting sequence . . . LRL2RξγLηγR . . .

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SLIDE 32

Converting to Lehner and Farey expansions

Read Lehner expansion of γ∞ starting at ξγ. Farey expansion of γ−∞ from right to left starting at ξγ. If the letter is the same as the previous (letter to the left), the digit is (2, −1), if it is different than the previous letter, the digit is (1, +1).

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SLIDE 33

Example

  • 2
  • 1

1 3/2 2 γ∞ γ-∞ ξγ ηγ

  R L L R L L

Cutting sequence . . . RRL2RξγLηγR . . . RξγLR . . . ❀ [ [(1, +1), (1, +1), . . . ] ] . . . LRLLRξγ ❀ (+1/1)(−1/2)(+1/1)(−1/2) . . .

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Action on Upper Half Plane

Case 1, 1 < γ∞ < 2. Define ρ on ±((1, 2) × (−∞, 1)) by (x, y) →

  • 1

a1−x , 1 a1−y

  • .
  • 2
  • 1

1 3/2 2 γ∞ γ-∞ ξγ ηγ

  R L L R L

ρ(γ∞) ρ(γ-∞) ρ(ηγ)=ξρ (γ)

. . . LRL2RξγLηγR · · · → . . . LRL2RLξρ(γ)Rηρ(γ) . . .

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Thank You

Questions?