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High-frequency instabilities of small-amplitude solutions of Hamiltonian PDEs Bernard Deconinck Department of Applied Mathematics University of Washington bernard@amath.washington.edu Hamiltonian PDEs: Analysis, Computations and Applications


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High-frequency instabilities of small-amplitude solutions of Hamiltonian PDEs

Bernard Deconinck

Department of Applied Mathematics University of Washington bernard@amath.washington.edu Hamiltonian PDEs: Analysis, Computations and Applications January 10-12, 2014

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Acknowledgements 1

I have known Walter a long time

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Acknowledgements 1

Actually, for about 15 years

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Acknowledgements 2

◮ Joint work with Olga Trichtchenko (UW) ◮ BD and Olga Trichtchenko, High-frequency instabilities of

small-amplitude solutions of Hamiltonian PDEs, To be submitted, 2014

◮ Support from the National Science Foundation

(NSF-DMS-1008001)

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The big picture

Consider the Hamiltonian PDE ut = J δH δu , (1) posed in a suitable function space of periodic functions. We examine traveling-wave solutions u(x, t) = U(x − ct) of this

  • system. These satisfy

− cUx = J δH δU . (2)

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Assumptions

  • 1. For a range of c values U = 0 is a solution of (2).

c Amplitude

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Assumptions

  • 1. For a range of c values U = 0 is a solution of (2).

c Amplitude

  • 2. The linearization around u = 0 of (1) is dispersive.
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Digression

◮ It is possible for linear, constant coefficient

Hamiltonian PDEs to be non-dispersive. Example. H = 2π qxpxdx, J =

  • 1

−1

  • :

qt = qxx, pt = −pxx.

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Digression

◮ It is possible for linear, constant coefficient

Hamiltonian PDEs to be non-dispersive. Example. H = 2π qxpxdx, J =

  • 1

−1

  • :

qt = qxx, pt = −pxx.

◮ Is it possible for linear, constant coefficient, dispersive

PDEs to be non-Hamiltonian?

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The big picture, continued

◮ As we will see, the u = 0 solution is spectrally

(neutrally) stable.

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The big picture, continued

◮ As we will see, the u = 0 solution is spectrally

(neutrally) stable.

◮ As we increase the amplitude of the solution, the

eigenvalues of the spectral stability problem move continuously in C.

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The big picture, continued

◮ Due to the quadrufold symmetry of the problem, the

  • nly way for eigenvalues to leave the imaginary axis is

by collision.

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The big picture, continued

◮ Given J and H, we shall establish necessary conditions

for eigenvalue collisions to result in eigenvalues off the imaginary axis, resulting in spectral instabilities of small-amplitude traveling wave solutions.

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The big picture, continued

◮ The goal is to obtain conditions that are easily used

and verified, at the expense of the precision of the conclusions reached. In other words, the goal is usability over rigor.

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The big picture, continued

◮ The goal is to obtain conditions that are easily used

and verified, at the expense of the precision of the conclusions reached. In other words, the goal is usability over rigor. Almost all conclusions are formulated in terms of the dispersion relation of the linear problem.

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The big picture, continued

◮ All calculations take place at the bifurcation point of

the trivial solution branch. By continuity, any stability conclusion holds for solutions on the bifurcation branch of small, but nonzero amplitude.

c Amplitude

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The big picture, continued

◮ All calculations take place at the bifurcation point of

the trivial solution branch. By continuity, any stability conclusion holds for solutions on the bifurcation branch of small, but nonzero amplitude.

c Amplitude

◮ In effect, the theory is finite dimensional, as only a

finite number of eigenvalues participate in a collision.

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Some literature

◮ MacKay & Saffman (1986): a criterion for the onset of

instability through the collision of eigenvalues in the water wave problem.

◮ MacKay (1987): the finite-dimensional case.

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Scalar Hamiltonian PDES with J = ∂x

(Examples: KdV, Whitham, . . . )

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Scalar Hamiltonian PDES with J = ∂x

(Examples: KdV, Whitham, . . . ) We consider equations whose linearization is of the form ut = −iω(−i∂x)u, where ω(k) (real valued) is the dispersion relation: ω(k) =

  • n=0

αnk2n+1, αj ∈ R, and H = −1 2 2π

  • n=0

αnu2

nxdx.

Note that 2π udx is a Casimir.

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Scalar Hamiltonian PDES with J = ∂x

In a moving coordinate frame, ut − cux = −iω(−i∂x)u ⇒ ut = −iΩ(−i∂x)u, with Ω(k) = ω(k) − kc.

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Scalar Hamiltonian PDES with J = ∂x

Step 1. Bifurcation point. We need a singular Jacobian, requiring Ω(k) = 0 ⇒ c = ω(k) k , the phase speed.

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Scalar Hamiltonian PDES with J = ∂x

Step 1. Bifurcation point. We need a singular Jacobian, requiring Ω(k) = 0 ⇒ c = ω(k) k , the phase speed. For periodic solutions, we need k = N, integer, so that c = ω(N) N . Typically, we choose N = 1.

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Scalar Hamiltonian PDES with J = ∂x

Step 2. Stability analysis. Let u(x, t) = eλtU(x) + c.c., with U(x) =

  • n=−∞

anei(n+µ)x, with µ ∈ [−1/2, 1/2). We get λµ

n = −iΩ(n + µ). ◮ All λ(µ) n

are imaginary. Thus the zero solution is neutrally spectrally stable.

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Scalar Hamiltonian PDES with J = ∂x

Step 3. Eigenvalue collisions. We need λ(µ)

n

= λ(µ)

m

⇒ ω(n + µ) − ω(m + µ) n − m = ω(N) N . Graphically, this is a condition expressing the equality of two slopes.

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N ω(m + µ) ω(n + µ) ω(k) k n + µ m + µ

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Scalar Hamiltonian PDES with J = ∂x

Step 4. Krein signature.

◮ The contribution to the Hamiltonian from a single

mode is ∼ |an|2Ω(n + µ)/(n + µ). The Krein signature

  • f this mode is the sign of this contribution.
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Scalar Hamiltonian PDES with J = ∂x

Step 4. Krein signature.

◮ The contribution to the Hamiltonian from a single

mode is ∼ |an|2Ω(n + µ)/(n + µ). The Krein signature

  • f this mode is the sign of this contribution.

◮ In order for two colliding eigenvalues to leave the

imaginary axis, it is necessary that they have opposite Krein signature.

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Scalar Hamiltonian PDES with J = ∂x

Step 4. Krein signature.

◮ The contribution to the Hamiltonian from a single

mode is ∼ |an|2Ω(n + µ)/(n + µ). The Krein signature

  • f this mode is the sign of this contribution.

◮ In order for two colliding eigenvalues to leave the

imaginary axis, it is necessary that they have opposite Krein signature.

◮ After simplification, this requires mn < 0.

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Scalar Hamiltonian PDES with J = ∂x: Summary

Consider a Hamiltonian PDEs with J = ∂x, whose linearization has the real-valued dispersion relation ω(k). In order for small-amplitude solutions of period 2πN to be susceptible to high-frequency instabilities, it is necessary that there exist m, n ∈ Z and µ ∈ [−1/2, 1/2) such that

◮ λ(µ) n

= i(n + µ) ω(N)

N

− iω(n + µ) = 0.

◮ (Collision condition)

ω(n + µ) − ω(m + µ) n − m = ω(N) N .

◮ (Krein signature condition) mn < 0.

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  • Example. KdV-like equations.

Consider equations of the form ut = ∂x(uxx + N(u)), where limǫ→0 N(ǫu)/ǫ = 0. Then ω = k3. ω(k) k

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  • Example. KdV-like equations.

Consider equations of the form ut = ∂x(uxx + N(u)), where limǫ→0 N(ǫu)/ǫ = 0. Then ω = k3. ω(k) k µ λ(µ)

n

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  • Example. KdV-like equations.

◮ There are no collisions away from λ = 0. Thus

small-amplitude periodic solutions of KdV-like equations are not susceptible to high-frequency instabilities.

◮ This result includes KdV, mKdV, generalized KdV,

etc.

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  • Example. KdV-like equations.

◮ There are no collisions away from λ = 0. Thus

small-amplitude periodic solutions of KdV-like equations are not susceptible to high-frequency instabilities.

◮ This result includes KdV, mKdV, generalized KdV,

etc.

◮ Solutions of superKdV-like equations are susceptible

to high-frequency instabilities. ut = uxxx + αuxxxxx + nonlinear.

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  • 2. Two-dimensional Hamiltonian PDEs with

canonical J

(Examples: Sine-Gordon, the water wave problem, . . . ) Here J =

  • 1

−1

  • ,

and we consider equations of the form qt = δH δp , pt = −δH δq .

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2-D Hamiltonian PDEs with canonical J

The Hamiltonian of their linearization can be written as H = 2π

  • 1

2

  • j=0

βjp2

jx + 1

2

  • j=0

γjq2

jx + p ∞

  • j=0

αjqjx

  • dx,

so that qt =

  • j=0

αjqjx +

  • j=0

(−1)jβjp2jx, pt = −

  • j=0

(−1)jγjq2jx −

  • j=0

(−1)jαjpjx.

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2-D Hamiltonian PDEs with canonical J

The dispersion relation is given by det iω + ∞

j=0 αj(ik)j

j=0 βjk2j

− ∞

j=0 γjk2j

iω − ∞

j=0 αj(−1)j(ik)j

  • = 0,

which gives ω1(k) and ω2(k), both real for real k. In a moving coordinate frame, the Hamiltonian has the extra term c 2π pqxdx.

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2-D Hamiltonian PDEs with canonical J

Step 1. Bifurcation point. As before, the bifurcation points from the trivial solution are found by finding for which value of c the Jacobian is

  • singular. This time, there are two solutions.

c1,2 = ω1,2(k) k = ω1,2(N) N . since k ∈ Z, for periodic solutions. c Amplitude

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2-D Hamiltonian PDEs with canonical J

Step 2. Stability analysis. Working with the first branch of solutions, we obtain λ(µ)

n,j = i(n + µ)c1 − iωj(n + µ),

for j = 1, 2, µ ∈ [−1/2, 1/2), n ∈ Z.

◮ All λ(µ) n,j are imaginary. Thus the zero solution is

neutrally spectrally stable.

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2-D Hamiltonian PDEs with canonical J

Step 3. Eigenvalue collisions. We need λ(µ)

n,j1 = λ(µ) m,j2

⇒ ωj1(n + µ) − ωj2(m + µ) n − m = ω1(N) N . Once more, this is a condition expressing the equality of two slopes.

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N ω(k) k n + µ m + µ ω1(k) ω2(k)

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2-D Hamiltonian PDEs with canonical J

Step 4. Krein signature.

◮ The linear system may be written as ut = JLu, where

L is the second variation of H. The Krein signature of the v mode may also be computed as the sign of v∗Lv.

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2-D Hamiltonian PDEs with canonical J

Step 4. Krein signature.

◮ The linear system may be written as ut = JLu, where

L is the second variation of H. The Krein signature of the v mode may also be computed as the sign of v∗Lv.

◮ For our setting, one finds that the signature of the

eigenmode (Q(µ)

n,j, P (µ) n,j )T is the sign of

λ(µ)

n,j det

  • Q(µ)

n,j

P (µ)

n,j

Q(µ)

n,j ∗

P (µ)

n,j ∗

  • .
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2-D Hamiltonian PDEs with canonical J

◮ Explicitly, the necessary condition for opposite Krein

signatures is

  • j=0

γj(n + µ)2j

  • j=0

γj(m + µ)2j×

  • ωj1(n + µ) +

  • j=0

α2j+1(−1)j(n + µ)2j+1

  • ×
  • ωj2(m + µ) +

  • j=0

α2j+1(−1)j(m + µ)2j+1

  • < 0.
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2-D Hamiltonian PDEs with canonical J: Summary

Consider a Hamiltonian PDEs with canonical J, whose linearization has the quadratic Hamiltonian H = 2π

  • 1

2

j=0 βjp2 jx + 1 2

j=0 γjq2 jx + p ∞ j=0 αjqjx

  • dx

with real-valued dispersion relations ω1,2(k). In order for small-amplitude solutions of period 2πN to be susceptible to high-frequency instabilities, it is necessary that there exist j1,2 ∈ (1, 2), m, n ∈ Z and µ ∈ [−1/2, 1/2) such that

◮ (Collision condition)

ωj1(n + µ) − ωj2(m + µ) n − m = ω(N) N .

◮ (Krein signature condition) See previous slide.

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  • Example. The water wave problem.

The linearized water wave problem is ηt = −i tanh(−ih∂x)qx, qt = −gη, with H = 2π 1 2q(−i tanh(−ih∂x)qx) + 1 2gη2

  • dx,

and ω2 = gk tanh(kh).

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  • Example. The water wave problem.

ω(k) k µ λ(µ)

j,n

→ there are collisions!

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  • Example. The water wave problem.

◮ The Krein condition gives ωj1ωj2g2 < 0, which is

always satisfied.

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  • Example. The water wave problem.

◮ The Krein condition gives ωj1ωj2g2 < 0, which is

always satisfied.

◮ This confirms that for the water wave problem all

colliding eigenvalues leave the imaginary axis.

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  • Example. The water wave problem.

◮ The Krein condition gives ωj1ωj2g2 < 0, which is

always satisfied.

◮ This confirms that for the water wave problem all

colliding eigenvalues leave the imaginary axis.

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  • Example. The Whitham equation vs. the water

wave problem.

Consider ut + ∂xN(u) + ∞

−∞

K(x − y)uy(y, t)dy = 0 ⇒ ut + ∂x

  • N(u) + ∂x

−∞

K(x − y)u(y, t)dy

  • = 0,

where K(x) = 1 2π ∞

−∞

c(k)eikxdk, with c(k) = ω(k)/k =

  • g tanh(kh)/k.
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  • Example. The Whitham equation vs. the water

wave problem.

Consider ut + ∂xN(u) + ∞

−∞

K(x − y)uy(y, t)dy = 0 ⇒ ut + ∂x

  • N(u) + ∂x

−∞

K(x − y)u(y, t)dy

  • = 0,

where K(x) = 1 2π ∞

−∞

c(k)eikxdk, with c(k) = ω(k)/k =

  • g tanh(kh)/k. The Hamiltonian of

the linearized equation is H = −1 2 ∞

−∞

−∞

K(x − y)u(x, t)u(y, t)dxdy.

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  • Example. The Whitham equation

µ λ(µ)

j,n ◮ There are no collisions (except at λ = 0). ◮ The Whitham equation does not capture the

high-frequency instabilities of small-amplitude solutions of the water wave problem.

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Thank you! Questions? Happy Birthday, Walter!