Effects of magnetic fields on q q interactions [1607.08160] - - PowerPoint PPT Presentation

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Effects of magnetic fields on q q interactions [1607.08160] - - PowerPoint PPT Presentation

Effects of magnetic fields on q q interactions [1607.08160] C.Bonati 1 , M.DElia 1 , M.Mariti 1 , M.Mesiti 1 , F.Negro 1 , A.Rucci 1 , F.Sanfilippo 2 1 Department of Physics of University of Pisa and INFN Pisa, Italy 2 School of Physics and


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Effects of magnetic fields on q¯ q interactions

[1607.08160]

C.Bonati1, M.D’Elia1, M.Mariti1, M.Mesiti1, F.Negro1, A.Rucci1, F.Sanfilippo2

1Department of Physics of University of Pisa and INFN Pisa, Italy 2School of Physics and Astronomy, University of Southampton, UK

Lattice 2016, 34th International Symposium

  • n Lattice Field Theory

28 July 2016

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table of contents

1

Introduction

2

Effects of the magnetic field on the static potential at T=0

3

What happens at finite temperatures? (T < Tc)

4

Conclusions

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intro physical conditions

QCD with strong magnetic fields eB ≃ m2

π ∼ 1015−16 T

Non-central heavy ion collisions with eB ∼ 1015T [Skokov et al. ’09] Possible production in early universe eB ∼ 1016T [Vachaspati ’91] In heavy ion collisions Expected eB ≃ 0.3 GeV2 at LHC in Pb+Pb at √sNN=4.5TeV and b=4fm Timescales depend on thermal medium properties (most pessimistic case: 0.1-0.5 fm/c) Spatial distribution of the field and lifetime are still debated

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intro turning on the B field

An external magnetic field B on the lattice is introduced through abelian parallel transports uµ(n) Abelian phases enter the Lagrangian by modifying the covariant derivative Uµ(n) → Uµ(n)uµ(n) External field is fixed: non-propagating fields, no kinetic term Periodic boundary conditions lead to the quantization condition |qmin|B = 2πb a2NxNy b ∈ Z

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intro static potential

In the confining phase at low temperatures, the Q ¯ Q interaction is well described by the Cornell potential VC(r) = −α r + σr + V0 σ ≃ (440MeV)2 α ∼ 0.4 On the lattice: At T=0 it can be extracted from the Wilson loop aV(a n) = − lim

nt→∞ log

W( n, nt + 1) W( n, nt)

  • For T>0 from Polyakov loop correlators

F(a n, T) ≃ −aNt logTrL†( r + n)TrL( n) what about the effects of B on the potential? (a first study: [Bonati et al. ’14])

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T=0 setup and continuum results at B=0

◆✉♠❡r✐❝❛❧ s❡t✉♣

  • tr❡❡✲❧❡✈❡❧ ✐♠♣r♦✈❡❞ ❣❛✉❣❡ ❛❝t✐♦♥
  • ◆f❂✷✰✶ r♦♦t❡❞ st❛❣❣❡r❡❞ ❢❡r♠✐♦♥s ✰ st♦✉t ✐♠♣r♦✈❡♠❡♥t
  • ❢♦✉r ❧❛tt✐❝❡s ✹✽3×✾✻✱ ✹✵4✱ ✸✷4 ❛♥❞ ✷✹4
  • s♣❛❝✐♥❣ ❛ ≃ ✵✳✶ ❢♠ t♦ ❛ ≃ ✵✳✷✹ ❢♠
  • s✐♠✉❧❛t✐♦♥s ❛t ♣❤②s✐❝❛❧ q✉❛r❦ ♠❛ss❡s

Parameters extracted from the continuum limit at B = 0 α = 0.395(22) √σ = 448(20) MeV r0 = 0.489(20) fm

0.01 0.02 0.03 0.04 0.05

a

2 [fm 2]

340 360 380 400 420 440 460 480

σ

1/2 [MeV]

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T=0 angular dependence

Turning on a constant uniform external field: residual rotation symmetry around B survives. Our ansatz: V(r, θ) = −α(θ, B) r + σ(θ, B)r + V0(θ, B) with θ angle between quarks direction and B. Angular dependence in Fourier expansion: O(θ, B) = ¯ O(B)

  • 1 −
  • n=1

cO

2n(B) cos(2nθ)

  • O = α, σ, V0

General features: Assumption: V(r, θ) is in the Cornell form ∀θ c2n+1 terms vanish ( B inversion θ → π − θ)

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T=0 angular dependence

Some details: fixed |e|B ∼ 1.0 GeV2 on two lattices aL ∼ 5 fm (| b| = 32) Wilson loop averaged separately on orthogonal axes Access to 8 angles using three B orientations Results: potential is anisotropic and V(r, θ) increases with θ good description in terms of c2’s only (∼ 0.2 − 0.3) ¯ O(B) compatible with values at B = 0

483 × 96 0.3 0.45 0.6 0.75 0.9 1.05 1.2 r [fm] 600 800 1000 1200 1400 1600 1800 V(r) [MeV] θ = 0° θ = 25° θ = 39° θ = 56° θ = 90° 0.125 0.25 0.375 0.5

θ

  • 1

1

(σ(θ)−σ)/c2

σ

a = 0.1535 fm a = 0.0989 fm

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T=0 anisotropy in the continuum

Questions: Does the anisotropy survive when a → 0? Dependence to B? Simplify the task: Angular dependence is fully described by the lowest coefficients c2s = ⇒ All the informations accessed by studying the potential along two directions only For each O = σ, α, V0 we can study its anisotropy (with B ˆ z) δO(B) = OXY(B) − OZ(B) OXY(B) + OZ(B) then δO ≃ cO

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T=0 anisotropy in the continuum

Continuum extrapolation using cO

2 = AO(1 + COa2)(|e|B)DO(1+EOa2)

O = σ, α, V0

0.25 0.5 0.75 1 1.25

eB [GeV

2]

0.1 0.2 0.3 0.4 0.5

c

σ 2

a = 0.2173 fm a = 0.1535 fm a = 0.1249 fm a = 0.0989 fm

0.25 0.5 0.75 1 1.25

eB [GeV

2]

  • 0.5
  • 0.4
  • 0.3
  • 0.2
  • 0.1

c

α 2

a = 0.2173 fm a = 0.1535 fm a = 0.1249 fm a = 0.0989 fm

Results: anisotropy cσ

2 of the string tension survives a → 0

2 and cV0 2 compatible with zero

¯ O(B) all compatible with values at B = 0

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T>0 effects on the free energy

what about (not so) high temperatures? ❙❡t✉♣✿

  • ❋✐①❡❞ ❛❂✵✳✵✾✽✾ ❢♠ ♦♥

❧❛tt✐❝❡s ✹✽3×◆t ✇✐t❤ ◆t❂✶✹✱✶✻✱✷✵ ✭❚ ❚c✮

  • ❙❡✈❡r❛❧ ♠❛❣♥❡t✐❝ q✉❛♥t❛

❜❂✵ t♦ ❜❂✻✹ ✇✐t❤ ❇✴✴③ Results: Anisotropy still visible but disappears at large r String tension σ decreases Cornell form fits only at small B

T=99.8 MeV 0.2 0.3 0.4 0.5 0.6 0.7 0.8

r [fm]

750 1000 1250 1500

FQQ(r) [MeV] |e|B = 0.00 GeV

2 (XYZ)

|e|B = 0.76 GeV

2 (XY)

|e|B = 0.76 GeV

2 (Z)

|e|B = 2.08 GeV

2 (XY)

|e|B = 2.08 GeV

2 (Z)

0,1 0,2 0,3 0,4 0,5 0,6 0,7 0,8 0,9 1

|e|B [GeV

2]

100 200 300 400 500 600

σ

1/2 [MeV]

T = 99.8 MeV (XY) T = 99.8 MeV (Z) T = 124.7 MeV (XY) T = 124.7 MeV (Z) T = 142.5 MeV (XY) T = 142.5 MeV (Z)

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T>0 effects on the free energy

From our results: Decrease of the free energy as B grows The effect is enhanced as T reaches Tc This is compatible with a decrease of Tc due to B [Bali et al.’12] Suppression of confining properties is evident before the appearance of inverse chiral magnetic catalysis Hence it seems to be the dominant phenomenon

T=124.7 MeV 0.2 0.3 0.4 0.5 0.6 0.7 0.8

r [fm]

750 1000 1250 1500

FQQ(r) [MeV] |e|B = 0.00 GeV

2 (XYZ)

|e|B = 0.52 GeV

2 (XY)

|e|B = 0.52 GeV

2 (Z)

|e|B = 1.04 GeV

2 (XY)

|e|B = 1.04 GeV

2 (Z) 0.2 0.4 0.6 0.8 1

|e|B [GeV

2]

  • 0.1

0.1 0.2 0.3

〈ψ _ ψ〉

r

T = 99.8 MeV T = 124.7 MeV T = 142.5 MeV

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conclusions and summary

Investigation of the effect of B on the Q ¯ Q interaction [arXiv:1607.08160] The static potential becomes anisotropic V(r) → V(r, θ, B) Genuine effects in the continuum limit Modifications mostly due to the string tension σ → σ(B, θ) ≃ σ

  • 1 − cσ

2 (B) cos 2θ

  • Anisotropy still visible at T > 0

Observations agree picture with deconfinement catalysis Possible implications: In meson production in heavy ion collisions [Guo et al. ’15] Heavy meson spectrum c¯ c and b¯ b [Alford and Strickland ’13, Bonati et al ’15]

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conclusions and summary

Investigation of the effect of B on the Q ¯ Q interaction [arXiv:1607.08160] The static potential becomes anisotropic V(r) → V(r, θ, B) Genuine effects in the continuum limit Modifications mostly due to the string tension σ → σ(B, θ) ≃ σ

  • 1 − cσ

2 (B) cos 2θ

  • Anisotropy still visible at T > 0

Observations agree picture with deconfinement catalysis Possible implications: In meson production in heavy ion collisions [Guo et al. ’15] Heavy meson spectrum c¯ c and b¯ b [Alford and Strickland ’13, Bonati et al ’15]

THANK YOU

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backup magnetic field on the lattice

With B ˆ z, a possible choice of the abelian links is uf

i; y = eia2qf Bzix

uf

i; x|ix=Lx = e−ia2qf LxBziy

and all the other equal to 1. A general B = (Bx, By, Bz): The quantization condition |qmin|B = 2πb a2NxNy b ∈ Z applies separately along each coordinate axis. If Nx = Ny = Nz the condition is the same and hence

  • B ∝

b = (bx, by, bz) Phase in the fermion matrix is the product

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backup anisotropy at T=0

The O(B) values are accessible computing the quantities RO(|e|B) = OXY(|e|B) + OZ(|e|B) 2O(|e|B = 0) = ¯ O(|e|B) O(|e|B = 0)

  • 1 −
  • n ❡✈❡♥

cO

2n

¯ O(|e|B) O(|e|B = 0) and are compatible with those at B = 0

0.25 0.5 0.75 1 1.25

eB [GeV

2]

0.8 0.9 1 1.1 1.2 1.3

α(B)/α(0) a = 0.2173 fm a = 0.1535 fm a = 0.1249 fm a = 0.0989 fm

0.25 0.5 0.75 1 1.25

eB [GeV

2]

0.9 0.95 1 1.05 1.1

σ(B)/σ(0) a = 0.2173 fm a = 0.1535 fm a = 0.1249 fm a = 0.0989 fm

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backup large B

Extension to large fields (at a = 0.0989 fm on 483 × 96) longitudinal string tension seems to vanish for |e|B ∼ 4 GeV2 problem: cut-off effects at |e|B ∼ 1/a2 ∼ 4 GeV2

1 2 3 4

eB [GeV

2]

0.5 1 1.5

σ(B) / σ(0) a = 0.0989 fm (XY) a = 0.0989 fm (Z)

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