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Section 6: Kinematics Section 6: Kinematics 6-1 Biomechanics - - PowerPoint PPT Presentation

Section 6: Kinematics Section 6: Kinematics 6-1 Biomechanics - angular kinematics Same as linear kinematics, but There is one vector along th the moment arm. t There is one vector F RMA perpendicular to the perpendicular


  1. Section 6: Kinematics Section 6: Kinematics 6-1

  2. Biomechanics - angular kinematics • Same as linear kinematics, but… • There is one vector along th the moment arm. t • There is one vector F RMA perpendicular to the perpendicular to the moment arm. MA F RD F r r 6-2 From: Legh

  3. Translational vs Rotational Translational vs Rotational • Li Linear momentum t • A Angular momentum l t = = mass × velocity inertia × angular velocity • d/dt (linear momentum) = • d/dt (angular momentum) applied forces = applied torques li d t • d/dt (position) = • d/dt (attitude) linear momentum/mass = “angular momentum/inertia” 6-3 From: Hall

  4. Vectors Vectors • Remember, Vectors Remember, Vectors are representative of the MAGNITUDE of a resultant FORCE 6-4 From: Legh F resultant

  5. Vectors Vectors • Remember, Vectors Remember, Vectors are representative of the MAGNITUDE of the resultant FORCE F M M F UR F compression F F distraction F DR 6-5 From: Legh F R

  6. Vectors Vectors • A vector is an abstract mathematical object with two properties: length or object with two properties: length or magnitude, and direction 6-6 From: Hall

  7. Moment Arm Moment Arm • The MOMENT ARM (M) ( ) is the perpendicular distance from the line of resultant force to the fulcrum (joint axis), A, or F M the distance from axis of rotation to the point of p F F EF muscle insertion, B. A B 6-7 From: Legh

  8. Torque Torque • Torque, or rotational q force, is a product of the rotational component(F ur ) x the moment arm, or the resultant force of muscular contraction (F M) F M x perpendicular distance p p M from F M to axis of F EF rotation. M NCF M R F F ditaction F DR 6-8 From: Legh F R

  9. Biomechanics Biomechanics Class III Lever Class III Lever The muscular force is between the fulcrum and the the fulcrum and the resistance force. The most common. The least efficient The least efficient. 6-9 From: Legh

  10. Angular Kinematic Analysis Angular Kinematic Analysis • Angular Kinematics g – Description of the circular motion or rotation of a body • Motion described in terms of (variables): – Angular position and displacement – Angular velocity – Angular acceleration • Rotation of body segments – e.g. Flexion of forearm about transverse axis through elbow joint centre centre • Rotation of whole body – e.g. Rotation of body around centre of mass (CM) during somersaulting somersaulting 6-10 From: Biolab

  11. Absolute and Relative Angles Absolute and Relative Angles • Absolute angles Absolute angles – Angle of a single body segment, relative to (normally) a right horizontal line (e.g. trunk, head, thigh) , , g ) • Relative Angles – Angle of one segment – Angle of one segment relative to another (e.g. knee, elbow, ankle) kl ) 6-11 From: Biolab

  12. Units of Measurement Units of Measurement • Angles are expressed in one of the following units: the following units: • Revolutions (Rev) arc ( d ) – Normally used to quantify body rotations in diving gymnastics rotations in diving, gymnastics θ etc. – 1 rev = 360º or 2 π radians radius ( r ) • Degrees (º) g ( ) – Normally used to quantify angular position, distance and displacement • • Radians (Rad) Radians (Rad) – Normally used to quantify d angular velocity and acceleration θ 1 radian = = – Convert degrees to radians by r r dividing by 57 3 dividing by 57.3 6-12 From: Biolab

  13. Method of Problem Solution Method of Problem Solution • Problem Statement : • Solution Check : Includes given data, specification of - Test for errors in reasoning by what is to be determined and a figure what is to be determined, and a figure verifying that the units of the verifying that the units of the showing all quantities involved. computed results are correct, • Free-Body Diagrams : - test for errors in computation by Create separate diagrams for each of Create separate diagrams for each of substituting given data and computed substituting given data and computed the bodies involved with a clear results into previously unused indication of all forces acting on equations based on the six principles, each body. y - always apply experience and physical y pp y p p y • Fundamental Principles : intuition to assess whether results seem The six fundamental principles are “reasonable” applied to express the conditions of rest or motion of each body. The rules of algebra are applied to solve the equations for the unknown quantities. titi 6-13 From: Rabiei, Chapter 1

  14. Free Body Diagrams y g • Space diagram represents the sketch of th the physical problem. h i l bl The free body Th f b d diagram selects the significant particle or points and draws the force system on or points and draws the force system on that particle or point. • Steps: • Steps: • 1. Imagine the particle to be isolated or cut free from its surroundings cut free from its surroundings. Draw or Draw or sketch its outlined shape. 6-14 From: Ekwue

  15. Free Body Diagrams Contd. • 2 2. Indicate on this sketch all the forces Indicate on this sketch all the forces that act on the particle. • These include active forces • These include active forces - tend to set tend to set the particle in motion e.g. from cables and weights and reactive forces caused by weights and reactive forces caused by constraints or supports that prevent motion motion. 6-15 From: Ekwue

  16. Free Body Diagrams Contd. • 3 3. Label Label known known forces forces with with their their magnitudes and directions. use letters to represent magnitudes and directions of represent magnitudes and directions of unknown forces. • Assume direction of force which may be • Assume direction of force which may be corrected later. 6-16 From: Ekwue

  17. Free Body Diagrams Free Body Diagrams • Most important analysis tool Most important analysis tool • Aids in identification of external forces • Procedure • Procedure – Identify the object to be isolated – Draw the object isolated (with relevant – Draw the object isolated (with relevant dimensions) – Draw vectors to represent all external forces p 6-17 From: Gabauer

  18. Free Body Diagrams Free Body Diagrams • Internal/External Force Internal/External Force – Depends on choice of object Person + Chair Person Only W T W P R C R F R C R C R F 6-18 From: Gabauer

  19. Free-Body Diagram First step in the static equilibrium analysis of a rigid body is identification of all forces acting on the body with a free-body diagram. • Select the extent of the free-body and detach it from the ground and all other bodies. • Indicate point of application, magnitude, and direction of external forces, including the rigid body weight. • Indicate point of application and assumed direction of unknown applied forces. These usually consist of reactions through which the ground and other bodies oppose the possible motion of the rigid body. • Include the dimensions necessary to compute • Include the dimensions necessary to compute the moments of the forces. 6-19 From: Rabiei, Chapter 4

  20. Homework Problem 6.1 SOLUTION: • Create a free-body diagram for the crane. • Determine B by solving the equation for the sum of the moments of all forces about A . Note there will be no contribution from the unknown reactions at A . • Determine the reactions at A by • Determine the reactions at A by A fixed crane has a mass of 1000 kg solving the equations for the sum of and is used to lift a 2400 kg crate. It all horizontal force components and is held in place by a pin at A and a p y p all vertical force components all vertical force components. rocker at B . The center of gravity of • Check the values obtained for the the crane is located at G . reactions by verifying that the sum of Determine the components of the Determine the components of the the moments about B of all forces is the moments about B of all forces is reactions at A and B . zero. 6-20 From: Rabiei, Chapter 4

  21. Sample Problem 6 2 Sample Problem 6.2 SOLUTION: • Create a free-body diagram of the joist. Note that the joist is a 3 force body acted upon by the rope, its weight, and the reaction at A . • The three forces must be concurrent for static equilibrium. Therefore, the reaction A man raises a 10 kg joist, of R must pass through the intersection of the p g length 4 m, by pulling on a rope. lines of action of the weight and rope forces. Determine the direction of the Find the tension in the rope and reaction force R . the reaction at A . • Utilize a force triangle to determine the magnitude of the reaction force R . 6-21 From: Rabiei, Chapter 4

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