RHIC Spin Flipper Commissioning M. Bai, M. Brennan, C. Dawson, R. - - PowerPoint PPT Presentation

rhic spin flipper commissioning
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RHIC Spin Flipper Commissioning M. Bai, M. Brennan, C. Dawson, R. - - PowerPoint PPT Presentation

RHIC Spin Flipper Commissioning M. Bai, M. Brennan, C. Dawson, R. Hulsart, Y. Makdisi, P. Oddo, C. Pai, P. Pile, P. Rosas, T. Roser Summary of what was done Measured the DSA spectrum with single ac dipole #1, #2, #4 and #5. Both regular 1024


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SLIDE 1

RHIC Spin Flipper Commissioning

  • M. Bai, M. Brennan, C. Dawson, R. Hulsart, Y. Makdisi, P.

Oddo,

  • C. Pai, P. Pile, P. Rosas, T. Roser
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SLIDE 2

Summary of what was done

  • Measured the DSA spectrum with single ac dipole #1, #2, #4

and #5. Both regular 1024 bpm turn by turn data as well as million turn bpm data were recorded

  • Measured DSA spectrum with single ac dipole bumps and

recorded turn by turn bpm data

  • Measured DSA spectrum with two ac dipole bumps and

recorded turn by turn bpm data

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SLIDE 3

Single AC Dipole Response

  • AC dipole #5 individually at 90A
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SLIDE 4

zero AC Dipole Response

  • All AC dipoles off
  • H DSA response at

revolution frequency is due to the bunch revolution, i.e. independent of ac dipole excitation

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SLIDE 5

Coherent Oscillation by #5 ac dipole

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SLIDE 6

DSA Response of Each AC Dipole

#5 #1 #2 #4

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SLIDE 7

Excitation of First AC dipole Bump

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SLIDE 8

DSA Response to AC dipole Bump(s)

1st ac dipole bump 2nd ac dipole bump both ac dipole bumps

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SLIDE 9

TurnByTurn BPM for both AC dipole bumps

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SLIDE 10

Conclusions

  • H DSA response is due to the tilts of ac dipoles. The data also

show that each ac dipole tilts slightly different. Plan to analyze the TbT bpm data to see how much roll of each ac dipole.

  • Plan to ask for another hour of beam time at injection to
  • Measure #3 response
  • Measure response with both ac dipole bumps but

sweeping the ac dipole tune from 0.49 to 0.51

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SLIDE 11

Now: Rotating field strength:

฀ 2V sin(2H )  orbit effect (non  rotating) 1.00V for H 15o ฀ 4V sin(H 2)sin( H )  0.14 V forH 15o  0.52V forH  30o 1.08V forH  45o

Rotating field strength: New: H V

New Spin Flipper Design: Thomas