Recent Advances on Mathematical Analysis and Simulations of Invisibility Cloaks with Metamaterials
Jichun Li University of Nevada Las Vegas (UNLV)
Jichun Li (UNLV) June 27, 2018 1 / 62
Recent Advances on Mathematical Analysis and Simulations of - - PowerPoint PPT Presentation
Recent Advances on Mathematical Analysis and Simulations of Invisibility Cloaks with Metamaterials Jichun Li University of Nevada Las Vegas (UNLV) Jichun Li (UNLV) June 27, 2018 1 / 62 Introduction to electromagenetic cloaking with
Jichun Li (UNLV) June 27, 2018 1 / 62
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Schurig, D.R. Smith) [Cited 4510 times as 2/25/15; 6115 times as 4/8/17; 6404 times as 8/26/17; 6785 times as 3/15/18]
times as 2/25/15; 3110 times as 4/8/17; 3250 times as 8/26/17; 3401 times as 3/15/18]
Frequencies” (by Schurig, Mock, etc.) [Cited 3689 times as 2/25/15; 5037 times as 4/8/17; 5289 times as 8/26/17; 5632 times as 3/15/18]
(by Ergin, Stenger, Brenner, Pendry, Wegener) [Cited 918 times as 3/15/18]
Milton, Nicorovici (May 3, 2006), Bouchitte, Schweizer (2010), Ammari etc (2013), Kohn, Weinstein etc (2008, 2014), G. Bao, J. Zou, H.Y. Liu, J.Z. Li, ...
Wang etc (CiCP2015, CMAME2016), D. Liang etc (JSC2016), Brenner, Gedicke, Sung (JSC2016, M2AS2017), D. Liang etc (JSC2016), J. Liu (OP2014), ...
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Figure 1 : (A) The simulation of the cloak with the exact material properties, (B) the simulation of the cloak with the reduced material properties, (C) the experimental measurement of the bare conducting cylinder, and (D) the experimental measurement of the cloaked conducting cylinder. Source: D. Schurig et al, Science, V.314, Nov. 2006, 977-980. Invisible to an incident plane wave at 8.5 GHz.
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Figure 2 : 2D microwave cloaking structure (background image) with a plot of the material parameters that are implemented. Source: D. Schurig et al, Science, V.314, Nov. 2006, 977-980. Reduced parameters: εz = (
b b−a)2,µr = ( r−a r )2,µθ = 1. Exact parameters:
εz = (
b b−a)2 r−a r ,µr = r−a r ,µθ = r r−a
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Shalaev (2007), Krowne, Zhang (2007), Marques, Martin, Sorolla (2008), Markos, Soukoulis (2008), Y. Hao, R. Mittra (2008), W. Cai, V. Shalaev (2009), Cui, Smith, Liu (2010), U. Leonhardt,
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i
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p
p
p
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pm
pm
∂B B B ∂t = −∇×E E E, (5) ∂D D D ∂t = ∇×H H H, (6) ε0εφ ∂ 2 ∂t2 +γ ∂ ∂t +w2
p
E E = ∂ 2 ∂t2 +γ ∂ ∂t +w2
p
D D +εφ ∂ 2 ∂t2 +γ ∂ ∂t
D D, (7) ∂ 2 ∂t2 +γm ∂ ∂t
∂ 2 ∂t2 +γm ∂ ∂t +ω2
pm
(8)
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pEt)
pMA∇×H.
pmH) = −∇×Et −γ∇×E.
pEt)+M∇×∇×Et +γM∇×∇×E
pmH)+ µ0Aω2 pMA∇×H.
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pεφMCEt,φ)]
pmH,∇×φ)+ µ0A(ω2 pMCMA∇×H,φ),
pmH,ψ)
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pεφMcEt,Et)(t)]+(∇×Et,∇×Et)(t)
pεφMcE,E)(t)
0 +||ωpmH||2 0)(t) ≤ CF(0),
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Figure 3 : (a): The cloak modeling setup; (b): A coarse mesh.
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Figure 4 : Ey at (a) t = 0.8ns (4000steps); (b) t = 1.6 ns; (c) t = 3.2 ns.
Figure 5 : Ey at (a) t = 4.0 ns; (b) t = 6.0 ns; (c) t = 8.0ns (40,000steps).
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Figure 6 : Ey at (a) t = 0.8ns (4000steps); (b) t = 1.6 ns; (c) t = 3.2 ns.
Figure 7 : Ey at (a) t = 4.0 ns; (b) t = 6.0 ns; (c) t = 8.0ns (40,000steps).
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x’=φ(x)
(b)
(x2,y2) (x1,y1) (x2,y2) (x1,y1) k(x2,y2) k(x1,y1)
O
. . . . . . . .
x x’ y’ y
O
x
′
= kx y1x2 −x1y2 y(x2 −x1)−x(y2 −y1) +(1−k)x, (15) y
′
= ky y1x2 −x1y2 y(x2 −x1)−x(y2 −y1) +(1−k)y. (16)
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x
′ = kx
K1 y −K2x +(1−k)x, y
′ = ky
K1 y −K2x +(1−k)y, (17) ∂x
′
∂x = (1−k)+ kK1y (y −K2x)2 = (1−k)+ k(1−k)(K1y
′)
(y
′ −K2x ′)2(1−kK3)
= (1−k)+K1K4y
′,
∂x
′
∂y = − kK1x (y −K2x)2 = − k(1−k)K1x
′
(y
′ −K2x ′)2(1−kK3) = −K1K4x ′,
∂y
′
∂x = kK1K2y (y −K2x)2 = k(1−k)K1K2y
′
(y
′ −K2x ′)2(1−kK3) = K1K2K4y ′,
∂y
′
∂y = (1−k)− kK1K2x (y −K2x)2 = (1−k)− k(1−k)K1K2x
′
(y
′ −K2x ′)2(1−kK3)
= (1−k)−K1K2K4x
′,
(18)
′(x1), K3 =
K1 y′−K2x′ , K4 = k(1−k) (y′−K2x′)2(1−kK3).
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ε
′(x ′) =
JJT det(J) =
′)
b0(x
′)
b0(x
′)
c0(x
′)
′)
b(x
′)
b(x
′)
c(x
′)
µ′(x
′) =
1 det(J),
(19)
a0(x
′) = (1−k)2 +2(1−k)K1K4y ′ +K 2
1 K 2 4
′)2 +(y ′)2
, b0(x
′) = K 2
1 K 2 4 K2
′)2 −(y ′)2
−(1−k)K1K4(x
′ +K2y ′),
c0(x
′) = (1−k)2 −2(1−k)K1K2K4x ′ +K 2
1 K 2 2 K 2 4
′)2 +(y ′)2
, det(J) = (1−k)2 +(1−k)K1K4(y
′ −K2x ′). Jichun Li (UNLV) June 27, 2018 23 / 62
′, we
′, we have decomposition ε ′ = PΛPT,
′)
λ2−λ1 ,
′)
′)−λ1
λ2−λ1 .
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e
m
Dt = ∇×H, (22) ε0λ2(Ett +γeEt +ω2
eE) = MADtt +γeMADt +ω2 eMBD,
(23) Bt = −∇×E, (24) µ0(µ∞Htt +γmHt +ω2
mH) = Btt +γmBt,
(25)
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2 =
0=v∈H(curl;Ω) (Mv,v) (v,v) and (ω∗ e)2 =
0=v∈H(curl;Ω) (ω2
ev,v)
(v,v) . Under
m ≤ (ω∗ e)2/λ ∗ 2, and γm and γe are constants, we
λ ∗
2 µ0(µ∞||Ht||2 0 +||ωmH||2 0)(t)
+ 1 ε0 (||Dt||2
0 +||ωe
0)(t)+ε0(||MEt||2 0 +||ωeME||2 0)(t)
≤ C[λ ∗
2ε0(||
√ MEt||2
0 +||ωe
√ ME||2
0)(0)+λ ∗ 2 µ0(µ∞||Ht||2 0 +||ωmH||2 0)(0)]
+[ 1 2ε0 (||Dt||2
0 +||ωe
0)(0)+ ε0
2 (||MEt||2
0 +||ωeME||2 0)(0)].
(26)
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h = {φh ∈ V
τ u
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− 3
2
h ,E − 1
2
h ,D − 1
2
h ,H0 h , for any n ≥ 0, find
n+ 1
2
h
h,E n+ 1
2
h
h,Hn+1 h
(δτD
n+ 1
2
h
,vh) = (Hn
h,∇×vh),
(31) ε0(Mδ 2
τ E n+ 1
2
h
,φh)+ε0γe(Mδ2τE
n+ 1
2
h
,φh)+ε0(ω2
eM ¯
E
n+ 1
2
h
,φh) = (δ 2
τ D n+ 1
2
h
,φh)+γe(δ2τD
n+ 1
2
h
,φh)+(MBω2
e ¯
D
n+ 1
2
h
,φh), (32) µ0µ∞(δ 2
τ Hn+1,ψh)+ µ0γm(δ2τHn+1,ψh)+ µ0(ω2 m ¯
Hn+1
h
,ψh) = −(∇×δτE
n+ 1
2
h
,ψh)−γm
E
n+ 1
2
h
,ψh
(33)
h,φh ∈ V 0 h,ψh ∈ Uh.
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n+ 1
2
h
n+ 1
2
h
h
2γ2 m ≤ (ω∗ e)2 and time step constraint τ < min{ h 12CinvCv , 1 48γe(λ ∗
2)
1 2
, 1 48γm(λ ∗
2)
1 2
, 1 24||ωe||L∞ , 1 12||ωe||L∞(λ ∗
2)
1 2
, h(ω∗
e)2
2γmCinvCv , hµ∞ CinvCvγm }, (34)
ε0|| √ MδτE
m+ 1
2
h
||2
0 +ε0||ωe
√ M E
m+ 1
2
h
||2
0 + µ0||δτHm+1 h
||2
0 + µ0||ωm
Hm+1
h
||2 + 1 ε0 ||δτD
m+ 1
2
h
||2
0 + 1
ε0 ||ωe
D
m+ 1
2
h
||2
0 +ε0||δτPhE m+ 1
2
h
||2 ≤ C(ε0|| √ MδτE
1 2
h ||2 0 +ε0||ωe
√ M E
1 2
h ||2 0 +ε0||
E
3 2
h ||2 0 + µ0||δτH1 h||2 0 + µ0||ωm
H1
h||2
+ 1 ε0 ||δτD
1 2
h ||2 0 + 1
ε0 ||ωe
D
1 2
h ||2 0 +ε0||δτPhE
1 2
h ||2 0).
(35)
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Figure 8 : The mesh used for the simulation of mushroom shaped cloak.
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Figure 9 : Electric fields Ey at various time steps. Top: t=6 ns, 12 ns, 15 ns; Bottom: t=24 ns, 30 ns, 45 ns.
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Figure 10 : The physical space of the carpet cloak.
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H2
d
H2−H1
H1H2 (H2−H1)d sgn(x)
H1H2 (H2−H1)d sgn(x) H2−H1 H2
H2 H2−H1 ( H1 d )2
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(a−c)2+4b2 2
(a−c)2+4b2 2
1 +p2 2 = 1, p1p3 +p2p4 = 0,
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2
p
pE
1λ2 +p2 2
3λ2 +p2 4
2
4
p.
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pE
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− 1
2
A ∂t2E||2 +ω2 p||M − 1
2
A ∂tE||2)+||∇×∂tE||2
1 2
A ∂tD||2 +||M
1 2
B D||2 +ε0µ0µλ2ω2 p||H||2
− 1
2
A ∂t2E||2 +ω2 p||M − 1
2
A ∂tE||2)+||∇×∂tE||2
1 2
A ∂tD||2 +||M
1 2
B D||2 +ε0µ0µλ2ω2 p||H||2
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2 = un+ 1 2 −un− 1 2
τ un+ 1
2 = un+ 1 2 −2un− 1 2 +un− 3 2
h,D − 1
2
h ,D − 3
2
h ,E − 1
2
h ,E − 3
2
h , for n ≥ 0 find
n+ 1
2
h
n+ 1
2
h
h, Hn+1 h
n+ 1
2
h
,φh
h ,∇×φh),
(42) ε0λ2
τ E n+ 1
2
h
,ϕh
p
n+ 1
2
h
,ϕh
τ D n+ 1
2
h
,ϕh
n+ 1
2
h
,ϕh
(43) µ0µ
h
,ψh
n+ 1
2
h
,ψh), (44)
h, ψh ∈ Uh.
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n+ 1
2
h
n+ 1
2
h
ENGn = ε0µ0µλ2(||M
− 1
2
A δ 2 τ E n+ 1
2
h
||2 +ω2
p||M − 1
2
A δτE n+ 1
2
h
||2)+||∇×δτE
n+ 1
2
h
||2 +||M
1 2
A δτD n+ 1
2
h
||2 +||M
1 2
B D n+ 1
2
h
||2 +ε0µ0µλ2ω2
p||Hn h||2.
(45)
A MB||2 , µ0µ
A MB||2 ,
inv||M1/2 A
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(i) ||δτ uk+ 1
2 ||2 := || uk+ 1 2 −uk− 1 2
τ ||2 ≤ 1 τ
tk+ 1 2 tk− 1 2
||∂t u||2ds, ∀ u ∈ H1(0,T;L2(Ω)), (ii) ||δ2
τ uk+ 1 2 ||2 := || uk+ 1 2 −2uk− 1 2 +uk− 3 2
τ2 ||2 ≤ 8 τ
tk+ 1 2 tk− 3 2
||∂t2 u||2ds, ∀ u ∈ H2(0,T;L2(Ω)), (iii) ||δ2
τ uk+ 1 2 −∂t2 u(tk+ 1 2
)||2 ≤ 4τ
tk+ 1 2 tk− 3 2
||∂t3 u||2ds, ∀ u ∈ H3(0,T;L2(Ω)), (iv) ||δ3
τ uk+ 1 2 ||2 ≤ 81
τ
tk+ 1 2 tk− 5 2
||∂t3 u||2ds, ∀ u ∈ H3(0,T;L2(Ω)), (v) ||δ3
τ uk+ 1 2 −δτ ∂t2 u(tk+ 1 2
)||2 ≤ 81τ
tk+ 1 2 tk− 5 2
||∂t4 u||2ds, ∀ u ∈ H4(0,T;L2(Ω)), (vi) ||δτ uk+ 1
2 −∂t u(tk )||2 ≤ τ
12
tk+ 1 2 tk− 1 2
||∂t2 u||2ds, ∀ u ∈ H2(0,T;L2(Ω)), (vii) ||δτ ∂t uk− 1
2 −δ2 τ u(tk )||2 ≤ 2τ
5
tk tk−2
||∂t3 u||2ds, ∀ u ∈ H3(0,T;L2(Ω)), (viii) ||δ2
τ ∂t u(tk )−δ3 τ uk+ 1 2 ||2 ≤ 256τ tk+ 1 2 tk− 5 2
||∂t4 u||2ds, ∀ u ∈ H4(0,T;L2(Ω)). Jichun Li (UNLV) June 27, 2018 43 / 62
(δτ D
n+ 1
2
h
,φ h) = ( Hn
h,∇×φ h)+(∂tDn −δτDn+ 1
2 ,φ h),
(47) ε0λ2(δ 2
τ
E
n+ 1
2
h
,ϕh)+ε0λ2ω2
p(
E
n+ 1
2
h
,ϕh)−(MAδ 2
τ
D
n+ 1
2
h
,ϕh)−(MB D
n+ 1
2
h
,ϕh) = ε0λ2(∂t2En+ 1
2 −δ 2
τ En+ 1
2 ,ϕh)−(MA(∂t2Dn+ 1 2 −δ 2
τ Dn+ 1
2 ),ϕh),
(48) µ0µ(δτ Hn+1
h
,ψh) = −(∇× E
n+ 1
2
h
,ψh)+ µ0µ(∂tHn+ 1
2 −δτHn+1,ψh),
(49)
h and ψh ∈ Uh. For simplicity, we assume
H0
h = Π2H0, D − 1
2
h
= ΠcD− 1
2 , D
− 3
2
h
= ΠcD− 3
2 , E
− 1
2
h
= ΠcE− 1
2 , E
− 3
2
h
= ΠcE− 3
2 . Jichun Li (UNLV) June 27, 2018 44 / 62
Errn =
1 2 A δτ
D
n+ 1 2 h
||2 +||M
1 2 B
D
n+ 1 2 h
||2 +||∇×δτ E
n+ 1 2 h
||2 +||∇× E
n+ 1 2 h
||2 +ε0µ0µλ2(||M
− 1 2 A
δ2
τ
E
n+ 1 2 h
||2 +||ωpM
− 1 2 A
δτ E
n+ 1 2 h
||2 +||ωpM
− 1 2 A
n+ 1 2 h
||2) 1/2 . (50)
max
t∈[0,T]
T
Hp(curl;Ω) +||∂t3 E||2 Hp(curl;Ω) +||∂t4 E||2 +||∇×∇×∂t E||2 Hp(curl;Ω) +||∂t3 D||2
+||∂t4 D||2 +||∂t D||2
Hp(curl;Ω) +||∂t2 D||2 Hp(curl;Ω) +||∂t2 H||2 +||∇×∂t3 H||2
ds < ∞,
Jichun Li (UNLV) June 27, 2018 45 / 62
Uh = {ψh ∈ L2(Ω) : ψh|K ∈ Pp, ∀ K ∈ Th}, V V V h = (Uh)2.
h,D − 1
2
h ,D − 3
2
h , E − 1
2
h ,E − 3
2
h , for n ≥ 0
n+ 1
2
h
n+ 1
2
h
h, Hn+1 h
δτ D
n+ 1 2 h
·φh =
Hn
h ·∇×φh + ∑ K∈νi
φh ×nik ·{{Hn
h }}ik ,
(51) ε0λ2
δ2
τ E n+ 1 2 h
·ϕh +ε0λ2
ω2
p E n+ 1 2 h
·ϕh =
MAδ2
τ D n+ 1 2 h
·ϕh +
MBD
n+ 1 2 h
·ϕh, (52) µ0µ
δτ Hn+1
h
ψh = −
E
n+ 1 2 h
·∇×ψh − ∑
K∈νi
ψh ·nik ×{{E
n+ 1 2 h
}}ik , (53)
h,ψh ∈ Uh. {{E n+ 1
2
h
n+ 1
2
h
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Figure 11 : Ex1. The Hz fields at 5000, 7000, 10000, 15000 time steps.
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Figure 12 : Ex2. The Hz fields at 5000, 7000, 10000, 15000 time steps.
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Figure 13 : Ex2. The Hz fields at 5000, 7000, 10000, 15000 time steps
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2
3
4
5
6
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Figure 14 : Snapshots of electric field Ey: 2000 time steps (Top Left); 4000 steps (Top Right); 8000 steps (Bottom Left); 10000 steps (Bottom Right).
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br,
c−a c−br − b−a c−bc,
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eεrMaE = ∂ttD +MbD,
mH = −∇×∂tE.
r ′
c−b . The parameters
c−a, ωe, µmax = b(c−b) a(c−a) and ωm come from the following Drude
r ′ r ′+K1 and µ′(r ′) =
c−a
r ′
e
m
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b
r
a
r
a
r
a
r
a
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h = u n+ 1
2
h
n− 1
2
h
τ un h = δτ(δτun h) = un+1 h
h +un−1 h
h = u n+ 1
2
h
n− 1
2
h
n− 1
2
h
n+ 1
2
h
n− 1
2
h
n− 3
2
h
h + ¯
h
− 3
2
h ,E − 1
2
h , D − 3
2
h ,D − 1
2
h ,H0 h, for any
n+ 1
2
h
h,E n+ 1
2
h
h, Hn+1 h
h,vh) = (Hn h,∇×vh), ∀ vh ∈ V 0 h,
τ E n− 1
2
h
eεrMa
n− 1
2
h
τ D n− 1
2
h
n− 1
2
h
h,
τ Hn h,ψh)+ µ0(ω2 m
h,ψh) = −(∇×δτEn h,ψh), ∀ ψh ∈ Uh.
Jichun Li (UNLV) June 27, 2018 58 / 62
Edisc(n) = ||δτDn
h||2 +||M1/2 b
¯ D
n h||2 + µ0µmax||δτHn+ 1
2 ||2 + µ0||ωm ¯
H
n+ 1
2
h
||2 +ε0εmax||ε
1 2
r M
1 2
a δτEn h||2 +ε0||ωeε
1 2
r M
1 2
a ¯
E
n h||2 +||∇×δτ ¯
E
n+ 1
2
h
||2 +ε0µ0µmax(εmax||ε
1 2
r M
1 2
a δ 2 τ E n+ 1
2
h
||2 +||ωeε
1 2
r M
1 2
a δτ ¯
E
n+ 1
2
h
||2).
Jichun Li (UNLV) June 27, 2018 59 / 62
ERRdisc(n) = ||δτ D
n h||2 +||M1/2 b
¯
n h||2 + µ0µmax||δτ
Hn+ 1
2 ||2 + µ0||ωm ¯
n+ 1
2
h
||2 +ε0εmax||ε
1 2
r M
1 2
a δτ
E
n h||2 +ε0||ωeε
1 2
r M
1 2
a ¯
n h||2 +||∇×δτ ¯
n+ 1
2
h
||2 +ε0µ0µmax(εmax||ε
1 2
r M
1 2
a δ 2 τ
E
n+ 1
2
h
||2 +||ωeε
1 2
r M
1 2
a δτ ¯
n+ 1
2
h
||2).
Jichun Li (UNLV) June 27, 2018 60 / 62
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Jichun Li (UNLV) June 27, 2018 61 / 62
Jichun Li (UNLV) June 27, 2018 62 / 62