Phase Transi+ons in Twin Higgs Models
Kohei Fujikura (TITECH)
Collaborators: Kohei Kamada (IBS), Yuichiro Nakai (Rutgers.U), Masahide Yamaguchi (TITECH).
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Phase Transi+ons in Twin Higgs Models Kohei Fujikura (TITECH) - - PowerPoint PPT Presentation
Phase Transi+ons in Twin Higgs Models Kohei Fujikura (TITECH) Collaborators: Kohei Kamada (IBS), Yuichiro Nakai (Rutgers.U), Masahide Yamaguchi (TITECH). 1 Contents p Naturalness of the Higgs mass p Twin Higgs Models p Phase Transitions in
Collaborators: Kohei Kamada (IBS), Yuichiro Nakai (Rutgers.U), Masahide Yamaguchi (TITECH).
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2
3
V (H)
Why???
SM Higgs Potential:V (φ) = m2|H|2 + λSM|H|4
R = m2 bare + δm2
vSM √ 2
Dynamics of Electroweak Symmetry Breaking
4
O(M 2
pl)
O(M 2
pl)
However, there are problems…
h =
− 3y2
t
4π2 Λ2 + 9g2
2
32π2 Λ2
+ λ 4π2 Λ2
Λ : cut − off scale
The measure of Fine-Tuning: ∆ ≡ (mR
h )2
δm2
h
For example, ∆ < 10−2
(mR
h )2 = (mbare h
)2 + δm2
h Unnatural Cancella5on! (1% tuning is needed) Top quark
SU(2)W
Higgs self-coupling
5
15625 = 98715625 - 98700000
∼ 102GeV
∼ 1019GeV
MSM
Mpl
Large Hierarchy Problem
Λ?
SUSY provides an excellent solu9on to Hierarchy Problem
Top Stop
Quadra9c divergence is cancelled by Top partner (Stop). (SUSY protects quadra9c divergence mass correc9ons.) SoF SUSY-breaking mass is important for fine-tuning. Scalartop is a colored state Strong Bounds
t
stop log
stop
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Soft Mass must be Heavy
Little Hierarchy Problem
∼ 102GeV
1019GeV
Large Hierarchy Problem
SUSY and Composite Higgs provide solu<on
h =
− 3y2
t
4π2 Λ2 + 9g2
2
32π2 Λ2
+ λ 4π2 Λ2
Λ : cut − off scale
Problem is quadra<c-divergence sensi<ve
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∼ TeV
How to solve?
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U(1)V
U(1)A
Charge LQED = −1 4FµνF µν + ¯ eL¯ σµDµeL + ¯ eRσµDµeR − me(¯ eLeR + ¯ eReL), Dµ ≡ ∂µ − ieAµ
When we take me → 0 limit, U(1)A symmetry is restored.
U(1)V × U(1)A invariant
U(1)V invariant
Aµ δme = me 3α 2π log ✓ Λ me ◆
Why log sensi4vity? Naive dimensional analysis However, ∆me ∼ 10−19, (Λ ∼ Mpl) Natural !!
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me is the only parameter which breaks the U(1)A symmetry.
V (|φ|) = λ ✓ |φ|2 − f 2 2 ◆2
φ(x) = 1 √ 2(f + σ(x))ei a(x)
f
NG Boson has shi=-symmetry:
a(x) → a(x) + const
L(σ, a) = −1 2∂µa(x)∂µa(x) + Lσ(σ)
Add explicit breaking source:
NG Boson acquires mass:
LU(1)breaking = −ρf 3(φ + φ∗) ρ → 0 U(1) symmetry is restored
a ∝ m2 a
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[ Z. Chacko, H.-S. Goh, and R. Harnik,Phys. Rev. Lett.96, 231802 (2006)]
Twin Higgs provides an elegant soluLon to the LiMle Hierarchy Problem SM Higgs is considered as pseudo-Nambu-Goldstone Boson
H = Φ1 Φ2 Φ3 Φ4
U(4) Fundamental RepresentaLon V = λ ✓ |H|2 − f 2 2 ◆2
HA ≡ ✓Φ1 Φ2 ◆
Spontaneous symmetry breaking 7 Goldstone Modes + one massive mode
4 of them are idenLfied with Standard Model Higgs
SM-like Higgs:
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Another Higgs : HB =
✓Φ3 Φ4 ◆
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<latexit sha1_base64="QSAqOqyjJFAF7z+FGKHFGgek7jk=">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</latexit><latexit sha1_base64="QSAqOqyjJFAF7z+FGKHFGgek7jk=">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</latexit><latexit sha1_base64="QSAqOqyjJFAF7z+FGKHFGgek7jk=">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</latexit><latexit sha1_base64="QSAqOqyjJFAF7z+FGKHFGgek7jk=">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</latexit>SM Higgs cannot be considered as pNGB
−yt ¯ QL ˜ HAuR + h.c.
HA : SU(2)W × U(1)Y
−ˆ yt ¯ ˆ QL ˜ HBˆ uR + h.c.
HB : SU(2) ˆ
W × U(1) ˆ Y
Introduce copy of SM Veff ⊃ − 3 8π2 Λ2(y2
t |HA|2 + ˆ
y2
t |HB|2) +
9 64π2 Λ2(g2
2|HA|2 + ˆ
g2
2|HB|2)
Veff ⊃ ✓ − 3y2
t
8π2 + 9g2
2
64π2 ◆ Λ2(|HA|2 + |HB|2)
Large mass corrections respect the U(4) symmetry
ˆ u : Twin top quark
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SU(3) ˆ
C × SU(2) ˆ W × U(1) ˆ Y
SU(3)C × SU(2)W × U(1)Y
Quarks and Leptons Twin Quarks and Leptons
Most important point is that the Twin partners do not have SM charge! (Neutral Naturalness)
Every quadraEc divergent mass correcEons are cancelled by its Twin partner
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Sub-leading correc+on does not respect the U(4) symmetry
Veff = λ ✓ |HA|2 + |HB|2 − f 2 2 ◆2 + σf 2|HA|2 + κ(|HA|4 + |HB|4)
U(4) → U(3)
Twin breaking term
Z2
Radia+ve Correc+ons VCW U(4) explicit breaking term controls pNGB mass! Spontaneously symmetry breaking
from top quark Twin top quark
This term must be dominant compared to U(4) breaking term λ >> σ, κ
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V (ϕ)CW = nm4(HA, HB) 64π2 log m2(HA, HB) Λ2
Integra5ng Out Massive Mode |HB|2 = f 2 2 − |HA|2
eff
It should match with SM Higgs potential! How is the tuning? ∆σ = 2 v2
SM
f 2
1 − 2 2v2
SM
f 2
∼ 2v2
SM
f 2
∆σ > 1 10
vSM f > 0.23
V low−energy
eff
is valid up to Λ ∼ 4πf Λ ∼ 5TeV ↔ f ∼ 400GeV
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SM
16
17
Large Hadron Collider
LISA, DECIGO and BBO
Spontaneous symmetry breaking in the early Universe
Phase transition
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First order phase transi/on
Order parameter is Higgs VEV.
T
Tunneling
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T = TC hφi 6= 0
First order phase transi/on proceeds through bubble nuclea/on
hφi 6= 0
hφi 6= 0
There are three sources of the Gravitational Wave Bubble collisions Sound Wave of the cosmic plasma Turbulence of the plasma
50 60 70 80 90 mH/GeV 80 90 100 110 120 130 Tc/GeV
symmetric confinement phase broken Higgs phase 1st order transition 2nd order endpoint
Electroweak phase transi5on is not first order in SM.
First-order phase transi5on
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BSM can change the situa5on!
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There are two spontaneous symmetry breakings (Global U(4) symmetry and EW symmetry)
Veff = λ ✓ |HA|2 + |HB|2 − f 2 2 ◆2 + σf 2|HA|2 + κ(|HA|4 + |HB|4)
U(4) Breaking Phase TransiCon Electroweak Phase TransiCon U(4) Breaking Phase TransiCon and Electroweak Phase TransiCon occur simultaneously E Electroweak Phase TransiCon U(4) Breaking P phase TransiCon
HA HB vB vA
(1) (0, 0) → (0, vB) → (vA, vB)
(3) (0, 0) → (vA, 0) → (vA, vB)
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HA =
φA √ 2
! , HB =
φB √ 2
!
Background field
nW = 6, : m2
W = g2 2φ2 A
4 , n ˆ
W = 9, : m2 ˆ W = ˆ
g2
2φ2 B
4 nZ = 3, : mZ = (g2
1 + g2 2)φ2 A
4 nt = −12, : m2
t = y2 t φ2 A
2 nˆ
t = −12, : m2 ˆ t = y2 t φ2 B
2
Field dependent mass d.o.f
Take account of
SU(2)W
SU(2) ˆ
W
U(1)Y
Top quark Twin Top quark
Integra>ng out massive mode φ2
B = f 2 − φ2 A
Peter Arnold(1994)
Perturba:on theory breakdown when
fB = 1 eβE − 1, E ≡ k2 + m2
W (φ)
fB >> 1 when mW (φ)β << 1
Numerical Simula:on
γ = g2
2
T mW (φ) ∼ g2T φ > 1 If γ(TC) > 1, we cannot believe perturbation!
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IR divergence comes from large occupa:on number
Expansion parameter
1 2 · · · ℓ ℓ + 1
g2lT 4 for l = 1, 2 g6T 4 ln(T/m) for l = 3 g6T 4(g2T/m)l−3 for l > 3
Linde.(1980)
Order of the phase transition should be analyzed by the non-perturbative method
Allowed region cannot sa6sfy φ(TC)
TC > g2 ∼ 0.65
Red line represent the only SM contribu6on
vSM f < 0.5
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V (φA, T)
φA(TC) TC
0.30 0.35 0.40 0.45 0.50 0.55 0.00 0.05 0.10 0.15 0.20
Sphaleron decoupling condi6on cannot be sa6sfied φA(TC)
TC > 1
Large breaking scale f thermal decoupling (Boltzmann suppression) Twin sector correc6ons do not give a contribu6on
vSM f
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Thanks to the Twin Z2 symmetry, the situa4on is similar to the electroweak phase transi4on in SM.
U(4) breaking Phase Transi4on Electroweak phase transi4on in SM
V = 1 2M 2(T)φ2
B − T
2π ✓ ˆ g2
2φ2 B
4 ◆3/2 − T 4π ✓ ˆ g2
2φ2 B
4 + Π(i)
W
◆ 3
2
− ✓ ˆ g2
2φ2
4 ◆ 3
2 !
+ λ + κ1(T) 4 φ4
B
M 2(T) = −λf 2 + ˆ y2
t
4 T 2 + 3ˆ g2
2
16 T 2
κ(T) = κ − 3ˆ y4
t
16π2 log ✓aF T 2 µ2 ◆ + 9ˆ g4
2
256π2 log ✓aBT 2 µ2 ◆
However… Well known
Situation is similar to electroweak phase transition in SM
(Cri6cal Temperature is different)
In SM, order of electroweak phase transi6on depends on λSM/g2
2 [K. Rummukainena, M. Tsypinb, K. Kajan6ec, M. Laine, and M. Shaposhnikov] (1998)
We can use the result of electroweak phase transi6on in SM ! U(4) breaking phase transition depends on (λ + κ)/ˆ
g2
2
es
g2(Λ)−g2(Λ) g2(Λ)
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Twin Top Quark : b yt ↔ Top Quark : yt
W : b
U(4) breaking phase transi2on cannot be first
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50 60 70 80 90 mH/GeV 80 90 100 110 120 130 Tc/GeV
symmetric confinement phase broken Higgs phase 1st order transition 2nd order endpoint
SM Rusult
First order phase transi2on!!
κ = λSM 2 ∼ 0.06
Matching condition with SM
uTwin Higgs provides excellent solu8on to the Li;le Hierarchy problem uElectroweak phase transi8on cannot be analyzed perturba8vely in Twin Higgs Models uIt is difficult to realize the first-order U(4) breaking phase transi8on without any UV comple8on uWe also analyze the U(4) breaking phase transi8on with light twin stops in SUSY comple8on and calculate a typical GW amplitude
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