Network Economics
- Lecture 1: Pricing of communication
services
Patrick Loiseau EURECOM Fall 2016
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Network Economics -- Lecture 1: Pricing of communication services - - PowerPoint PPT Presentation
Network Economics -- Lecture 1: Pricing of communication services Patrick Loiseau EURECOM Fall 2016 1 References M. Chiang. Networked Life, 20 Questions and Answers, CUP 2012. Chapter 11 and 12. See the videos on
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and 12.
– See the videos on www.coursera.org
Modeling and Engineering, Zhen Liu, Cathy H. Xia (Eds), Springer 2008. (Tutorial given at SIGMETRICS 2008).
– Available online: http://robotics.eecs.berkeley.edu/~wlr/Papers/EconomicModels_Sigmetrics.pdf
Pricing,” S. Sen, C. Joe-Wong, S. Ha, and M. Chiang (Eds.), Wiley, 2014.
– Available at http://www.dtc.umn.edu/~odlyzko/doc/smart.pricing.pdf
Theory”, CUP 2007. Chapters 17, 18, 19, etc.
– Available online: http://www.cambridge.org/journals/nisan/downloads/Nisan_Non- printable.pdf
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x [ui(x)− px]
x [ui(x)− px]
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utility u(x) x px x(p) = max[u(x) − px] maximized net benefit
consumer has a utility u x for a quantity x of a service. In
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i∈N
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x(p) x u′(x) CS(p) p px $
x( p)
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– User demand; costs structure; regulation; competition
– R. Wilson. “Nonlinear pricing”, OUP 1997.
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i∈N
i∈N
NE =
SO =
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pricing: Feasibility and benefits”, in Proc. of IEEE ICDCS 2011.
– Waiting function – Implementation (app)
Performance Modeling and Engineering, Zhen Liu, Cathy H. Xia (Eds), Springer 2008.
Pricing and Bandwidth Trading”, in Proc. of IEEE International Workshop on Bandwidth on Demand 2008.
“Incentive Mechanisms for Internet Congestion Management: Fixed-Budget Rebate versus Time-of-Day Pricing”, IEEE/ACM Transactions on Networking, 2013 (to appear).
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c + d(Nt)1t>0
c
Nt = xt
c c
c
xc = xt
c t
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c + d(Nt)1t>0 = λc,
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c + d(Nt)1t>0
cgt c
c
t
c + d(Nt)1t>0 + pt
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i=1 N
j∈ai
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alpha beta alpha beta 2, 1 0, 0 1, 2 0, 0 P1 P2
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alpha beta alpha beta 5, 2
1, 4
P1 P2
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heads tails heads tails 1, -1
1, -1
P1 P2
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Network 1 Network 2
Expensive Small Utilization High QoS Inexpensive High Utilization Low QoS
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+
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p
1
p
2 1/2 1/2 1/3 1/3 2/3 2/3 1 1
p
2
(p
1
) p
1
(p
2
)
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