SLIDE 27 Introduction The center and cyclicity problems Time-reversibility and a polynomial subalgebra The center variety of the quadratic system The cyclicity of the quadratic system
We look for an algebraic invariant curves in the form f = c00+c10x+c01y+c20x2+c11xy+c02y 2+c30x3+c21x2y+c12xy 2+c03y 3 and find ℓ1 = 1 + 2 b10 x − a01 b2,−1 x2 + 2 a01 y + 2 a01 b10 x y − a01 b2
10
b2,−1 y 2, ℓ2 = (2 b10 b2
2,−1+6 b2 10 b2 2,−1 x+3 b10 3 b2 2,−1 x2−3 a01 b10 b3 2,−1 x2−a01 b2 10 b3 2,−1
6 a01 b10 b2
2,−1 y−3 b4 10 b2,−1 x y+6 a01 b2 10 b2 2,−1 x y−3 a2 01 b3 2,−1 x y+3 a01 b3 10 b2 2,−
3 a2
01 b10 b3 2,−1x2 y−3 a01 b3 10 b2,−1 y 2+3 a2 01 b10 b2 2,−1 y 2−3 a01 b4 10 b2,−1 x y 2+3 a2 01
a01 b5
10 y 3 − a2 01 b3 10 b2,−1 y 3)/(2 b10 b2 2,−1)
with the cofactors k1 = 2 (b10 x − a01 y) and k2 = 3 (b10 x − a01 y) ,
- respectively. The equation α1k1 + α2k2 = 0 has a solution
α1 = −3, α2 = 2, therefore the corresponding system has a Darboux first integral ℓ−3
1 ℓ2 2 ≡ c. The integral is defined when b10b2,−1 = 0. However
V(J3) \ V(b10b2,−1) = V(J3). Therefore every system from V(J3) has a center at the origin. Each system from V(J4) have a center at the origin (in this case the
Valery Romanovski Limit cycles, centers and time-reversibility in systems of polynomial