Fine scales of decay and an application to decay of waves in a - - PowerPoint PPT Presentation

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Fine scales of decay and an application to decay of waves in a - - PowerPoint PPT Presentation

Fine scales of decay and an application to decay of waves in a viscoelastic boundary damping model (International Workshop on Operator Theory and its Applications) Reinhard Stahn (TU Dresden) (joint with Jan Rozendaal and David Seifert) August


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Fine scales of decay and an application to decay of waves in a viscoelastic boundary damping model

(International Workshop on Operator Theory and its Applications)

Reinhard Stahn (TU Dresden) (joint with Jan Rozendaal and David Seifert) August 15, 2017

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Theory

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General bounds for semiuniform decay

Mainly motivated by the wave equation in the past decade there has been much activity in semiuniform decay of C0-semigroups (Batkai, Batty, Borichev, Chill, Duyckaerts, Engel, Liu, Martinez, Prüss, Rao, Rozendaal, Schnaubelt, D. Seifert, Stahn, Tomilov, Veraar). A famous result is the following:

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General bounds for semiuniform decay

Mainly motivated by the wave equation in the past decade there has been much activity in semiuniform decay of C0-semigroups (Batkai, Batty, Borichev, Chill, Duyckaerts, Engel, Liu, Martinez, Prüss, Rao, Rozendaal, Schnaubelt, D. Seifert, Stahn, Tomilov, Veraar). A famous result is the following:

Theorem (Batty-Duyckaerts 2008)

Let −A be the generator of a bounded C0-SG T on a Banach space X with σ(A) ∩ iR = ∅. For s ≥ 0 let M(s) := sup

|ξ|≤s

  • (iξ + A)−1
  • .

Let Mlog(s) = M(s) log(2 + s + M(s)). Then ∀t > 0 : c M−1(c2t) ≤

  • T(t)A−1

C M−1

log (c1t)

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General bounds for semiuniform decay

Mainly motivated by the wave equation in the past decade there has been much activity in semiuniform decay of C0-semigroups (Batkai, Batty, Borichev, Chill, Duyckaerts, Engel, Liu, Martinez, Prüss, Rao, Rozendaal, Schnaubelt, D. Seifert, Stahn, Tomilov, Veraar). A famous result is the following:

Theorem (Batty-Duyckaerts 2008)

Let −A be the generator of a bounded C0-SG T on a Banach space X with σ(A) ∩ iR = ∅. For s ≥ 0 let M(s) := sup

|ξ|≤s

  • (iξ + A)−1
  • .

Let Mlog(s) = M(s) log(2 + s + M(s)). Then ∀t > 0 : c M−1(c2t) ≤

  • T(t)A−1

C M−1

log (c1t)

Question: Can one remove the logarithmic loss?

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Can one remove the logarithmic loss?

In general the answer is NO:

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Can one remove the logarithmic loss?

In general the answer is NO: (a) ∃A normal: M(s) ∼ log(s) and

  • T(t)A−1

∼ 1/M−1

log (4t) = 1/e2 √ t.

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Can one remove the logarithmic loss?

In general the answer is NO: (a) ∃A normal: M(s) ∼ log(s) and

  • T(t)A−1

∼ 1/M−1

log (4t) = 1/e2 √ t.

(b) Let α > 0. Exists A and X: M(s) ≈ sα and

  • T(t)A−1

≈ 1/M−1

log (t) ∼ (log(t)/t)1/α. [Borichev-Tomilov, 2010].

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Can one remove the logarithmic loss?

In general the answer is NO: (a) ∃A normal: M(s) ∼ log(s) and

  • T(t)A−1

∼ 1/M−1

log (4t) = 1/e2 √ t.

(b) Let α > 0. Exists A and X: M(s) ≈ sα and

  • T(t)A−1

≈ 1/M−1

log (t) ∼ (log(t)/t)1/α. [Borichev-Tomilov, 2010].

But in some cases one can replace Mlog by M:

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Can one remove the logarithmic loss?

In general the answer is NO: (a) ∃A normal: M(s) ∼ log(s) and

  • T(t)A−1

∼ 1/M−1

log (4t) = 1/e2 √ t.

(b) Let α > 0. Exists A and X: M(s) ≈ sα and

  • T(t)A−1

≈ 1/M−1

log (t) ∼ (log(t)/t)1/α. [Borichev-Tomilov, 2010].

But in some cases one can replace Mlog by M: (c) Trivial case. If M(s) ≈ eαs then M−1

log (t) ≈ M−1(t) ≈ α−1 log(t).

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Can one remove the logarithmic loss?

In general the answer is NO: (a) ∃A normal: M(s) ∼ log(s) and

  • T(t)A−1

∼ 1/M−1

log (4t) = 1/e2 √ t.

(b) Let α > 0. Exists A and X: M(s) ≈ sα and

  • T(t)A−1

≈ 1/M−1

log (t) ∼ (log(t)/t)1/α. [Borichev-Tomilov, 2010].

But in some cases one can replace Mlog by M: (c) Trivial case. If M(s) ≈ eαs then M−1

log (t) ≈ M−1(t) ≈ α−1 log(t).

(d) If X Hilbert and M(s) ≈ sα for some α > 0 [Borichev-Tomilov, 2010]. Generalized by [Batty-Chill-Tomilov, 2016] for some regularly varying resolvent growths.

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Can one remove the logarithmic loss?

In general the answer is NO: (a) ∃A normal: M(s) ∼ log(s) and

  • T(t)A−1

∼ 1/M−1

log (4t) = 1/e2 √ t.

(b) Let α > 0. Exists A and X: M(s) ≈ sα and

  • T(t)A−1

≈ 1/M−1

log (t) ∼ (log(t)/t)1/α. [Borichev-Tomilov, 2010].

But in some cases one can replace Mlog by M: (c) Trivial case. If M(s) ≈ eαs then M−1

log (t) ≈ M−1(t) ≈ α−1 log(t).

(d) If X Hilbert and M(s) ≈ sα for some α > 0 [Borichev-Tomilov, 2010]. Generalized by [Batty-Chill-Tomilov, 2016] for some regularly varying resolvent growths. Our aim: To find all admissible resolvent growth bounds M allowing to replace Mlog by M in Hilbert spaces.

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Admissible resolvent growth bounds

Definition

We call a non-decreasing function M : [0, ∞) → (0, ∞) admissible if for all bounded C0-SGs T ∼ −A on Hilbert spaces with σ(A) ∩ iR = ∅ and ∀s ≥ 0 : sup

|ξ|≤s

  • (iξ + A)−1
  • ≤ C1M(s)

it holds that ∀t ≥ 0 :

  • T(t)A−1

C2 M−1(t).

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Admissible resolvent growth bounds

Definition

We call a non-decreasing function M : [0, ∞) → (0, ∞) admissible if for all bounded C0-SGs T ∼ −A on Hilbert spaces with σ(A) ∩ iR = ∅ and ∀s ≥ 0 : sup

|ξ|≤s

  • (iξ + A)−1
  • ≤ C1M(s)

it holds that ∀t ≥ 0 :

  • T(t)A−1

C2 M−1(t). Any M given by sα or sα/ log(s) is admissible [BoTo10, BaChTo16] if α > 0.

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Admissible resolvent growth bounds

Definition

We call a non-decreasing function M : [0, ∞) → (0, ∞) admissible if for all bounded C0-SGs T ∼ −A on Hilbert spaces with σ(A) ∩ iR = ∅ and ∀s ≥ 0 : sup

|ξ|≤s

  • (iξ + A)−1
  • ≤ C1M(s)

it holds that ∀t ≥ 0 :

  • T(t)A−1

C2 M−1(t). Any M given by sα or sα/ log(s) is admissible [BoTo10, BaChTo16] if α > 0. M(s) = log(s) is not admissible.

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Admissible resolvent growth bounds

Definition

We call a non-decreasing function M : [0, ∞) → (0, ∞) admissible if for all bounded C0-SGs T ∼ −A on Hilbert spaces with σ(A) ∩ iR = ∅ and ∀s ≥ 0 : sup

|ξ|≤s

  • (iξ + A)−1
  • ≤ C1M(s)

it holds that ∀t ≥ 0 :

  • T(t)A−1

C2 M−1(t). Any M given by sα or sα/ log(s) is admissible [BoTo10, BaChTo16] if α > 0. M(s) = log(s) is not admissible. Admissibility of M(s) = sα log(s) was unknown so far.

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Admissible resolvent growth bounds

Definition

We call a non-decreasing function M : [0, ∞) → (0, ∞) admissible if for all bounded C0-SGs T ∼ −A on Hilbert spaces with σ(A) ∩ iR = ∅ and ∀s ≥ 0 : sup

|ξ|≤s

  • (iξ + A)−1
  • ≤ C1M(s)

it holds that ∀t ≥ 0 :

  • T(t)A−1

C2 M−1(t). Any M given by sα or sα/ log(s) is admissible [BoTo10, BaChTo16] if α > 0. M(s) = log(s) is not admissible. Admissibility of M(s) = sα log(s) was unknown so far.

Remark

We will see that M admissible implies M−1(ct) ≈ M−1(t) for all c > 0.

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Our main result

Theorem (Rozendaal-Seifert-Stahn 2017)

A non-decreasing function M : [0, ∞) → (0, ∞) is admissible if and

  • nly if it has positive increase (M ∈ PI), that is:

∃λ > 1 : lim inf

s→∞

M(λs) M(s) > 1

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Our main result

Theorem (Rozendaal-Seifert-Stahn 2017)

A non-decreasing function M : [0, ∞) → (0, ∞) is admissible if and

  • nly if it has positive increase (M ∈ PI), that is:

∃λ > 1 : lim inf

s→∞

M(λs) M(s) > 1 The condition M ∈ PI is equivalent to ∃ρ, s0 > 0, b ∈ (0, 1]∀s0 ≤ s ≤ R : M(R) M(s) ≥ b R s ρ .

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Our main result

Theorem (Rozendaal-Seifert-Stahn 2017)

A non-decreasing function M : [0, ∞) → (0, ∞) is admissible if and

  • nly if it has positive increase (M ∈ PI), that is:

∃λ > 1 : lim inf

s→∞

M(λs) M(s) > 1 The condition M ∈ PI is equivalent to ∃ρ, s0 > 0, b ∈ (0, 1]∀s0 ≤ s ≤ R : M(R) M(s) ≥ b R s ρ . Plugging in R = M−1(ct) and s = M−1(t) one can deduce that M−1(ct) ≈ M−1(t) for any c > 1.

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Our main result

Theorem (Rozendaal-Seifert-Stahn 2017)

A non-decreasing function M : [0, ∞) → (0, ∞) is admissible if and

  • nly if it has positive increase (M ∈ PI), that is:

∃λ > 1 : lim inf

s→∞

M(λs) M(s) > 1 The condition M ∈ PI is equivalent to ∃ρ, s0 > 0, b ∈ (0, 1]∀s0 ≤ s ≤ R : M(R) M(s) ≥ b R s ρ . Plugging in R = M−1(ct) and s = M−1(t) one can deduce that M−1(ct) ≈ M−1(t) for any c > 1.

Remark

Necessity of M ∈ PI for all normal semigroups.

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Sufficiency of M ∈ PI

(a) Fix x ∈ D(A) and t > 0, let g(τ) = 1[0,t](τ)T(τ)x and write g(t) = n + 1 tn+1 t snT(t − s)T(s)ds = (n + 1)! tn+1 t T(t − s)T ∗n ∗ g(s)ds.

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Sufficiency of M ∈ PI

(a) Fix x ∈ D(A) and t > 0, let g(τ) = 1[0,t](τ)T(τ)x and write g(t) = n + 1 tn+1 t snT(t − s)T(s)ds = (n + 1)! tn+1 t T(t − s)T ∗n ∗ g(s)ds. (b) A truncation (δ − φR) ∗ T ∗n ∗ +φR ∗ T ∗n∗ allows to treat the second term as a Fourier multiplier on L2(R; L(D(A), X)). The First term can be estimated by C/R.

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Sufficiency of M ∈ PI

(a) Fix x ∈ D(A) and t > 0, let g(τ) = 1[0,t](τ)T(τ)x and write g(t) = n + 1 tn+1 t snT(t − s)T(s)ds = (n + 1)! tn+1 t T(t − s)T ∗n ∗ g(s)ds. (b) A truncation (δ − φR) ∗ T ∗n ∗ +φR ∗ T ∗n∗ allows to treat the second term as a Fourier multiplier on L2(R; L(D(A), X)). The First term can be estimated by C/R. (c) Crucial in the estimation of the second term is the inequality (for large n) R sup

|ξ|≤R

  • (iξ − A)−n
  • L(D(A),X) ≤ R sup

1≤s≤R

s−1M(s)n ≤ b−nM(R)n. Only here we use M ∈ PI.

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Sufficiency of M ∈ PI

(a) Fix x ∈ D(A) and t > 0, let g(τ) = 1[0,t](τ)T(τ)x and write g(t) = n + 1 tn+1 t snT(t − s)T(s)ds = (n + 1)! tn+1 t T(t − s)T ∗n ∗ g(s)ds. (b) A truncation (δ − φR) ∗ T ∗n ∗ +φR ∗ T ∗n∗ allows to treat the second term as a Fourier multiplier on L2(R; L(D(A), X)). The First term can be estimated by C/R. (c) Crucial in the estimation of the second term is the inequality (for large n) R sup

|ξ|≤R

  • (iξ − A)−n
  • L(D(A),X) ≤ R sup

1≤s≤R

s−1M(s)n ≤ b−nM(R)n. Only here we use M ∈ PI. (d) Optimization of the two estimates with respect to R finally yields the

  • ptimal decay rate.
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Application

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A model for sound reflection

Let Ω ⊂ Rd be a bounded domain. The “velocity potential” U satisfies

  • Utt(t, x) − ∆U(t, x)

= 0 (t ∈ R, x ∈ Ω), ∂nU(t, x) + k ∗ Ut(t, x) = 0 (t ∈ R, x ∈ ∂Ω). Pressure p = Ut, fluid velocity v = −∇U. Here k ∈ L1(0, ∞) is completely monotonic, i.e. there exists a Radon measure ν ≥ 0 s.t. k(t) = ∞

0 e−τtdν(τ).

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A model for sound reflection

Let Ω ⊂ Rd be a bounded domain. The “velocity potential” U satisfies

  • Utt(t, x) − ∆U(t, x)

= 0 (t ∈ R, x ∈ Ω), ∂nU(t, x) + k ∗ Ut(t, x) = 0 (t ∈ R, x ∈ ∂Ω). Pressure p = Ut, fluid velocity v = −∇U. Here k ∈ L1(0, ∞) is completely monotonic, i.e. there exists a Radon measure ν ≥ 0 s.t. k(t) = ∞

0 e−τtdν(τ). It is possible to rewrite the model as an abstract

Cauchy problem ˙ x + Ax = 0, x(0) = x0.

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A model for sound reflection

Let Ω ⊂ Rd be a bounded domain. The “velocity potential” U satisfies

  • Utt(t, x) − ∆U(t, x)

= 0 (t ∈ R, x ∈ Ω), ∂nU(t, x) + k ∗ Ut(t, x) = 0 (t ∈ R, x ∈ ∂Ω). Pressure p = Ut, fluid velocity v = −∇U. Here k ∈ L1(0, ∞) is completely monotonic, i.e. there exists a Radon measure ν ≥ 0 s.t. k(t) = ∞

0 e−τtdν(τ). It is possible to rewrite the model as an abstract

Cauchy problem ˙ x + Ax = 0, x(0) = x0.

Theorem (Desch-Fasangova-Milota-Probst 2010, Stahn 2017)

(i) The operator −A generates a C0-semigroup of contractions. Moreover A is injective and σ(−A) ∩ iR ⊆ {0}. (ii) ∃s0 > 0∀ |s| ≤ s0 :

  • (is + A)−1

≤ C |s|−1. (iii) A is invertible iff ∃ε > 0 : ν([0, ε)) = 0.

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Bound on resolvent in terms of acoustic impedance

The 1D setting allows to explicitly calculate the resolvent of A.

Theorem (Stahn 2017)

Let Ω = (0, 1). Then for all s ≥ 1 c ℜˆ k(is) ≤ sup

1≤|ξ|≤s

  • (iξ + A)−1

C ℜˆ k(is) . Moreover the spectrum determines the resolvent growth.

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Bound on resolvent in terms of acoustic impedance

The 1D setting allows to explicitly calculate the resolvent of A.

Theorem (Stahn 2017)

Let Ω = (0, 1). Then for all s ≥ 1 c ℜˆ k(is) ≤ sup

1≤|ξ|≤s

  • (iξ + A)−1

C ℜˆ k(is) . Moreover the spectrum determines the resolvent growth. Under mild additional assumptions on Ω and ˆ k one can prove the upper bound also in higher dimensions. The proof is now based on recently proved trace properties of Laplace-Neumann eigenfunctions

  • f Ω (see [Barnett-Hassel-Tacy 2016]).
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Decay rates in terms of acoustic impedance

Corollary

Let Ω = (0, 1) assume ∃ε > 0 : ν([0, ε)) = 0 and define M(s) = (ℜˆ k(is))−1. Then ∀t ≥ 1 :

  • T(t)A−1

C M−1(ct) holds for some c, C > 0 if (and only if) 1/ℜˆ k(i·) ∈ PI.

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Decay rates in terms of acoustic impedance

Corollary

Let Ω = (0, 1) assume ∃ε > 0 : ν([0, ε)) = 0 and define M(s) = (ℜˆ k(is))−1. Then ∀t ≥ 1 :

  • T(t)A−1

C M−1(ct) holds for some c, C > 0 if (and only if) 1/ℜˆ k(i·) ∈ PI. We note that the freedom in ˆ k allows for a large class of decay rates:

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Decay rates in terms of acoustic impedance

Corollary

Let Ω = (0, 1) assume ∃ε > 0 : ν([0, ε)) = 0 and define M(s) = (ℜˆ k(is))−1. Then ∀t ≥ 1 :

  • T(t)A−1

C M−1(ct) holds for some c, C > 0 if (and only if) 1/ℜˆ k(i·) ∈ PI. We note that the freedom in ˆ k allows for a large class of decay rates:

Proposition

Let α ∈ (0, 2) and l : R+ → (0, ∞) be a slowly varying function. Then

  • ne can choose ν in such a way that ν|[0,1) = 0 and

ℜˆ k(is)−1 ∼ sαl(s) as s → ∞.

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Literature

Fine scales of decay: [1] Batty, Chill, Tomilov. Fine scales of decay of operator semigroups. JEMS 2016. [2] Rozendaal, Seifert, Stahn. tba. On arXiv in September/October 2017.

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Literature

Fine scales of decay: [1] Batty, Chill, Tomilov. Fine scales of decay of operator semigroups. JEMS 2016. [2] Rozendaal, Seifert, Stahn. tba. On arXiv in September/October 2017. Regular Variation: [3] Bingham, Goldie, Teugels. Regular Variation. Cambridge Univ. Press 1987.

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Literature

Fine scales of decay: [1] Batty, Chill, Tomilov. Fine scales of decay of operator semigroups. JEMS 2016. [2] Rozendaal, Seifert, Stahn. tba. On arXiv in September/October 2017. Regular Variation: [3] Bingham, Goldie, Teugels. Regular Variation. Cambridge Univ. Press 1987. Viscoelastic boundary damping: [4] Desch, Fasangova, Milota, Probst. Stabilization through viscoelastic boundary damping: a semigroup approach. Semigroup Forum 2010. [5] Stahn. On the decay rate for the wave equation with viscoelastic boundary damping. arXiv 2017. See also: A. Benaissa et. al.; B. Mbodje; J. Prüss.

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Thank you for your attention!