CONFINEMENT IN MULTI-PARTON SECTORS OF TWO DIMENSIONAL GAUGE - - PowerPoint PPT Presentation

confinement in multi parton sectors of two dimensional
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CONFINEMENT IN MULTI-PARTON SECTORS OF TWO DIMENSIONAL GAUGE - - PowerPoint PPT Presentation

CONFINEMENT IN MULTI-PARTON SECTORS OF TWO DIMENSIONAL GAUGE THEORIES Daniele Dorigoni, Gabriele Veneziano, J W 1 How to calculate masses of particles ? Lattice Diagonalize Hamiltonian Light Cone Discretization QCD equations:


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CONFINEMENT IN MULTI-PARTON SECTORS OF TWO DIMENSIONAL GAUGE THEORIES

Daniele Dorigoni, Gabriele Veneziano, J W 1 How to calculate masses of particles ?

  • Lattice
  • Diagonalize Hamiltonian
  • Light Cone Discretization
  • QCD equations: coupled Bethe-Salpeter equations on the LC
  • Simplifications: large N planar diagrams - single traces
  • less dimensions
  • even quantum mechanics (but at N → ∞)
  • supersymmetry

1

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2 Planar gauge theory in 1+1 dimensions

  • The history

FT on the light cone – C. Thorn (’77) Warm-up: D=1+1, QCD2 – ’t Hooft (’74) fermions in funamental irrep

LargeN

− → no multiparton states. YM+with addjoint matter – Klebanov et al. (’93) matter = fermions or scalars ( = reduced Y M3 ) SY M2 – Matsumura et al. (’95) D=4 Wilson and Glazek (’93) Hiller et al. (’98) QCD4 on the light cone – Brodsky et al. (since ’70)

2

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2.1

One way: Light Cone Discretization P + =

  • n=2

n

  • i=1 p+

i ,

p+

i > 0

K =

  • n=2

n

  • i=1 ri,

K, ri − natural, Cutoff K = ⇒ partitions {r1, r2, . . .} = ⇒ states |{r} = Tr[a†(r1)a†(r2)...a†(rp)]|0 (1) |{r} = ⇒ {r}|H|{r′} = ⇒ En

3

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2.2

Second way: integral equations in the continuum

  • Different cutoff – directly in the continuum

H|Φ = M 2|Φ (2) |Φ → Φn(x1, x2, . . . , xn) ↔

☛ ✡ ✟ ✠ ☛ ✡ ✟ ✠

=

☛ ✡ ✟ ✠ ② ✭✭ ❤❤ ✭✭ ❤❤

+

☛ ✡ ✟ ✠ ② PP ✏✏

+

☛ ✡ ✟ ✠ ② PP ✏✏

M 2Φn(x1 . . . xn) = A ⊗ Φn + B ⊗ Φn−2 + C ⊗ Φn+2 (3)

4

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  • Interpretation: proton is invariant against elementary processes
  • Fundamental: contain DGLAP and BFKL evolution eqns.
  • Emission and absorption are present (parton recombination)

The cutoff: n ≤ nmax (4) nmax = 2 ’t Hooft equation – exact for QCD2 (with fundamental fermions)

5

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  • EQUATIONS

|Φ =

  • n=2
  • [dx]δ(1 − x1 − x2 − . . . xn)Φn(x1, x2, . . . xn)Tr[a†(x1)a†(x2) . . . a†(xn)]|0

EXAMPLE 1: QCD2 ( fundamental fermions ) M 2f(x) = m2

 1

x + 1 1 − x

  f(x) + λ

π

1

dy (y − x)2 [f(x) − f(y)] f(x) = Φ2(x, 1 − x)

6

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EXAMPLE 2: SY M2 restricted to the two-parton sector There are two coupled equations in the bosonic sector M 2φbb(x) = m2

b

 1

x + 1 1 − x

  φbb(x) + λ

2 φbb(x)

  • x(1 − x)

−2λ π

1

(x + y)(2 − x − y) 4

  • x(1 − x)y(1 − y)

[φbb(y) − φbb(x)] (y − x)2 dy + λ 2π

1

1 (y − x) φff(y)

  • x(1 − x)

dy M 2φff(x) = m2

f

 1

x + 1 1 − x

  φff(x)

−2λ π

1

[φff(y) − φff(x)] (y − x)2 dy + λ 2π

1

1 (x − y) φbb(y)

  • y(1 − y)

dy and the single one in the fermionic sector M 2φbf(x) =

  m2

b

x + m2

f

1 − x

   φbf(x) + 2λ

π φbf(x) √x + x −2λ π

1

(x + y) 2√xy [φbf(y) − φbf(x)] (y − x)2 dy − λ 2π

1

1 (1 − y − x) φbf(y) √xy dy (5)

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Example 3: Y M2 with addjoint fermionc matter - all parton-number sectors M 2φn(x1 . . . xn) = m2 x1 φn(x1 . . . xn) + λ π 1 (x1 + x2)2

x1+x2

dyφn(y, x1 + x2 − y, x3 . . . xn) + λ π

x1+x2

dy (x1 − y)2 {φn(x1, x2, x3 . . . xn) −φn(y, x1 + x2 − y, x3 . . . xn)} + λ π

x1

dy

x1−y

dzφn+2(y, z, x1 − y − z, x2 . . . xn)

  

1 (y + z)2 − 1 (x1 − y)2

  

+ λ πφn−2(x1 + x2 + x3, x4 . . . xn)

  

1 (x1 + x2)2 − 1 (x1 − x3)2

  

± cyclic permutations of (x1 . . . xn)

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3 Coulomb divergences

  • IR divergencies (logarithmic) couple different multiplicity sectors
  • Coulomb divergencies (linear), but they cancel within one multiplicity
  • Can be done independently for each parton multiplicity p

A possibility

→ Solve Coulomb problem first, and then successively add radiation Simplified Hamiltonian, SY M2 reduced from SY M4 (Dorigoni), keeping only Coulomb terms Hquad

C

= λ π

dk

k

dq q2 Tr[A†

kAk]

(6) Hquartic

C

= − g2 2π

dp1dp2

  p1

dq q2 Tr[A†

p1B† p2Bp2+qAp1−q] +

p2

dq q2 Tr(A†

p2B† p1Bp1+qAp2−q)

 

(7)

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4 Two partons |k, K − k, k = 1, .., K − 1 (8) k|H|k′ ⇒ |Φn ⇒ Φn(k)FT ⇒ Φn(d12) (9)

100 50 50 100 0.0 0.2 0.4 0.6 0.8 1.0 100 50 50 100 0.0 0.1 0.2 0.3 0.4 0.5 100 50 50 100 0.0 0.1 0.2 0.3 0.4 0.5 100 50 50 100 0.0 0.1 0.2 0.3 0.4 0.5 100 50 50 100 0.0 0.1 0.2 0.3 0.4 0.5 50 50 100 0.0 0.1 0.2 0.3 0.4 0.5

Figure 1: ρn(d12), p = 2, K = 200, n = 1, 25, 50, 100, 150, 199. 10

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5 Three partons - generalization of the ’t Hooft solution to many bodies |k1, k2, K − k1 − k2, k1 = 1, .., K − 2, k2 = 1, .., K − k1 − 1 (10) k1, k2|H|k′

1, k′ 2 ⇒ |Φn ⇒ Φn(k1, k2) FT

⇒ Φn(d13, d23) (11)

11

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Figure 2: ρ1(d13, d23) 12

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Figure 3: |ρ10(d13, d23) 13

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Figure 4: ρ50(d13, d23) 14

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Figure 5: ρ100(d13, d23) 15

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Figure 6: ρ200(d13, d23) 16

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Figure 7: ρ300(d13, d23) 17

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Figure 8: ρ400(d13, d23) 18

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The highest state

Figure 9: ρ406(d13, d23)

A ”mercedes” configuration

19

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”Stringy” plot for two partons

50 100 150 200 20 40 60 80 100 Px12x21 P E2 Λ Figure 10: Eigenenergies of the, p=2, excited states as a function of the relative separation between two partons, K = 30, 50, 100, 200. 20

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Extrapolation 1: in K → ∞

50 100 150 200 250 300 0.0 0.1 0.2 0.3 0.4 0.5 P xPx12x21 E2 Λ x Figure 11: 21

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Extrapolation 2: in a = 2π

P → 0 0.000 0.005 0.010 0.015 0.020 0.42 0.44 0.46 0.48 0.50 a 2Π x E2 Λ x Figure 12: 22

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Families of states with three partons

10 5 5 10 10 5 5 10 10 5 5 10 10 5 5 10 10 5 5 10 10 5 5 10 10 5 5 10 10 5 5 10 10 5 5 10 10 5 5 10 10 5 5 10 10 5 5 10

Figure 13: Contour plots of ρn(d13, d23), as partons are moved further away. Series A : n = 10, 19, 28, 41, 54, 72, 4 ≤ l = |d12| + |d23| + |d31| ≤ 14. The minimal distance between partons = 1. 23

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5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5

Figure 14: Series B. As above but on the Dalitz plot. Now diquarks are allowed, dmin = 0 24

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20 40 60 80 5 10 15 20 25 30 Px12x23x31 P E3 Λ all series Figure 15: ρ406(d13, d23) 25

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”Stringy” plot for three partons

50 100 150 200 250 300 20 40 60 80 100 P x P E3 Λ

  • ne series K40,60,80,100

Figure 16: Eigenenergies of the, p=3, excited states as a function of the combined length of strings stretching between three partons.

= ⇒ String tensions extracted from E2(l) and E3(l) seem to be consistent.

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Four partons

Figure 17: Structure of eigenstates with four partons. Contour plots in three relative distances (d14, d24, d34) for states no. 1,9,35,60,100,165 spanning the whole range of states for K = 12, rmax = 165. 27

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20 40 60 80 100 5 10 15 20 Px12x23x34x41 P E4 Λ K20 Figure 18: Eigenenergies of the four parton states vs. the combined string length (all series). 28

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6 Inclusive distributions

6.1 Number of pairs at distance ∆

Dr(∆) =

  • dp−1

∆p−1

p−1

  • i=1 δ(∆ − dip)|ψr(

∆p−1)|2, (12)

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10 5 5 10 0.0 0.5 1.0 1.5 2.0 10 5 5 10 0.0 0.2 0.4 0.6 0.8 1.0 10 5 5 10 0.0 0.2 0.4 0.6 0.8 1.0 10 5 5 10 0.0 0.2 0.4 0.6 0.8 1.0 10 5 5 10 0.0 0.2 0.4 0.6 0.8 1.0 10 5 5 10 0.0 0.2 0.4 0.6 0.8 1.0 10 5 5 10 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 10 5 5 10 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 10 5 5 10 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 10 5 5 10 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 10 5 5 10 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 10 5 5 10 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7

Figure 19: Inclusive parton densities for four partons and for lower states r = 1, 4, 5, 6, 9, 12, 13, 14, 15, 20, 26, 29, K = 27, rmax = 2600. 30

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6.2 A simple application: massless Schwinger Model

What about the screening ? (Kutasov, Gross et al., Armoni and Sonnenschien) SM: Exact solution in the two fermion sector - one free (composite) boson. a†

n|0 =

1 √n

n−1

  • r=1 b†

rd† n−r|0,

n = K. (13) Therefore the, normalized, p=4 component of the two boson eigenstates read (K2 = K/2) |m = a†

K2+ma† K2−m|0 =

1

  • K2

2 − m2 K2+m−1

  • r=1

b†

rd† K2+m−r K2−m−1

  • s=1

b†

sd† K2−m−s|0.

(14) The states are labeled by the relative momentum 2m, −(K2 − 2) ≤ m ≤ (K2 − 2) and have mass-squared eigenvalue M 2

m = e2

π K2 K2

2 − m2,

(15) and have the following four parton Fock wave functions f (m)

K (k1, k2, k3, k4) = f (m) K (k1, k2, K2 + m − k1, K2 − m − k2) =

1

  • K2

2 − m2,

1 ≤ k1 ≤ K2 + m − 1, 1 ≤ k2 ≤ K2 − m − 1, (16)

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which result in the following inclusive densities

10 5 5 10 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 10 5 5 10 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 10 5 5 10 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 10 5 5 10 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 10 5 5 10 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 10 5 5 10 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7

Figure 20: Massless Schwinger Model: inclusive parton densities for four partons and for lower states r = 1, ..., 6, K = 20. 32

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7 Summary and the future

  • ’t Hooft solutions have a very simple interpretation in the configuration space.
  • Generalization to more partons

a) is readily possible, and b) also confirms a simple string picture (at fixed p).

  • Future: generalizations of the (1+1) Coulomb problem

supersymmetry high multiplicities

  • Add radiation
  • Mass gap in the 1+1 supersymmetric theory
  • ASV equivalence
  • 33