Advanced Enzyme Kinetics and Metabolism BOC 324 Part A Dr. A. - - PowerPoint PPT Presentation

advanced enzyme kinetics and metabolism boc 324
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Advanced Enzyme Kinetics and Metabolism BOC 324 Part A Dr. A. - - PowerPoint PPT Presentation

Advanced Enzyme Kinetics and Metabolism BOC 324 Part A Dr. A. van Tonder (for 3 rd quarter; Part B in 4 th quarter with Dr. E. van Heerden) BOC 324 Part A SOURCES Textbook: Biochemistry Mathews et al : Ch 11 pp. 360-413 Internet


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SLIDE 1

Advanced Enzyme Kinetics and Metabolism BOC 324

Part A

  • Dr. A. van Tonder

(for 3rd quarter; Part B in 4th quarter with Dr. E. van Heerden)

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SLIDE 2

BOC 324 Part A SOURCES

Textbook:

“Biochemistry” Mathews et al : Ch 11 pp. 360-413

Internet Resources:

http://www-biol.paisley.ac.uk/kinetics/contents.html http://www.cf.ac.uk/biosi/staff/kille/dentals/dental5_99/

Articles:

Articles 1-8 are in the study guide

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SLIDE 3

Advanced Enzyme Kinetics

TOPICS:

1. Enzyme kinetics: Basics 2. Determination of kinetic constants 3. Kinetics of enzyme inhibitors 4. Kinetics of multisubstrate reactions 5. Kinetics of allosteric enzymes

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SLIDE 4

MIND MAP

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SLIDE 5
  • 1. Enzyme Kinetics: Basics

Contents

 Revision : BOC226 work (Ch 11 in Mathews) plus Internet sources plus Wikipedia (article #8) Steady state models for 1S, 1P when [S]>>[E] The effect of [S] on v The effects of [E] The meaning of kcat and kcat/Km The significance of Km, kcat and kcat/Km

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SLIDE 6

REVISION

What is an enzyme?

It is a BIOLOGICAL CATALYST!!! The reaction catalysed by an enzyme uses exactly the same reactants and produces exactly the same products as the uncatalysed reaction.  Like other catalysts, enzymes do not alter the position of equilibrium between substrates and products.  However, unlike uncatalysed chemical reactions, enzyme-catalysed reactions display saturation kinetics.

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SLIDE 7

For a given enzyme concentration and for relatively low substrate concentrations, the reaction rate increases linearly with substrate concentration; the enzyme molecules are largely free to catalyze the reaction, and increasing substrate concentration means an increasing rate at which the enzyme and substrate molecules encounter one another:

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SLIDE 8

 What an enzyme does: e.g.:

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SLIDE 9

The reduction of activation energy (ΔG) increases the number of reactant molecules with enough energy to reach the activation energy and form the product.  By providing an alternative reaction route and by stabilizing intermediates the enzyme reduces the energy required to reach the highest energy transition state of the reaction. Not so simple – may look like this:

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SLIDE 10

The favored model for the enzyme-substrate interaction is the induced fit model of Daniel Koshland (1958)....

 This model proposes that the initial interaction

between enzyme and substrate is relatively weak, but that these weak interactions rapidly induce conformational changes in the enzyme that strengthen binding.

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SLIDE 11

Catalysis by induced fit

  • Stabilising effect of strong

enzyme binding.

  • Two different mechanisms of

substrate binding: uniform binding: strong substrate binding, differential binding: strong transition state binding.

  • The stabilizing effect of

uniform binding increases both substrate and transition state binding affinity, while differential binding increases

  • nly

transition state binding affinity.

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SLIDE 12

These conformational changes also bring catalytic residues in the active site close to the chemical bonds in the substrate that will be altered in the reaction.  After binding takes place, one or more mechanisms of catalysis lowers the energy of the reaction's transition state, by providing an alternative chemical pathway for the reaction.  There are five possible mechanisms of "over the barrier" catalysis as well as a "through the barrier" mechanism (see Wikipedia article for detail):

  • Catalysis by bond strain
  • Catalysis by proximity and orientation
  • Catalysis involving proton donors/acceptors (Acid/Base

Catalysis)

  • Electrostatic catalysis
  • Covalent catalysis
  • Quantum tunnelling
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SLIDE 13
  • 1. Catalysis by bond strain
  • The affinity of the enzyme to the transition state is

greater than to the substrate itself.

  • Induces structural rearrangements which strain substrate

bonds into a position closer to the conformation of the transition state, so lowering the energy difference between the substrate and transition state and helping catalyze the reaction.

2. Catalysis by proximity and orientation

  • Increases the rate of the reaction as enzyme-substrate

interactions align reactive chemical groups and hold them close together.

  • This reduces the entropy of the reactants and thus makes

reactions such as ligations or addition reactions more favourable

  • There is a reduction in the overall loss of entropy when

two reactants become a single product.

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SLIDE 14

3. Catalysis involving proton donors/acceptors (Acid / Base Catalysis)

  • Proton donors and acceptors, i.e. acids and bases, may

donate and accept protons in order to stabilize developing charges in the transition state.

  • Typically has the effect of activating nucleophile and

electrophile groups, or stabilizing leaving groups.

4. Electrostatic catalysis

  • Stabilization of charged transition states can also be by

residues in the active site forming ionic bonds (or partial ionic charge interactions) with the intermediate.

  • These bonds can either come from acidic or basic side

chains found on amino acids such as Lys, Arg, Asp or Glu or come from metal cofactors such as zinc.

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SLIDE 15

5. Covalent catalysis

  • Involves the substrate forming a transient covalent bond

with residues in the active site.

  • Adds additional covalent intermediate to the reaction, and

helps to reduce the energy of later transition states of the reaction.

  • Covalent bond must, at a later stage in the reaction, be

broken to regenerate the enzyme.

  • Found in enzymes such as proteases like chymotrypsin and

trypsin, where an acyl-enzyme intermediate is formed.

6. Quantum tunnelling

  • Some enzymes operate with kinetics which are faster than

predicted.

  • In "through the barrier" models, a proton or an electron

can tunnel through activation barriers.

  • Quantum tunnelling for protons has been observed in

tryptamine oxidation by aromatic amine dehydrogenase.

  • Does not appear to provide a major catalytic advantage.
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SLIDE 16

The two most important kinetic properties of an enzyme are:

  • 1. how quickly the enzyme becomes saturated

with a particular substrate, and

  • 2. the maximum rate it can achieve.

Knowing these properties suggests what an enzyme might do in the cell and can show how the enzyme will respond to changes in these conditions. [E] + [S] [ES] [E] + [P]

k1 k-1 kcat

v0 = Vmax [S] Km + [S]

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SLIDE 17

 Enzyme kinetics is the

study

  • f

the chemical reactions that are catalysed by enzymes, with a focus on their reaction rates.  The study of an enzyme's kinetics reveals the catalytic mechanism of this enzyme, its role in metabolism, how its activity is controlled, and how a drug or a poison might inhibit the enzyme.

Dihydrofolate reductase from E. coli with its two substrates, dihydrofolate (right) and NADPH (left), bound in the active site.

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SLIDE 18

What is the most plentiful single enzyme on earth? Answer: ribulose bisphosphate carboxylase /

  • xygenase (or RUBISCO)
  • Catalyses the attachment of

carbon dioxide to ribulose bisphosphate, a short sugar chain with five carbon atoms and then clips the lengthened chain into two identical phosphoglycerate pieces.

  • Why so abundant? It fixes
  • nly about three carbon

dioxide molecules per second so plants make more of it – half of the protein in chloroplasts is Rubisco. 2 x 8 protein chains

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SLIDE 19

Steady State Models for 1S, 1P

Concentrations Time Pre-steady state ES forming Steady state ES almost constant

[E]t [E] [ES] [P] [S]

[E] + [S] [ES] [E] + [P]

k1 k-1 kcat

[S] (mM) >> [E]t (10-8 - 10-10M) [S] changes, [E]t constant Assumptions and Givens:  d[ES]/dt = O (Steady state)  [P] = 0 at t = 0  v = d[P]/dt = kcat [ES]  [E]t = [E] + [ES]  Vmax = kcat[E]t  Km = {k-1 + kcat}/k1 = [S]½ at V0 = ½Vmax  v0 = Vmax [S] = kcat[E]t[S] Km + [S] Km + [S]

Cannot measure

Michaelis-Menten

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SLIDE 20

max

] [ ] [ S K S V v

m

MICHEALIS-MENTEN KINETICS

Leonor Michaelis (1875-1949) Maud Menten (1879-1960)

1913

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SLIDE 21

M-M: The Effect of [S] on v

Low [S] : [S] << Km

V0 = {Vmax/Km}[S] V0 [S]

First order reaction

[S] = Km

V0 = {Vmax[S]}/2[S] V0 = ½Vmax [S] > Km :

 mixed order reaction

High [S] : [S] >> Km

V0 = {kcat[E]t[S] }/[S] = kcat[E]t = Vmax

Zero order reaction E is saturated with S

v0 = Vmax [S] Km + [S]

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SLIDE 22

The Effects of [E]

High [S] : [S] >> Km v0 = kcat[E]t = Vmax Vmax [E]t Km independent of [E]

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SLIDE 23

Deviations from Michaelis-Menten kinetics [S]o vo [S]o vo

Substrate inhibition Positive co-operativity

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SLIDE 24

Deviations from Michaelis-Menten kinetics [S]o vo [S]o vo

Negative co-operativity Alternative pathways

E EAB EA EB Products

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SLIDE 25

Deviations from Michaelis-Menten kinetics [S]o vo

Two or more molecules

  • f the same substrate

[S]o vo

Failure to determine vo

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SLIDE 26

Deviations from Michaelis-Menten kinetics [S]o vo

More than one enzyme catalysing the same reaction

max max

] [ ] [ ] [ ] [ S K S V S K S V v

b m b a m a

Vm

a

Km

a

Vm

b

Km

b

Vm

tot

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SLIDE 27

Deviations from Michaelis-Menten kinetics [S]o vo

Failure to subtract blank rate

Blank rate Enzyme reaction plus blank rate

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SLIDE 28

The meaning of kcat and kcat/Km

Km is a useful kinetic constant Indicates [S] at ½Vmax  Suggests putative [S] in vivo Not an independent constant Independent constants obtained by extrapolating to low or high [S]  Vmax and kcat at very high [S] Vmax/Km and kcat/Km at very low [S] The catalytic constant kcat is the first

  • rder rate constant for the conversion
  • f the ES complex to E + P.

It is measured when the enzyme is saturated with substrate (region A) The ratio kcat/Km is the second-order rate constant for the conversion of E + S to E + P at very low [S] (region B)

Region A V0 = kcat[E]1[S]0 Region B V0 = (kcat/Km)[E]1[S]1 ES E + P kcat kcat Km E + S E + P

A B

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SLIDE 29

The significance of Km, kcat and kcat/Km

Km (M) = (k-1 + kcat)/k1

If k-1 >> kcat, then Km k-1/k1 = ([E][S]) / [ES] = Kd Km is an inverse measure of binding strength Large Km can also be due to large kcat Interpretation of Km as Kd for [ES] must be used with caution Km is not an independent kinetic constant

kcat (s-1) -Turnover number

Measures the number of S molecules converted to P per E molecule per second - the rate of the catalytic process Compare catalytic productivity of different enzymes 1/ kcat (s) = time required for 1 E molecule to convert 1 S to P kcat = Vmax/[E]t

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SLIDE 30

kcat/Km (M-1.s-1) If [S] << Km, then [E]t = [E] (most E is free) V0 = (kcat/Km ) [E][S] kcat/Km is a second order rate constant that is a direct measure of E efficiency Compare enzyme specificity for different substrates VA/VB = {kcat/Km }A/ {kcat/Km }B Reaction rate cannot exceed rate of diffusion, = 108-1010 Enzymes such as carbonic anhydrase, acetylcholine esterase, fumarase with kcat/Km 108 have reached the highest level of catalytic evolution

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SLIDE 31

 Enzyme assays follow changes in the concentration of either substrates or products to measure the rate of reaction.  There are many methods of measurement:

  • Spectrophotometric assays observe change in the

absorbance of light between products and reactants (most convenient since they allow the rate of the reaction to be measured continuously);

  • Radiometric assays involve the incorporation or release
  • f radioactivity to measure the amount of product made
  • ver time (i.e., they are discontinuous assays).

 The most sensitive enzyme assays use lasers focused through a microscope to observe changes in single enzyme molecules as they catalyse their reactions.

How do we obtain V0 at different [S]?

  • Continuous assays (spectrophotometric)
  • Fixed time assays (spectrophotometric or radiometric)
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SLIDE 32
  • 2. Determination of Kinetic

Constants

Contents

Graphical Methods Lineweaver-Burk Eadie Hofstee Hanes/Woolf Direct Linear i.e. linear transformations Best fit curve to Michaelis equation

v0 = Vmax [S] Km + [S]

y = mx + c

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SLIDE 33

Graphical Methods:

1/v0 = {(Km/Vmax) (1/[S])} + 1/Vmax

1/v vs 1/S ADVANTAGES:

  • Straight line (y = mx +c)

is easy to draw

  • Vmax does not have to be

determined directly

  • Can read Km and Vmax

easily from the graph

Lineweaver- Burk Graph

Hans Lineweaver and Dean Burk in 1934

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Lineweaver-Burk Graph: Disadvantages

Not acceptable:

  • This plot conceals a poor fit between the data and a straight line
  • Large error at low [S] where measurements are less accurate
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Eadie- Hofstee Graph

v0 = -Km (v0 / [S] ) + Vmax

V = - Km + Vmax V [S]

Advantages:

  • Error is not so severe as with the Lineweaver-Burk plot
  • Generally regarded as being a better technique than LB.
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SLIDE 36

Eadie-Hofstee Graph: Disadvantages

  • Scatter in the data

resulting in values for Km and Vmax which are skewed away from the true values.

  • The

dependent variable v0 occurs in both the x- and y- axis

  • Large error at low

[S]

Slope = -Km Vmax

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SLIDE 37

Hanes/Woolf Graph

+ [S] V Vmax 1 [S] = Km Vmax

Advantages:

  • Direct readout of Km
  • Calculate Vmax from

Km/Vmax intercept

  • Safer to use-

distortion of error bars is minimal

  • Less scatter than

Lineweaver-Burke or Eadie-Hofstee

  • Velocity (dependent)

data does not influence the data on the x-axis

[S]/v0 = (1/Vmax)[S] + Km/Vmax

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SLIDE 38

Hanes/Woolf Graph: Disadvantages

Both axes represent an independent variable: [substrate] Still get errors at low [S]

Slope = 1/Vmax

  • Km
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SLIDE 39

Direct Linear Graph

Vmax = (v0/[S])Km + v0

Join –S and v data points on x and y axis and then extrapolate into positive quadrant. Intersect used to determine Vmax and Km

Advantages:

  • Reliable.
  • No calculations required
  • Kinetic constants read directly off plot
  • Recommended equally with least square

fit to hyperbola.

Eisenthal & Cornish-Bowden, 1974

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Direct Linear Graph: How it copes with errors

Km and Vmax are calculated from the median values

Disadvantage: no provision for replicate values of v

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Best Curve Fit: non-linear regression

(BEST METHOD OF ALL)

If the mechanism is known and complex then the data must be reconciled to the appropriate model (hypothesis) - usually by use of a computer-aided analysis involving a weighted least-squares fit. Many such computer programs are currently available; If the mechanism is not known, initial attempts are usually made to fit the data to the Michaelis-Menten kinetic model:

d[P] =

dt (eqn 1)

v0 = Vmax [S]

Km + [S]

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SLIDE 42

Use of equation 1 involves the determination of the initial rate of reaction over a wide range of substrate concentrations. Equation 1 can be utilised directly using a computer program, involving a weighted least-squares fit, where the parameters for determining the hyperbolic relationship between the initial rate of reaction and initial substrate concentration (i.e.. Km and Vmax) are chosen in order to minimise the errors between the data and the model, and the assumption is made that the errors inherent in the practically determined data are normally distributed about their mean (error-free) value. Example of such a program is GraphPad Prism (Article #7):

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For programs such as Prism that easily do nonlinear regression, the best way to determine Km and Vmax is to fit a hyperbola directly to the substrate-velocity data:

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SLIDE 44

This topic of non-linear regression will be expanded upon during the practical sessions… See also Article #7 for more detailed information