CEE 697K ENVIRONMENTAL REACTION KINETICS Lecture #19 Chloramines - - PDF document

cee 697k
SMART_READER_LITE
LIVE PREVIEW

CEE 697K ENVIRONMENTAL REACTION KINETICS Lecture #19 Chloramines - - PDF document

11/19/2013 Updated: 19 November 2013 CEE 679 Kinetics Lecture #19 1 Print version CEE 697K ENVIRONMENTAL REACTION KINETICS Lecture #19 Chloramines Cont: Primary Literature Enzyme Kinetics: basics Brezonik, pp. 419-450 Introduction David


slide-1
SLIDE 1

11/19/2013 1

CEE 697K

ENVIRONMENTAL REACTION KINETICS

Introduction

David A. Reckhow

CEE 679 Kinetics Lecture #19 1

Updated: 19 November 2013

Print version

Lecture #19

Chloramines Cont: Primary Literature Enzyme Kinetics: basics

Brezonik, pp. 419-450

Conclusions

 “Overall the model calculations suggest that

biodegradation is…..not likely to play a major role in most water distribution systems”

 “the conditions needed for significant HAA removals in a

distribution system (i.e., total biomass densities > 105 cells/cm2 over long distances of pipe) are unlikely in the US water distribution systems where total chlorine residuals typically are high and thus inhibit the development of biofilm

  • n pipe walls”

But this seems to contradict their introductory conclusion – how to reconcile?

David A. Reckhow

2

CEE 679 Kinetics Lecture #19

slide-2
SLIDE 2

11/19/2013 2

CEE 679 Kinetics Lecture #19

What could they have concluded?

 Variability vs diurnal demand

5 10 15 20 25 30 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 Q/Qavg u (ft/s) t (hr) C (ug/L) David A. Reckhow

3

Objective/hypothesis

 Not really stated, but they did end the intro with:  “In this work, computer simulations were performed to predict

the fate of three HAAs (MCAA, DCAA, and TCAA) along a distribution system and within a biologically active filter. Sensitivity analyses were performed to investigate the effects

  • f physical parameters (e.g., fluid velocity) and biological

parameters (e.g., biodegradation kinetics, biomass density) on HAA removal”

David A. Reckhow

4

CEE 679 Kinetics Lecture #19

slide-3
SLIDE 3

11/19/2013 3

What could they have said?

 To determined if observed HAA loss could be

attributed to biodegradation on pipe walls given known physical and microbial characteristics of distribution systems

 To estimate spatial and temporal variability of HAA

concentrations based on a rational physical model

  • f biodegradation in distribution systems

David A. Reckhow

5

CEE 679 Kinetics Lecture #19

What could they have done?

 Find some direct evidence for biodegradation of

HAAs in distribution systems

 A product of the enzymatic reaction?  Chlorohydroxyacetate?  Evidence of abiotic reactions?  Increase in MCAA?

David A. Reckhow

6

CEE 679 Kinetics Lecture #19

slide-4
SLIDE 4

11/19/2013 4

What else?

 Consider mass

transfer resistance within biofilm

David A. Reckhow

7

CEE 679 Kinetics Lecture #19

What should be done next?

 Experimental Work  In-situ controlled study of flow velocity vs DCAA loss in

a pipe segment?

 Effect of biocide in above segment?  Model Refinement  Account for internal mass transfer resistance  Combine with growth model for HAA degraders

David A. Reckhow

8

CEE 679 Kinetics Lecture #19

slide-5
SLIDE 5

11/19/2013 5

SANCHO Model

 B1: biologically fixed bacteria  B2: adsorbed bacteria 9

B1 B2 H1

H2

S CO2

Cl2 Mortality

B3

Cl2 Cl2

Mortality

BDOC

Fixed Bacteria

Free Bacteria

Input (H1, H2, B3) Output Internal Processes

David A. Reckhow

CEE 679 Kinetics Lecture #19

David A. Reckhow

10

CEE 679 Kinetics Lecture #19

slide-6
SLIDE 6

11/19/2013 6

David A. Reckhow

11

CEE 679 Kinetics Lecture #19

David A. Reckhow

12

CEE 679 Kinetics Lecture #19

slide-7
SLIDE 7

11/19/2013 7

Effect of Zn on HAAs

David A. Reckhow

CEE 679 Kinetics Lecture #19

13

 Effect of Zinc on the Transformation of HAAs in

Drinking Water

 Wei Wang and Lizhong Zhu  Journal of Hazardous Materials 174:40-46.

Enzymatic Reactions

David A. Reckhow

CEE 679 Kinetics Lecture #19

14

 Many ways of illustrating the steps  Substrate(s) bond to active site  Product(s) form via transition state  Product(s) are released

slide-8
SLIDE 8

11/19/2013 8

Basic Enzyme Kinetics

David A. Reckhow

CEE 679 Kinetics Lecture #19

15

 Irreversible  Single intermediate  The overall rate is determined by the RLS, k2  But we don’t know [ES], so we can get it by the SS mass

balance

 Again, we only know [Eo] or [Etot], not free [E], so:

] [ ] [ ] ][ [ ] [

2 1 1

ES k ES k S E k dt ES d    

E + S ES  E + P → ←

k1 k-1 k2

] [ ] [ ] [

2 ES

k dt P d dt S d r    

 

] [ ] [ ] [ ] [ ] [

2 1 1

ES k ES k S ES E k

  

 Note that some references use k2 for k-1, and k3 for k2

Reactants, products and Intermediates

David A. Reckhow

CEE 679 Kinetics Lecture #19

16

 Simple Progression of

components for simple single intermediate enzyme reaction

 Shaded block shows steady

state intermediates

 Assumes [S]>>[E]t  From Segel, 1975; Enzyme

Kinetics

slide-9
SLIDE 9

11/19/2013 9

Basic Enzyme Kinetics II

David A. Reckhow

CEE 679 Kinetics Lecture #19

17

 And solving for [ES],

] ][ [ ] [ ] [ ] ][ [

1 2 1 1

S E k ES k ES k S ES k

 

 2 1 1 1

] [ ] ][ [ ] [ k k S k S E k ES

 

1 2 1

] [ ] ][ [ ] [

k k k

  • S

S E ES

 

Michaelis-Menten

David A. Reckhow

CEE 679 Kinetics Lecture #19

18

 Irreversible  Single intermediate

] [ ] [ ] [ ] ][ [ ] [

max 2

1 2 1

S K S r S S E k dt P d r

s k k k

   

E + S ES  E + P → ←

k1 k-1 k2

] [ ] [

2 ES

k dt P d r  

1 2 1

] [ ] ][ [ ] [

k k k

  • S

S E ES

 

slide-10
SLIDE 10

11/19/2013 10

Michaelis Menten Kinetics

David A. Reckhow

CEE 679 Kinetics Lecture #19

19

Substrate Concentration

20 40 60 80 100 120

Reaction Rate

20 40 60 80 100

rmax

0.5rmax

Ks

 Classical substrate plot

] [ ] [ ] [

max

S K S r dt P d r

s 

 

Substrate and growth

David A. Reckhow

CEE 679 Kinetics Lecture #19

20

 If we consider Y  We can define a microorganism-specific substrate

utilization rate, U

 And the maximum rates are then

] [ ] [ ] [ 1

max

S K S dt X d X

s 

    dt dX Y dt S d dt P d r 1 ] [ ] [    

Y YX dt dX X r U     Y k U

max max

  

] [ ] [ ] [ 1 S K S k dt S d X U

s 

 

and

slide-11
SLIDE 11

11/19/2013 11

Linearizations

David A. Reckhow

CEE 679 Kinetics Lecture #19

21

 Lineweaver-Burke  Double reciprocal plot Wikipedia version Voet & Voet version

David A. Reckhow

CEE 679 Kinetics Lecture #19

22

 das

slide-12
SLIDE 12

11/19/2013 12

David A. Reckhow

CEE 679 Kinetics Lecture #19

23

 Lineweaver Burk  Hanes  Eadie-Hofstee

3 types Compare predictions

David A. Reckhow

CEE 679 Kinetics Lecture #19

24

 ad

slide-13
SLIDE 13

11/19/2013 13

Multi-step

David A. Reckhow

CEE 679 Kinetics Lecture #19

25

 Double intermediate  Also gives:  But now:  Note what happens when: k3 >> k2

] [ ] [ ] [

max

S K S r dt P d r

s 

 

E + S ES  EP2  2E + P2 → ←

k1 k-1 k2

3 2 3 2 max

] [ k k E k k r

P1

k3

    1

3 2 2 1 3

k k k k k k Ks   

David A. Reckhow

CEE 679 Kinetics Lecture #19

26

 To next lecture

slide-14
SLIDE 14

11/19/2013 14

Enzymatic Reactions

David A. Reckhow

CEE 679 Kinetics Lecture #19

27

 Many ways of illustrating the steps  Substrate(s) bond to active site  Product(s) form via transition state  Product(s) are released

Basic Enzyme Kinetics

David A. Reckhow

CEE 679 Kinetics Lecture #19

28

 Irreversible  Single intermediate  The overall rate is determined by the RLS, k2  But we don’t know [ES], so we can get it by the SS mass

balance

 Again, we only know [Eo] or [Etot], not free [E], so:

] [ ] [ ] ][ [ ] [

2 1 1

ES k ES k S E k dt ES d    

E + S ES  E + P → ←

k1 k-1 k2

] [ ] [ ] [

2 ES

k dt P d dt S d r    

 

] [ ] [ ] [ ] [ ] [

2 1 1

ES k ES k S ES E k

  

 Note that some references use k2 for k-1, and k3 for k2

slide-15
SLIDE 15

11/19/2013 15

Reactants, products and Intermediates

David A. Reckhow

CEE 679 Kinetics Lecture #19

29

 Simple Progression of

components for simple single intermediate enzyme reaction

 Shaded block shows steady

state intermediates

 Assumes [S]>>[E]t  From Segel, 1975; Enzyme

Kinetics

Basic Enzyme Kinetics II

David A. Reckhow

CEE 679 Kinetics Lecture #19

30

 And solving for [ES],

] ][ [ ] [ ] [ ] ][ [

1 2 1 1

S E k ES k ES k S ES k

 

 2 1 1 1

] [ ] ][ [ ] [ k k S k S E k ES

 

1 2 1

] [ ] ][ [ ] [

k k k

  • S

S E ES

 

slide-16
SLIDE 16

11/19/2013 16

Michaelis-Menten

David A. Reckhow

CEE 679 Kinetics Lecture #19

31

 Irreversible  Single intermediate

] [ ] [ ] [ ] ][ [ ] [

max 2

1 2 1

S K S r S S E k dt P d r

s k k k

   

E + S ES  E + P → ←

k1 k-1 k2

] [ ] [

2 ES

k dt P d r  

1 2 1

] [ ] ][ [ ] [

k k k

  • S

S E ES

 

Michaelis Menten Kinetics

David A. Reckhow

CEE 679 Kinetics Lecture #19

32

Substrate Concentration

20 40 60 80 100 120

Reaction Rate

20 40 60 80 100

rmax

0.5rmax

Ks

 Classical substrate plot

] [ ] [ ] [

max

S K S r dt P d r

s 

 

slide-17
SLIDE 17

11/19/2013 17

Substrate and growth

David A. Reckhow

CEE 679 Kinetics Lecture #19

33

 If we consider Y  We can define a microorganism-specific substrate

utilization rate, U

 And the maximum rates are then

] [ ] [ ] [ 1

max

S K S dt X d X

s 

    dt dX Y dt S d dt P d r 1 ] [ ] [    

Y YX dt dX X r U     Y k U

max max

  

] [ ] [ ] [ 1 S K S k dt S d X U

s 

 

and

Linearizations

David A. Reckhow

CEE 679 Kinetics Lecture #19

34

 Lineweaver-Burke  Double reciprocal plot Wikipedia version Voet & Voet version

slide-18
SLIDE 18

11/19/2013 18

David A. Reckhow

CEE 679 Kinetics Lecture #19

35

 das

David A. Reckhow

CEE 679 Kinetics Lecture #19

36

 Lineweaver Burk  Hanes  Eadie-Hofstee

3 types

slide-19
SLIDE 19

11/19/2013 19

Compare predictions

David A. Reckhow

CEE 679 Kinetics Lecture #19

37

 ad

Multi-step

David A. Reckhow

CEE 679 Kinetics Lecture #19

38

 Double intermediate  Also gives:  But now:  Note what happens when: k3 >> k2

] [ ] [ ] [

max

S K S r dt P d r

s 

 

E + S ES  EP2  2E + P2 → ←

k1 k-1 k2

3 2 3 2 max

] [ k k E k k r

P1

k3

    1

3 2 2 1 3

k k k k k k Ks   

slide-20
SLIDE 20

11/19/2013 20

David A. Reckhow

CEE 679 Kinetics Lecture #19

39

 To next lecture