Visualizing Harmonic analysis: roots of exponential polynomials - - PowerPoint PPT Presentation

visualizing harmonic analysis roots of exponential
SMART_READER_LITE
LIVE PREVIEW

Visualizing Harmonic analysis: roots of exponential polynomials - - PowerPoint PPT Presentation

Visualizing Harmonic analysis: roots of exponential polynomials ICERM June 18, 2014 Sinai Robins Based on some joint work with Nick Gravin, Dmitry Shiryaev, and Mihalis Kolountzakis Wednesday, June 18, 14 Outline Part I. History of tilings


slide-1
SLIDE 1

Visualizing Harmonic analysis: roots of exponential polynomials

Sinai Robins Based on some joint work with Nick Gravin, Dmitry Shiryaev, and Mihalis Kolountzakis

ICERM June 18, 2014

Wednesday, June 18, 14

slide-2
SLIDE 2

Outline

Part I. History of tilings (1-tilings) Part II. Multi-tilings (k-tilings), recent results Part III. Harmonic analysis approaches/ideas

Wednesday, June 18, 14

slide-3
SLIDE 3

Part I. History of tilings (1-tilings)

What kind of tilings?

Wednesday, June 18, 14

slide-4
SLIDE 4

Part I. History of tilings (1-tilings)

What kind of tilings? We fix one object

Wednesday, June 18, 14

slide-5
SLIDE 5

Part I. History of tilings (1-tilings)

What kind of tilings? We fix one object

?

Wednesday, June 18, 14

slide-6
SLIDE 6

Part I. History of tilings (1-tilings)

What kind of tilings? We fix one object

? ?

Wednesday, June 18, 14

slide-7
SLIDE 7

Part I. History of tilings (1-tilings)

What kind of tilings? We fix one object

Voderberg tiling

?

Wednesday, June 18, 14

slide-8
SLIDE 8

The Hirschhorn tiling

(Michael Hirschhorn, 1976, UNSW)

Wednesday, June 18, 14

slide-9
SLIDE 9

Part I. History of tilings (1-tilings)

  • 1. We fix one object
  • 2. Even more, we focus on translational tilings
  • 3. Finally, we invoke the assumption that
  • ur object is convex.

What kind of tilings do we study here?

Wednesday, June 18, 14

slide-10
SLIDE 10

Part I. History of tilings (1-tilings)

What kind of tilings?

Wednesday, June 18, 14

slide-11
SLIDE 11

So we consider translations by one convex object P (necessarily a polytope), and we tile Euclidean space by a set of discrete translation vectors Λ, so that (almost) every point gets covered exactly once.

Example.

This Fedorov solid (also known as a Rhombic Dodecahedron) tiles R3

Wednesday, June 18, 14

slide-12
SLIDE 12

Indicator functions

Definition. Given any set P ⊂ Rd, we define 1P (x) := ( 1 if x ∈ P if x / ∈ P.

Wednesday, June 18, 14

slide-13
SLIDE 13

So to be a bit more Bourbaki about it, we may write:

Definition. We say that P tiles Rd with the discrete multi set of vectors Λ if X

λ∈Λ

1P +λ(v) = 1, for all v / ∈ ∂P + Λ.

Wednesday, June 18, 14

slide-14
SLIDE 14

Question 1. What is the structure of a polytope P that tiles all of Euclidean space by translations, with some discrete set of vectors Λ? For example, when is it a zonotope? What do its facets look like?

Wednesday, June 18, 14

slide-15
SLIDE 15

Question 1. What is the structure of a polytope P that tiles all of Euclidean space by translations, with some discrete set of vectors Λ? Question 2. What is the structure of the discrete set of vectors Λ? For example, when is it a zonotope? What do its facets look like? For example, does Λ have to be a lattice? When? Why? Can Λ be a finite union of lattices?

Wednesday, June 18, 14

slide-16
SLIDE 16

1-tilings in R3

Nikolai Fyodorovich Fedorov

  • Theorem. (Fedorov, 1885) There are 5 different combinatorial types of con-

vex bodies that tile R3.

Wednesday, June 18, 14

slide-17
SLIDE 17

What about higher dimensions? Can we “classify” all polytopes that tile Rd by translations?

1-tilings in Rd

Wednesday, June 18, 14

slide-18
SLIDE 18

Minkowski gave necessary conditions for a polytope to tile Rd.

The first results for tiling Euclidean space in general dimension were given by Hermann Minkowski.

Minkowski gives a partial answer

Wednesday, June 18, 14

slide-19
SLIDE 19

Minkowski’s result

  • Theorem. (Minkowski, 1897)

If a convex polytope P tiles Rd by translations, then:

  • 1. P must be centrally symmetric
  • 2. Each facet of P must be centrally symmetric

Wednesday, June 18, 14

slide-20
SLIDE 20
  • Corollary. Every polytope that tiles R1, R2, or R3

by translations is a zonotope.

Minkowski’s result

  • Theorem. (Minkowski, 1897)

If a convex polytope P tiles Rd by translations, then:

  • 1. P must be centrally symmetric
  • 2. Each facet of P must be centrally symmetric

Wednesday, June 18, 14

slide-21
SLIDE 21
  • Corollary. Every polytope that tiles R1, R2, or R3

by translations is a zonotope.

Minkowski’s result

  • Theorem. (Minkowski, 1897)

If a convex polytope P tiles Rd by translations, then:

  • 1. P must be centrally symmetric
  • 2. Each facet of P must be centrally symmetric

What’s that?

Wednesday, June 18, 14

slide-22
SLIDE 22

Zonotopes

Definition. A Zonotope is a polytope P with the following equivalent properties:

  • 1. All of the faces of P are centrally symmetric
  • 2. P is the Minkowski sum of a finite number of line-segments
  • 3. P is the affine image of some n-dimensional cube [0, 1]n.

Wednesday, June 18, 14

slide-23
SLIDE 23

A zonotope with 9 generators

Example.

This is the projection of a 9-dimensional cube into R3

Wednesday, June 18, 14

slide-24
SLIDE 24

The 24-cell, a source of counterexamples

The 24-cell is a 4-dimensional polytope, arising as the Voronoi cell of the lattice D4 ⊂ R4.

Wednesday, June 18, 14

slide-25
SLIDE 25

The 24-cell, a source of counterexamples

The 24-cell is a 4-dimensional polytope, arising as the Voronoi cell of the lattice D4 ⊂ R4.

It tiles R4 but it is not a zonotope.

The lattice D4 is defined by: D4 := {x ∈ Zd | Pd

k=1 xk ≡ 0 mod 2}

Wednesday, June 18, 14

slide-26
SLIDE 26

The 24-cell, a source of counterexamples

The 24-cell is a 4-dimensional polytope, arising as the Voronoi cell of the lattice D4 ⊂ R4.

It tiles R4 but it is not a zonotope.

  • Quiz. why not?

The lattice D4 is defined by: D4 := {x ∈ Zd | Pd

k=1 xk ≡ 0 mod 2}

Wednesday, June 18, 14

slide-27
SLIDE 27

The 24-cell, a source of counterexamples

The 24-cell is a 4-dimensional polytope, arising as the Voronoi cell of the lattice D4 ⊂ R4.

It tiles R4 but it is not a zonotope.

  • Quiz. why not?
  • Answer. It has a face which is not centrally symmetric.

The lattice D4 is defined by: D4 := {x ∈ Zd | Pd

k=1 xk ≡ 0 mod 2}

Wednesday, June 18, 14

slide-28
SLIDE 28
  • Def. A Voronoi cell (at the origin) of any lattice

L is defined to be {x ∈ Rd | d(x, 0) ≤ d(x, l), for all l ∈ L} This region is, almost by definition, a polytope (why?).

Wednesday, June 18, 14

slide-29
SLIDE 29
  • Def. A Voronoi cell (at the origin) of any lattice

L is defined to be {x ∈ Rd | d(x, 0) ≤ d(x, l), for all l ∈ L} This region is, almost by definition, a polytope (why?).

Wednesday, June 18, 14

slide-30
SLIDE 30
  • Def. A Voronoi cell (at the origin) of any lattice

L is defined to be {x ∈ Rd | d(x, 0) ≤ d(x, l), for all l ∈ L} This region is, almost by definition, a polytope (why?).

Wednesday, June 18, 14

slide-31
SLIDE 31

The Venkov-McMullen result, a converse to Minkowski

After 50 years passed, a converse to Minkowski’s Theorem was found.

  • Theorem. (Minkowski, 1897; Venkov, 1954; McMullen, 1980)

A convex polytope P tiles Rd by translations if and only if:

  • 1. P is centrally symmetric
  • 2. Each of the facets of P is centrally symmetric.
  • 3. Each belt of P contains either 4 or 6 codimension 2 faces.

Wednesday, June 18, 14

slide-32
SLIDE 32

The Venkov-McMullen result, a converse to Minkowski

After 50 years passed, a converse to Minkowski’s Theorem was found.

  • Theorem. (Minkowski, 1897; Venkov, 1954; McMullen, 1980)

A convex polytope P tiles Rd by translations if and only if:

  • 1. P is centrally symmetric
  • 2. Each of the facets of P is centrally symmetric.
  • 3. Each belt of P contains either 4 or 6 codimension 2 faces.

In R4: 52 distinct tiling polytopes In R5: a few thousand. . . .

Wednesday, June 18, 14

slide-33
SLIDE 33

The Venkov-McMullen result, a converse to Minkowski

After 50 years passed, a converse to Minkowski’s Theorem was found.

  • Theorem. (Minkowski, 1897; Venkov, 1954; McMullen, 1980)

A convex polytope P tiles Rd by translations if and only if:

  • 1. P is centrally symmetric
  • 2. Each of the facets of P is centrally symmetric.
  • 3. Each belt of P contains either 4 or 6 codimension 2 faces.

In R4: 52 distinct tiling polytopes In R5: a few thousand. . . .

What’s that?

Wednesday, June 18, 14

slide-34
SLIDE 34

Example.

The red belt for this zonotope consists of 8 faces (1-dimensional faces).

Wednesday, June 18, 14

slide-35
SLIDE 35

Example.

The red belt for this zonotope consists of 8 faces (1-dimensional faces).

Wednesday, June 18, 14

slide-36
SLIDE 36

Example.

The red belt for this zonotope consists of 8 faces (1-dimensional faces).

Wednesday, June 18, 14

slide-37
SLIDE 37

Example.

The red belt for this zonotope consists of 8 faces (1-dimensional faces).

Wednesday, June 18, 14

slide-38
SLIDE 38

Example.

The red belt for this zonotope consists of 8 faces (1-dimensional faces).

Wednesday, June 18, 14

slide-39
SLIDE 39

Example.

The red belt for this zonotope consists of 8 faces (1-dimensional faces).

Wednesday, June 18, 14

slide-40
SLIDE 40

Example.

The red belt for this zonotope consists of 8 faces (1-dimensional faces).

Wednesday, June 18, 14

slide-41
SLIDE 41

Example.

The red belt for this zonotope consists of 8 faces (1-dimensional faces).

Wednesday, June 18, 14

slide-42
SLIDE 42

Example.

The red belt for this zonotope consists of 8 faces (1-dimensional faces).

This polytope therefore does not tile R3 by translations, since it violates condition (3) of the Venkov-McMullen Theorem.

Wednesday, June 18, 14

slide-43
SLIDE 43
  • Example. Does this one tile by translations?

Wednesday, June 18, 14

slide-44
SLIDE 44

Example.

Yes!

Does this one tile by translations?

Wednesday, June 18, 14

slide-45
SLIDE 45

Example.

Another construction for this Fedorov solid is obtained by truncating the octahedron. Yet another construction for it is obtained by considering it as a Permutahedron in R4

Yes!

Wednesday, June 18, 14

slide-46
SLIDE 46

Part II. Multi-tilings (k-tilings)

Wednesday, June 18, 14

slide-47
SLIDE 47

Tiling with multiplicities

A natural generalization of a tiling is a tiling with multiplicity k. (also called a k-tiling, or a multi-tiling)

X

λ∈Λ

1P +λ(v) = k,

Definition. We say that a polytope P tiles Rd with a discrete set of translation vectors Λ if for all v / ∈ ∂P + Λ.

Wednesday, June 18, 14

slide-48
SLIDE 48
  • Example. The integer octagon

Wednesday, June 18, 14

slide-49
SLIDE 49

Wednesday, June 18, 14

slide-50
SLIDE 50

Wednesday, June 18, 14

slide-51
SLIDE 51

Wednesday, June 18, 14

slide-52
SLIDE 52

Wednesday, June 18, 14

slide-53
SLIDE 53

Wednesday, June 18, 14

slide-54
SLIDE 54

Wednesday, June 18, 14

slide-55
SLIDE 55

Wednesday, June 18, 14

slide-56
SLIDE 56

2-dimensional results for k-tilings

1994: Bolle gave a nice combinatorial characterization of all lattice k- tilings of R2 in terms of distances between vertices of a polygon.

Wednesday, June 18, 14

slide-57
SLIDE 57

2-dimensional results for k-tilings

1994: Bolle gave a nice combinatorial characterization of all lattice k- tilings of R2 in terms of distances between vertices of a polygon.

2000: Kolountzakis proved that for every k-tiling of R2 with a multiset Λ, Λ must be a finite union of lattices.

Wednesday, June 18, 14

slide-58
SLIDE 58

2-dimensional results for k-tilings

1994: Bolle gave a nice combinatorial characterization of all lattice k- tilings of R2 in terms of distances between vertices of a polygon.

2000: Kolountzakis proved that for every k-tiling of R2 with a multiset Λ, Λ must be a finite union of lattices.

2013: Dmitry Shiryaev has recently shown (Ph.d thesis) that in R2 every k-tiler must in fact tile with one lattice (i.e. must be periodic).

Wednesday, June 18, 14

slide-59
SLIDE 59

A structure theorem for d-dimensional polytopes that multi-tile

Theorem.(Gravin, R., Shiryaev, Combinatorica, 2012) Suppose a polytope P multiply-tiles Rd with a discrete multiset L. Then P is symmetric, and each facet of P is also symmetric.

Wednesday, June 18, 14

slide-60
SLIDE 60

A partial converse

Suppose that a polytope P enjoys the following properties:

  • 1. P is symmetric
  • 2. Each facet of P is also symmetric
  • 3. P is a rational polytope (all vertices are rational points).

Then P multi-tiles with the integer lattice Zd.

Wednesday, June 18, 14

slide-61
SLIDE 61

Suppose P k-tiles Rd with the set of translation vectors Λ. Then for every general position of -P, there are exactly k points of Λ in the interior of -P.

Technique: counting Λ-points inside P

(“standing at v and looking at λ” versus “standing at λ and looking at v)

Easy proof: X

λ∈Λ

1−P +v(λ) = X

λ∈Λ

1P +λ(v) = k, because λ ∈ −P + v if and only if v ∈ P + λ.

Wednesday, June 18, 14

slide-62
SLIDE 62

Solid angles (volumes of spherical polytopes) play an equivalent role, too!

The previous simple observation has an interesting extension. Let ωP (x) be the proportion of P which intersects a small sphere centered at x ∈ Rd. It’s also called a solid angle at x, relative to P.

  • Theorem. (2013, Gravin, R, Shiryaev) A polytope P k-tiles Rd with

the discrete set of translations Λ if and only if

P

λ∈Λ ωP +v(λ) = k,

for all v ∈ Rd.

Wednesday, June 18, 14

slide-63
SLIDE 63
  • Example. An integer octagon that 7-tiles R2.
  • Example. An integer octagon that 7-tiles R2.

Wednesday, June 18, 14

slide-64
SLIDE 64

Part III. Harmonic analysis approach/ideas

Wednesday, June 18, 14

slide-65
SLIDE 65

A structure theorem for the 3-dimensional set of translation vectors

Theorem.(Gravin, Kolountzakis, R., Shiryaev, 2013, to appear in Discrete and Computational Geometry) Suppose a polytope P multiply-tiles with a discrete multiset L, and suppose that P is not a two-flat zonotope. Then L is a finite union of translated lattices.

Wednesday, June 18, 14

slide-66
SLIDE 66

A structure theorem for the 3-dimensional set of translation vectors

(Proof uses the idempotent theorem in Fourier analysis, due to Meyer and later developed by Paul Cohen.)

Theorem.(Gravin, Kolountzakis, R., Shiryaev, 2013, to appear in Discrete and Computational Geometry) Suppose a polytope P multiply-tiles with a discrete multiset L, and suppose that P is not a two-flat zonotope. Then L is a finite union of translated lattices.

Wednesday, June 18, 14

slide-67
SLIDE 67

A two-flat zonotope with 9 generators Example.

Wednesday, June 18, 14

slide-68
SLIDE 68

A two-flat zonotope with 9 generators Example.

We discovered it by playing with the formulas for the Fourier transform of polytopes.

Wednesday, June 18, 14

slide-69
SLIDE 69

Wednesday, June 18, 14

slide-70
SLIDE 70

Wednesday, June 18, 14

slide-71
SLIDE 71

Wednesday, June 18, 14

slide-72
SLIDE 72

(This is an easy Lemma, but already shows a distinct approach)

Wednesday, June 18, 14

slide-73
SLIDE 73

Wednesday, June 18, 14

slide-74
SLIDE 74

x cos(x) = y cos(y)

Example.

The real zero set of the Fourier transform of the square [0,1]^2 (w.r.t. uniform measure)

Wednesday, June 18, 14

slide-75
SLIDE 75

Harmonic Analysis approach

Thus, we can study the vanishing of the Fourier transform of a polytope, namely ˆ 1P (m) = 0. The vanishing of Fourier transforms of convex bodies in general has been studied, in the context of the Fuglede conjecture, by Alex Iosevich, Mihalis Kolountzakis, Mate Matolci, Izabella Laba, Terry Tao, and others.

Wednesday, June 18, 14

slide-76
SLIDE 76

Harmonic Analysis approach

Some other open questions:

  • 1. Give an analogue of the Venkov-McMullen converse for k-tilings.

2. Given k, describe all polytopes that k-tile. What is the smallest non- trivial k that is possible in dimension d?

Wednesday, June 18, 14

slide-77
SLIDE 77

Harmonic Analysis approach

Some other open questions:

  • 1. Give an analogue of the Venkov-McMullen converse for k-tilings.

2. Given k, describe all polytopes that k-tile. What is the smallest non- trivial k that is possible in dimension d?

  • 3. Find the number of vertices of a k-tiler.

4. Most importantly for us: Using the vanishing set (as a subset of Rd)

  • f the Fourier transform ˆ

1P (m), classify all k-tiling polytopes. Focus on d = 2 first.

Wednesday, June 18, 14

slide-78
SLIDE 78

Harmonic Analysis approach

Something that we keep seeing is that it’s very fruitful to simultaneously think about the Fourier analysis and the Discrete/Combinatorial geometry.

Nick Gravin, Mihail Kolountzakis, Sinai Robins, and Dmitry Shiryaev, Struc- ture results for multiple tilings in 3D, Discrete & Computational Geometry, (2013), 50, 1033-1050. Nick Gravin, Sinai Robins, and Dima Shiryaev, Translational tilings by a polytope, with multiplicity, Combinatorica 32 (6), (2012) 629-648.

References

Wednesday, June 18, 14