Unit 7: Sources of magnetic field Oersteds experiment. Biot and - - PowerPoint PPT Presentation

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Unit 7: Sources of magnetic field Oersteds experiment. Biot and - - PowerPoint PPT Presentation

Unit 7: Sources of magnetic field Oersteds experiment. Biot and Savarts law. Jean-Baptiste Biot Flix Savart Magnetic field lined Magnetic field created by a circular loop Ampres law (A.L.). Applications


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SLIDE 1

Unit 7: Sources of magnetic field

  • Oersted’s experiment.
  • Biot and Savart’s law.
  • Magnetic field lined
  • Magnetic field created by a circular loop
  • Ampère’s law (A.L.). Applications
  • Straight current-carrying wire
  • Coil

Jean-Baptiste Biot Félix Savart André Marie Ampère

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SLIDE 2

Oersted’s experiment. 1820

Tipler, chapter 27,2

  • 1. If switch is off, there isn’t

current and compass needle is aligned along north-south axis

  • 2. If switch is on, current

aligns compass needle perpendicular to current.

  • 3. If current flows in opposite

direction, compass needle is aligned in opposite direction.

An electric current creates a magnetic field

F F

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SLIDE 3

Biot and Savart’s law

  • Magnetic field created by a

current is perpendicular to current, and depends on the intensity of current and distance from current.

Tipler, chapter 27-2

  • Magnetic field created by a

current element (Idl ) at a point P is:

B  d

i

P

2 r 3

r d i 4 r d i 4 d u l r l B             

dl direction is the same as i 0 (vacuum magnetic permittivity)=410-7 Tm/A

r

r

r u   

r 

l  d

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SLIDE 4

 

B A 3

r d 4 i r l B     

  • Magnetic field created by a finite piece of wire is the

sum (integral) of each current element at P:

l  d

B 

i

A B

Biot and Savart’s law

P

This equation can be applied to different conductor shapes, straight conductors, circular conductors,…….

r 

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SLIDE 5

i

Tipler, chapter 27.2

  • Magnetic field lines created by a straight current-

carrying wire are circular in shape around conductor:

Magnetic field lines

Direction of magnetic field comes from right-hand or screw rule

B 

B  B 

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SLIDE 6
  • Magnetic field lines created

by a circular loop:

i

Magnetic field lines

https://www.youtube.com/watch?v=V-M07N4a6-Y

B  B  B 

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SLIDE 7
  • As magnetic poles cannot exist isolated (north pole or

south pole), any field line exiting from a north pole must go to a south pole, and all magnetic field lines are closed lines.

Magnetic field lines

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SLIDE 8
  • Ampère’s law relates the integral of magnetic field

along a closed line and the intensity passing through a surface enclosed by this line. Closed line C must be chosen by us (if possible, should be a magnetic field line):

 

 

c i i

I d  l B  

I1 I2 Ii ... c

Tipler, chapter 27.4

Ampère’s law.

Ampère’s law

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SLIDE 9
  • Each intensity has it own sign, according to the

r¡ght-hand or screw rule.

  • Ampère’s law is equivalent (in Electromagnetism), to Gauss’s

law in Electrostatics.

I1>0 I2>0 Ii<0 c I>0 ...

Ampère’s law.

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SLIDE 10
  • It’s used to compute magnetic fields where symmetry

exists.

  • In order to easily compute the integral of line, the

chosen closed line C should have two features:

  • a) Modulus of magnetic field should be equal at every

points on closed line C.

  • b) Magnetic field vector (B) should be parallel to closed

line C at every points along C.

  • In this way: 

 

   

c c c

BL dl B Bdl dl B  

Ampère’s law.

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SLIDE 11

i

  • Let’s take a straight current-carrying wire. Field

lines

  • f

this conductor are circumferences. Choosing one of such lines of radius R, surface enclosed by such line and applying A.L:

R

B B B B L

I R 2 B dl B d

L L

      

 

l B  

R 2 I B   

Tipler, chapter 27.4

Application of A.L: straight current-carrying wire.

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SLIDE 12
  • A conductor creates a magnetic field on second conductor

and a force appears on this conductor. The same happens

  • n first conductor.

Tipler, chapter 27.4

Force between two straight current-carrying wires

d I2 I1  B2  B1  F21  F12  

http://www.youtube.com/watch?v=43AeuDvWc0k

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SLIDE 13

R 2 Ni B   

  • Applying A.L. to middle line of toroid and to circle

enclosed by this line:

Tipler, chapter 27.4

i i

R

N turns

B

NI R 2 B dl B d

L L

      

 

l B  

Application of A.L: toroid (circular solenoid).

By applying A.L. at points outside

  • f toroid, result is that magnetic

field is zero at any point outside toroid.  B=0  B=0

B B B

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SLIDE 14

ni L Ni B    

  • If L>>>r, the magnetic field inside a solenoid can be taken as

uniform, and null outside the solenoid. From toroid (L=2R):

Application of A.L: solenoid.

L N n 

Number of turns by unit of lenght

S Ni    

Magnetic moment of a solenoid: Magnetic moment by unit of volume inside a solenoid is called magnetization:

B SL S Ni V M         

B r

B B

L

N turns