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The SeibergWitten theory Coulomb phase of N = 1 SO ( N ) N = 1, SO ( - PowerPoint PPT Presentation

The SeibergWitten theory Coulomb phase of N = 1 SO ( N ) N = 1, SO ( N ) F = N 2: SO ( N ) SU ( F = N 2) U (1) R 0 generic point in the classical moduli space SO ( N ) SO (2) U (1) homomorphic U (1) coupling = YM 2 +


  1. The Seiberg–Witten theory

  2. Coulomb phase of N = 1 SO ( N ) N = 1, SO ( N ) F = N − 2: SO ( N ) SU ( F = N − 2) U (1) R Φ 0 generic point in the classical moduli space SO ( N ) → SO (2) ≈ U (1) homomorphic U (1) coupling τ = θ YM 2 π + 4 πi g 2 , transforms under electric–magnetic duality ( E i → B i , B i → − E i ) as: S : τ → − 1 τ not a symmetry, exchanges two equivalent descriptions one weakly coupled, one strongly coupled

  3. Coulomb phase of N = 1 SO ( N ) shifting θ YM by 2 π is a symmetry T : τ → τ + 1 in general τ → ατ + β γτ + δ where α, β, γ, δ are integers ( α, β, γ, δ ∈ Z ) and αδ − βγ = 1 S and T generate SL (2 , Z ) gives a set of equivalent U (1) gauge theories different holomorphic couplings

  4. Coulomb phase of N = 1 SO ( N ) as a function on the moduli space, τ depends on flavor invariant z = det ΦΦ for large z the theory is weakly coupled and we know that the holomor- phic SO ( N ) gauge coupling is � z � i τ SO ≈ 2 π ln Λ b where b = 3( N − 2) − F = 2( N − 2) SO ( N ) → SO (4) ≈ SU (2) × SU (2) → SU (2) D → U (1) so the U (1) gauge coupling g is related to the SO ( N ) coupling by 1 1 1 g 2 = SO + g 2 g 2 SO � z � τ ≈ i π ln Λ b

  5. Coulomb phase of N = 1 SO ( N ) τ has a singularity in the complex variable z at z = ∞ as z → e 2 πi z , τ is shifted by − 2 called a monodromy monodromy of τ at z = ∞ M ∞ = T − 2 consider Φ i Φ j → e 2 πi Φ i Φ j z → e F · 2 πi z τ → τ − 2 F and the the monodromy of τ at ∞ on moduli space is M F ∞ = T − 2 F τ is not a single-valued function on the moduli space even at weak coupling

  6. Coulomb phase of N = 1 SO ( N ) 4 π g 2 = Im τ is invariant under M ∞ (single-valued at weak coupling) single-valued everywhere ⇒ derivatives would be well-defined, by holo- morphy � � dx 2 + d 2 d 2 Im τ = 0 dy 2 where z = x + iy ⇒ Im τ harmonic function , < 0 somewhere, ⇒ g is imaginary Im τ is not single-valued everywhere moduli space has complicated topology or additional singular points

  7. Singular points some particles become massless singular points have their own monodromies at least two monodromies that do not commute with M ∞ otherwise Im τ single-valued and g 2 < 0 with only one other monodromy, circling one is equivalent to circling around the other, and hence the two monodromies commute monodromy is determined by the perturbative β function

  8. Singular points imagine a weakly coupled dual U (1) gauge theory near a singular point with k light flavors W i = ( z − z i ) � k j =1 c j φ + j φ − j + O ( z − z i ) 2 perturbative holomorphic dual coupling is τ i ≈ i ˜ b ˜ 2 π ln( z − z i ) + const . b = − � ˜ 4 fj + 2 3 Q 2 3 Q 2 sj j if all k light flavors have unit charges ˜ b = − 2 k τ i is T 2 k monodromy in ˜ “duality transformation” � τ i = D z i τ monodromy in τ at the singularity z i is M z i = D − 1 z i T 2 k D z i

  9. Singular points we need [ M 0 , M z i ] � = 0 D z i must be nontrivial, and thus contain an odd power of S (and possibly some power of T ). S interchanges electric and magnetic fields the dual quarks must have magnetic charge!

  10. Dual with one more Flavor dual of SO ( N ) with N − 1 flavors is (for N > 3) SU ( F = N − 1) SO (3) U (1) R N − 2 φ N − 1 2 M ′ 1 N − 1 with a superpotential M ′ 2 µ φ j φ i − 1 N,N − 1 det M ′ ji W = 64Λ 2 N − 5 integrate out one flavor with a mass term 1 2 mM ′ N − 1 ,N − 1 M : mesons composed of the remaining light flavors eqm give φ N − 1 φ N − 1 = µ det M N,N − 1 − µm 32Λ 2 N − 5 near det M = 0, SO (3) → U (1)

  11. Dual with F = N − 2 effective superpotential is: � � M ij φ + i φ − j . 1 det M W eff = 2 µ f Λ 2 N − 4 N,N − 2 dual holomorphic gauge coupling is τ = − i � π ln (det M ) + const . at strong coupling for large det M

  12. Monodromy at det M = 0 r = rank( M ), F − r = N − 2 − r massless flavors at det M = 0 Consider M 0 such that det M 0 = 0, and take M 0 → e 2 πi M 0 then τ → � � τ + 2( F − r ) a shift for each zero eigenvalue monodromy of τ at the singular point M 0 is M F − r = D − 1 0 T 2( F − r ) D 0 0 corresponding to a monodromy in τ on the z -plane M 0 = D − 1 0 T 2 D 0 , because of the electric–magnetic duality, φ ± are magnetically charged τ → 0 ⇒ τ → ∞ � strong and weak coupling interchanged

  13. Dual of the Dual magnetic dual of SO ( N ) with F = N − 1 is SO (3) To get the correct dual of the dual, the SO ( F + 1) dual of SO (3) with F flavors must have a dual superpotential 2 µ φ j φ i + ǫα det( φ j φ i ) W = M ji � α determined by consistency ǫ = ± 1 since SO (3) theory has a discrete axial Z 4 F symmetry 2 πi 4 F Q Q → e while SO ( F + 1) theory only has a Z 2 F symmetry (for F > 2). Under the full Z 4 F the det( φ j φ i ) term changes sign, and θ YM is shifted θ YM → θ YM + π

  14. Dual of the Dual of SO ( N ) with F = N − 1, dual dual superpotential � W = M ji N ij + N ij � det M µ d j d i − N,N − 1 + ǫα det( d j d i ) 2 � 64Λ 2 N − 5 2 µ couples the dual meson N ij = φ i φ j to the dual–dual quarks d j . µ = − µ , the eqm for N ij sets M ji = d j d i as we expect with � for ǫ = 1, � � W = 0 if 1 α = 64Λ 2 N − 5 N,N − 1 dual of the dual is the original theory for ǫ = 1, what about ǫ = − 1?

  15. The dyonic dual: ǫ = − 1 SO ( N ) SU ( F = N − 1) U (1) R 1 d F W dyonic = − det( d i d j ) 32Λ 2 N − 5 N,N − 1 d = ( d i , d F ) , i = 1 , . . . , N − 2 add a mass term 1 2 m d F d F , integrate out one flavor eqm for d i gives d i d F = 0 For det( d i d j ) � = 0, SO ( N ) ⇒ U (1) we have (using Λ 2 N − 4 N,N − 2 = m Λ 2 N − 5 N,N − 1 ) � � 1 − det( d i d j ) d + W eff = 1 F d − 2 m 16Λ 2 N − 4 F N,N − 2

  16. The dyonic dual: ǫ = − 1 Near det( d i d j ) = 16Λ 2 N − 4 N,N − 2 ≡ z d , the fields d + F and d − F are light duals of monopoles with θ YM → θ YM + π , are dyons electric and magnetic charge one light field, monodromy of the dyonic coupling must be � � M z d = T 2 charges are such that φ ± i Φ i ∼ d ± F m → 0 ⇒ Λ N,N − 2 → 0, light dyon point → light monopole point at m = 0 SO (3) dual with IR fixed point

  17. Monodromies assuming two singular points in the interior of the moduli space monodromy of τ at z d is determined M 0 M z d = M ∞ M ∞ M M z d 0 z 0 d

  18. Web of Three Dualities: mass term three points where different particles are light and weakly interacting Integrating out a flavor in electric theory gives SO ( N ) with F = N − 3 two branches: runaway vacuum and confinement magnetic dual: monopole VEV, dual Meissner effect ↔ confinement light monopoles ↔ hybrids h i = W α W α Q N − 4 . dyonic dual: dyon VEV ↔ “oblique” confinement (in terms of light meson M ′′ ) 16 m 2 Λ 2 N − 4 16 Λ 2 N − 3 � d + F d − F � = N,N − 2 = N,N − 3 m det M ′′ m det M ′′ yields a runaway superpotential 8 Λ 2 N − 3 N,N − 3 W eff = det M ′′ similar to N = 2 Seiberg–Witten theory difference is that the N = 1 monopoles, dyons are not BPS states

  19. Elliptic curves τ not a single-valued function, transforms under SL (2 , Z ) τ is a section of an SL (2 , Z ) bundle SL (2 , Z ) is the modular symmetry group of a torus section ↔ modular parameter of a torus torus is the solution of a cubic (elliptic) complex equation in two complex dimensions: y 2 = x 3 + Ax 2 + Bx + C ≡ ( x − x 1 )( x − x 2 )( x − x 3 ) where x, y ∈ C , A , B , C single-valued functions of the moduli and pa- rameters of the gauge theory

  20. Modular parameter of a torus making a lattice of points in C using τ and 1 as basis vectors a τ b b a 1 identify opposite sides → torus with modular parameter τ

  21. Equivalent Lattice using new basis vectors ατ + β and γτ + δ If α, β, γ, δ ∈ Z and αδ − βγ = 1 then the new lattice contained in old transformation is invertible with another set of integers αδ − βγ = 1 ensures new parallelogram encloses one basic parallelogram Rescaling second basis vector to 1, the rescaled first basis vector is τ → ατ + β γτ + δ SL (2 , Z ) of torus ↔ SL (2 , Z ) of the U (1) gauge theory

  22. Elliptic Curve and the Torus y 2 = x 3 + Ax 2 + Bx + C ≡ ( x − x 1 )( x − x 2 )( x − x 3 ) y is square root, x plane two sheets that meet along branch cuts cubic has three zeroes, one branch cut between two of the zeroes, other branch cut between the third zero and ∞ ∞ x 3 b x x 2 1 a including point at ∞ , cut plane is topologically ∼ two spheres con- nected by two tubes ∼ torus, a and b cycles of torus

  23. Modular Parameter of the Torus given by the ratio of the periods, ω 1 and ω 2 , of the torus: � � dx dx y , τ ( A, B, C ) = ω 2 ω 1 = y , ω 2 = a b ω 1 where a and b are basis of cycles around the torus cycles ↔ two sides of the parallelogram holomorphic coupling τ is singular when a cycle shrinks to zero, i.e. when two roots meet or one roots goes to ∞ , branch cuts disappears, torus is singular

  24. Singular Tori Two roots are equal if the discriminant vanishes ∆ = Π i<j ( x i − x j ) 2 = 4 A 3 C − B 2 A 2 − 18 ABC + 4 B 3 + 27 C 2 = 0 single-valued A , B , C easier to determine than the multi-valued τ given A , B , and C we can calculate τ

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