Concentration for Coulomb gases and Coulomb transport inequalities - - PowerPoint PPT Presentation

concentration for coulomb gases and coulomb transport
SMART_READER_LITE
LIVE PREVIEW

Concentration for Coulomb gases and Coulomb transport inequalities - - PowerPoint PPT Presentation

Concentration for Coulomb gases and Coulomb transport inequalities Myl` ene Ma da U. Lille, Laboratoire Paul Painlev e Joint work with Djalil Chafa and Adrien Hardy U. Paris-Dauphine and U. Lille ICERM, Providence - February


slide-1
SLIDE 1

Concentration for Coulomb gases and Coulomb transport inequalities

Myl` ene Ma¨ ıda

  • U. Lille, Laboratoire Paul Painlev´

e Joint work with Djalil Chafa¨ ı and Adrien Hardy

  • U. Paris-Dauphine and U. Lille

ICERM, Providence - February 2018

slide-2
SLIDE 2

2

Outline of the talk

slide-3
SLIDE 3

2

Outline of the talk

◮ Coulomb gases : definition and known results

slide-4
SLIDE 4

2

Outline of the talk

◮ Coulomb gases : definition and known results ◮ Concentration inequalities

slide-5
SLIDE 5

2

Outline of the talk

◮ Coulomb gases : definition and known results ◮ Concentration inequalities ◮ Outline of the proof and Coulomb transport inequalities

slide-6
SLIDE 6

3

Coulomb gases (d ≥ 2)

We consider the Poisson equation ∆g = −cdδ0. The fundamental solution is given by g(x) := − log |x| for d = 2,

1 |x|d−2

for d ≥ 3. A gas of N particles interacting according to the Coulomb law would have an energy given by HN(x1, . . . , xN) :=

  • i=j

g(xi − xj) + N

N

  • i=1

V (xi).

slide-7
SLIDE 7

4

We denote by PN

V ,β the Gibbs measure on (Rd)N associated to this

energy : dPN

V ,β(x1, . . . , xN) =

1 Z N

V ,β

e− β

2 HN(x1,...,xN)dx1, . . . , dxN

slide-8
SLIDE 8

4

We denote by PN

V ,β the Gibbs measure on (Rd)N associated to this

energy : dPN

V ,β(x1, . . . , xN) =

1 Z N

V ,β

e− β

2 HN(x1,...,xN)dx1, . . . , dxN

Example (Ginibre) : let MN be an N by N matrix with iid entries with law NC(0, 1

N ), then the eigenvalues have joint law PN |x|2,2 with

dPN

|x|2,2(x1, . . . , xN) ∼

  • i<j

|xi − xj|2e−N N

i=1 |xi|2

slide-9
SLIDE 9

5

Global asymptotics of the empirical measure

slide-10
SLIDE 10

5

Global asymptotics of the empirical measure

Our main subject of study is the empirical measure ˆ µN := 1 N

N

  • i=1

δxi.

slide-11
SLIDE 11

5

Global asymptotics of the empirical measure

Our main subject of study is the empirical measure ˆ µN := 1 N

N

  • i=1

δxi. One can rewrite HN(x1, . . . , xN) = N2E=

V (ˆ

µN) := N2

  • x=y

g(x − y)ˆ µN(dx)ˆ µN(dy) +

  • V (x)ˆ

µN(dx)

  • .
slide-12
SLIDE 12

5

Global asymptotics of the empirical measure

Our main subject of study is the empirical measure ˆ µN := 1 N

N

  • i=1

δxi. One can rewrite HN(x1, . . . , xN) = N2E=

V (ˆ

µN) := N2

  • x=y

g(x − y)ˆ µN(dx)ˆ µN(dy) +

  • V (x)ˆ

µN(dx)

  • .

More generally, one can define, for any µ ∈ P(Rd), EV (µ) := g(x − y) + 1 2V (x) + 1 2V (y)

  • µ(dx)µ(dy).
slide-13
SLIDE 13

6

If V is admissible, there exists a unique minimizer µV of the functional EV and it is compactly suppported.

slide-14
SLIDE 14

6

If V is admissible, there exists a unique minimizer µV of the functional EV and it is compactly suppported. If V is continuous, one can check that almost surely ˆ µN converges weakly to µV .

slide-15
SLIDE 15

6

If V is admissible, there exists a unique minimizer µV of the functional EV and it is compactly suppported. If V is continuous, one can check that almost surely ˆ µN converges weakly to µV . A large deviation principle, due to Chafa¨ ı, Gozlan and Zitt is also available :

slide-16
SLIDE 16

6

If V is admissible, there exists a unique minimizer µV of the functional EV and it is compactly suppported. If V is continuous, one can check that almost surely ˆ µN converges weakly to µV . A large deviation principle, due to Chafa¨ ı, Gozlan and Zitt is also available : for d a distance that metrizes the weak topology (for example Fortet-Mourier) one has in particular 1 N2 log PN

V ,β(d(ˆ

µN, µV ) ≥ r) − − − − →

N→∞ −β

2 inf

d(µ,µV )≥r(EV (µ) − EV (µV )).

slide-17
SLIDE 17

6

If V is admissible, there exists a unique minimizer µV of the functional EV and it is compactly suppported. If V is continuous, one can check that almost surely ˆ µN converges weakly to µV . A large deviation principle, due to Chafa¨ ı, Gozlan and Zitt is also available : for d a distance that metrizes the weak topology (for example Fortet-Mourier) one has in particular 1 N2 log PN

V ,β(d(ˆ

µN, µV ) ≥ r) − − − − →

N→∞ −β

2 inf

d(µ,µV )≥r(EV (µ) − EV (µV )).

What about concentration ?

slide-18
SLIDE 18

6

If V is admissible, there exists a unique minimizer µV of the functional EV and it is compactly suppported. If V is continuous, one can check that almost surely ˆ µN converges weakly to µV . A large deviation principle, due to Chafa¨ ı, Gozlan and Zitt is also available : for d a distance that metrizes the weak topology (for example Fortet-Mourier) one has in particular 1 N2 log PN

V ,β(d(ˆ

µN, µV ) ≥ r) − − − − →

N→∞ −β

2 inf

d(µ,µV )≥r(EV (µ) − EV (µV )).

What about concentration ? Local behavior extensively using several variations of the concept of renormalized energy (see in particular Simona’s talk this morning).

slide-19
SLIDE 19

7

Concentration estimates

slide-20
SLIDE 20

7

Concentration estimates

We will consider both the bounded Lipschitz distance dBL and the Wassertein W1 distance, where we recall that dBL(µ, ν) = sup

f ∞ ≤ 1 f Lip ≤ 1

  • f d(µ − ν); W1(µ, ν) =

sup

f Lip≤1

  • f d(µ − ν)
slide-21
SLIDE 21

7

Concentration estimates

We will consider both the bounded Lipschitz distance dBL and the Wassertein W1 distance, where we recall that dBL(µ, ν) = sup

f ∞ ≤ 1 f Lip ≤ 1

  • f d(µ − ν); W1(µ, ν) =

sup

f Lip≤1

  • f d(µ − ν)

Theorem

If V is C2 and V and ∆V satisfy some growth conditions,

slide-22
SLIDE 22

7

Concentration estimates

We will consider both the bounded Lipschitz distance dBL and the Wassertein W1 distance, where we recall that dBL(µ, ν) = sup

f ∞ ≤ 1 f Lip ≤ 1

  • f d(µ − ν); W1(µ, ν) =

sup

f Lip≤1

  • f d(µ − ν)

Theorem

If V is C2 and V and ∆V satisfy some growth conditions,then there exist a > 0, b ∈ R, c(β) such that for all N ≥ 2 and for all r > 0, PN

V ,β(d(ˆ

µN, µV ) ≥ r) ≤ e−aβN2r 2+1d=2

β 4 N log N+bβN2− 2 d +c(β)N

slide-23
SLIDE 23

8

More insight about the growth conditions :

slide-24
SLIDE 24

8

More insight about the growth conditions :

◮ ∆V has to grow not faster then V

slide-25
SLIDE 25

8

More insight about the growth conditions :

◮ ∆V has to grow not faster then V ◮ as soon as the model is well defined, the concentration estimate

holds for dBL

slide-26
SLIDE 26

8

More insight about the growth conditions :

◮ ∆V has to grow not faster then V ◮ as soon as the model is well defined, the concentration estimate

holds for dBL

◮ if moreover V (x) c|x|κ, for some κ > 0, we can say more about

c(β) near 0 and near ∞

slide-27
SLIDE 27

8

More insight about the growth conditions :

◮ ∆V has to grow not faster then V ◮ as soon as the model is well defined, the concentration estimate

holds for dBL

◮ if moreover V (x) c|x|κ, for some κ > 0, we can say more about

c(β) near 0 and near ∞

◮ if moreover V (x) c|x|2, the concentration estimate holds for W1

slide-28
SLIDE 28

8

More insight about the growth conditions :

◮ ∆V has to grow not faster then V ◮ as soon as the model is well defined, the concentration estimate

holds for dBL

◮ if moreover V (x) c|x|κ, for some κ > 0, we can say more about

c(β) near 0 and near ∞

◮ if moreover V (x) c|x|2, the concentration estimate holds for W1 ◮ the latter allows to get the almost sure convergence of

W1(ˆ µN, µV ) to zero down to β ≃ log N

N

slide-29
SLIDE 29

8

More insight about the growth conditions :

◮ ∆V has to grow not faster then V ◮ as soon as the model is well defined, the concentration estimate

holds for dBL

◮ if moreover V (x) c|x|κ, for some κ > 0, we can say more about

c(β) near 0 and near ∞

◮ if moreover V (x) c|x|2, the concentration estimate holds for W1 ◮ the latter allows to get the almost sure convergence of

W1(ˆ µN, µV ) to zero down to β ≃ log N

N

◮ if the potential is subquadratic, a, b and c(β) can be made more

explicit.

slide-30
SLIDE 30

9

A few more comments :

slide-31
SLIDE 31

9

A few more comments :

◮ Possible rewriting : there exist r0, C > 0, such that for all N ≥ 2, if

r ≥

  • r0
  • log N

N

if d = 2 r0 N−1/d if d ≥ 3, PN

V ,β(d(ˆ

µN, µV ) ≥ r) ≤ e−CN2r 2.

slide-32
SLIDE 32

9

A few more comments :

◮ Possible rewriting : there exist r0, C > 0, such that for all N ≥ 2, if

r ≥

  • r0
  • log N

N

if d = 2 r0 N−1/d if d ≥ 3, PN

V ,β(d(ˆ

µN, µV ) ≥ r) ≤ e−CN2r 2.

◮ thanks to the large deviation results of CGZ, we know that we are

in the right scale

slide-33
SLIDE 33

9

A few more comments :

◮ Possible rewriting : there exist r0, C > 0, such that for all N ≥ 2, if

r ≥

  • r0
  • log N

N

if d = 2 r0 N−1/d if d ≥ 3, PN

V ,β(d(ˆ

µN, µV ) ≥ r) ≤ e−CN2r 2.

◮ thanks to the large deviation results of CGZ, we know that we are

in the right scale

◮ for Ginibre, the constants can be computed explicitely ; improves

  • n previous results based on determinantal structure (can we use

the Gaussian nature of the entries ?)

slide-34
SLIDE 34

9

A few more comments :

◮ Possible rewriting : there exist r0, C > 0, such that for all N ≥ 2, if

r ≥

  • r0
  • log N

N

if d = 2 r0 N−1/d if d ≥ 3, PN

V ,β(d(ˆ

µN, µV ) ≥ r) ≤ e−CN2r 2.

◮ thanks to the large deviation results of CGZ, we know that we are

in the right scale

◮ for Ginibre, the constants can be computed explicitely ; improves

  • n previous results based on determinantal structure (can we use

the Gaussian nature of the entries ?)

◮ non optimal local laws can be deduced

slide-35
SLIDE 35

10

Outline of the proof

slide-36
SLIDE 36

10

Outline of the proof

Special case when V = δK, for K a compact set of Rd.

slide-37
SLIDE 37

10

Outline of the proof

Special case when V = δK, for K a compact set of Rd. First ingredient : lower bound on the partition function. There exists C such that Z N

V ,β ≥ e− β

2 N2EV (µV )−NC.

slide-38
SLIDE 38

10

Outline of the proof

Special case when V = δK, for K a compact set of Rd. First ingredient : lower bound on the partition function. There exists C such that Z N

V ,β ≥ e− β

2 N2EV (µV )−NC.

For A ⊂ (Rd)N, PN

V ,β(A)

= 1 Z N

V ,β

  • A

e− β

2 HN(x1,...,xN)dx1 . . . dxN

slide-39
SLIDE 39

10

Outline of the proof

Special case when V = δK, for K a compact set of Rd. First ingredient : lower bound on the partition function. There exists C such that Z N

V ,β ≥ e− β

2 N2EV (µV )−NC.

For A ⊂ (Rd)N, PN

V ,β(A)

= 1 Z N

V ,β

  • A

e− β

2 HN(x1,...,xN)dx1 . . . dxN

≤ eNC

  • A

e− β

2 N2(E= V (ˆ

µN)−EV (µV ))dx1 . . . dxN

slide-40
SLIDE 40

10

Outline of the proof

Special case when V = δK, for K a compact set of Rd. First ingredient : lower bound on the partition function. There exists C such that Z N

V ,β ≥ e− β

2 N2EV (µV )−NC.

For A ⊂ (Rd)N, PN

V ,β(A)

= 1 Z N

V ,β

  • A

e− β

2 HN(x1,...,xN)dx1 . . . dxN

≤ eNC

  • A

e− β

2 N2(E= V (ˆ

µN)−EV (µV ))dx1 . . . dxN

≤ eNCe− β

2 N2 infA(E= V (ˆ

µN)−EV (µV ))(volK)N

slide-41
SLIDE 41

10

Outline of the proof

Special case when V = δK, for K a compact set of Rd. First ingredient : lower bound on the partition function. There exists C such that Z N

V ,β ≥ e− β

2 N2EV (µV )−NC.

For A ⊂ (Rd)N, PN

V ,β(A)

= 1 Z N

V ,β

  • A

e− β

2 HN(x1,...,xN)dx1 . . . dxN

≤ eNC

  • A

e− β

2 N2(E= V (ˆ

µN)−EV (µV ))dx1 . . . dxN

≤ eNCe− β

2 N2 infA(E= V (ˆ

µN)−EV (µV ))(volK)N

We want to take A := {d(ˆ µN, µV ) ≥ r}.

slide-42
SLIDE 42

11

Coulomb transport inequalities

slide-43
SLIDE 43

11

Coulomb transport inequalities

We aim at an inequality of the type : for any µ ∈ P(Rd), d(µ, µV )2 ≤ CV (EV (µ) − EV (µV )).

slide-44
SLIDE 44

11

Coulomb transport inequalities

We aim at an inequality of the type : for any µ ∈ P(Rd), d(µ, µV )2 ≤ CV (EV (µ) − EV (µV )). This inequality is the Coulomb counterpart of Talagrand T1 inequality : ν satisfies T1 iif there exists C > 0 such that for any µ ∈ P(Rd), W1(µ, ν)2 ≤ CH(µ|ν).

slide-45
SLIDE 45

11

Coulomb transport inequalities

We aim at an inequality of the type : for any µ ∈ P(Rd), d(µ, µV )2 ≤ CV (EV (µ) − EV (µV )). This inequality is the Coulomb counterpart of Talagrand T1 inequality : ν satisfies T1 iif there exists C > 0 such that for any µ ∈ P(Rd), W1(µ, ν)2 ≤ CH(µ|ν). In 1D, previous results by Biane-Voiculescu, Hiai-Petz-Ueda, Ledoux-Popescu, M.-Maurel-Segala

slide-46
SLIDE 46

11

Coulomb transport inequalities

We aim at an inequality of the type : for any µ ∈ P(Rd), d(µ, µV )2 ≤ CV (EV (µ) − EV (µV )). This inequality is the Coulomb counterpart of Talagrand T1 inequality : ν satisfies T1 iif there exists C > 0 such that for any µ ∈ P(Rd), W1(µ, ν)2 ≤ CH(µ|ν). In 1D, previous results by Biane-Voiculescu, Hiai-Petz-Ueda, Ledoux-Popescu, M.-Maurel-Segala To point out what is specific to the Coulombian nature of the interaction, we will show the following local version of our inequality :

slide-47
SLIDE 47

11

Coulomb transport inequalities

We aim at an inequality of the type : for any µ ∈ P(Rd), d(µ, µV )2 ≤ CV (EV (µ) − EV (µV )). This inequality is the Coulomb counterpart of Talagrand T1 inequality : ν satisfies T1 iif there exists C > 0 such that for any µ ∈ P(Rd), W1(µ, ν)2 ≤ CH(µ|ν). In 1D, previous results by Biane-Voiculescu, Hiai-Petz-Ueda, Ledoux-Popescu, M.-Maurel-Segala To point out what is specific to the Coulombian nature of the interaction, we will show the following local version of our inequality : Proposition For any compact set D of Rd, there exists CD such that for any µ, ν ∈ P(D) such that E(µ) < ∞ and E(ν) < ∞, W1(µ, ν)2 ≤ CDE(µ − ν).

slide-48
SLIDE 48

12

Proof of the Proposition

slide-49
SLIDE 49

12

Proof of the Proposition

If µ and ν have their support in D, there exists D+ such that W1(µ, ν) = sup

f Lip ≤ 1 f ∈ C(D+)

  • f d(µ − ν)
slide-50
SLIDE 50

12

Proof of the Proposition

If µ and ν have their support in D, there exists D+ such that W1(µ, ν) = sup

f Lip ≤ 1 f ∈ C(D+)

  • f d(µ − ν)

By a density argument, one can asumme that η := µ − ν has a smooth density h,

slide-51
SLIDE 51

12

Proof of the Proposition

If µ and ν have their support in D, there exists D+ such that W1(µ, ν) = sup

f Lip ≤ 1 f ∈ C(D+)

  • f d(µ − ν)

By a density argument, one can asumme that η := µ − ν has a smooth density h, let Uη := g ∗ h.

slide-52
SLIDE 52

12

Proof of the Proposition

If µ and ν have their support in D, there exists D+ such that W1(µ, ν) = sup

f Lip ≤ 1 f ∈ C(D+)

  • f d(µ − ν)

By a density argument, one can asumme that η := µ − ν has a smooth density h, let Uη := g ∗ h. From the Poisson equation, we know that for any smooth function ϕ,

  • ∆ϕ(y)g(y)dy = −cdϕ(0).
slide-53
SLIDE 53

12

Proof of the Proposition

If µ and ν have their support in D, there exists D+ such that W1(µ, ν) = sup

f Lip ≤ 1 f ∈ C(D+)

  • f d(µ − ν)

By a density argument, one can asumme that η := µ − ν has a smooth density h, let Uη := g ∗ h. From the Poisson equation, we know that for any smooth function ϕ,

  • ∆ϕ(y)g(y)dy = −cdϕ(0).

Choosing ϕ(y) = h(x − y), we get that

  • ∆h(x − y)g(y)dy = −cdh(x)
slide-54
SLIDE 54

12

Proof of the Proposition

If µ and ν have their support in D, there exists D+ such that W1(µ, ν) = sup

f Lip ≤ 1 f ∈ C(D+)

  • f d(µ − ν)

By a density argument, one can asumme that η := µ − ν has a smooth density h, let Uη := g ∗ h. From the Poisson equation, we know that for any smooth function ϕ,

  • ∆ϕ(y)g(y)dy = −cdϕ(0).

Choosing ϕ(y) = h(x − y), we get that

  • ∆h(x − y)g(y)dy = −cdh(x)

But we also have

  • ∆h(x − y)g(y)dy =
  • ∆g(x − y)h(y)dy = ∆Uη(x).
slide-55
SLIDE 55

13

Therefore, for any Lipschitz function with support in D+

  • f dη = − 1

cd

  • f (x)∆Uη(x)dx = − 1

cd

  • ∇f (x) · ∇Uη(x)dx
slide-56
SLIDE 56

13

Therefore, for any Lipschitz function with support in D+

  • f dη = − 1

cd

  • f (x)∆Uη(x)dx = − 1

cd

  • ∇f (x) · ∇Uη(x)dx

We can now conclude as

  • ∇f (x) · ∇Uη(x)dx
  • D+

|∇f | · |∇Uη| ≤

  • D+

|∇Uη| ≤

  • vol(D+)
  • |∇Uη|2

1/2 .

slide-57
SLIDE 57

13

Therefore, for any Lipschitz function with support in D+

  • f dη = − 1

cd

  • f (x)∆Uη(x)dx = − 1

cd

  • ∇f (x) · ∇Uη(x)dx

We can now conclude as

  • ∇f (x) · ∇Uη(x)dx
  • D+

|∇f | · |∇Uη| ≤

  • D+

|∇Uη| ≤

  • vol(D+)
  • |∇Uη|2

1/2 . But

  • |∇Uη|2 = cdE(η).
slide-58
SLIDE 58

14

Thank you for your attention !