Supersymmetry: a very basic, biased and completely incomplete - - PowerPoint PPT Presentation

supersymmetry a very basic biased and completely
SMART_READER_LITE
LIVE PREVIEW

Supersymmetry: a very basic, biased and completely incomplete - - PowerPoint PPT Presentation

NExT PhD school, Coseners House, July 2011 Supersymmetry: a very basic, biased and completely incomplete introduction Michael Kr amer (RWTH Aachen) 1 / 65 Outline The supersymmetric harmonic oscillator Motivation for SUSY: Symmetry


slide-1
SLIDE 1

NExT PhD school, Cosener’s House, July 2011

Supersymmetry: a very basic, biased and completely incomplete introduction

Michael Kr¨ amer (RWTH Aachen)

1 / 65

slide-2
SLIDE 2

Outline

◮ The supersymmetric harmonic oscillator ◮ Motivation for SUSY: Symmetry & the hierarchy problem ◮ The MSSM ◮ SUSY searches

2 / 65

slide-3
SLIDE 3

References

◮ Supersymmetry and the MSSM: An Elementary introduction

Ian J.R. Aitchison, e-Print: hep-ph/0505105

◮ A Supersymmetry primer

Stephen P. Martin, e-Print: hep-ph/9709356

◮ Theory and phenomenology of sparticles

  • M. Drees, R. Godbole, P. Roy, World Scientific

◮ Hide and seek with supersymmetry

Herbi Dreiner, e-Print: hep-ph/9902347

◮ Beyond the standard model for hill walkers

John R. Ellis, e-Print: hep-ph/9812235

3 / 65

slide-4
SLIDE 4

Outline

◮ The supersymmetric harmonic oscillator ◮ Motivation for SUSY: Symmetry & the hierarchy problem ◮ The MSSM ◮ SUSY searches

4 / 65

slide-5
SLIDE 5

The supersymmetric harmonic oscillator

Recall raising and lowering operators in quantum mechanics b+|nB = √ nB + 1 |nB + 1 b−|nB = √nB |nB − 1 where b−|0 = 0 and [b−, b+] = 1; [b−, b−] = [b+, b+] = 0 → b+/b− creates/annihilates bosons

5 / 65

slide-6
SLIDE 6

The supersymmetric harmonic oscillator

Recall raising and lowering operators in quantum mechanics b+|nB = √ nB + 1 |nB + 1 b−|nB = √nB |nB − 1 where b−|0 = 0 and [b−, b+] = 1; [b−, b−] = [b+, b+] = 0 → b+/b− creates/annihilates bosons Analogously for fermions f +|nF = √ nF + 1|nF + 1 f −|nF = √nF|nF − 1 But fermions obey Pauli exclusion principle → only two states |0 and f +|0 = |1 So for fermions f +|0 = |1, f −|1 = |0 and f −|0 = f +|1 = 0

5 / 65

slide-7
SLIDE 7

For fermions f +|0 = |1, f −|1 = |0 and f −|0 = f +|1 = 0 Matrix representation:

with |0 ≡ „ 1 « and |1 ≡ „ 0 1 «

  • ne has

f + = „ 0 0 1 0 « and f − = „ 0 1 0 0 « and

{f −, f +} = 1; {f −, f −} = {f +, f +} = 0 .

6 / 65

slide-8
SLIDE 8

For fermions f +|0 = |1, f −|1 = |0 and f −|0 = f +|1 = 0 Matrix representation:

with |0 ≡ „ 1 « and |1 ≡ „ 0 1 «

  • ne has

f + = „ 0 0 1 0 « and f − = „ 0 1 0 0 « and

{f −, f +} = 1; {f −, f −} = {f +, f +} = 0 . Thus, bosonic and fermionic Hamilton operators take the form HB = ωB

  • b+b− + 1

2

  • HF

= ωF

  • f +f − − 1

2

  • 6 / 65
slide-9
SLIDE 9

SUSY transformations

SUSY operators act on product space |nB|nF ≡ |nBnF where nB = 0, 1, . . . , ∞; nF = 0, 1

7 / 65

slide-10
SLIDE 10

SUSY transformations

SUSY operators act on product space |nB|nF ≡ |nBnF where nB = 0, 1, . . . , ∞; nF = 0, 1 Need to construct operators with Q+|nBnF ∝ |nB − 1, nF + 1 Q−|nBnF ∝ |nB + 1, nF − 1 so that Q+|boson ∝ |fermion Q+|fermion = 0 Q−|fermion ∝ |boson Q−|boson = 0 .

7 / 65

slide-11
SLIDE 11

SUSY transformations

SUSY operators act on product space |nB|nF ≡ |nBnF where nB = 0, 1, . . . , ∞; nF = 0, 1 Need to construct operators with Q+|nBnF ∝ |nB − 1, nF + 1 Q−|nBnF ∝ |nB + 1, nF − 1 so that Q+|boson ∝ |fermion Q+|fermion = 0 Q−|fermion ∝ |boson Q−|boson = 0 . A simple choice is Q+ = b−f + Q− = b+f −

where (f +)2 = (f −)2 = 0 ⇒ Q2

+ = Q2 − = 0 .

7 / 65

slide-12
SLIDE 12

We now want to construct a SUSY invariant Hamilton operator so that [HSUSY, Q±] = 0 .

8 / 65

slide-13
SLIDE 13

We now want to construct a SUSY invariant Hamilton operator so that [HSUSY, Q±] = 0 . The simple choice HSUSY = {Q+, Q−} works.

[Check e.g. [HSUSY, Q+] = Q+Q−Q+ + Q−Q+Q+ − Q+Q+Q− − Q+Q−Q+ = 0 .]

8 / 65

slide-14
SLIDE 14

We now want to construct a SUSY invariant Hamilton operator so that [HSUSY, Q±] = 0 . The simple choice HSUSY = {Q+, Q−} works.

[Check e.g. [HSUSY, Q+] = Q+Q−Q+ + Q−Q+Q+ − Q+Q+Q− − Q+Q−Q+ = 0 .]

Now recall Q+ = √ω b−f + Q− = √ω b+f − so that HSUSY = ω{b−f +, b+f −} = ω(b−f +b+f − + b+f −b−f +) = ω((1 + b+b−)f +f − + b+b−(1 − f +f −)) = ω(f +f − + b+b−) = HB + HF provided we set ωB = ωF = ω .

8 / 65

slide-15
SLIDE 15

The energy spectrum of the SUSY oscillator has remarkable features HSUSY|nBnF = ω(NB + NF)|nBnF → E = ω(nB + nF) → the energy of the ground state is zero

9 / 65

slide-16
SLIDE 16

The energy spectrum of the SUSY oscillator has remarkable features HSUSY|nBnF = ω(NB + NF)|nBnF → E = ω(nB + nF) → the energy of the ground state is zero The spectrum of the SUSY oscillator: Energies E20 = E11 = 2ω E10 = E01 = ω E00 = 0

9 / 65

slide-17
SLIDE 17

Summary of the SUSY oscillator

◮ If we start with a bosonic system we need to introduce fermions

(and vice versa)

◮ We need identical couplings: ωF = ωB ◮ The spectrum consists of pairs of states (bosonic/fermionic) with

the same energy

◮ The energy of the ground state is zero

10 / 65

slide-18
SLIDE 18

Summary of the SUSY oscillator

◮ If we start with a bosonic system we need to introduce fermions

(and vice versa) → for a SUSY extension of the SM we will have to introduce SUSY partners for all SM particles

◮ We need identical couplings: ωF = ωB

→ SUSY extensions of the SM do not introduce new couplings

◮ The spectrum consists of pairs of states (bosonic/fermionic) with

the same energy → SM particles and SUSY partners have the same mass (and internal quantum numbers)

◮ The energy of the ground state is zero

→ SUSY QFTs have less divergences

11 / 65

slide-19
SLIDE 19

Outline

◮ The supersymmetric harmonic oscillator ◮ Motivation for SUSY: Symmetry & the hierarchy problem ◮ The MSSM ◮ SUSY searches

12 / 65

slide-20
SLIDE 20

Why supersymmetric quantum field theory?

SUSY is a symmetry which relates fermions and bosons: Q|fermion = |boson Q|boson = |fermion Q is s spinorial generator, i.e. has spin = 1/2.

13 / 65

slide-21
SLIDE 21

Why supersymmetric quantum field theory?

SUSY is a symmetry which relates fermions and bosons: Q|fermion = |boson Q|boson = |fermion Q is s spinorial generator, i.e. has spin = 1/2. To construct a Lagrangian which is supersymmetric, i.e. invariant under |fermion ↔ |boson we will need to double the spectrum.

13 / 65

slide-22
SLIDE 22

Why supersymmetric quantum field theory?

SUSY is a symmetry which relates fermions and bosons: Q|fermion = |boson Q|boson = |fermion Q is s spinorial generator, i.e. has spin = 1/2. To construct a Lagrangian which is supersymmetric, i.e. invariant under |fermion ↔ |boson we will need to double the spectrum. Example: electron (ψe)L(s = 1/2) ↔ φ˜

eL(s = 0) (scalar electron ˜

eL) (ψe)R(s = 1/2) ↔ φ˜

eR(s = 0) (scalar electron ˜

eR)

Note: ˜ eL/R are called ”left/right-handed” selectron to indicate SUSY partner (scalar particle has no helicity).

13 / 65

slide-23
SLIDE 23

How do we characterize a particle? Consider Lorentz group (rotations & boosts) with invariants PµPµ = m2 and WµW µ = −m2s(s + 1) . Pµ: energy momentum operator Wµ = 1

2ǫµνρσPνMρσ: Pauli-Lubanski spin vector

where Mµν = angular momentum tensor = xµPnu − xνPµ + 1

2Σµν

→ particles are characterized by Lorentz invariants: mass and spin

14 / 65

slide-24
SLIDE 24

How do we characterize a particle? Consider Lorentz group (rotations & boosts) with invariants PµPµ = m2 and WµW µ = −m2s(s + 1) . Pµ: energy momentum operator Wµ = 1

2ǫµνρσPνMρσ: Pauli-Lubanski spin vector

where Mµν = angular momentum tensor = xµPnu − xνPµ + 1

2Σµν

→ particles are characterized by Lorentz invariants: mass and spin The

  • Lorentz

Gauge

  • symmetry is an
  • external

internal

  • symmetry.

→ invariants of gauge symmetries (“charges”) do not change in space and time → the generators of the gauge group T a commute with the generators

  • f the Lorentz group [T a, Pµ] = 0 and [T a, Mµν] = 0

14 / 65

slide-25
SLIDE 25

The Coleman-Mandula theorem

Coleman & Mandula, ”All Possible Symmetries of the S Matrix”,

PRD 159 (1967):

The only possible conserved quantities that transform as tensors under the Lorentz group are the generators of the Lorentz group (Pµ, Mµν) and Lorentz scalars (internal symmetries). According to Coleman & Mandula, if we add to the Lorentz symmetry any further external symmetry, whose generators are tensors, then the scattering process must be trivial, i.e. there is no scattering at all. Let us work this out in an example. . .

15 / 65

slide-26
SLIDE 26

We consider 2 → 2 spinless scattering and take, for simplicity, p2

i = m2 i = m2.

Momentum conservation implies p1 + p2 = p3 + p4.

16 / 65

slide-27
SLIDE 27

We consider 2 → 2 spinless scattering and take, for simplicity, p2

i = m2 i = m2.

Momentum conservation implies p1 + p2 = p3 + p4. Now let us postulate an additional external symmetry, e.g. a conserved tensor Rµν = pµpν − 1

4gµνm2.

If Rµν is conserved, then R1

µν + R2 µν

= R3

µν + R4 µν

and thus p1

µp1 ν + p2 µp2 ν

= p3

µp3 ν + p4 µp4 ν .

16 / 65

slide-28
SLIDE 28

Specifically, in the center-of-mass frame we have

p1 = (E, 0, 0, p) p2 = (E, 0, 0, −p) p3 = (E, 0, p sin θ, p cos θ) p4 = (E, 0, −p sin θ, −p cos θ)

Let us look at e.g. µ = ν = 4. We find 2p2 = 2p2 cos θ . ⇒ θ = 0, i.e. no scattering

17 / 65

slide-29
SLIDE 29

The Haag-Lopuszanski-Sohnius theorem

Tensors aµ1···µN are combinations of Lorentz vector indices, which each transform like a vector: a′

µ1···µN = Λ ν1 µ1 · · · Λ νN µN aµ1···µN

→ tensors are bosons This points to the loop-hole in the Coleman-Mandula “no-go” theorem: The argument of Coleman-Mandula does not apply to conserved charges transforming as spinors.

18 / 65

slide-30
SLIDE 30

The Haag-Lopuszanski-Sohnius theorem

Tensors aµ1···µN are combinations of Lorentz vector indices, which each transform like a vector: a′

µ1···µN = Λ ν1 µ1 · · · Λ νN µN aµ1···µN

→ tensors are bosons This points to the loop-hole in the Coleman-Mandula “no-go” theorem: The argument of Coleman-Mandula does not apply to conserved charges transforming as spinors. Haag, Lopuszanski & Sohnius (1975): Supersymmetry is the only possible external symmetry of the scattering amplitude beyond Lorentz symmetry, for which the scattering is non-trivial.

18 / 65

slide-31
SLIDE 31

The Haag-Lopuszanski-Sohnius theorem

Tensors aµ1···µN are combinations of Lorentz vector indices, which each transform like a vector: a′

µ1···µN = Λ ν1 µ1 · · · Λ νN µN aµ1···µN

→ tensors are bosons This points to the loop-hole in the Coleman-Mandula “no-go” theorem: The argument of Coleman-Mandula does not apply to conserved charges transforming as spinors. Haag, Lopuszanski & Sohnius (1975): Supersymmetry is the only possible external symmetry of the scattering amplitude beyond Lorentz symmetry, for which the scattering is non-trivial. How could nature have ignored this last possible external symmetry?

18 / 65

slide-32
SLIDE 32

Supersymmetry

What is the algebra of the SUSY generators Qα? One can work out that [Pµ, Qα] = [Mµν, Qα] = −i(σµν)β

αQβ

{Qα, Qβ} = {Qα, Q†

β}

= 2(σµ)αβPµ

where σµ = (1, σi), ¯ σµ = (1, σi), σµν = (σµ¯ σν − σν ¯ σµ)/4.

19 / 65

slide-33
SLIDE 33

Supersymmetry

What is the algebra of the SUSY generators Qα? One can work out that [Pµ, Qα] = [Mµν, Qα] = −i(σµν)β

αQβ

{Qα, Qβ} = {Qα, Q†

β}

= 2(σµ)αβPµ

where σµ = (1, σi), ¯ σµ = (1, σi), σµν = (σµ¯ σν − σν ¯ σµ)/4.

Q raises by spin 1/2, Q† lowers by spin 1/2

19 / 65

slide-34
SLIDE 34

Supersymmetry

What are the immediate consequences of SUSY invariance? [Pµ, Q] = 0 ⇒ [m2, Q] = [PµPµ, Q] = 0

20 / 65

slide-35
SLIDE 35

Supersymmetry

What are the immediate consequences of SUSY invariance? [Pµ, Q] = 0 ⇒ [m2, Q] = [PµPµ, Q] = 0 Thus we must have

e = me .

20 / 65

slide-36
SLIDE 36

Supersymmetry

What are the immediate consequences of SUSY invariance? [Pµ, Q] = 0 ⇒ [m2, Q] = [PµPµ, Q] = 0 Thus we must have

e = me .

But we have not seen a 511 keV= m˜

e charged ([Q, T a] = 0) scalar

→ SUSY must be broken At what scale? What is the mass of the supersymmetric particles?

20 / 65

slide-37
SLIDE 37

The hierarchy problem and the scale of SUSY breaking

21 / 65

slide-38
SLIDE 38

The hierarchy problem and the scale of SUSY breaking

Let us first look at electrodynamics: The Coulomb field of the electron is Eself = 3

5 e2 re .

This can be interpreted as a contribution to the electron mass: mec2 = me,0c2 + Eself .

21 / 65

slide-39
SLIDE 39

The hierarchy problem and the scale of SUSY breaking

Let us first look at electrodynamics: The Coulomb field of the electron is Eself = 3

5 e2 re .

This can be interpreted as a contribution to the electron mass: mec2 = me,0c2 + Eself . However, with re ∼

< 10−17 cm (exp. bound on point-like nature) one has

mec2 = 511 keV = (−9999.489 + 10000.000) keV → fine-tuning!

21 / 65

slide-40
SLIDE 40

Is there fine-tuning in quantum electrodynamics?

22 / 65

slide-41
SLIDE 41

Is there fine-tuning in quantum electrodynamics? Coulomb self-energy in time-ordered perturbation theory:

22 / 65

slide-42
SLIDE 42

Is there fine-tuning in quantum electrodynamics? Coulomb self-energy in time-ordered perturbation theory: But also have positron e+ with Q(e+) = −Q(e−) and m(e+) = m(e−) → new diagram

22 / 65

slide-43
SLIDE 43

Is there fine-tuning in quantum electrodynamics? Coulomb self-energy in time-ordered perturbation theory: But also have positron e+ with Q(e+) = −Q(e−) and m(e+) = m(e−) → new diagram → mec2 = me,0c2

  • 1 + 3α

4π ln

  • mecre
  • 22 / 65
slide-44
SLIDE 44

We found that mec2 = me,0c2 1 + 3α

4π ln

  • mecre
  • .

So even if re = 1/MPlanck = 1.6 × 10−33 cm, the corrections to the electron mass are small mec2 ≈ me,0c2 (1 + 0.1) . Also, if me,0 = 0 then me = 0 to all orders: the mass is protected by a (chiral) symmetry

23 / 65

slide-45
SLIDE 45

We found that mec2 = me,0c2 1 + 3α

4π ln

  • mecre
  • .

So even if re = 1/MPlanck = 1.6 × 10−33 cm, the corrections to the electron mass are small mec2 ≈ me,0c2 (1 + 0.1) . Also, if me,0 = 0 then me = 0 to all orders: the mass is protected by a (chiral) symmetry Recall ’t Hooft’s naturalness argument

23 / 65

slide-46
SLIDE 46

Now let us look at the scalar (=Higgs) self-energy:

24 / 65

slide-47
SLIDE 47

Now let us look at the scalar (=Higgs) self-energy: ⇒ ∆m2

φ = 2N(f ) λ2 f

  • d4k

(2π)4

  • 1

k2 − m2

f

+ 2m2

f

(k2 − m2

f )2

  • The integral is divergent, so we introduce a momentum cut-off.

[Recall that d4k ∼ k3dk → R Λdkk3/(k2−m2

f ) ∼ Λ2 and

R Λdkk3/(k2−m2

f )2 ∼ ln Λ.]

24 / 65

slide-48
SLIDE 48

Now let us look at the scalar (=Higgs) self-energy: ⇒ ∆m2

φ = 2N(f ) λ2 f

  • d4k

(2π)4

  • 1

k2 − m2

f

+ 2m2

f

(k2 − m2

f )2

  • The integral is divergent, so we introduce a momentum cut-off.

[Recall that d4k ∼ k3dk → R Λdkk3/(k2−m2

f ) ∼ Λ2 and

R Λdkk3/(k2−m2

f )2 ∼ ln Λ.]

Straightforward calculation gives ∆m2

φ = N(f ) λ2 f

8π2

  • Λ2 + 3m2

f ln

Λ2 + m2

f

m2

f

  • + 2m2

f

Λ2 Λ2 + m2

f

  • .

24 / 65

slide-49
SLIDE 49

Because of the quadratic divergence we find ∆m2

φ(Λ = MPlanck) ≈ 1035GeV2 = (3 × 1017 GeV)2

25 / 65

slide-50
SLIDE 50

Because of the quadratic divergence we find ∆m2

φ(Λ = MPlanck) ≈ 1035GeV2 = (3 × 1017 GeV)2

and so m2

φ ∼

< 1 TeV2 = m2

φ,0 + ∆m2 φ

implies a huge fine-tuning:

Comment: it is essential that Λ < ∞, i.e. we assume that new physics sets in at E ∼ Λ. Is this a tautology? No: we assume new physics at some very high scale Λ and find that the standard model needs new physics well below Λ.

The natural mass scale of a scalar field is the highest scale in nature.

25 / 65

slide-51
SLIDE 51

The SUSY solution to the hierarchy problem

26 / 65

slide-52
SLIDE 52

The SUSY solution to the hierarchy problem

Let us increase the particle content (as for the e− self-energy) Before we had Now we include in addition two scalars ˜ fL, ˜ fR with couplings Lφ˜

f = −

˜ λ2

f

2 φ2 |˜ fL|2 + |˜ fR|2 −v ˜ λ2

f φ

fL|2 + |˜ fR|2 + λf √ 2 Af φ˜ fL˜ f ∗

R + h.c.

  • which lead to additional contributions to the self-energy:

26 / 65

slide-53
SLIDE 53

The additional contributions to the Higgs mass are: ∆m2

φ

= ˜ λ2

f N(˜

f ) d4k (2π)4

  • 1

k2 − m2

˜ fL

+ 1 k2 − m2

˜ fR

  • +

(˜ λ2

f v)2 N(˜

f ) d4k (2π)4

  • 1

(k2 − m2

˜ fL)2 +

1 (k2 − m2

˜ fR)2

  • +

(λf Af )2 N(˜ f ) d4k (2π)4 1 (k2 − m2

˜ fL)(k2 − m2 ˜ fR)

.

27 / 65

slide-54
SLIDE 54

The additional contributions to the Higgs mass are: ∆m2

φ

= ˜ λ2

f N(˜

f ) d4k (2π)4

  • 1

k2 − m2

˜ fL

+ 1 k2 − m2

˜ fR

  • +

(˜ λ2

f v)2 N(˜

f ) d4k (2π)4

  • 1

(k2 − m2

˜ fL)2 +

1 (k2 − m2

˜ fR)2

  • +

(λf Af )2 N(˜ f ) d4k (2π)4 1 (k2 − m2

˜ fL)(k2 − m2 ˜ fR)

. The first term cancels the SM Λ2-contribution if ˜ λf = λf and N(˜ f ) = N(f ) as required in SUSY.

27 / 65

slide-55
SLIDE 55

The cancellation happens because of spin-statistics:

fermion loop → (-1) boson-loop → (+1)

28 / 65

slide-56
SLIDE 56

The cancellation happens because of spin-statistics:

fermion loop → (-1) boson-loop → (+1)

Note:

◮ the cancellation of quadratic divergences is independent of

fL, m˜ fR, Af . ◮ the term ∝ Af φ˜

fL˜ f ∗

R breaks SUSY but does not lead to

Λ2 divergences → ”soft” SUSY breaking

28 / 65

slide-57
SLIDE 57

Let us look at the finite SM + SUSY contributions: ∆m2

φ

= λ2

f N(f )

16π2

  • −2m2

f

  • 1 − ln m2

f

µ2

  • + 4m2

f ln m2 f

µ2 + 2m2

˜ f

  • 1 − ln

m2

˜ f

µ2

  • − 4m2

˜ f ln

m2

˜ f

µ2 − |Af |2 ln m2

˜ f

µ2

  • ,

where we have assumed m˜

fL = m˜ fR = m˜ f .

29 / 65

slide-58
SLIDE 58

Let us look at the finite SM + SUSY contributions: ∆m2

φ

= λ2

f N(f )

16π2

  • −2m2

f

  • 1 − ln m2

f

µ2

  • + 4m2

f ln m2 f

µ2 + 2m2

˜ f

  • 1 − ln

m2

˜ f

µ2

  • − 4m2

˜ f ln

m2

˜ f

µ2 − |Af |2 ln m2

˜ f

µ2

  • ,

where we have assumed m˜

fL = m˜ fR = m˜ f .

One has ∆m2

φ = 0

for Af = 0 and m˜

f = mf

(SUSY)

29 / 65

slide-59
SLIDE 59

Let us look at the finite SM + SUSY contributions: ∆m2

φ

= λ2

f N(f )

16π2

  • −2m2

f

  • 1 − ln m2

f

µ2

  • + 4m2

f ln m2 f

µ2 + 2m2

˜ f

  • 1 − ln

m2

˜ f

µ2

  • − 4m2

˜ f ln

m2

˜ f

µ2 − |Af |2 ln m2

˜ f

µ2

  • ,

where we have assumed m˜

fL = m˜ fR = m˜ f .

One has ∆m2

φ = 0

for Af = 0 and m˜

f = mf

(SUSY) But SUSY is broken, i.e. m2

˜ f = m2 f + δ2. Thus

∆m2

φ = λ2 f N(f )

8π2 δ2

  • 2 + ln m2

f

µ2

  • + O(δ4)

To have ∆m2

φ small, we thus need m2 ˜ f = m2 f + δ2 = O(1 TeV2)

29 / 65

slide-60
SLIDE 60

Supersymmetry: Summary of first lecture

SUSY is great!

Must have been tired yesterday. . .

30 / 65

slide-61
SLIDE 61

Motivation for supersymmetry A Priori:

◮ SUSY is the unique maximal external symmetry in Nature. ◮ Weak-scale SUSY provides a solution to the hierarchy problem.

A Posteriori:

◮ SUSY allows for unification of Standard Model gauge interactions. ◮ SUSY provides dark matter candidates. ◮ SUSY QFT’s allow for precision calculations. ◮ SUSY provides a rich phenomenology and is testable at the LHC.

31 / 65

slide-62
SLIDE 62

Outline

◮ The supersymmetric harmonic oscillator ◮ Motivation for SUSY: Symmetry & the hierarchy problem ◮ The MSSM ◮ SUSY searches

32 / 65

slide-63
SLIDE 63

The Minimal Supersymmetric extension of the SM

◮ external symmetries: Poincare symmetry & supersymmetry ◮ internal symmetries: SU(3)⊗SU(2)⊗U(1) gauge symmetries ◮ minimal particle content

33 / 65

slide-64
SLIDE 64

Gauge coupling unification

In QFT the gauge couplings “run”: dαi(µ) d ln µ2 = βi(αi(µ)) The beta-functions βi depend on the gauge group and on the matter multiplets to which the gauge bosons couple. Only particles with mass < µ contribute to the βi and to the evolution of the coupling at any given mass scale µ. The Standard Model couplings evolve with µ according to SU(3) : β3,0 = (33 − 4ng)/(12π) SU(2) : β2,0 = (22 − 4ng − nh/2)/(12π) U(1) : β1,0 = (−4ng − 3nh/10)/(12π) where ng = 3 is the number of quark and lepton generations and nh = 1 is the number of Higgs doublet fields in the Standard Model.

34 / 65

slide-65
SLIDE 65

Gauge coupling unification

Loop contributions of superpartners change the beta-functions. In the MSSM one finds: SU(3) : βSUSY

3,0

= (27 − 6ng)/(12π) SU(2) : βSUSY

2,0

= (18 − 6ng − 3nh/2)/(12π) U(1) : βSUSY

1,0

= (−6ng − 9nh/10)/(12π)

35 / 65

slide-66
SLIDE 66

Gauge coupling unification

Loop contributions of superpartners change the beta-functions. In the MSSM one finds: SU(3) : βSUSY

3,0

= (27 − 6ng)/(12π) SU(2) : βSUSY

2,0

= (18 − 6ng − 3nh/2)/(12π) U(1) : βSUSY

1,0

= (−6ng − 9nh/10)/(12π)

35 / 65

slide-67
SLIDE 67

R-parity

◮ In the SM baryon and lepton number are accidental symmetries ◮ The most general superpotential of the SUSY-SM contains baryon

and lepton number violating terms: W ∈ λijkLiLjE k + λ′

ijkLiQjDk + κiLiH2

  • lepton number violating

+ λ′′

ijkUiDjDk

  • baryon number violating

36 / 65

slide-68
SLIDE 68

R-parity

◮ In the SM baryon and lepton number are accidental symmetries ◮ The most general superpotential of the SUSY-SM contains baryon

and lepton number violating terms: W ∈ λijkLiLjE k + λ′

ijkLiQjDk + κiLiH2

  • lepton number violating

+ λ′′

ijkUiDjDk

  • baryon number violating

LQD and UDD couplings lead to rapid proton decay → impose discrete symmetry: R-parity R = (−1)3B+L+2S → RSM = + and RSUSY = −

36 / 65

slide-69
SLIDE 69

R-parity

R-parity conservation has dramatic phenomenological consequences:

◮ lightest SUSY particle (LSP) is absolutely stable

→ dark matter candidate if also electrically neutral

◮ in collider experiments SUSY particles can only be produced in pairs ◮ in many models SUSY collider events contain missing ET

37 / 65

slide-70
SLIDE 70

SUSY breaking

Supersymmetry: mass(e−) = mass(˜ e−

L,R)

→ SUSY must be broken No agreed model of supersymmetry breaking → phenomenological ansatz Must preserve solution to hierarchy problem → “soft” SUSY breaking

38 / 65

slide-71
SLIDE 71

SUSY breaking

Supersymmetry: mass(e−) = mass(˜ e−

L,R)

→ SUSY must be broken No agreed model of supersymmetry breaking → phenomenological ansatz Must preserve solution to hierarchy problem → “soft” SUSY breaking Introduce

◮ gaugino masses M1/2χχ: M1 ˜

B ˜ B, M2 ˜ W ˜ W , M3˜ g ˜ g

◮ squark and slepton masses M2 0φ†φ:

m2

˜ eL˜

e†

eL, m2

˜ eR˜

e†

eR, m2

˜ uL˜

u†

uL, m2

˜ uR ˜

u†

uR etc.

◮ trilinear couplings Aijkφiφjφk: Ae ij

˜ νi ˜ ej

  • L

h1˜ ejR etc.

◮ Higgs mass terms Bijφiφj: Bh1h2 etc.

38 / 65

slide-72
SLIDE 72

SUSY breaking

MSSM w/o breaking: two additional parameters from Higgs sector Soft SUSY breaking

◮ Ae ij, Ad ij, Au ij

→ 27 real + 27 phases

◮ M2 ˜ Q, M2 ˜ U, M2 ˜ D, M2 ˜ L, M2 ˜ E → 30 real + 15 phases ◮ M1, M2, M3

→ 3 real + 1 phase → 124 parameters in the MSSM!

(but strong constraints from FCNS’s, flavour mixing and CP violation)

39 / 65

slide-73
SLIDE 73

SUSY breaking

MSSM w/o breaking: two additional parameters from Higgs sector Soft SUSY breaking

◮ Ae ij, Ad ij, Au ij

→ 27 real + 27 phases

◮ M2 ˜ Q, M2 ˜ U, M2 ˜ D, M2 ˜ L, M2 ˜ E → 30 real + 15 phases ◮ M1, M2, M3

→ 3 real + 1 phase → 124 parameters in the MSSM!

(but strong constraints from FCNS’s, flavour mixing and CP violation)

Simple framework constrained MSSM: breaking is universal at GUT scale

◮ universal scalar masses: M2

˜ Q, M2 ˜ U, M2 ˜ D, M2 ˜ L, M2 ˜ E → M2 0 at MGUT

◮ universal gaugino masses: M1, M2, M3 → M1/2 at MGUT ◮ universal trilinear couplings Ae

ij, Ad ij, Au ij → A · he ij, A · hd ij, A · hu ij at MGUT

→ 6 additional parameters: M0, M1/2, A, B, µ, tan(β)

39 / 65

slide-74
SLIDE 74

SUSY mass spectrum

In QFT the (s)particle masses “run”: dMi(µ) d ln µ2 = γiMi

40 / 65

slide-75
SLIDE 75

SUSY mass spectrum

In QFT the (s)particle masses “run”: dMi(µ) d ln µ2 = γiMi

  • 200

200 400 600 2 4 6 8 10 12 14 16 GeV log10(µ/GeV) (µ2+mHd

2)1/2

(µ2+mHu

2)1/2

M1 M2 M3 mQl mEr SOFTSUSY3.0.5 SPS1a

40 / 65

slide-76
SLIDE 76

SUSY mass spectrum

In QFT the (s)particle masses “run”: dMi(µ) d ln µ2 = γiMi

  • 200

200 400 600 2 4 6 8 10 12 14 16 GeV log10(µ/GeV) (µ2+mHd

2)1/2

(µ2+mHu

2)1/2

M1 M2 M3 mQl mEr SOFTSUSY3.0.5 SPS1a typical mass pattern e.g. from M1(µ) α1(µ) = M2(µ) α2(µ) = M3(µ) α3(µ) → M3(MZ) : M2(MZ) : M1(MZ) ≃ 7 : 2 : 1

40 / 65

slide-77
SLIDE 77

Radiative EWK symmetry breaking

◮ RGE drives (µ2 + mH2

u) negative → EWK symmetry breaking

◮ Masses of W and Z bosons fix B and |µ| ◮ cMSSM has 4 1/2 parameters:

M0, M1/2, A, tan(β) and sign(µ)

41 / 65

slide-78
SLIDE 78

Mixing

After SU(2)L × U(1)Y breaking, mixing will occur between any two or more fields which have the same color, charge and spin

◮ ( ˜

W ±, ˜ H±) → ˜ χ±

i=1,2: charginos ◮ (˜

B, ˜ W 3, ˜ H0

1,2) → ˜

χ0

i=1,2,3,4: neutralinos ◮ (˜

tL,˜ tR) → ˜ t1,2 etc.: sfermion mass eigenstates

42 / 65

slide-79
SLIDE 79

Mixing

After SU(2)L × U(1)Y breaking, mixing will occur between any two or more fields which have the same color, charge and spin

◮ ( ˜

W ±, ˜ H±) → ˜ χ±

i=1,2: charginos ◮ (˜

B, ˜ W 3, ˜ H0

1,2) → ˜

χ0

i=1,2,3,4: neutralinos ◮ (˜

tL,˜ tR) → ˜ t1,2 etc.: sfermion mass eigenstates Note:

◮ mixing involves various SUSY parameters

→ cross sections and branching ratios become model dependent

◮ sfermion mixing ∝ mf

→ large only for 3rd generation (˜ t1,2, ˜ τ1,2)

42 / 65

slide-80
SLIDE 80

Outline

◮ The supersymmetric harmonic oscillator ◮ Motivation for SUSY: Symmetry & the hierarchy problem ◮ The MSSM ◮ SUSY searches

43 / 65

slide-81
SLIDE 81

Summary of SUSY searches so far. . .

44 / 65

slide-82
SLIDE 82

Summary of SUSY searches so far. . . . . . but let’s see what to expect in 2011 & 2012. . .

44 / 65

slide-83
SLIDE 83

Outline

◮ The supersymmetric harmonic oscillator ◮ Motivation for SUSY: Symmetry & the hierarchy problem ◮ The MSSM ◮ SUSY searches

◮ indirect searches through quantum fluctuations ◮ direct searches at colliders 45 / 65

slide-84
SLIDE 84

Indirect SUSY searches

Wealth of precision measurements from B/K physics, (g − 2), astrophysics (DM) and collider limits → constraints on certain SUSY masses e.g. through anomalous magnetic moment (g − 2)

46 / 65

slide-85
SLIDE 85

Indirect SUSY searches: (g − 2)µ

Hamiltonian for interaction of µ-spin with external magnetic field H = gµ e 2mµ

  • Sµ ·

B with gµ = 2 in leading order Loop-corrections modify the interaction of the µ with the electromagnetic field ⇒ g − 2 2

  • QED

= α 2π = 0.00116114

23 / 51

slide-86
SLIDE 86

Indirect SUSY searches: (g − 2)µ

There are additional diagrams in supersymmetric QED, e.g. which is given by I =

  • d4k

(2π)4 (ie √ 2)PR 1 k − M˜

γ

PL(ie √ 2) i (p′ − k)2 − m2

˜ µL

×(ie)(p′ + p − 2k)ν i (p − k)2 − m2

˜ µL

After a short calculation (using standard QED techniques) one finds g − 2 2

  • SQED

= −m2

µe2

8π2 1 dx x2(1 − x) m2

µx2 + (m2 ˜ µL − M2 ˜ γ − m2 µ)x + M2 ˜ γ

24 / 51

slide-87
SLIDE 87

Indirect SUSY searches: (g − 2)µ

In the limit m˜

µL ≫ M˜ γ, mµ we find

g − 2 2

  • SQED

= − α 6π m2

µ

m2

˜ µL ◮ SUSY contribution decouples rapidly for m˜ µL ≫ mµ ◮ SUSY contribution ∝ mf → effects in (g − 2)e suppressed

Including mixing: → dependence on further SUSY parameters (A and tan β)

25 / 51

slide-88
SLIDE 88

Indirect SUSY searches

→ CMSSM fit to B, K and EWK observables, (g − 2)µ and ΩDM

47 / 65

slide-89
SLIDE 89

Indirect SUSY searches

→ CMSSM fit to B, K and EWK observables, (g − 2)µ and ΩDM

h A H

+

H

1

χ

2

χ

3

χ

4

χ

1 +

χ

2 +

χ

R

l ~

L

l ~

1

τ ∼

2

τ ∼

R

q ~

L

q ~

1

b ~

2

b ~

1

t ~

2

t ~ g ~ Particle Mass [GeV] 200 400 600 800 1000 1200 1400 Mass Spectrum of SUSY Particles no LHC

Environment σ 1 Environment σ 2 Best Fit Value

Mass Spectrum of SUSY Particles no LHC

47 / 65

slide-90
SLIDE 90

Indirect SUSY searches

→ CMSSM fit to B, K and EWK observables, (g − 2)µ and ΩDM

h A H

+

H

1

χ

2

χ

3

χ

4

χ

1 +

χ

2 +

χ

R

l ~

L

l ~

1

τ ∼

2

τ ∼

R

q ~

L

q ~

1

b ~

2

b ~

1

t ~

2

t ~ g ~ Particle Mass [GeV] 200 400 600 800 1000 1200 1400 Mass Spectrum of SUSY Particles no LHC

Environment σ 1 Environment σ 2 Best Fit Value

Mass Spectrum of SUSY Particles no LHC

◮ global fits point to light sparticle spectrum with ˜

m < 1 TeV

◮ current data cannot constrain more general SUSY models

47 / 65

slide-91
SLIDE 91

Indirect SUSY searches

→ CMSSM fit without (g − 2)µ and ΩDM

◮ prediction of light SUSY spectrum rests on (g − 2)µ and ΩDM

48 / 65

slide-92
SLIDE 92

SUSY particle production at the LHC

SUSY particles would be produced at the LHC via QCD processes

49 / 65

slide-93
SLIDE 93

SUSY particle production at the LHC

SUSY particles would be produced at the LHC via QCD processes

˜ q˜ g ˜ q˜ q ˜ q¯ ˜ q ˜ g˜ g m˜

q = m˜ g

NLO+NLL √s = 7 TeV; σ (pp → ˜ g˜ g/˜ q¯ ˜ q/˜ q˜ q/˜ q˜ g + X) [pb]

m [GeV]

1200 1000 800 600 400 200 1000 100 10 1 0.1 0.01 0.001

→ σ ≈ 100 fb for m ≈ 1000 GeV at √ S = 7 TeV

49 / 65

slide-94
SLIDE 94

SUSY particle production at the LHC

SUSY particles would be produced at the LHC via QCD processes

˜ q˜ g ˜ q˜ q ˜ q¯ ˜ q ˜ g˜ g m˜

q = m˜ g

NLO+NLL √s = 14 TeV; σ (pp → ˜ g˜ g/˜ q¯ ˜ q/˜ q˜ q/˜ q˜ g + X) [pb]

m [GeV]

3000 2500 2000 1500 1000 500

103 101

10 1

10−1 10−2 10−3 10−4 10−5

→ σ ≈ 2.5 pb for m ≈ 1000 GeV at √ S = 14 TeV

50 / 65

slide-95
SLIDE 95

SUSY searches at hadron colliders

→ Powerful MSSM signature at the LHC: cascade decays with ET,miss

51 / 65

slide-96
SLIDE 96

SUSY searches at hadron colliders

→ Powerful MSSM signature at the LHC: cascade decays with ET,miss Generic signature for many new physics models which address – the hierarchy problem – the origin of dark matter → predict spectrum of new particles at the TeV-scale with weakly interacting & stable particle (← discrete parity)

51 / 65

slide-97
SLIDE 97

Squark and gluino searches at the LHC Atlas limits (165 pb−1)

[GeV] m

500 1000 1500 2000 2500

[GeV]

1/2

m

150 200 250 300 350 400 450 500 550 600

(600) g ~ (800) g ~ (1000) g ~ ( 6 ) q ~ ( 1 ) q ~ (1400) q ~

>0 µ = 0, = 10, A β MSUGRA/CMSSM: tan

=7 TeV s ,

  • 1

= 165 pb

int

L 0 lepton 2011 combined

Preliminary ATLAS

0 lepton 2011 combined

1 ±

χ ∼ LEP 2

  • 1

<0, 2.1 fb µ =3, β , tan q ~ , g ~ D0

  • 1

<0, 2 fb µ =5, β , tan q ~ , g ~ CDF Observed 95% C.L. limit Median expected limit Observed 95 % C.L. limit

s

CL Median expected limit

s

CL Reference point 2010 data PCL 95% C.L. limit CMS 2010 Razor,Jets/MHT

→ m˜

q ≈ m˜ g ∼

> 950 GeV

52 / 65

slide-98
SLIDE 98

Direct SUSY searches at the LHC: expected limits

The LHC is probing the preferred region of SUSY parameter space

[GeV] M 100 200 300 400 500 600 700 800 [GeV]

1/2

M 200 300 400 500 600 700 800 [GeV] M 100 200 300 400 500 600 700 800 [GeV]

1/2

M 200 300 400 500 600 700 800

2D 95% CL no LHC 1D 68% CL no LHC

  • 1

95% CL exclusion 35pb

  • 1

95% CL exclusion 1fb

  • 1

95% CL exclusion 2fb

  • 1

95% CL exclusion 7fb 53 / 65

slide-99
SLIDE 99

Direct SUSY searches at the LHC: expected limits

But what if we do not see any SUSY signal at the LHC?

[GeV] M 100 200 300 400 500 600 700 800 [GeV]

1/2

M 200 300 400 500 600 700 800 [GeV] M 100 200 300 400 500 600 700 800 [GeV]

1/2

M 200 300 400 500 600 700 800

2D 95% CL no LHC 1D 68% CL no LHC

  • 1

95% CL exclusion 35pb

  • 1

95% CL exclusion 1fb

  • 1

95% CL exclusion 2fb

  • 1

95% CL exclusion 7fb 54 / 65

slide-100
SLIDE 100

Direct SUSY searches at the LHC: expected limits

We have considered the SUSY search in the 4 jets + ET,miss signature with Meff =

i pT,i + ET,miss

55 / 65

slide-101
SLIDE 101

Direct SUSY searches at the LHC: expected limits

◮ The simulation of Meff is based on Herwig++, Delphes and

NLO+NLL K-factors.

FITTINO 4 jets 0 lepton LO FITTINO 4 jets 0 lepton NLO 56 / 65

slide-102
SLIDE 102

Direct SUSY searches at the LHC: expected limits

◮ The 4 jets +ET,miss signature is rather independent of tan β and A0 [GeV]

eff

M 500 1000 1500 2000 2500 3000 3500 4000

  • 1

10 1 10

2

10

3

10

SM =0 =10, A β tan =1000 =10, A β tan =1000 =20, A β tan =1000 =30, A β tan =1000 =40, A β tan =1000 =50, A β tan

[GeV]

eff

M 500 1000 1500 2000 2500 3000 3500 4000

  • 1

10 1 10

2

10

3

10

= 500

1/2

= 500, M M

57 / 65

slide-103
SLIDE 103

Global SUSY fits with projected LHC exclusions

◮ Low-energy observables, DM and LHC exclusions with 2 fb−1 [GeV] M 500 1000 1500 2000 2500 3000 3500 [GeV]

1/2

M 200 400 600 800 1000 1200 1400 1600 1800 2000 2200

  • 1

2D 95% CL 2fb

  • 1

1D 68% CL 2fb

  • 1

95% CL exclusion 2fb 58 / 65

slide-104
SLIDE 104

Global SUSY fits with projected LHC exclusions

◮ Low-energy observables, DM and LHC exclusions with 2 fb−1

h A H

+

H

1

χ

2

χ

3

χ

4

χ

1 +

χ

2 +

χ

R

l ~

L

l ~

1

τ ∼

2

τ ∼

R

q ~

L

q ~

1

b ~

2

b ~

1

t ~

2

t ~ g ~ Particle Mass [GeV] 500 1000 1500 2000 2500 3000 3500 4000

  • 1

Mass Spectrum of SUSY Particles 2fb

Environment σ 1 Environment σ 2 Best Fit Value

  • 1

Mass Spectrum of SUSY Particles 2fb

59 / 65

slide-105
SLIDE 105

Global SUSY fits with projected LHC exclusions

◮ Low-energy observables, DM and LHC exclusions with 7 fb−1

h A H

+

H

1

χ

2

χ

3

χ

4

χ

1 +

χ

2 +

χ

R

l ~

L

l ~

1

τ ∼

2

τ ∼

R

q ~

L

q ~

1

b ~

2

b ~

1

t ~

2

t ~ g ~ Particle Mass [GeV] 500 1000 1500 2000 2500 3000 3500 4000

  • 1

Mass Spectrum of SUSY Particles 7fb

Environment σ 1 Environment σ 2 Best Fit Value

  • 1

Mass Spectrum of SUSY Particles 7fb

60 / 65

slide-106
SLIDE 106

Global SUSY fits with projected LHC exclusions

◮ what happens if we take out (g − 2)µ and ΩDM?

61 / 65

slide-107
SLIDE 107

Global SUSY fits with projected LHC exclusions

◮ what happens if we take out (g − 2)µ and ΩDM?

h A H

+

H

1

χ

2

χ

3

χ

4

χ

1 +

χ

2 +

χ

R

l ~

L

l ~

1

τ ∼

2

τ ∼

R

q ~

L

q ~

1

b ~

2

b ~

1

t ~

2

t ~ g ~ Particle Mass [GeV] 2000 4000 6000 8000 10000 12000

  • 1

Mass Spectrum of SUSY Particles NoOmegaNoGmin2 7fb

Environment σ 1 Environment σ 2 Best Fit Value

  • 1

Mass Spectrum of SUSY Particles NoOmegaNoGmin2 7fb

61 / 65

slide-108
SLIDE 108

Global SUSY fits with projected LHC exclusions

◮ LHC mass limits on squarks are rather model independent

no LHC

  • 1

35pb

  • 1

1fb

  • 1

2fb

  • 1

7fb

mass range [GeV]

1000 2000 3000

R

q ~ Mass of

Environment σ 1 Environment σ 2 Best Fit Value

R

q ~ Mass of

62 / 65

slide-109
SLIDE 109

Global SUSY fits with projected LHC exclusions: is there a tension?

→ LEOs prefer low mass scales (for non-coloured sector) → LHC prefers high mass scales (for coloured sector) Is there a tension building up?

63 / 65

slide-110
SLIDE 110

Global SUSY fits with projected LHC exclusions: is there a tension?

→ LEOs prefer low mass scales (for non-coloured sector) → LHC prefers high mass scales (for coloured sector) Is there a tension building up? Let us look at the best fit points:

M0 M1/2 A0 tan β χ2/ndf no LHC 77+114

−31

333+89

−87

426+70

−735

13+10

−8

19/20 35 pb−1 126+189

−54

400+109

−40

724+722

−780

17+14

−9

20/21 1 fb−1 235+389

−103

601+148

−63

627+1249

−717

31+19

−18

24/21 2 fb−1 254+456

−128

647+157

−74

771+1254

−879

30+20

−19

24/21 7 fb−1 403+436

−281

744+142

−150

781+1474

−918

43+11

−33

25/21

→ even the CMSSM would ”survive” the 2011/2012 LHC run [Note: aSUSY

µ

∼ sgn(µ) tanβ M−2

SUSY and ΩDM require larger tanβ]

63 / 65

slide-111
SLIDE 111

Comparison of global CMSSM fits with and without LHC exclusions

There has been a lot of activity recently, see e.g.

Allanach, arXiv:1102.3149 [hep-ph], Buchmueller et al., arXiv:1102.4585 [hep-ph], Bechtle et al., arXiv:1102.4693 [hep-ph], Allanach et al., arXiv:1103.0969 [hep-ph] by John Ellis

]

2

[GeV/c m 100 200 300 400 500 600 700 800 900 1000 ]

2

[GeV/c

1/2

m 100 200 300 400 500 600 700 800 900 1000

SPS1a BenchB2 Ben0 Ben1 Ben2 Fittino Pre Fittino35 Fittino1 Fittino2 Fittino7 MC preLHC

t

α MC + CMS

t

MC + ATLAS 0l + CMS ME

→ the analyses differ in detail, but there is good agreement overall

64 / 65

slide-112
SLIDE 112

SUSY searches: Summary & Conclusions

◮ CMSSM fits to B, K and EWK observables, (g − 2)µ and ΩDM

◮ point to light sparticle spectrum with ˜

m < 1 TeV

◮ cannot constrain more general SUSY models ◮ upper limits on sparticle masses rest on (g − 2)µ and ΩDM 65 / 65

slide-113
SLIDE 113

SUSY searches: Summary & Conclusions

◮ CMSSM fits to B, K and EWK observables, (g − 2)µ and ΩDM

◮ point to light sparticle spectrum with ˜

m < 1 TeV

◮ cannot constrain more general SUSY models ◮ upper limits on sparticle masses rest on (g − 2)µ and ΩDM

◮ The LHC is now probing the SUSY parameter space favoured by

low-energy observables and DM

◮ It is possible to reconcile LE measurements with a possible

non-discovery of SUSY in the 7 TeV run, even in very constrained models like the CMSSM.

◮ LHC searches mostly constrain the coloured sparticle sector and can

push squark and gluino mass limits up to about 1.5 TeV in 2011/2012.

65 / 65