supersymmetry a very basic biased and completely
play

Supersymmetry: a very basic, biased and completely incomplete - PowerPoint PPT Presentation

NExT PhD school, Coseners House, July 2011 Supersymmetry: a very basic, biased and completely incomplete introduction Michael Kr amer (RWTH Aachen) 1 / 65 Outline The supersymmetric harmonic oscillator Motivation for SUSY: Symmetry


  1. We consider 2 → 2 spinless scattering and take, for simplicity, p 2 i = m 2 i = m 2 . Momentum conservation implies p 1 + p 2 = p 3 + p 4 . Now let us postulate an additional external symmetry, e.g. a conserved tensor R µν = p µ p ν − 1 4 g µν m 2 . If R µν is conserved, then R 1 µν + R 2 R 3 µν + R 4 = µν µν p 1 µ p 1 ν + p 2 µ p 2 p 3 µ p 3 ν + p 4 µ p 4 and thus = ν . ν 16 / 65

  2. Specifically, in the center-of-mass frame we have = ( E , 0 , 0 , p ) p 1 = ( E , 0 , 0 , − p ) p 2 p 3 = ( E , 0 , p sin θ, p cos θ ) p 4 = ( E , 0 , − p sin θ, − p cos θ ) Let us look at e.g. µ = ν = 4. We find 2 p 2 = 2 p 2 cos θ . ⇒ θ = 0, i.e. no scattering 17 / 65

  3. The Haag-Lopuszanski-Sohnius theorem Tensors a µ 1 ··· µ N are combinations of Lorentz vector indices, which each transform like a vector: µ 1 ··· µ N = Λ ν 1 µ 1 · · · Λ ν N a ′ µ N a µ 1 ··· µ N → tensors are bosons This points to the loop-hole in the Coleman-Mandula “no-go” theorem: The argument of Coleman-Mandula does not apply to conserved charges transforming as spinors. 18 / 65

  4. The Haag-Lopuszanski-Sohnius theorem Tensors a µ 1 ··· µ N are combinations of Lorentz vector indices, which each transform like a vector: µ 1 ··· µ N = Λ ν 1 µ 1 · · · Λ ν N a ′ µ N a µ 1 ··· µ N → tensors are bosons This points to the loop-hole in the Coleman-Mandula “no-go” theorem: The argument of Coleman-Mandula does not apply to conserved charges transforming as spinors. Haag, Lopuszanski & Sohnius (1975): Supersymmetry is the only possible external symmetry of the scattering amplitude beyond Lorentz symmetry, for which the scattering is non-trivial. 18 / 65

  5. The Haag-Lopuszanski-Sohnius theorem Tensors a µ 1 ··· µ N are combinations of Lorentz vector indices, which each transform like a vector: µ 1 ··· µ N = Λ ν 1 µ 1 · · · Λ ν N a ′ µ N a µ 1 ··· µ N → tensors are bosons This points to the loop-hole in the Coleman-Mandula “no-go” theorem: The argument of Coleman-Mandula does not apply to conserved charges transforming as spinors. Haag, Lopuszanski & Sohnius (1975): Supersymmetry is the only possible external symmetry of the scattering amplitude beyond Lorentz symmetry, for which the scattering is non-trivial. How could nature have ignored this last possible external symmetry? 18 / 65

  6. Supersymmetry What is the algebra of the SUSY generators Q α ? One can work out that [ P µ , Q α ] = 0 [ M µν , Q α ] − i ( σ µν ) β = α Q β { Q α , Q β } = 0 { Q α , Q † 2( σ µ ) αβ P µ β } = where σ µ = (1 , σ i ), ¯ σ µ = (1 , σ i ), σ µν = ( σ µ ¯ σ ν − σ ν ¯ σ µ ) / 4. 19 / 65

  7. Supersymmetry What is the algebra of the SUSY generators Q α ? One can work out that [ P µ , Q α ] = 0 [ M µν , Q α ] − i ( σ µν ) β = α Q β { Q α , Q β } = 0 { Q α , Q † 2( σ µ ) αβ P µ β } = where σ µ = (1 , σ i ), ¯ σ µ = (1 , σ i ), σ µν = ( σ µ ¯ σ ν − σ ν ¯ σ µ ) / 4. Q raises by spin 1/2, Q † lowers by spin 1/2 19 / 65

  8. Supersymmetry What are the immediate consequences of SUSY invariance? [ P µ , Q ] = 0 [ m 2 , Q ] = [ P µ P µ , Q ] = 0 ⇒ 20 / 65

  9. Supersymmetry What are the immediate consequences of SUSY invariance? [ P µ , Q ] = 0 [ m 2 , Q ] = [ P µ P µ , Q ] = 0 ⇒ Thus we must have e = m e . m ˜ 20 / 65

  10. Supersymmetry What are the immediate consequences of SUSY invariance? [ P µ , Q ] = 0 [ m 2 , Q ] = [ P µ P µ , Q ] = 0 ⇒ Thus we must have e = m e . m ˜ e charged ([ Q , T a ] = 0) scalar But we have not seen a 511 keV= m ˜ → SUSY must be broken At what scale? What is the mass of the supersymmetric particles? 20 / 65

  11. The hierarchy problem and the scale of SUSY breaking 21 / 65

  12. The hierarchy problem and the scale of SUSY breaking Let us first look at electrodynamics: e 2 The Coulomb field of the electron is E self = 3 r e . 5 This can be interpreted as a contribution to the electron mass: m e c 2 = m e , 0 c 2 + E self . 21 / 65

  13. The hierarchy problem and the scale of SUSY breaking Let us first look at electrodynamics: e 2 The Coulomb field of the electron is E self = 3 r e . 5 This can be interpreted as a contribution to the electron mass: m e c 2 = m e , 0 c 2 + E self . < 10 − 17 cm (exp. bound on point-like nature) one has However, with r e ∼ m e c 2 = 511 keV = ( − 9999 . 489 + 10000 . 000) keV → fine-tuning! 21 / 65

  14. Is there fine-tuning in quantum electrodynamics? 22 / 65

  15. Is there fine-tuning in quantum electrodynamics? Coulomb self-energy in time-ordered perturbation theory: 22 / 65

  16. Is there fine-tuning in quantum electrodynamics? Coulomb self-energy in time-ordered perturbation theory: But also have positron e + with Q ( e + ) = − Q ( e − ) and m ( e + ) = m ( e − ) → new diagram 22 / 65

  17. Is there fine-tuning in quantum electrodynamics? Coulomb self-energy in time-ordered perturbation theory: But also have positron e + with Q ( e + ) = − Q ( e − ) and m ( e + ) = m ( e − ) → new diagram � � �� 1 + 3 α � → m e c 2 = m e , 0 c 2 4 π ln m e cr e 22 / 65

  18. m e c 2 = m e , 0 c 2 � � �� 1 + 3 α � We found that 4 π ln . m e cr e So even if r e = 1 / M Planck = 1 . 6 × 10 − 33 cm, the corrections to the electron mass are small m e c 2 ≈ m e , 0 c 2 (1 + 0 . 1) . Also, if m e , 0 = 0 then m e = 0 to all orders: the mass is protected by a (chiral) symmetry 23 / 65

  19. m e c 2 = m e , 0 c 2 � � �� 1 + 3 α � We found that 4 π ln . m e cr e So even if r e = 1 / M Planck = 1 . 6 × 10 − 33 cm, the corrections to the electron mass are small m e c 2 ≈ m e , 0 c 2 (1 + 0 . 1) . Also, if m e , 0 = 0 then m e = 0 to all orders: the mass is protected by a (chiral) symmetry Recall ’t Hooft’s naturalness argument 23 / 65

  20. Now let us look at the scalar (=Higgs) self-energy: 24 / 65

  21. Now let us look at the scalar (=Higgs) self-energy: � � � d 4 k 2 m 2 1 ⇒ ∆ m 2 φ = 2 N ( f ) λ 2 f + k 2 − m 2 ( k 2 − m 2 f (2 π ) 4 f ) 2 f The integral is divergent, so we introduce a momentum cut-off. R Λ dkk 3 / ( k 2 − m 2 R Λ dkk 3 / ( k 2 − m 2 f ) ∼ Λ 2 and [Recall that d 4 k ∼ k 3 dk → f ) 2 ∼ ln Λ.] 24 / 65

  22. Now let us look at the scalar (=Higgs) self-energy: � � � d 4 k 2 m 2 1 ⇒ ∆ m 2 φ = 2 N ( f ) λ 2 f + k 2 − m 2 ( k 2 − m 2 f (2 π ) 4 f ) 2 f The integral is divergent, so we introduce a momentum cut-off. R Λ dkk 3 / ( k 2 − m 2 R Λ dkk 3 / ( k 2 − m 2 f ) ∼ Λ 2 and [Recall that d 4 k ∼ k 3 dk → f ) 2 ∼ ln Λ.] Straightforward calculation gives � � Λ 2 + m 2 � � φ = N ( f ) λ 2 Λ 2 Λ 2 + 3 m 2 ∆ m 2 + 2 m 2 f f f ln . Λ 2 + m 2 f 8 π 2 m 2 f f 24 / 65

  23. Because of the quadratic divergence we find φ (Λ = M Planck ) ≈ 10 35 GeV 2 = (3 × 10 17 GeV) 2 ∆ m 2 25 / 65

  24. Because of the quadratic divergence we find φ (Λ = M Planck ) ≈ 10 35 GeV 2 = (3 × 10 17 GeV) 2 ∆ m 2 and so < 1 TeV 2 = m 2 m 2 φ, 0 + ∆ m 2 φ ∼ φ implies a huge fine-tuning: Comment: it is essential that Λ < ∞ , i.e. we assume that new physics sets in at E ∼ Λ. Is this a tautology? No: we assume new physics at some very high scale Λ and find that the standard model needs new physics well below Λ. The natural mass scale of a scalar field is the highest scale in nature. 25 / 65

  25. The SUSY solution to the hierarchy problem 26 / 65

  26. The SUSY solution to the hierarchy problem Let us increase the particle content (as for the e − self-energy) Before we had Now we include in addition two scalars ˜ f L , ˜ f R with couplings � λ f ˜ � λ 2 2 φ 2 � f R | 2 � � f R | 2 � f L | 2 + | ˜ f L | 2 + | ˜ | ˜ − v ˜ | ˜ A f φ ˜ f L ˜ f λ 2 f ∗ √ L φ ˜ f = − f φ + R + h.c. 2 which lead to additional contributions to the self-energy: 26 / 65

  27. The additional contributions to the Higgs mass are: � d 4 k � � 1 1 ˜ f N (˜ ∆ m 2 λ 2 = f ) + φ k 2 − m 2 k 2 − m 2 (2 π ) 4 ˜ ˜ f L f R � d 4 k � � 1 1 f v ) 2 N (˜ (˜ λ 2 + f ) f L ) 2 + ( k 2 − m 2 ( k 2 − m 2 (2 π ) 4 f R ) 2 ˜ ˜ � d 4 k 1 ( λ f A f ) 2 N (˜ + f ) ( k 2 − m 2 f L )( k 2 − m 2 (2 π ) 4 f R ) ˜ ˜ . 27 / 65

  28. The additional contributions to the Higgs mass are: � d 4 k � � 1 1 ˜ f N (˜ ∆ m 2 λ 2 = f ) + φ k 2 − m 2 k 2 − m 2 (2 π ) 4 ˜ ˜ f L f R � d 4 k � � 1 1 f v ) 2 N (˜ (˜ λ 2 + f ) f L ) 2 + ( k 2 − m 2 ( k 2 − m 2 (2 π ) 4 f R ) 2 ˜ ˜ � d 4 k 1 ( λ f A f ) 2 N (˜ + f ) ( k 2 − m 2 f L )( k 2 − m 2 (2 π ) 4 f R ) ˜ ˜ . The first term cancels the SM Λ 2 -contribution if ˜ N (˜ λ f = λ f and f ) = N ( f ) as required in SUSY. 27 / 65

  29. The cancellation happens because of spin-statistics: fermion loop → (-1) boson-loop → (+1) 28 / 65

  30. The cancellation happens because of spin-statistics: fermion loop → (-1) boson-loop → (+1) Note: ◮ the cancellation of quadratic divergences is independent of m ˜ f L , m ˜ f R , A f . ◮ the term ∝ A f φ ˜ f L ˜ f ∗ R breaks SUSY but does not lead to Λ 2 divergences → ”soft” SUSY breaking 28 / 65

  31. Let us look at the finite SM + SUSY contributions: � � � λ 2 1 − ln m 2 f ln m 2 f N ( f ) ∆ m 2 − 2 m 2 f + 4 m 2 f = φ f 16 π 2 µ 2 µ 2 � � � m 2 m 2 m 2 µ 2 − | A f | 2 ln ˜ ˜ ˜ + 2 m 2 f − 4 m 2 f f 1 − ln f ln , ˜ ˜ f µ 2 µ 2 where we have assumed m ˜ f L = m ˜ f R = m ˜ f . 29 / 65

  32. Let us look at the finite SM + SUSY contributions: � � � λ 2 1 − ln m 2 f ln m 2 f N ( f ) ∆ m 2 − 2 m 2 f + 4 m 2 f = φ f 16 π 2 µ 2 µ 2 � � � m 2 m 2 m 2 µ 2 − | A f | 2 ln ˜ ˜ ˜ + 2 m 2 f − 4 m 2 f f 1 − ln f ln , ˜ ˜ f µ 2 µ 2 where we have assumed m ˜ f L = m ˜ f R = m ˜ f . One has ∆ m 2 φ = 0 for A f = 0 and m ˜ f = m f (SUSY) 29 / 65

  33. Let us look at the finite SM + SUSY contributions: � � � λ 2 1 − ln m 2 f ln m 2 f N ( f ) ∆ m 2 − 2 m 2 f + 4 m 2 f = φ f 16 π 2 µ 2 µ 2 � � � m 2 m 2 m 2 µ 2 − | A f | 2 ln ˜ ˜ ˜ + 2 m 2 f − 4 m 2 f f 1 − ln f ln , ˜ ˜ f µ 2 µ 2 where we have assumed m ˜ f L = m ˜ f R = m ˜ f . One has ∆ m 2 φ = 0 for A f = 0 and m ˜ f = m f (SUSY) But SUSY is broken, i.e. m 2 f = m 2 f + δ 2 . Thus ˜ � � φ = λ 2 2 + ln m 2 f N ( f ) ∆ m 2 δ 2 + O ( δ 4 ) f 8 π 2 µ 2 f + δ 2 = O (1 TeV 2 ) To have ∆ m 2 φ small, we thus need m 2 f = m 2 ˜ 29 / 65

  34. Supersymmetry: Summary of first lecture SUSY is great! Must have been tired yesterday. . . 30 / 65

  35. Motivation for supersymmetry A Priori: ◮ SUSY is the unique maximal external symmetry in Nature. ◮ Weak-scale SUSY provides a solution to the hierarchy problem. A Posteriori: ◮ SUSY allows for unification of Standard Model gauge interactions. ◮ SUSY provides dark matter candidates. ◮ SUSY QFT’s allow for precision calculations. ◮ SUSY provides a rich phenomenology and is testable at the LHC. 31 / 65

  36. Outline ◮ The supersymmetric harmonic oscillator ◮ Motivation for SUSY: Symmetry & the hierarchy problem ◮ The MSSM ◮ SUSY searches 32 / 65

  37. The Minimal Supersymmetric extension of the SM ◮ external symmetries: Poincare symmetry & supersymmetry ◮ internal symmetries: SU(3) ⊗ SU(2) ⊗ U(1) gauge symmetries ◮ minimal particle content 33 / 65

  38. Gauge coupling unification In QFT the gauge couplings “run”: d α i ( µ ) d ln µ 2 = β i ( α i ( µ )) The beta-functions β i depend on the gauge group and on the matter multiplets to which the gauge bosons couple. Only particles with mass < µ contribute to the β i and to the evolution of the coupling at any given mass scale µ . The Standard Model couplings evolve with µ according to SU ( 3 ) : β 3 , 0 = (33 − 4 n g ) / (12 π ) SU ( 2 ) : β 2 , 0 = (22 − 4 n g − n h / 2) / (12 π ) U ( 1 ) : β 1 , 0 = ( − 4 n g − 3 n h / 10) / (12 π ) where n g = 3 is the number of quark and lepton generations and n h = 1 is the number of Higgs doublet fields in the Standard Model. 34 / 65

  39. Gauge coupling unification Loop contributions of superpartners change the beta-functions. In the MSSM one finds: β SUSY SU ( 3 ) : = (27 − 6 n g ) / (12 π ) 3 , 0 β SUSY SU ( 2 ) : = (18 − 6 n g − 3 n h / 2) / (12 π ) 2 , 0 β SUSY U ( 1 ) : = ( − 6 n g − 9 n h / 10) / (12 π ) 1 , 0 35 / 65

  40. Gauge coupling unification Loop contributions of superpartners change the beta-functions. In the MSSM one finds: β SUSY SU ( 3 ) : = (27 − 6 n g ) / (12 π ) 3 , 0 β SUSY SU ( 2 ) : = (18 − 6 n g − 3 n h / 2) / (12 π ) 2 , 0 β SUSY U ( 1 ) : = ( − 6 n g − 9 n h / 10) / (12 π ) 1 , 0 35 / 65

  41. R -parity ◮ In the SM baryon and lepton number are accidental symmetries ◮ The most general superpotential of the SUSY-SM contains baryon and lepton number violating terms: W ∈ λ ijk L i L j E k + λ ′ λ ′′ ijk L i Q j D k + κ i L i H 2 + ijk U i D j D k � �� � � �� � lepton number violating baryon number violating 36 / 65

  42. R -parity ◮ In the SM baryon and lepton number are accidental symmetries ◮ The most general superpotential of the SUSY-SM contains baryon and lepton number violating terms: W ∈ λ ijk L i L j E k + λ ′ λ ′′ ijk L i Q j D k + κ i L i H 2 + ijk U i D j D k � �� � � �� � lepton number violating baryon number violating LQD and UDD couplings lead to rapid proton decay → impose discrete symmetry: R -parity R = ( − 1) 3 B + L +2 S → R SM = + and R SUSY = − 36 / 65

  43. R -parity R -parity conservation has dramatic phenomenological consequences: ◮ lightest SUSY particle (LSP) is absolutely stable → dark matter candidate if also electrically neutral ◮ in collider experiments SUSY particles can only be produced in pairs ◮ in many models SUSY collider events contain missing E T 37 / 65

  44. SUSY breaking Supersymmetry: mass( e − ) = mass(˜ e − L , R ) → SUSY must be broken No agreed model of supersymmetry breaking → phenomenological ansatz Must preserve solution to hierarchy problem → “soft” SUSY breaking 38 / 65

  45. SUSY breaking Supersymmetry: mass( e − ) = mass(˜ e − L , R ) → SUSY must be broken No agreed model of supersymmetry breaking → phenomenological ansatz Must preserve solution to hierarchy problem → “soft” SUSY breaking Introduce ◮ gaugino masses M 1 / 2 χχ : M 1 ˜ B ˜ B , M 2 ˜ W ˜ W , M 3 ˜ g ˜ g ◮ squark and slepton masses M 2 0 φ † φ : e † e † u † u † m 2 e L , m 2 e R , m 2 u L , m 2 e L ˜ L ˜ e R ˜ R ˜ u L ˜ L ˜ u R ˜ R ˜ u R etc. ˜ ˜ ˜ ˜ � ˜ � ν i ◮ trilinear couplings A ijk φ i φ j φ k : A e h 1 ˜ e jR etc. ij ˜ e j L ◮ Higgs mass terms B ij φ i φ j : Bh 1 h 2 etc. 38 / 65

  46. SUSY breaking MSSM w/o breaking: two additional parameters from Higgs sector Soft SUSY breaking ◮ A e ij , A d ij , A u → 27 real + 27 phases ij ◮ M 2 Q , M 2 U , M 2 D , M 2 L , M 2 E → 30 real + 15 phases ˜ ˜ ˜ ˜ ˜ ◮ M 1 , M 2 , M 3 → 3 real + 1 phase → 124 parameters in the MSSM! (but strong constraints from FCNS’s, flavour mixing and CP violation) 39 / 65

  47. SUSY breaking MSSM w/o breaking: two additional parameters from Higgs sector Soft SUSY breaking ◮ A e ij , A d ij , A u → 27 real + 27 phases ij ◮ M 2 Q , M 2 U , M 2 D , M 2 L , M 2 E → 30 real + 15 phases ˜ ˜ ˜ ˜ ˜ ◮ M 1 , M 2 , M 3 → 3 real + 1 phase → 124 parameters in the MSSM! (but strong constraints from FCNS’s, flavour mixing and CP violation) Simple framework constrained MSSM: breaking is universal at GUT scale ◮ universal scalar masses: M 2 Q , M 2 U , M 2 D , M 2 L , M 2 E → M 2 0 at M GUT ˜ ˜ ˜ ˜ ˜ ◮ universal gaugino masses: M 1 , M 2 , M 3 → M 1 / 2 at M GUT ◮ universal trilinear couplings A e ij , A d ij , A u ij → A · h e ij , A · h d ij , A · h u ij at M GUT → 6 additional parameters: M 0 , M 1 / 2 , A , B , µ , tan( β ) 39 / 65

  48. SUSY mass spectrum In QFT the (s)particle masses “run”: dM i ( µ ) d ln µ 2 = γ i M i 40 / 65

  49. SUSY mass spectrum In QFT the (s)particle masses “run”: dM i ( µ ) d ln µ 2 = γ i M i SPS1a 600 m Ql ( µ 2 +m Hd 2 ) 1/2 400 M 3 GeV M 2 200 M 1 m Er 0 ( µ 2 +m Hu 2 ) 1/2 SOFTSUSY3.0.5 -200 2 4 6 8 10 12 14 16 log 10 ( µ /GeV) 40 / 65

  50. SUSY mass spectrum In QFT the (s)particle masses “run”: dM i ( µ ) d ln µ 2 = γ i M i SPS1a 600 m Ql ( µ 2 +m Hd 2 ) 1/2 typical mass pattern e.g. from 400 M 3 M 1 ( µ ) α 1 ( µ ) = M 2 ( µ ) α 2 ( µ ) = M 3 ( µ ) GeV α 3 ( µ ) M 2 200 M 1 m Er → M 3 ( M Z ) : M 2 ( M Z ) : M 1 ( M Z ) ≃ 7 : 2 : 1 0 ( µ 2 +m Hu 2 ) 1/2 SOFTSUSY3.0.5 -200 2 4 6 8 10 12 14 16 log 10 ( µ /GeV) 40 / 65

  51. Radiative EWK symmetry breaking ◮ RGE drives ( µ 2 + m H 2 u ) negative → EWK symmetry breaking ◮ Masses of W and Z bosons fix B and | µ | ◮ cMSSM has 4 1/2 parameters: M 0 , M 1 / 2 , A , tan( β ) and sign( µ ) 41 / 65

  52. Mixing After SU(2) L × U(1) Y breaking, mixing will occur between any two or more fields which have the same color, charge and spin ◮ ( ˜ W ± , ˜ χ ± H ± ) → ˜ i =1 , 2 : charginos ◮ (˜ B , ˜ W 3 , ˜ H 0 χ 0 1 , 2 ) → ˜ i =1 , 2 , 3 , 4 : neutralinos ◮ (˜ t L , ˜ t R ) → ˜ t 1 , 2 etc.: sfermion mass eigenstates 42 / 65

  53. Mixing After SU(2) L × U(1) Y breaking, mixing will occur between any two or more fields which have the same color, charge and spin ◮ ( ˜ W ± , ˜ χ ± H ± ) → ˜ i =1 , 2 : charginos ◮ (˜ B , ˜ W 3 , ˜ H 0 χ 0 1 , 2 ) → ˜ i =1 , 2 , 3 , 4 : neutralinos ◮ (˜ t L , ˜ t R ) → ˜ t 1 , 2 etc.: sfermion mass eigenstates Note: ◮ mixing involves various SUSY parameters → cross sections and branching ratios become model dependent ◮ sfermion mixing ∝ m f → large only for 3rd generation (˜ t 1 , 2 , ˜ τ 1 , 2 ) 42 / 65

  54. Outline ◮ The supersymmetric harmonic oscillator ◮ Motivation for SUSY: Symmetry & the hierarchy problem ◮ The MSSM ◮ SUSY searches 43 / 65

  55. Summary of SUSY searches so far. . . 44 / 65

  56. Summary of SUSY searches so far. . . . . . but let’s see what to expect in 2011 & 2012. . . 44 / 65

  57. Outline ◮ The supersymmetric harmonic oscillator ◮ Motivation for SUSY: Symmetry & the hierarchy problem ◮ The MSSM ◮ SUSY searches ◮ indirect searches through quantum fluctuations ◮ direct searches at colliders 45 / 65

  58. Indirect SUSY searches Wealth of precision measurements from B / K physics, ( g − 2), astrophysics (DM) and collider limits → constraints on certain SUSY masses e.g. through anomalous magnetic moment ( g − 2) 46 / 65

  59. Indirect SUSY searches: ( g − 2) µ Hamiltonian for interaction of µ -spin with external magnetic field e � S µ · � H = g µ B 2 m µ with g µ = 2 in leading order Loop-corrections modify the interaction of the µ with the electromagnetic field � g − 2 � = α 2 π = 0 . 00116114 ⇒ 2 QED 23 / 51

  60. Indirect SUSY searches: ( g − 2) µ There are additional diagrams in supersymmetric QED, e.g. which is given by √ √ d 4 k � 1 i = (2 π ) 4 ( ie 2) P R P L ( ie 2) I ( p ′ − k ) 2 − m 2 � k − M ˜ γ ˜ µ L i × ( ie )( p ′ + p − 2 k ) ν ( p − k ) 2 − m 2 ˜ µ L After a short calculation (using standard QED techniques) one finds � 1 = − m 2 µ e 2 x 2 (1 − x ) � g − 2 � dx µ x 2 + ( m 2 µ L − M 2 µ ) x + M 2 2 8 π 2 m 2 γ − m 2 0 SQED ˜ ˜ ˜ γ 24 / 51

  61. Indirect SUSY searches: ( g − 2) µ In the limit m ˜ γ , m µ we find µ L ≫ M ˜ m 2 � g − 2 � = − α µ m 2 2 6 π SQED ˜ µ L ◮ SUSY contribution decouples rapidly for m ˜ µ L ≫ m µ ◮ SUSY contribution ∝ m f → effects in ( g − 2) e suppressed Including mixing: → dependence on further SUSY parameters ( A and tan β ) 25 / 51

  62. Indirect SUSY searches → CMSSM fit to B , K and EWK observables, ( g − 2) µ and Ω DM 47 / 65

  63. Indirect SUSY searches → CMSSM fit to B , K and EWK observables, ( g − 2) µ and Ω DM Mass Spectrum of SUSY Particles no LHC Mass Spectrum of SUSY Particles no LHC 1 Environment σ 1400 2 σ Environment Best Fit Value 1200 Particle Mass [GeV] 1000 800 600 400 200 0 ~ ~ ∼ ∼ ~ ~ ~ ~ ~ ~ ~ + 0 0 0 H 0 0 0 0 χ + χ + h A H χ χ χ χ τ τ q q t t g l l b b 1 2 1 2 3 4 1 2 R L R L 1 2 1 2 47 / 65

  64. Indirect SUSY searches → CMSSM fit to B , K and EWK observables, ( g − 2) µ and Ω DM Mass Spectrum of SUSY Particles no LHC Mass Spectrum of SUSY Particles no LHC 1 Environment σ 1400 2 σ Environment Best Fit Value 1200 Particle Mass [GeV] 1000 800 600 400 200 0 ~ ~ ∼ ∼ ~ ~ ~ ~ ~ ~ ~ + 0 0 0 H 0 0 0 0 χ + χ + h A H χ χ χ χ τ τ q q t t g l l b b 1 2 1 2 3 4 1 2 R L R L 1 2 1 2 ◮ global fits point to light sparticle spectrum with ˜ m < 1 TeV ◮ current data cannot constrain more general SUSY models 47 / 65

  65. Indirect SUSY searches → CMSSM fit without ( g − 2) µ and Ω DM ◮ prediction of light SUSY spectrum rests on ( g − 2) µ and Ω DM 48 / 65

  66. SUSY particle production at the LHC SUSY particles would be produced at the LHC via QCD processes 49 / 65

  67. SUSY particle production at the LHC SUSY particles would be produced at the LHC via QCD processes 1000 q¯ σ (pp → ˜ g˜ g / ˜ q / ˜ ˜ q˜ q / ˜ q˜ g + X) [pb] √ s = 7 TeV; 100 q = m ˜ m ˜ g NLO+NLL 10 1 0 . 1 ˜ g ˜ g q ¯ ˜ ˜ q 0 . 01 q ˜ ˜ q q ˜ ˜ g 0 . 001 200 400 600 800 1000 1200 m [GeV] √ → σ ≈ 100 fb for m ≈ 1000 GeV at S = 7 TeV 49 / 65

  68. SUSY particle production at the LHC SUSY particles would be produced at the LHC via QCD processes 10 3 q¯ σ (pp → ˜ g˜ g / ˜ ˜ q / ˜ q˜ q / ˜ q˜ g + X) [pb] √ s = 14 TeV; 10 1 q = m ˜ m ˜ g 10 NLO+NLL 1 10 − 1 10 − 2 g ˜ ˜ g 10 − 3 q ¯ ˜ ˜ q 10 − 4 q ˜ ˜ q ˜ q ˜ 10 − 5 g 500 1000 1500 2000 2500 3000 m [GeV] √ → σ ≈ 2 . 5 pb for m ≈ 1000 GeV at S = 14 TeV 50 / 65

  69. SUSY searches at hadron colliders → Powerful MSSM signature at the LHC: cascade decays with E T , miss 51 / 65

  70. SUSY searches at hadron colliders → Powerful MSSM signature at the LHC: cascade decays with E T , miss Generic signature for many new physics models which address – the hierarchy problem – the origin of dark matter → predict spectrum of new particles at the TeV-scale with weakly interacting & stable particle ( ← discrete parity) 51 / 65

  71. Squark and gluino searches at the LHC Atlas limits (165 pb − 1 ) β µ MSUGRA/CMSSM: tan = 10, A = 0, >0 0 600 [GeV] ATLAS Preliminary Observed 95% C.L. limit Median expected limit 550 0 lepton 2011 combined 0 lepton 2011 combined 1/2 int -1 L = 165 pb , s =7 TeV CL Observed 95 % C.L. limit s m 500 CL Median expected limit s ~ q (1400) Reference point 450 2010 data PCL 95% C.L. limit CMS 2010 Razor,Jets/MHT ~ 400 q ∼ ( ~ ± 1 χ g (1000) LEP 2 0 0 1 0 ) ~ ~ β µ -1 D0 g , q , tan =3, <0, 2.1 fb 350 ~ ~ β µ -1 CDF g , q , tan =5, <0, 2 fb 300 ~ g (800) ~ q ( 6 0 0 250 ) ~ 200 g (600) 150 500 1000 1500 2000 2500 m [GeV] 0 > 950 GeV → m ˜ q ≈ m ˜ g ∼ 52 / 65

  72. Direct SUSY searches at the LHC: expected limits The LHC is probing the preferred region of SUSY parameter space 2D 95% CL no LHC 1D 68% CL no LHC -1 95% CL exclusion 35pb 800 800 -1 95% CL exclusion 1fb -1 95% CL exclusion 2fb 95% CL exclusion 7fb -1 700 700 600 600 [GeV] [GeV] 500 500 1/2 1/2 M M 400 400 300 300 200 200 0 0 100 100 200 200 300 300 400 400 500 500 600 600 700 700 800 800 M M [GeV] [GeV] 0 0 53 / 65

  73. Direct SUSY searches at the LHC: expected limits But what if we do not see any SUSY signal at the LHC? 2D 95% CL no LHC 1D 68% CL no LHC -1 95% CL exclusion 35pb 800 800 -1 95% CL exclusion 1fb -1 95% CL exclusion 2fb 95% CL exclusion 7fb -1 700 700 600 600 [GeV] [GeV] 500 500 1/2 1/2 M M 400 400 300 300 200 200 0 0 100 100 200 200 300 300 400 400 500 500 600 600 700 700 800 800 M M [GeV] [GeV] 0 0 54 / 65

  74. Direct SUSY searches at the LHC: expected limits We have considered the SUSY search in the 4 jets + E T , miss signature with M eff = � i p T , i + E T , miss 55 / 65

Download Presentation
Download Policy: The content available on the website is offered to you 'AS IS' for your personal information and use only. It cannot be commercialized, licensed, or distributed on other websites without prior consent from the author. To download a presentation, simply click this link. If you encounter any difficulties during the download process, it's possible that the publisher has removed the file from their server.

Recommend


More recommend