Some inverse problems for dispersive partial differential equations. - - PowerPoint PPT Presentation

some inverse problems for dispersive partial differential
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Some inverse problems for dispersive partial differential equations. - - PowerPoint PPT Presentation

Some inverse problems for dispersive partial differential equations. Alberto Mercado Saucedo. Universidad T ecnica Federico Santa Mar a, Valpara so Chile. 29 Col oquio Brasileiro de Matem atica, IMPA, 2013 Alberto Mercado


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SLIDE 1

Some inverse problems for dispersive partial differential equations.

Alberto Mercado Saucedo.

Universidad T´ ecnica Federico Santa Mar´ ıa, Valpara´ ıso Chile.

29 Col´

  • quio Brasileiro de Matem´

atica, IMPA, 2013

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 1 / 28

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SLIDE 2

Presentation of the problem

The Korteweg-de Vries (KdV) equation yt(t, x) + yxxx(t, x) + yx(t, x) + y(t, x)yx(t, x) = 0, is a nonlinear dispersive equation that serves as a mathematical model to study the propagation of long water waves in channels of relatively shallow depth and flat bottom. Here, y(t, x) = surface elevation of the water wave at time t and position x. The study of water waves moving over variable topography has been considered. If we denote h = h(x) the variations in depth of the channel, then the proposed model becomes (after scaling) yt(t, x) + h2(x)yxxx(t, x) + ( p h(x)y(t, x))x + 1 p h(x) y(t, x)yx(t, x) = 0. (1) Thus, we are led to consider variable coefficients KdV equations to model the water wave propagation in non-flat channels.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 2 / 28

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SLIDE 3

Presentation of the problem

The Korteweg-de Vries (KdV) equation yt(t, x) + yxxx(t, x) + yx(t, x) + y(t, x)yx(t, x) = 0, is a nonlinear dispersive equation that serves as a mathematical model to study the propagation of long water waves in channels of relatively shallow depth and flat bottom. Here, y(t, x) = surface elevation of the water wave at time t and position x. The study of water waves moving over variable topography has been considered. If we denote h = h(x) the variations in depth of the channel, then the proposed model becomes (after scaling) yt(t, x) + h2(x)yxxx(t, x) + ( p h(x)y(t, x))x + 1 p h(x) y(t, x)yx(t, x) = 0. (1) Thus, we are led to consider variable coefficients KdV equations to model the water wave propagation in non-flat channels.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 2 / 28

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SLIDE 4

Presentation of the problem

We will deal with the KdV equation with non-constant coefficient a = a(x) given by 8 > > < > > : yt + a(x)yxxx + yx + yyx = g, 8(x, t) 2 (0, L) ⇥ (0, T), y(t, 0) = g0(t), y(t, L) = g1(t), 8t 2 (0, T), yx(t, L) = g2(t), 8t 2 (0, T), y(0, x) = y0(x), 8x 2 (0, L), where the initial data y0, the source term g, and the functions g0, g1, g2 are assumed to be known. In this context, the principal coefficient a = a(x) represents the deepness of the bottom

  • f the channel where the water wave propagates.

If a > 0 is bounded by below and above, the direct problem is well posed.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 3 / 28

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SLIDE 5

Presentation of the problem

We will deal with the KdV equation with non-constant coefficient a = a(x) given by 8 > > < > > : yt + a(x)yxxx + yx + yyx = g, 8(x, t) 2 (0, L) ⇥ (0, T), y(t, 0) = g0(t), y(t, L) = g1(t), 8t 2 (0, T), yx(t, L) = g2(t), 8t 2 (0, T), y(0, x) = y0(x), 8x 2 (0, L), where the initial data y0, the source term g, and the functions g0, g1, g2 are assumed to be known. In this context, the principal coefficient a = a(x) represents the deepness of the bottom

  • f the channel where the water wave propagates.

If a > 0 is bounded by below and above, the direct problem is well posed.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 3 / 28

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SLIDE 6

Presentation of the problem

We are concerned with the inverse problem of recovering the shape of the bottom of a channel, from partial knowledge of the solution of 8 > > < > > : yt + a(x)yxxx + yx + yyx = g, 8(x, t) 2 (0, L) ⇥ (0, T), y(t, 0) = g0(t), y(t, L) = g1(t), 8t 2 (0, T), yx(t, L) = g2(t), 8t 2 (0, T), y(0, x) = y0(x), 8x 2 (0, L),

Inverse Problem

Can we recover a = a(x) from some partial knowldege of y = y(x, t)?

Inverse Problem (Uniqueness)

Given some boundary observations Obs(y), is there a unique a = a(x) ? i.e. Obs(y) = Obs(˜ y) = ) a = ˜ a?

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 4 / 28

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SLIDE 7

Presentation of the problem

We are concerned with the inverse problem of recovering the shape of the bottom of a channel, from partial knowledge of the solution of 8 > > < > > : yt + a(x)yxxx + yx + yyx = g, 8(x, t) 2 (0, L) ⇥ (0, T), y(t, 0) = g0(t), y(t, L) = g1(t), 8t 2 (0, T), yx(t, L) = g2(t), 8t 2 (0, T), y(0, x) = y0(x), 8x 2 (0, L),

Inverse Problem

Can we recover a = a(x) from some partial knowldege of y = y(x, t)?

Inverse Problem (Uniqueness)

Given some boundary observations Obs(y), is there a unique a = a(x) ? i.e. Obs(y) = Obs(˜ y) = ) a = ˜ a?

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 4 / 28

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SLIDE 8

Presentation of the problem

We are concerned with the inverse problem of recovering the shape of the bottom of a channel, from partial knowledge of the solution of 8 > > < > > : yt + a(x)yxxx + yx + yyx = g, 8(x, t) 2 (0, L) ⇥ (0, T), y(t, 0) = g0(t), y(t, L) = g1(t), 8t 2 (0, T), yx(t, L) = g2(t), 8t 2 (0, T), y(0, x) = y0(x), 8x 2 (0, L),

Inverse Problem

Can we recover a = a(x) from some partial knowldege of y = y(x, t)?

Inverse Problem (Uniqueness)

Given some boundary observations Obs(y), is there a unique a = a(x) ? i.e. Obs(y) = Obs(˜ y) = ) a = ˜ a?

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 4 / 28

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SLIDE 9

Presentation of the problem

8 > > < > > : yt + a(x)yxxx + yx + yyx = g, 8(x, t) 2 (0, L) ⇥ (0, T), y(t, 0) = g0(t), y(t, L) = g1(t), 8t 2 (0, T), yx(t, L) = g2(t), 8t 2 (0, T), y(0, x) = y0(x), 8x 2 (0, L),

Inverse Problem (Stability)

ka ˜ akX  CkObs(y) Obs(˜ y)kY ?

Inverse Problem (Reconstruction)

Given some measurement Obs(y), is it possible to reconstruct the coefficient a = a(x)? In this talk, we are concerned with the stability of the inverse problem. Remark: This kind of inverse problem is called a single-measurement IP

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 5 / 28

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SLIDE 10

Presentation of the problem

8 > > < > > : yt + a(x)yxxx + yx + yyx = g, 8(x, t) 2 (0, L) ⇥ (0, T), y(t, 0) = g0(t), y(t, L) = g1(t), 8t 2 (0, T), yx(t, L) = g2(t), 8t 2 (0, T), y(0, x) = y0(x), 8x 2 (0, L),

Inverse Problem (Stability)

ka ˜ akX  CkObs(y) Obs(˜ y)kY ?

Inverse Problem (Reconstruction)

Given some measurement Obs(y), is it possible to reconstruct the coefficient a = a(x)? In this talk, we are concerned with the stability of the inverse problem. Remark: This kind of inverse problem is called a single-measurement IP

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 5 / 28

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SLIDE 11

Presentation of the problem

8 > > < > > : yt + a(x)yxxx + yx + yyx = g, 8(x, t) 2 (0, L) ⇥ (0, T), y(t, 0) = g0(t), y(t, L) = g1(t), 8t 2 (0, T), yx(t, L) = g2(t), 8t 2 (0, T), y(0, x) = y0(x), 8x 2 (0, L),

Inverse Problem (Stability)

ka ˜ akX  CkObs(y) Obs(˜ y)kY ?

Inverse Problem (Reconstruction)

Given some measurement Obs(y), is it possible to reconstruct the coefficient a = a(x)? In this talk, we are concerned with the stability of the inverse problem. Remark: This kind of inverse problem is called a single-measurement IP

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 5 / 28

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SLIDE 12

Recovering the main coefficient in KdV

8 > > < > > : yt + a(x)yxxx + yx + yyx = g, 8(x, t) 2 (0, L) ⇥ (0, T), y(t, 0) = g0(t), y(t, L) = g1(t), 8t 2 (0, T), yx(t, L) = g2(t), 8t 2 (0, T), y(0, x) = y0(x), 8x 2 (0, L),

Inverse Problem (Stability)

ka ˜ akX  CkObs(y) Obs(˜ y)kY ? We hope to get only boundary observations: kyx(t, 0) ˜ yx(t, 0)k, kyxx(t, 0) ˜ yxx(t, 0)k

  • r

kyxx(t, L) ˜ yxx(t, L)k

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 6 / 28

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SLIDE 13

Recovering the main coefficient in KdV

8 > > < > > : yt + a(x)yxxx + yx + yyx = g, 8(x, t) 2 (0, L) ⇥ (0, T), y(t, 0) = g0(t), y(t, L) = g1(t), 8t 2 (0, T), yx(t, L) = g2(t), 8t 2 (0, T), y(0, x) = y0(x), 8x 2 (0, L),

Inverse Problem (Stability)

ka ˜ akX  CkObs(y) Obs(˜ y)kY ? We hope to get only boundary observations: kyx(t, 0) ˜ yx(t, 0)k, kyxx(t, 0) ˜ yxx(t, 0)k

  • r

kyxx(t, L) ˜ yxx(t, L)k

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 6 / 28

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SLIDE 14

The approach

1

The Bukhgeim-Klibanov-Malinsky method.

2

Carleman estimate for the linearized equation. BUKHGEIM, KLIBANOV, 1981; KLIBANOV, MALINSKY 1991: Inverse problems with Carleman estimates. PUEL, YAMAMOTO 1996; YAMAMOTO, 1999; IMANUVILOV, YAMAMOTO 2001: Wave equation. IMANUVILOV, YAMAMOTO 1998, BENABDALLAH, GAITAN,LE ROUSSEAU:2007 Parabolic equations. BAUDOUIN, PUEL 2002; CARDOULIS,CRISTOFOL, GAITAN 2008; MERCADO,OSSES, ROSIER 2008: Schr¨

  • dinger equation.

EGGER, ENGL, KLIBANOV, 2005; BOULAKIA, GRANDMONT, OSSES, 2009: Nonlinear equations. BELLASSOUED, YAMAMOTO 2006; BELLASSOUED, CHOULLI, 2009 : Logarithmic stability for the wave equation and the Schr¨

  • dinger equation

ISAKOV, Inverse problems for partial differential equations, Springer, 2006.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 7 / 28

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SLIDE 15

The approach

1

The Bukhgeim-Klibanov-Malinsky method.

2

Carleman estimate for the linearized equation. BUKHGEIM, KLIBANOV, 1981; KLIBANOV, MALINSKY 1991: Inverse problems with Carleman estimates. PUEL, YAMAMOTO 1996; YAMAMOTO, 1999; IMANUVILOV, YAMAMOTO 2001: Wave equation. IMANUVILOV, YAMAMOTO 1998, BENABDALLAH, GAITAN,LE ROUSSEAU:2007 Parabolic equations. BAUDOUIN, PUEL 2002; CARDOULIS,CRISTOFOL, GAITAN 2008; MERCADO,OSSES, ROSIER 2008: Schr¨

  • dinger equation.

EGGER, ENGL, KLIBANOV, 2005; BOULAKIA, GRANDMONT, OSSES, 2009: Nonlinear equations. BELLASSOUED, YAMAMOTO 2006; BELLASSOUED, CHOULLI, 2009 : Logarithmic stability for the wave equation and the Schr¨

  • dinger equation

ISAKOV, Inverse problems for partial differential equations, Springer, 2006.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 7 / 28

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SLIDE 16

The approach

1

The Bukhgeim-Klibanov-Malinsky method.

2

Carleman estimate for the linearized equation. BUKHGEIM, KLIBANOV, 1981; KLIBANOV, MALINSKY 1991: Inverse problems with Carleman estimates. PUEL, YAMAMOTO 1996; YAMAMOTO, 1999; IMANUVILOV, YAMAMOTO 2001: Wave equation. IMANUVILOV, YAMAMOTO 1998, BENABDALLAH, GAITAN,LE ROUSSEAU:2007 Parabolic equations. BAUDOUIN, PUEL 2002; CARDOULIS,CRISTOFOL, GAITAN 2008; MERCADO,OSSES, ROSIER 2008: Schr¨

  • dinger equation.

EGGER, ENGL, KLIBANOV, 2005; BOULAKIA, GRANDMONT, OSSES, 2009: Nonlinear equations. BELLASSOUED, YAMAMOTO 2006; BELLASSOUED, CHOULLI, 2009 : Logarithmic stability for the wave equation and the Schr¨

  • dinger equation

ISAKOV, Inverse problems for partial differential equations, Springer, 2006.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 7 / 28

slide-17
SLIDE 17

The approach

1

The Bukhgeim-Klibanov-Malinsky method.

2

Carleman estimate for the linearized equation. BUKHGEIM, KLIBANOV, 1981; KLIBANOV, MALINSKY 1991: Inverse problems with Carleman estimates. PUEL, YAMAMOTO 1996; YAMAMOTO, 1999; IMANUVILOV, YAMAMOTO 2001: Wave equation. IMANUVILOV, YAMAMOTO 1998, BENABDALLAH, GAITAN,LE ROUSSEAU:2007 Parabolic equations. BAUDOUIN, PUEL 2002; CARDOULIS,CRISTOFOL, GAITAN 2008; MERCADO,OSSES, ROSIER 2008: Schr¨

  • dinger equation.

EGGER, ENGL, KLIBANOV, 2005; BOULAKIA, GRANDMONT, OSSES, 2009: Nonlinear equations. BELLASSOUED, YAMAMOTO 2006; BELLASSOUED, CHOULLI, 2009 : Logarithmic stability for the wave equation and the Schr¨

  • dinger equation

ISAKOV, Inverse problems for partial differential equations, Springer, 2006.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 7 / 28

slide-18
SLIDE 18

The approach

1

The Bukhgeim-Klibanov-Malinsky method.

2

Carleman estimate for the linearized equation. BUKHGEIM, KLIBANOV, 1981; KLIBANOV, MALINSKY 1991: Inverse problems with Carleman estimates. PUEL, YAMAMOTO 1996; YAMAMOTO, 1999; IMANUVILOV, YAMAMOTO 2001: Wave equation. IMANUVILOV, YAMAMOTO 1998, BENABDALLAH, GAITAN,LE ROUSSEAU:2007 Parabolic equations. BAUDOUIN, PUEL 2002; CARDOULIS,CRISTOFOL, GAITAN 2008; MERCADO,OSSES, ROSIER 2008: Schr¨

  • dinger equation.

EGGER, ENGL, KLIBANOV, 2005; BOULAKIA, GRANDMONT, OSSES, 2009: Nonlinear equations. BELLASSOUED, YAMAMOTO 2006; BELLASSOUED, CHOULLI, 2009 : Logarithmic stability for the wave equation and the Schr¨

  • dinger equation

ISAKOV, Inverse problems for partial differential equations, Springer, 2006.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 7 / 28

slide-19
SLIDE 19

The approach

1

The Bukhgeim-Klibanov-Malinsky method.

2

Carleman estimate for the linearized equation. BUKHGEIM, KLIBANOV, 1981; KLIBANOV, MALINSKY 1991: Inverse problems with Carleman estimates. PUEL, YAMAMOTO 1996; YAMAMOTO, 1999; IMANUVILOV, YAMAMOTO 2001: Wave equation. IMANUVILOV, YAMAMOTO 1998, BENABDALLAH, GAITAN,LE ROUSSEAU:2007 Parabolic equations. BAUDOUIN, PUEL 2002; CARDOULIS,CRISTOFOL, GAITAN 2008; MERCADO,OSSES, ROSIER 2008: Schr¨

  • dinger equation.

EGGER, ENGL, KLIBANOV, 2005; BOULAKIA, GRANDMONT, OSSES, 2009: Nonlinear equations. BELLASSOUED, YAMAMOTO 2006; BELLASSOUED, CHOULLI, 2009 : Logarithmic stability for the wave equation and the Schr¨

  • dinger equation

ISAKOV, Inverse problems for partial differential equations, Springer, 2006.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 7 / 28

slide-20
SLIDE 20

The approach

1

The Bukhgeim-Klibanov-Malinsky method.

2

Carleman estimate for the linearized equation. BUKHGEIM, KLIBANOV, 1981; KLIBANOV, MALINSKY 1991: Inverse problems with Carleman estimates. PUEL, YAMAMOTO 1996; YAMAMOTO, 1999; IMANUVILOV, YAMAMOTO 2001: Wave equation. IMANUVILOV, YAMAMOTO 1998, BENABDALLAH, GAITAN,LE ROUSSEAU:2007 Parabolic equations. BAUDOUIN, PUEL 2002; CARDOULIS,CRISTOFOL, GAITAN 2008; MERCADO,OSSES, ROSIER 2008: Schr¨

  • dinger equation.

EGGER, ENGL, KLIBANOV, 2005; BOULAKIA, GRANDMONT, OSSES, 2009: Nonlinear equations. BELLASSOUED, YAMAMOTO 2006; BELLASSOUED, CHOULLI, 2009 : Logarithmic stability for the wave equation and the Schr¨

  • dinger equation

ISAKOV, Inverse problems for partial differential equations, Springer, 2006.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 7 / 28

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SLIDE 21

BMK method

We follow ideas of Bukhgeim, Klibanov (1981), and Klibanov, Malinsky (1991). If we set: u = y ˜ y and σ = ˜ a a then u solves the following KdV equation: 8 < : ut + a(x)uxxx + (1 + ˜ y)ux + ˜ yxu + uux = σ˜ yxxx, 8(x, t) 2 (0, L) ⇥ (0, T), u(t, 0) = 0, u(t, L) = 0, ux(t, L) = 0 8t 2 (0, T), u(x, 0) = 0, 8x 2 (0, L). Then z = ut satisfies the following equation: 8 < : zt + a(x)zxxx + (1 + y)zx + yxz = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0, zx(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L), where fσ = σ(x)˜ yxxxt ˜ yxtu ˜ ytux.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 8 / 28

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SLIDE 22

BMK method

We follow ideas of Bukhgeim, Klibanov (1981), and Klibanov, Malinsky (1991). If we set: u = y ˜ y and σ = ˜ a a then u solves the following KdV equation: 8 < : ut + a(x)uxxx + (1 + ˜ y)ux + ˜ yxu + uux = σ˜ yxxx, 8(x, t) 2 (0, L) ⇥ (0, T), u(t, 0) = 0, u(t, L) = 0, ux(t, L) = 0 8t 2 (0, T), u(x, 0) = 0, 8x 2 (0, L). Then z = ut satisfies the following equation: 8 < : zt + a(x)zxxx + (1 + y)zx + yxz = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0, zx(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L), where fσ = σ(x)˜ yxxxt ˜ yxtu ˜ ytux.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 8 / 28

slide-23
SLIDE 23

BMK method

We follow ideas of Bukhgeim, Klibanov (1981), and Klibanov, Malinsky (1991). If we set: u = y ˜ y and σ = ˜ a a then u solves the following KdV equation: 8 < : ut + a(x)uxxx + (1 + ˜ y)ux + ˜ yxu + uux = σ˜ yxxx, 8(x, t) 2 (0, L) ⇥ (0, T), u(t, 0) = 0, u(t, L) = 0, ux(t, L) = 0 8t 2 (0, T), u(x, 0) = 0, 8x 2 (0, L). Then z = ut satisfies the following equation: 8 < : zt + a(x)zxxx + (1 + y)zx + yxz = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0, zx(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L), where fσ = σ(x)˜ yxxxt ˜ yxtu ˜ ytux.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 8 / 28

slide-24
SLIDE 24

BMK method

Then z = ut satisfies the following equation: 8 < : zt + a(x)zxxx + (1 + y)zx + yxz = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0, zx(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L), where fσ = σ(x)˜ yxxxt ˜ yxtu ˜ ytux. We would like to have an estimate like kz(x, 0)kX  CkfσkY + (boundary terms) where: We shall need y0,xxx(x) bounded by below by a positive constant. The constant C can be chosen small enough. We will use Carleman estimates. Remark: This kind of inequality is called observability in control theory

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 9 / 28

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SLIDE 25

BMK method

Then z = ut satisfies the following equation: 8 < : zt + a(x)zxxx + (1 + y)zx + yxz = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0, zx(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L), where fσ = σ(x)˜ yxxxt ˜ yxtu ˜ ytux. We would like to have an estimate like kz(x, 0)kX  CkfσkY + (boundary terms) where: We shall need y0,xxx(x) bounded by below by a positive constant. The constant C can be chosen small enough. We will use Carleman estimates. Remark: This kind of inequality is called observability in control theory

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 9 / 28

slide-26
SLIDE 26

BMK method

Then z = ut satisfies the following equation: 8 < : zt + a(x)zxxx + (1 + y)zx + yxz = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0, zx(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L), where fσ = σ(x)˜ yxxxt ˜ yxtu ˜ ytux. We would like to have an estimate like kz(x, 0)kX  CkfσkY + (boundary terms) where: We shall need y0,xxx(x) bounded by below by a positive constant. The constant C can be chosen small enough. We will use Carleman estimates. Remark: This kind of inequality is called observability in control theory

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 9 / 28

slide-27
SLIDE 27

BMK method

Then z = ut satisfies the following equation: 8 < : zt + a(x)zxxx + (1 + y)zx + yxz = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0, zx(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L), where fσ = σ(x)˜ yxxxt ˜ yxtu ˜ ytux. We would like to have an estimate like kz(x, 0)kX  CkfσkY + (boundary terms) where: We shall need y0,xxx(x) bounded by below by a positive constant. The constant C can be chosen small enough. We will use Carleman estimates. Remark: This kind of inequality is called observability in control theory

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 9 / 28

slide-28
SLIDE 28

BMK method

Then z = ut satisfies the following equation: 8 < : zt + a(x)zxxx + (1 + y)zx + yxz = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0, zx(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L), where fσ = σ(x)˜ yxxxt ˜ yxtu ˜ ytux. We would like to have an estimate like kz(x, 0)kX  CkfσkY + (boundary terms) where: We shall need y0,xxx(x) bounded by below by a positive constant. The constant C can be chosen small enough. We will use Carleman estimates. Remark: This kind of inequality is called observability in control theory

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 9 / 28

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SLIDE 29

Carleman inequalities.

Carleman inequalities were introduced by Trosten Carleman in 1939 in the study of uniqueness for some PDE’s. Since then, Carleman inequalities have been widely used in the study of : Unique continuation properties. Control problems of equations with non-regular lower order terms. Control problems of semi-linear equations. Some inverse problems. Lebeau-Robianno (1995), Fursikov-Imanuvilov (1996), Tataru (1996).

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 10 / 28

slide-30
SLIDE 30

Carleman inequalities.

Carleman inequalities were introduced by Trosten Carleman in 1939 in the study of uniqueness for some PDE’s. Since then, Carleman inequalities have been widely used in the study of : Unique continuation properties. Control problems of equations with non-regular lower order terms. Control problems of semi-linear equations. Some inverse problems. Lebeau-Robianno (1995), Fursikov-Imanuvilov (1996), Tataru (1996).

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 10 / 28

slide-31
SLIDE 31

Carleman estimates. An example.

Consider L = ∆ for functions w 2 C∞

c (Ω).

We define Lφw = e−λφL(eλφw) ∆(eλφw) = eλφ λ2|rφ|2w + λ∆φw + 2λrφ · rw + ∆w

  • If φ(x) = α · x

with α 2 Rn \ {0} then: Lφw = λ2|α|2w + ∆w + 2λα · rw

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 11 / 28

slide-32
SLIDE 32

Carleman estimates. An example.

Consider L = ∆ for functions w 2 C∞

c (Ω).

We define Lφw = e−λφL(eλφw) ∆(eλφw) = eλφ λ2|rφ|2w + λ∆φw + 2λrφ · rw + ∆w

  • If φ(x) = α · x

with α 2 Rn \ {0} then: Lφw = λ2|α|2w + ∆w + 2λα · rw

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 11 / 28

slide-33
SLIDE 33

Carleman estimates. An example.

Consider L = ∆ for functions w 2 C∞

c (Ω).

We define Lφw = e−λφL(eλφw) ∆(eλφw) = eλφ λ2|rφ|2w + λ∆φw + 2λrφ · rw + ∆w

  • If φ(x) = α · x

with α 2 Rn \ {0} then: Lφw = λ2|α|2w + ∆w + 2λα · rw

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 11 / 28

slide-34
SLIDE 34

Carleman estimates. An example.

Consider L = ∆ for functions w 2 C∞

c (Ω).

We define Lφw = e−λφL(eλφw) ∆(eλφw) = eλφ λ2|rφ|2w + λ∆φw + 2λrφ · rw + ∆w

  • If φ(x) = α · x

with α 2 Rn \ {0} then: Lφw = λ2|α|2w + ∆w + 2λα · rw

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 11 / 28

slide-35
SLIDE 35

Carleman estimates. An example.

Consider L = ∆ for functions w 2 Cc(Ω). ∆(eλφw) = eλφ(λ2|rφ|2w + λ∆φw + 2λrφ · rw + ∆w) If φ(x) = α · x with α 2 Rn \ {0} then: Lφw = λ2|α|2w + ∆w | {z }

Aw

+ 2λα · rw | {z }

Bw

A is self-adjoint. B is anti-adjoint.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 12 / 28

slide-36
SLIDE 36

Carleman estimates. An example.

Consider L = ∆ for functions w 2 Cc(Ω). ∆(eλφw) = eλφ(λ2|rφ|2w + λ∆φw + 2λrφ · rw + ∆w) If φ(x) = α · x with α 2 Rn \ {0} then: Lφw = λ2|α|2w + ∆w | {z }

Aw

+ 2λα · rw | {z }

Bw

A is self-adjoint. B is anti-adjoint.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 12 / 28

slide-37
SLIDE 37

Carleman estimates. An example.

Lφw = λ2|α|2w + ∆w | {z }

Aw

+ 2λα · rw | {z }

Bw

We have kLφwk2

L2 = kAwk2 L2 + kBwk2 L2 + 2 hAw, BwiL2

(2) A is self-adjoint and B is anti-adjoint (and both have constant coefficients), we get 2 hAw, BwiL2 = h[A, B]w, wiL2 = 0, 8 w 2 C∞

c (Ω)

Thus kLφwkL2 2λkα · rwkL2 (3) λδkwkL2 (4) Which means that λke−λφukL2  Cke−λφ∆ukL2 (5)

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 13 / 28

slide-38
SLIDE 38

Carleman estimates. An example.

Lφw = λ2|α|2w + ∆w | {z }

Aw

+ 2λα · rw | {z }

Bw

We have kLφwk2

L2 = kAwk2 L2 + kBwk2 L2 + 2 hAw, BwiL2

(2) A is self-adjoint and B is anti-adjoint (and both have constant coefficients), we get 2 hAw, BwiL2 = h[A, B]w, wiL2 = 0, 8 w 2 C∞

c (Ω)

Thus kLφwkL2 2λkα · rwkL2 (3) λδkwkL2 (4) Which means that λke−λφukL2  Cke−λφ∆ukL2 (5)

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 13 / 28

slide-39
SLIDE 39

Carleman estimates. An example.

Lφw = λ2|α|2w + ∆w | {z }

Aw

+ 2λα · rw | {z }

Bw

We have kLφwk2

L2 = kAwk2 L2 + kBwk2 L2 + 2 hAw, BwiL2

(2) A is self-adjoint and B is anti-adjoint (and both have constant coefficients), we get 2 hAw, BwiL2 = h[A, B]w, wiL2 = 0, 8 w 2 C∞

c (Ω)

Thus kLφwkL2 2λkα · rwkL2 (3) λδkwkL2 (4) Which means that λke−λφukL2  Cke−λφ∆ukL2 (5)

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 13 / 28

slide-40
SLIDE 40

Carleman estimates. An example.

Lφw = λ2|α|2w + ∆w | {z }

Aw

+ 2λα · rw | {z }

Bw

We have kLφwk2

L2 = kAwk2 L2 + kBwk2 L2 + 2 hAw, BwiL2

(2) A is self-adjoint and B is anti-adjoint (and both have constant coefficients), we get 2 hAw, BwiL2 = h[A, B]w, wiL2 = 0, 8 w 2 C∞

c (Ω)

Thus kLφwkL2 2λkα · rwkL2 (3) λδkwkL2 (4) Which means that λke−λφukL2  Cke−λφ∆ukL2 (5)

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 13 / 28

slide-41
SLIDE 41

Carleman estimates. An example.

In other cases: Lφw = λ2|rφ|2w + ∆w | {z }

Aw

+ 2λrφ · rw | {z }

Bw

We have kLφwk2

L2 = kAwk2 L2 + kBwk2 L2 + 2 hAw, BwiL2

(6) 2 hAw, BwiL2 = h[A, B]w, wiL2 = lower order + boundary terms, 8 w 2 C∞

c (Ω)

Thus, we need to prove an estimate h[A, B]w, wiL2 λδkwkHkObs(w) (7)

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 14 / 28

slide-42
SLIDE 42

Carleman estimates. An example.

In other cases: Lφw = λ2|rφ|2w + ∆w | {z }

Aw

+ 2λrφ · rw | {z }

Bw

We have kLφwk2

L2 = kAwk2 L2 + kBwk2 L2 + 2 hAw, BwiL2

(6) 2 hAw, BwiL2 = h[A, B]w, wiL2 = lower order + boundary terms, 8 w 2 C∞

c (Ω)

Thus, we need to prove an estimate h[A, B]w, wiL2 λδkwkHkObs(w) (7)

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 14 / 28

slide-43
SLIDE 43

Carleman inequalities.

In general, given a differential operator P and a smooth function φ, we define Pφ = eλφPe−λφ Remark that Pφ = p(x, D + iλrφ) For instance, φ is pseudoconvex if: For P = ∂t ∆ if |rφ| 6= 0 For P = ∂2

t ∆ if φ is convex.

For P = i∂t ∆ si φ is convex. Boundary condition: Usually is required ∂φ ∂ν < 0 in ∂Ω.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 15 / 28

slide-44
SLIDE 44

Carleman inequalities.

In general, given a differential operator P and a smooth function φ, we define Pφ = eλφPe−λφ Remark that Pφ = p(x, D + iλrφ) For instance, φ is pseudoconvex if: For P = ∂t ∆ if |rφ| 6= 0 For P = ∂2

t ∆ if φ is convex.

For P = i∂t ∆ si φ is convex. Boundary condition: Usually is required ∂φ ∂ν < 0 in ∂Ω.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 15 / 28

slide-45
SLIDE 45

Carleman inequalities.

In general, given a differential operator P and a smooth function φ, we define Pφ = eλφPe−λφ Remark that Pφ = p(x, D + iλrφ)

Theorem (Carleman inequalities)

If φ is pseudoconvex with respect to P then kvkHm

λ  CkPφvkL2

for λ large enough. For instance, φ is pseudoconvex if: For P = ∂t ∆ if |rφ| 6= 0 For P = ∂2

t ∆ if φ is convex.

For P = i∂t ∆ si φ is convex. Boundary condition: Usually is required ∂φ ∂ν < 0 in ∂Ω.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 15 / 28

slide-46
SLIDE 46

Carleman inequalities.

In general, given a differential operator P and a smooth function φ, we define Pφ = eλφPe−λφ Remark that Pφ = p(x, D + iλrφ)

Theorem (Carleman inequalities)

If φ is pseudoconvex with respect to P then kvkHm

λ  CkPφvkL2

for λ large enough. For instance, φ is pseudoconvex if: For P = ∂t ∆ if |rφ| 6= 0 For P = ∂2

t ∆ if φ is convex.

For P = i∂t ∆ si φ is convex. Boundary condition: Usually is required ∂φ ∂ν < 0 in ∂Ω.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 15 / 28

slide-47
SLIDE 47

Carleman inequalities.

If the previous properties are not satisfied in a set ω ⇢ Ω or ω ⇢ ∂Ω , then Pφ = eλφPe−λφ Remark that Pφ = p(x, D + iλrφ)

Theorem (Carleman inequalities)

If φ is pseudoconvex with respect to P then kvkHm

λ  CkPφvkL2 + kvkHm(ω)

for λ large enough. For instance, φ is pseudoconvex if: For P = ∂t ∆ if |rφ| 6= 0 For P = ∂2

t ∆ if φ is convex.

For P = i∂t ∆ si φ is convex. Boundary condition: Usually is required ∂φ ∂ν < 0 in ∂Ω.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 16 / 28

slide-48
SLIDE 48

Carleman inequalities.

If the previous properties are not satisfied in a set ω ⇢ Ω or ω ⇢ ∂Ω , then Pφ = eλφPe−λφ Remark that Pφ = p(x, D + iλrφ)

Theorem (Carleman inequalities)

If φ is pseudoconvex with respect to P then kvkHm

λ  CkPφvkL2 + kvkHm(ω)

for λ large enough. In the original variable, we get: ke−λφwkHm  Cke−λφPwkL2 + ke−λφwkHm(ω) | {z }

  • bservation

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 17 / 28

slide-49
SLIDE 49

BMK method - Wave equation

8 < : ztt a(x)zxx = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xx(x), 8x 2 (0, L), What happens for wave equation? Extend the solution to (T, T) by using the symmetry under the change of variable t ! (T t). Use Carleman inequalities on (T, T). The time t = 0 is not singular and you get kz(x, 0)kX  CkfσkY + (boundary terms), with C small.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 18 / 28

slide-50
SLIDE 50

BMK method - Wave equation

8 < : ztt a(x)zxx = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xx(x), 8x 2 (0, L), What happens for wave equation? Extend the solution to (T, T) by using the symmetry under the change of variable t ! (T t). Use Carleman inequalities on (T, T). The time t = 0 is not singular and you get kz(x, 0)kX  CkfσkY + (boundary terms), with C small.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 18 / 28

slide-51
SLIDE 51

BMK method - Wave equation

8 < : ztt a(x)zxx = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xx(x), 8x 2 (0, L), What happens for wave equation? Extend the solution to (T, T) by using the symmetry under the change of variable t ! (T t). Use Carleman inequalities on (T, T). The time t = 0 is not singular and you get kz(x, 0)kX  CkfσkY + (boundary terms), with C small.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 18 / 28

slide-52
SLIDE 52

BMK method - Wave equation

8 < : ztt a(x)zxx = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xx(x), 8x 2 (0, L), What happens for wave equation? Extend the solution to (T, T) by using the symmetry under the change of variable t ! (T t). Use Carleman inequalities on (T, T). The time t = 0 is not singular and you get kz(x, 0)kX  CkfσkY + (boundary terms), with C small.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 18 / 28

slide-53
SLIDE 53

BMK method - Schr¨

  • dinger equation

8 < : izt + a(x)zxx = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xx(x), 8x 2 (0, L), What happens for the Schr¨

  • dinger equation?

The Carleman weight is singular at t = 0 and t = T. Extend the solution to (T, T) by defining the solution for negative time as z(x, t) := ¯ z(x, t), fσ(x, t) = ¯ fσ(x, t) Use Carleman inequalities on (T, T). The time t = 0 is not singular anymore and you get kz(x, 0)kX  CkfσkY + (boundary terms), with C small. Remark: The method needs Re(y0(x)) to be zero.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 19 / 28

slide-54
SLIDE 54

BMK method - Schr¨

  • dinger equation

8 < : izt + a(x)zxx = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xx(x), 8x 2 (0, L), What happens for the Schr¨

  • dinger equation?

The Carleman weight is singular at t = 0 and t = T. Extend the solution to (T, T) by defining the solution for negative time as z(x, t) := ¯ z(x, t), fσ(x, t) = ¯ fσ(x, t) Use Carleman inequalities on (T, T). The time t = 0 is not singular anymore and you get kz(x, 0)kX  CkfσkY + (boundary terms), with C small. Remark: The method needs Re(y0(x)) to be zero.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 19 / 28

slide-55
SLIDE 55

BMK method - Schr¨

  • dinger equation

8 < : izt + a(x)zxx = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xx(x), 8x 2 (0, L), What happens for the Schr¨

  • dinger equation?

The Carleman weight is singular at t = 0 and t = T. Extend the solution to (T, T) by defining the solution for negative time as z(x, t) := ¯ z(x, t), fσ(x, t) = ¯ fσ(x, t) Use Carleman inequalities on (T, T). The time t = 0 is not singular anymore and you get kz(x, 0)kX  CkfσkY + (boundary terms), with C small. Remark: The method needs Re(y0(x)) to be zero.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 19 / 28

slide-56
SLIDE 56

BMK method - Schr¨

  • dinger equation

8 < : izt + a(x)zxx = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xx(x), 8x 2 (0, L), What happens for the Schr¨

  • dinger equation?

The Carleman weight is singular at t = 0 and t = T. Extend the solution to (T, T) by defining the solution for negative time as z(x, t) := ¯ z(x, t), fσ(x, t) = ¯ fσ(x, t) Use Carleman inequalities on (T, T). The time t = 0 is not singular anymore and you get kz(x, 0)kX  CkfσkY + (boundary terms), with C small. Remark: The method needs Re(y0(x)) to be zero.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 19 / 28

slide-57
SLIDE 57

BMK method - Schr¨

  • dinger equation

8 < : izt + a(x)zxx = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xx(x), 8x 2 (0, L), What happens for the Schr¨

  • dinger equation?

The Carleman weight is singular at t = 0 and t = T. Extend the solution to (T, T) by defining the solution for negative time as z(x, t) := ¯ z(x, t), fσ(x, t) = ¯ fσ(x, t) Use Carleman inequalities on (T, T). The time t = 0 is not singular anymore and you get kz(x, 0)kX  CkfσkY + (boundary terms), with C small. Remark: The method needs Re(y0(x)) to be zero.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 19 / 28

slide-58
SLIDE 58

BMK method - Schr¨

  • dinger equation

8 < : izt + a(x)zxx = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xx(x), 8x 2 (0, L), What happens for the Schr¨

  • dinger equation?

The Carleman weight is singular at t = 0 and t = T. Extend the solution to (T, T) by defining the solution for negative time as z(x, t) := ¯ z(x, t), fσ(x, t) = ¯ fσ(x, t) Use Carleman inequalities on (T, T). The time t = 0 is not singular anymore and you get kz(x, 0)kX  CkfσkY + (boundary terms), with C small. Remark: The method needs Re(y0(x)) to be zero.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 19 / 28

slide-59
SLIDE 59

BMK method - Heat equations

8 < : zt a(x)zxx = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xx(x), 8x 2 (0, L), What happens for the heat equation? Observability kz(x, 0)kX  CkfσkY + (boundary terms), can not be proved for parabolic equation. Instead, one gets kz(x, T0)kX  CkfσkY + (boundary terms). We use the equation kz(x, T0)k = kut(x, T0)k = kσR(x, T0) + a(x)uxx(x, T0)k kσR(x, T0)k ka(x)uxx(x, T0)k and we have to add an observation like kyxx(x, T0) ˜ yxx(x, T0)k!

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 20 / 28

slide-60
SLIDE 60

BMK method - Heat equations

8 < : zt a(x)zxx = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xx(x), 8x 2 (0, L), What happens for the heat equation? Observability kz(x, 0)kX  CkfσkY + (boundary terms), can not be proved for parabolic equation. Instead, one gets kz(x, T0)kX  CkfσkY + (boundary terms). We use the equation kz(x, T0)k = kut(x, T0)k = kσR(x, T0) + a(x)uxx(x, T0)k kσR(x, T0)k ka(x)uxx(x, T0)k and we have to add an observation like kyxx(x, T0) ˜ yxx(x, T0)k!

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 20 / 28

slide-61
SLIDE 61

BMK method - Heat equations

8 < : zt a(x)zxx = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xx(x), 8x 2 (0, L), What happens for the heat equation? Observability kz(x, 0)kX  CkfσkY + (boundary terms), can not be proved for parabolic equation. Instead, one gets kz(x, T0)kX  CkfσkY + (boundary terms). We use the equation kz(x, T0)k = kut(x, T0)k = kσR(x, T0) + a(x)uxx(x, T0)k kσR(x, T0)k ka(x)uxx(x, T0)k and we have to add an observation like kyxx(x, T0) ˜ yxx(x, T0)k!

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 20 / 28

slide-62
SLIDE 62

BMK method - Heat equations

8 < : zt a(x)zxx = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xx(x), 8x 2 (0, L), What happens for the heat equation? Observability kz(x, 0)kX  CkfσkY + (boundary terms), can not be proved for parabolic equation. Instead, one gets kz(x, T0)kX  CkfσkY + (boundary terms). We use the equation kz(x, T0)k = kut(x, T0)k = kσR(x, T0) + a(x)uxx(x, T0)k kσR(x, T0)k ka(x)uxx(x, T0)k and we have to add an observation like kyxx(x, T0) ˜ yxx(x, T0)k!

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 20 / 28

slide-63
SLIDE 63

BMK method - KdV equation

8 < : zt + a(x)zxxx + (1 + y)zx + yxz = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0, zx(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L), What happens for KdV equation? Not parabolic neither hyperbolic. From a control point of view, in some cases it is parabolic and in others hyperbolic. KdV has only one time-derivative and so the change t ! T t is not adequate. But it has the symmetry t ! T t and x ! L x, which allows to define the solution for negative times. Carleman estimate on (T, T) ⇥ (0, L). Time t = 0 is not singular any more for Carleman and therefore kz(x, 0)kX  CkfσkY + (boundary terms), is obtained with C small. Remark: Some symmetry conditions have to be imposed.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 21 / 28

slide-64
SLIDE 64

BMK method - KdV equation

8 < : zt + a(x)zxxx + (1 + y)zx + yxz = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0, zx(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L), What happens for KdV equation? Not parabolic neither hyperbolic. From a control point of view, in some cases it is parabolic and in others hyperbolic. KdV has only one time-derivative and so the change t ! T t is not adequate. But it has the symmetry t ! T t and x ! L x, which allows to define the solution for negative times. Carleman estimate on (T, T) ⇥ (0, L). Time t = 0 is not singular any more for Carleman and therefore kz(x, 0)kX  CkfσkY + (boundary terms), is obtained with C small. Remark: Some symmetry conditions have to be imposed.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 21 / 28

slide-65
SLIDE 65

BMK method - KdV equation

8 < : zt + a(x)zxxx + (1 + y)zx + yxz = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0, zx(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L), What happens for KdV equation? Not parabolic neither hyperbolic. From a control point of view, in some cases it is parabolic and in others hyperbolic. KdV has only one time-derivative and so the change t ! T t is not adequate. But it has the symmetry t ! T t and x ! L x, which allows to define the solution for negative times. Carleman estimate on (T, T) ⇥ (0, L). Time t = 0 is not singular any more for Carleman and therefore kz(x, 0)kX  CkfσkY + (boundary terms), is obtained with C small. Remark: Some symmetry conditions have to be imposed.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 21 / 28

slide-66
SLIDE 66

BMK method - KdV equation

8 < : zt + a(x)zxxx + (1 + y)zx + yxz = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0, zx(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L), What happens for KdV equation? Not parabolic neither hyperbolic. From a control point of view, in some cases it is parabolic and in others hyperbolic. KdV has only one time-derivative and so the change t ! T t is not adequate. But it has the symmetry t ! T t and x ! L x, which allows to define the solution for negative times. Carleman estimate on (T, T) ⇥ (0, L). Time t = 0 is not singular any more for Carleman and therefore kz(x, 0)kX  CkfσkY + (boundary terms), is obtained with C small. Remark: Some symmetry conditions have to be imposed.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 21 / 28

slide-67
SLIDE 67

BMK method - KdV equation

8 < : zt + a(x)zxxx + (1 + y)zx + yxz = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0, zx(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L), What happens for KdV equation? Not parabolic neither hyperbolic. From a control point of view, in some cases it is parabolic and in others hyperbolic. KdV has only one time-derivative and so the change t ! T t is not adequate. But it has the symmetry t ! T t and x ! L x, which allows to define the solution for negative times. Carleman estimate on (T, T) ⇥ (0, L). Time t = 0 is not singular any more for Carleman and therefore kz(x, 0)kX  CkfσkY + (boundary terms), is obtained with C small. Remark: Some symmetry conditions have to be imposed.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 21 / 28

slide-68
SLIDE 68

BMK method - KdV equation

8 < : zt + a(x)zxxx + (1 + y)zx + yxz = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0, zx(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L), What happens for KdV equation? Not parabolic neither hyperbolic. From a control point of view, in some cases it is parabolic and in others hyperbolic. KdV has only one time-derivative and so the change t ! T t is not adequate. But it has the symmetry t ! T t and x ! L x, which allows to define the solution for negative times. Carleman estimate on (T, T) ⇥ (0, L). Time t = 0 is not singular any more for Carleman and therefore kz(x, 0)kX  CkfσkY + (boundary terms), is obtained with C small. Remark: Some symmetry conditions have to be imposed.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 21 / 28

slide-69
SLIDE 69

BMK method - KdV equation

8 < : zt + a(x)zxxx + (1 + y)zx + yxz = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0, zx(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L), What happens for KdV equation? Not parabolic neither hyperbolic. From a control point of view, in some cases it is parabolic and in others hyperbolic. KdV has only one time-derivative and so the change t ! T t is not adequate. But it has the symmetry t ! T t and x ! L x, which allows to define the solution for negative times. Carleman estimate on (T, T) ⇥ (0, L). Time t = 0 is not singular any more for Carleman and therefore kz(x, 0)kX  CkfσkY + (boundary terms), is obtained with C small. Remark: Some symmetry conditions have to be imposed.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 21 / 28

slide-70
SLIDE 70

BMK method - KdV equation

8 < : zt + a(x)zxxx + (1 + y)zx + yxz = fσ, 8(x, t) 2 (0, L) ⇥ (0, T), z(t, 0) = 0, z(t, L) = 0, zx(t, L) = 0 8t 2 (0, T), z(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L), What happens for KdV equation? Not parabolic neither hyperbolic. From a control point of view, in some cases it is parabolic and in others hyperbolic. KdV has only one time-derivative and so the change t ! T t is not adequate. But it has the symmetry t ! T t and x ! L x, which allows to define the solution for negative times. Carleman estimate on (T, T) ⇥ (0, L). Time t = 0 is not singular any more for Carleman and therefore kz(x, 0)kX  CkfσkY + (boundary terms), is obtained with C small. Remark: Some symmetry conditions have to be imposed.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 21 / 28

slide-71
SLIDE 71

BMK method - Extension for negative time

Symmetric extension to (0, L) ⇥ (T, T) of g defined on (0, L) ⇥ (0, T): gs(x, t) = ( g(x, t) if x 2 [0, L], t 2 [0, T], g(L x, t) if x 2 [0, L], t 2 [T, 0). Anti-symmetric extension to (0, L) ⇥ (T, T) of g defined on (0, L) ⇥ (0, T): ga(x, t) = ( g(x, t) if x 2 [0, L], t 2 [0, T], g(L x, t) if x 2 [0, L], t 2 [T, 0). Defining v = zs, we obtain: 8 > > > > > < > > > > > : vt + a(x)vxxx + (1 + ys)vx + (yx)av = f a

σ,

8x 2 (0, L), t 2 (T, T), v(t, 0) = 0, v(t, L) = 0, 8t 2 (T, T), vx(t, L) = ( 0, 8t 2 (0, T), zx(0, t), 8t 2 (T, 0). v(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L).

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 22 / 28

slide-72
SLIDE 72

BMK method - Extension for negative time

Symmetric extension to (0, L) ⇥ (T, T) of g defined on (0, L) ⇥ (0, T): gs(x, t) = ( g(x, t) if x 2 [0, L], t 2 [0, T], g(L x, t) if x 2 [0, L], t 2 [T, 0). Anti-symmetric extension to (0, L) ⇥ (T, T) of g defined on (0, L) ⇥ (0, T): ga(x, t) = ( g(x, t) if x 2 [0, L], t 2 [0, T], g(L x, t) if x 2 [0, L], t 2 [T, 0). Defining v = zs, we obtain: 8 > > > > > < > > > > > : vt + a(x)vxxx + (1 + ys)vx + (yx)av = f a

σ,

8x 2 (0, L), t 2 (T, T), v(t, 0) = 0, v(t, L) = 0, 8t 2 (T, T), vx(t, L) = ( 0, 8t 2 (0, T), zx(0, t), 8t 2 (T, 0). v(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L).

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 22 / 28

slide-73
SLIDE 73

BMK method - Extension for negative time

Symmetric extension to (0, L) ⇥ (T, T) of g defined on (0, L) ⇥ (0, T): gs(x, t) = ( g(x, t) if x 2 [0, L], t 2 [0, T], g(L x, t) if x 2 [0, L], t 2 [T, 0). Anti-symmetric extension to (0, L) ⇥ (T, T) of g defined on (0, L) ⇥ (0, T): ga(x, t) = ( g(x, t) if x 2 [0, L], t 2 [0, T], g(L x, t) if x 2 [0, L], t 2 [T, 0). Defining v = zs, we obtain: 8 > > > > > < > > > > > : vt + a(x)vxxx + (1 + ys)vx + (yx)av = f a

σ,

8x 2 (0, L), t 2 (T, T), v(t, 0) = 0, v(t, L) = 0, 8t 2 (T, T), vx(t, L) = ( 0, 8t 2 (0, T), zx(0, t), 8t 2 (T, 0). v(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L).

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 22 / 28

slide-74
SLIDE 74

BMK method - Extension for negative time

The solution of 8 > > > > > < > > > > > : vt + a(x)vxxx + (1 + ys)vx + (yx)av = f a

σ,

8x 2 (0, L), t 2 (T, T), v(t, 0) = 0, v(t, L) = 0, 8t 2 (T, T), vx(t, L) = ( 0, 8t 2 (0, T), zx(0, t), 8t 2 (T, 0). v(x, 0) = σ(x)y0,xxx(x), 8x 2 (0, L). satisfies a Carleman estimate which allows to prove kv(x, 0)kX  CkfσkY + (boundary terms) with C small.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 23 / 28

slide-75
SLIDE 75

Carleman estimates - Lv = vt + avxxx = f

Any v 2 L2(T, T; H3 \ H1

0(0, L)) and a weight function φ(x, t) = β(x) (T +t)(T −t).

w = e−λφv, and Lφw = e−λφL(eλφw) where λ is a large parameter to be chosen later. The obtained Carleman estimate is an inequality like λ5kwk2

L2

φ + λ3kwxk2

L2

φ + λkwxxk2

L2

φ + 1

λkwtk2

L2

φ  C kLφwk2

L2

φ + B.D.(w)

Note that w(T, 0) = 0, and therefore kw(0, x)k2

L2

φ = 2

Z 0

−T

Z wwt  ✓ λ Z Z |w|2 ◆1/2 ✓ 1 λ Z Z |wt|2 ◆1/2  1 λ2 ✓ λ5 Z Z |w|2 ◆1/2 ⇣ kLφwk2

L2

φ + B.D.(w)

⌘1/2  1 λ2 ⇣ kLφwk2

L2

φ + B.D.(w)

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 24 / 28

slide-76
SLIDE 76

Carleman estimates - Lv = vt + avxxx = f

Any v 2 L2(T, T; H3 \ H1

0(0, L)) and a weight function φ(x, t) = β(x) (T +t)(T −t).

w = e−λφv, and Lφw = e−λφL(eλφw) where λ is a large parameter to be chosen later. The obtained Carleman estimate is an inequality like λ5kwk2

L2

φ + λ3kwxk2

L2

φ + λkwxxk2

L2

φ + 1

λkwtk2

L2

φ  C kLφwk2

L2

φ + B.D.(w)

Note that w(T, 0) = 0, and therefore kw(0, x)k2

L2

φ = 2

Z 0

−T

Z wwt  ✓ λ Z Z |w|2 ◆1/2 ✓ 1 λ Z Z |wt|2 ◆1/2  1 λ2 ✓ λ5 Z Z |w|2 ◆1/2 ⇣ kLφwk2

L2

φ + B.D.(w)

⌘1/2  1 λ2 ⇣ kLφwk2

L2

φ + B.D.(w)

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 24 / 28

slide-77
SLIDE 77

Carleman estimates - Lv = vt + avxxx = f

Any v 2 L2(T, T; H3 \ H1

0(0, L)) and a weight function φ(x, t) = β(x) (T +t)(T −t).

w = e−λφv, and Lφw = e−λφL(eλφw) where λ is a large parameter to be chosen later. The obtained Carleman estimate is an inequality like λ5kwk2

L2

φ + λ3kwxk2

L2

φ + λkwxxk2

L2

φ + 1

λkwtk2

L2

φ  C kLφwk2

L2

φ + B.D.(w)

Note that w(T, 0) = 0, and therefore kw(0, x)k2

L2

φ = 2

Z 0

−T

Z wwt  ✓ λ Z Z |w|2 ◆1/2 ✓ 1 λ Z Z |wt|2 ◆1/2  1 λ2 ✓ λ5 Z Z |w|2 ◆1/2 ⇣ kLφwk2

L2

φ + B.D.(w)

⌘1/2  1 λ2 ⇣ kLφwk2

L2

φ + B.D.(w)

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 24 / 28

slide-78
SLIDE 78

Carleman estimates - Lv = vt + avxxx = f

Any v 2 L2(T, T; H3 \ H1

0(0, L)) and a weight function φ(x, t) = β(x) (T +t)(T −t).

w = e−λφv, and Lφw = e−λφL(eλφw) where λ is a large parameter to be chosen later. The obtained Carleman estimate is an inequality like λ5kwk2

L2

φ + λ3kwxk2

L2

φ + λkwxxk2

L2

φ + 1

λkwtk2

L2

φ  C kLφwk2

L2

φ + B.D.(w)

Note that w(T, 0) = 0, and therefore kw(0, x)k2

L2

φ = 2

Z 0

−T

Z wwt  ✓ λ Z Z |w|2 ◆1/2 ✓ 1 λ Z Z |wt|2 ◆1/2  1 λ2 ✓ λ5 Z Z |w|2 ◆1/2 ⇣ kLφwk2

L2

φ + B.D.(w)

⌘1/2  1 λ2 ⇣ kLφwk2

L2

φ + B.D.(w)

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 24 / 28

slide-79
SLIDE 79

Carleman estimates - Lv = vt + avxxx = f

Any v 2 L2(T, T; H3 \ H1

0(0, L)) and a weight function φ(x, t) = β(x) (T +t)(T −t).

w = e−λφv, and Lφw = e−λφL(eλφw) where λ is a large parameter to be chosen later. The obtained Carleman estimate is an inequality like λ5kwk2

L2

φ + λ3kwxk2

L2

φ + λkwxxk2

L2

φ + 1

λkwtk2

L2

φ  C kLφwk2

L2

φ + B.D.(w)

Note that w(T, 0) = 0, and therefore kw(0, x)k2

L2

φ = 2

Z 0

−T

Z wwt  ✓ λ Z Z |w|2 ◆1/2 ✓ 1 λ Z Z |wt|2 ◆1/2  1 λ2 ✓ λ5 Z Z |w|2 ◆1/2 ⇣ kLφwk2

L2

φ + B.D.(w)

⌘1/2  1 λ2 ⇣ kLφwk2

L2

φ + B.D.(w)

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 24 / 28

slide-80
SLIDE 80

Carleman estimates for KdV.

Rosier [2004]. Null control of the surface of a water wave by means of a wavemaker at the left end-point. Glass-Guerrero [2008]. Cost of the null control of KdV by means of a control at the left end-point. Both papers prove Carleman estimates with one parameter λ > 0. For us, it is important a second parameter. Look at one dominating term: λ5 ZZ φ4

x(axφx 5aφxx + 4a2φxx)|w|2

This impose bad conditions of kind kax/akL∞  M. Solution is to choose φ such that φxx ⇡ s2ϕ with a second parameter s > 0.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 25 / 28

slide-81
SLIDE 81

Carleman estimates for KdV.

Rosier [2004]. Null control of the surface of a water wave by means of a wavemaker at the left end-point. Glass-Guerrero [2008]. Cost of the null control of KdV by means of a control at the left end-point. Both papers prove Carleman estimates with one parameter λ > 0. For us, it is important a second parameter. Look at one dominating term: λ5 ZZ φ4

x(axφx 5aφxx + 4a2φxx)|w|2

This impose bad conditions of kind kax/akL∞  M. Solution is to choose φ such that φxx ⇡ s2ϕ with a second parameter s > 0.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 25 / 28

slide-82
SLIDE 82

Carleman estimates for KdV.

Rosier [2004]. Null control of the surface of a water wave by means of a wavemaker at the left end-point. Glass-Guerrero [2008]. Cost of the null control of KdV by means of a control at the left end-point. Both papers prove Carleman estimates with one parameter λ > 0. For us, it is important a second parameter. Look at one dominating term: λ5 ZZ φ4

x(axφx 5aφxx + 4a2φxx)|w|2

This impose bad conditions of kind kax/akL∞  M. Solution is to choose φ such that φxx ⇡ s2ϕ with a second parameter s > 0.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 25 / 28

slide-83
SLIDE 83

Carleman estimates for KdV.

Rosier [2004]. Null control of the surface of a water wave by means of a wavemaker at the left end-point. Glass-Guerrero [2008]. Cost of the null control of KdV by means of a control at the left end-point. Both papers prove Carleman estimates with one parameter λ > 0. For us, it is important a second parameter. Look at one dominating term: λ5 ZZ φ4

x(axφx 5aφxx + 4a2φxx)|w|2

This impose bad conditions of kind kax/akL∞  M. Solution is to choose φ such that φxx ⇡ s2ϕ with a second parameter s > 0.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 25 / 28

slide-84
SLIDE 84

Carleman estimates for KdV.

Rosier [2004]. Null control of the surface of a water wave by means of a wavemaker at the left end-point. Glass-Guerrero [2008]. Cost of the null control of KdV by means of a control at the left end-point. Both papers prove Carleman estimates with one parameter λ > 0. For us, it is important a second parameter. Look at one dominating term: λ5 ZZ φ4

x(axφx 5aφxx + 4a2φxx)|w|2

This impose bad conditions of kind kax/akL∞  M. Solution is to choose φ such that φxx ⇡ s2ϕ with a second parameter s > 0.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 25 / 28

slide-85
SLIDE 85

Carleman estimates for KdV.

Rosier [2004]. Null control of the surface of a water wave by means of a wavemaker at the left end-point. Glass-Guerrero [2008]. Cost of the null control of KdV by means of a control at the left end-point. Both papers prove Carleman estimates with one parameter λ > 0. For us, it is important a second parameter. Look at one dominating term: λ5 ZZ φ4

x(axφx 5aφxx + 4a2φxx)|w|2

This impose bad conditions of kind kax/akL∞  M. Solution is to choose φ such that φxx ⇡ s2ϕ with a second parameter s > 0.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 25 / 28

slide-86
SLIDE 86

Main Result.

8 > > < > > : yt + a(x)yxxx + yx + yyx = g, 8(x, t) 2 (0, L) ⇥ (0, T), y(t, 0) = g0(t), y(t, L) = g1(t), 8t 2 (0, T), yx(t, L) = g2(t), 8t 2 (0, T), y(0, x) = y0(x), 8x 2 (0, L). Data (g, gk, y0) fixed and regular enough!

Theorem (M, Baudouin, Cerpa, Crepeau; JIIP 2013)

Let |y0,xxx(x)| δ > 0, symmetric wrt L/2. Let Σ = n a symmetric wrt L/2 . a a0 > 0, kakW 3,∞  M1, and ky(a)kW 1,∞(Q)  M2

  • There exists a constant C = C(L, T, a0, M1, M2, δ) > 0 such that for any a, ˜

a 2 Σ: Cka ˜ akL2(0,L)  kyx(t, 0) ˜ yx(t, 0)kH1(0,T ) + kyxx(t, 0) ˜ yxx(t, 0)kH1(0,T ) + kyxx(t, L) ˜ yxx(t, L)kH1(0,T )

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 26 / 28

slide-87
SLIDE 87

Future work

Deal with the original model: yt(t, x) + h2(x)yxxx(t, x) + ( p h(x)y(t, x))x + 1 p h(x) y(t, x)yx(t, x) = f. (8) Remove the symmetry hypothesis. Reconstruction: Follow ideas of a work of Baudouin-de Buhan-Ervedoza, where is proposed a constructive algorithm to rebuild the potential in a wave equation.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 27 / 28

slide-88
SLIDE 88

Future work

Deal with the original model: yt(t, x) + h2(x)yxxx(t, x) + ( p h(x)y(t, x))x + 1 p h(x) y(t, x)yx(t, x) = f. (8) Remove the symmetry hypothesis. Reconstruction: Follow ideas of a work of Baudouin-de Buhan-Ervedoza, where is proposed a constructive algorithm to rebuild the potential in a wave equation.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 27 / 28

slide-89
SLIDE 89

Future work

Deal with the original model: yt(t, x) + h2(x)yxxx(t, x) + ( p h(x)y(t, x))x + 1 p h(x) y(t, x)yx(t, x) = f. (8) Remove the symmetry hypothesis. Reconstruction: Follow ideas of a work of Baudouin-de Buhan-Ervedoza, where is proposed a constructive algorithm to rebuild the potential in a wave equation.

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 27 / 28

slide-90
SLIDE 90

Muito obrigado!

Alberto Mercado (UTFSM) Inverse Problems for dispersive PDEs IMPA, 2013 28 / 28