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D ( 1)- quadruples Mihai Cipu Report on D ( 1)-quadruples Prologue Terminology Main problems Existence A conjecture Mihai Cipu Classical approach to find quadi Starting point IMAR, Bucharest, ROMANIA Alternative approach


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SLIDE 1

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Report on D(−1)-quadruples

Mihai Cipu

IMAR, Bucharest, ROMANIA

Representation Theory XVI Dubrovnik, 28th June 2019 (joint work with N. C. Bonciocat and M. Mignotte)

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SLIDE 2

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Outline

1 Prologue

Terminology

2 Main problems

Existence A conjecture

3 Classical approach to find quadi

Starting point

4 Alternative approach

Different viewpoint A particular case The general case

5 References

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SLIDE 3

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Terminology

D(n) − m-set = set of m positive integers, the product

  • f any two being a perfect square minus n
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SLIDE 4

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Terminology

D(n) − m-set = set of m positive integers, the product

  • f any two being a perfect square minus n

n-pair = D(n) − 2-set

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SLIDE 5

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Terminology

D(n) − m-set = set of m positive integers, the product

  • f any two being a perfect square minus n

n-pair = D(n) − 2-set n-triple = D(n) − 3-set

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SLIDE 6

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Terminology

D(n) − m-set = set of m positive integers, the product

  • f any two being a perfect square minus n

n-pair = D(n) − 2-set n-triple = D(n) − 3-set n-quadruple = D(n) − 4-set

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SLIDE 7

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Terminology

D(n) − m-set = set of m positive integers, the product

  • f any two being a perfect square minus n

n-pair = D(n) − 2-set n-triple = D(n) − 3-set n-quadruple = D(n) − 4-set n-quintuple = D(n) − 5-set

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SLIDE 8

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Terminology

D(n) − m-set = set of m positive integers, the product

  • f any two being a perfect square minus n

n-pair = D(n) − 2-set n-triple = D(n) − 3-set n-quadruple = D(n) − 4-set n-quintuple = D(n) − 5-set n = −1 = ⇒ pardi, tridi, quadi

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SLIDE 9

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Fundamental question

How large a D(n) − m-set can be?

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SLIDE 10

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Fundamental question

How large a D(n) − m-set can be? Infinite if n = 0

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SLIDE 11

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Fundamental question

How large a D(n) − m-set can be? Infinite if n = 0 From now on n = 0

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SLIDE 12

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Fundamental question

How large a D(n) − m-set can be? Infinite if n = 0 From now on n = 0 Dujella 2004 Any D(n) − m-set has m ≤ 31 if 1 ≤ |n| ≤ 400 m < 15.476 log |n| if |n| > 400

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SLIDE 13

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Better answers

Brown, Gupta-Singh, Mohanty-Ramasamy 1985 There are no D(4k + 2)-quadruples

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SLIDE 14

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Better answers

Brown, Gupta-Singh, Mohanty-Ramasamy 1985 There are no D(4k + 2)-quadruples Dujella 2004 There are no D(1)-sextuples and only finitely many D(1)-quintuples

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SLIDE 15

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Better answers

Brown, Gupta-Singh, Mohanty-Ramasamy 1985 There are no D(4k + 2)-quadruples Dujella 2004 There are no D(1)-sextuples and only finitely many D(1)-quintuples Dujella-Luca 2005 Any D(n) − m-set with n prime has m < 3 · 2168

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SLIDE 16

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Better answers

Brown, Gupta-Singh, Mohanty-Ramasamy 1985 There are no D(4k + 2)-quadruples Dujella 2004 There are no D(1)-sextuples and only finitely many D(1)-quintuples Dujella-Luca 2005 Any D(n) − m-set with n prime has m < 3 · 2168 Dujella-Fuchs 2005 There is no D(−1)-quadruple whose smallest element is ≥ 2. Hence, there is no D(−1)-quintuple

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SLIDE 17

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Better answers

Brown, Gupta-Singh, Mohanty-Ramasamy 1985 There are no D(4k + 2)-quadruples Dujella 2004 There are no D(1)-sextuples and only finitely many D(1)-quintuples Dujella-Luca 2005 Any D(n) − m-set with n prime has m < 3 · 2168 Dujella-Fuchs 2005 There is no D(−1)-quadruple whose smallest element is ≥ 2. Hence, there is no D(−1)-quintuple Dujella-Filipin-Fuchs 2007 There are only finitely many D(−1)-quadruples

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SLIDE 18

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Very recent results

He-Togb´ e-Ziegler 2019 There is no D(1)-quintuple

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SLIDE 19

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Very recent results

He-Togb´ e-Ziegler 2019 There is no D(1)-quintuple Bliznac Trebjeˇ sanin-Filipin 2019 There is no D(4)-quintuple

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SLIDE 20

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

A conjecture

Dujella 1993 if n ∈ S := {−4, −3, −1, 3, 5, 12, 20} and n = 4k + 2 then there exists at least one D(n)-quadruple

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SLIDE 21

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

A conjecture

Dujella 1993 if n ∈ S := {−4, −3, −1, 3, 5, 12, 20} and n = 4k + 2 then there exists at least one D(n)-quadruple Conjecture for n ∈ S does not exist D(n)-quadruples

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SLIDE 22

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

How to find D(−1)-sets

Prolongation: start with a pair, extend it to a triple, then to a quadruple . . .

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SLIDE 23

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

How to find D(−1)-sets

Prolongation: start with a pair, extend it to a triple, then to a quadruple . . . Prolongation to a quadruple requires to solve a system

  • f three generalized Pell equations
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SLIDE 24

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

How to find D(−1)-sets

Prolongation: start with a pair, extend it to a triple, then to a quadruple . . . Prolongation to a quadruple requires to solve a system

  • f three generalized Pell equations

Throughout {1, b, c, d} will be a quadi with 1 < b < c < d

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SLIDE 25

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

How to find D(−1)-sets

Prolongation: start with a pair, extend it to a triple, then to a quadruple . . . Prolongation to a quadruple requires to solve a system

  • f three generalized Pell equations

Throughout {1, b, c, d} will be a quadi with 1 < b < c < d r, s, t are the positive integers defined by b − 1 = r 2, c − 1 = s2, bc − 1 = t2

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D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Existence of quadis

∃ D(−1)-quadruples ⇐ ⇒ the system z2 − cx2 = c − 1, bz2 − cy 2 = c − b, y 2 − bx2 = b − 1 is solvable in positive integers

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D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Existence of quadis

∃ D(−1)-quadruples ⇐ ⇒ the system z2 − cx2 = c − 1, bz2 − cy 2 = c − b, y 2 − bx2 = b − 1 is solvable in positive integers ⇐ ⇒ z = vm = wn, where the integer sequences (vp)p≥0, (wp)p≥0 are given by explicit formulæ vp = s 2

  • (s + √c)2p + (s − √c)2p

, wp = s √ b + ρr√c 2 √ b (t + √ bc)2p + s √ b − ρr√c 2 √ b (t − √ bc)2p for some fixed ρ ∈ {−1, 1}

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SLIDE 28

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Existence of quadis

∃ D(−1)-quadruples ⇐ ⇒ the system z2 − cx2 = c − 1, bz2 − cy 2 = c − b, y 2 − bx2 = b − 1 is solvable in positive integers ⇐ ⇒ z = vm = wn, where the integer sequences (vp)p≥0, (wp)p≥0 are given by explicit formulæ vp = s 2

  • (s + √c)2p + (s − √c)2p

, wp = s √ b + ρr√c 2 √ b (t + √ bc)2p + s √ b − ρr√c 2 √ b (t − √ bc)2p for some fixed ρ ∈ {−1, 1} Similarly for x, y

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SLIDE 29

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Classical approach

Establish inequalities between b, c, m, n by transforming equalities of the form z = vm, z = wn into congruences

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SLIDE 30

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Classical approach

Establish inequalities between b, c, m, n by transforming equalities of the form z = vm, z = wn into congruences Associate a linear form in three logarithms to vm = wn and use Baker’s theory to obtain absolute bounds on c

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SLIDE 31

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Classical approach

Establish inequalities between b, c, m, n by transforming equalities of the form z = vm, z = wn into congruences Associate a linear form in three logarithms to vm = wn and use Baker’s theory to obtain absolute bounds on c Long computations give necessary conditions for the existence of D(−1)-quadruples, including b > 1.024 · 1013 and max{1014b, b1.16} < c < min{9.6 b4, 10148}

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SLIDE 32

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Where to search for quadis

100 200 300 400 500 2 3 4 5 6 log10c logbc

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SLIDE 33

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Novel approach

Featuring the positive parameter f = t − rs

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SLIDE 34

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Novel approach

Featuring the positive parameter f = t − rs Squaring f + rs = t, one gets r 2 + s2 = 2frs + f 2 (*) Our approach is essentially a study of solutions in positive integers to equation (*) in its various disguises, starting with (s − rf )2 − (f 2 − 1)r 2 = f 2

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SLIDE 35

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

New results

Theorem There are no D(−1)–quadruples with f = gcd(r, s). In particular, there exists no D(−1)–quadruple for which the corresponding f has no prime divisor congruent to 1 modulo 4.

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SLIDE 36

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

New results

Theorem There are no D(−1)–quadruples with f = gcd(r, s). In particular, there exists no D(−1)–quadruple for which the corresponding f has no prime divisor congruent to 1 modulo 4. Theorem If c ≥ b2 then c > 16b3.

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SLIDE 37

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Properties in the special case

When gcd(r, s) = f , the cardinal equation has positive solutions r = f (γk − γk) γ − γ , s = f (γk+1 − γk+1) γ − γ , k ∈ N, with γ = f + √ f 2 − 1 and γ = f − √ f 2 − 1

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SLIDE 38

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Properties in the special case

When gcd(r, s) = f , the cardinal equation has positive solutions r = f (γk − γk) γ − γ , s = f (γk+1 − γk+1) γ − γ , k ∈ N, with γ = f + √ f 2 − 1 and γ = f − √ f 2 − 1 Always γ2k−1 < b and c b < γ2

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SLIDE 39

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Properties in the special case

When gcd(r, s) = f , the cardinal equation has positive solutions r = f (γk − γk) γ − γ , s = f (γk+1 − γk+1) γ − γ , k ∈ N, with γ = f + √ f 2 − 1 and γ = f − √ f 2 − 1 Always γ2k−1 < b and c b < γ2 For k ≥ 2 it holds γ2 − 1 2 < c b

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SLIDE 40

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

First step in the proof of Theorem A

No quadi has c > b3 in the special case.

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SLIDE 41

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

First step in the proof of Theorem A

No quadi has c > b3 in the special case. b3 ≤ c = ⇒ γ4k−2 < b2 ≤ c b < γ2

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SLIDE 42

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

First step in the proof of Theorem A

No quadi has c > b3 in the special case. b3 ≤ c = ⇒ γ4k−2 < b2 ≤ c b < γ2 = ⇒ k < 1

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SLIDE 43

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

First step in the proof of Theorem A

No quadi has c > b3 in the special case. b3 ≤ c = ⇒ γ4k−2 < b2 ≤ c b < γ2 = ⇒ k < 1 Experimental result: no quadi has f ≤ 107. In the special case no quadi has f ≤ 109

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SLIDE 44

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Second step in the proof of Theorem A

c ≥ b2 = ⇒ k = 1 = ⇒ b = f 2 + 1, c = 4f 4 + 1, t = 2f 3 + f

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SLIDE 45

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Second step in the proof of Theorem A

c ≥ b2 = ⇒ k = 1 = ⇒ b = f 2 + 1, c = 4f 4 + 1, t = 2f 3 + f vm ≡ 2f 2 (mod 8f 6) wn ≡ 2(ρn + 1)f 2 + 4n3 + 8n 3 ρ + 4n2

  • f 4 (mod 8f 6)

for suitable ρ ∈ {±1}

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SLIDE 46

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Second step in the proof of Theorem A

c ≥ b2 = ⇒ k = 1 = ⇒ b = f 2 + 1, c = 4f 4 + 1, t = 2f 3 + f vm ≡ 2f 2 (mod 8f 6) wn ≡ 2(ρn + 1)f 2 + 4n3 + 8n 3 ρ + 4n2

  • f 4 (mod 8f 6)

for suitable ρ ∈ {±1} Observe that n is even and use this to deduce n = 4f 2u for some positive integer u. Come back to the congruence to get u ≡ 0 (mod f 2), so that n ≥ 4f 4.

slide-47
SLIDE 47

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Second step in the proof of Theorem A

c ≥ b2 = ⇒ k = 1 = ⇒ b = f 2 + 1, c = 4f 4 + 1, t = 2f 3 + f vm ≡ 2f 2 (mod 8f 6) wn ≡ 2(ρn + 1)f 2 + 4n3 + 8n 3 ρ + 4n2

  • f 4 (mod 8f 6)

for suitable ρ ∈ {±1} Observe that n is even and use this to deduce n = 4f 2u for some positive integer u. Come back to the congruence to get u ≡ 0 (mod f 2), so that n ≥ 4f 4. This inequality and Matveev’s theorem yield f < 11300

slide-48
SLIDE 48

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Third step in the proof of Theorem A

b3/2 ≤ c < b2 = ⇒ k = 2

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SLIDE 49

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Third step in the proof of Theorem A

b3/2 ≤ c < b2 = ⇒ k = 2 Now it is preferable to use y = Un = ul, where ul+2 = (4b − 2)ul+1 − ul, u0 = r, u1 = (2b − 1)r, Un+2 = (4bc − 2)Un+1 − Un, U0 = ρr, U1 = (2bc − 1)ρr + 2bst.

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SLIDE 50

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Third step in the proof of Theorem A

b3/2 ≤ c < b2 = ⇒ k = 2 Now it is preferable to use y = Un = ul, where ul+2 = (4b − 2)ul+1 − ul, u0 = r, u1 = (2b − 1)r, Un+2 = (4bc − 2)Un+1 − Un, U0 = ρr, U1 = (2bc − 1)ρr + 2bst. The congruence mod r 2 gives n ≥ r − 2 = 2(f 2 − 1) > 1.999f 2. From f > 109 it results n > 1018, in contradiction with a previous result

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SLIDE 51

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

The general case

Write f = f1f2, with f1 the product of all the prime divisors of f which are congruent to 1 modulo 4, multiplicity included. From now on f1 ≥ 5

slide-52
SLIDE 52

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

The general case

Write f = f1f2, with f1 the product of all the prime divisors of f which are congruent to 1 modulo 4, multiplicity included. From now on f1 ≥ 5 Then r = f2u, s = f2v, with (v − fu)2 − (f 2 − 1)u2 = f 2

1 .

slide-53
SLIDE 53

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

The general case

Write f = f1f2, with f1 the product of all the prime divisors of f which are congruent to 1 modulo 4, multiplicity included. From now on f1 ≥ 5 Then r = f2u, s = f2v, with (v − fu)2 − (f 2 − 1)u2 = f 2

1 .

r = f2

  • ε γk − ε γk

γ − γ , s = f2

  • ε γk+1 − ε γk+1

γ − γ , k ≥ 0, with ε = v0 + u0 √ f 2 − 1 a fundamental solution to the generalized Pell equation V 2 − (f 2 − 1)U2 = f 2

1 and

ε = v0 − u0 √ f 2 − 1.

slide-54
SLIDE 54

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Properties in the general case

Always γ2k < b and c b < γ2

slide-55
SLIDE 55

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Properties in the general case

Always γ2k < b and c b < γ2 For k ≥ 1 it holds γ2 − 1 2 < c b

slide-56
SLIDE 56

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Properties in the general case

Always γ2k < b and c b < γ2 For k ≥ 1 it holds γ2 − 1 2 < c b k = 0 ⇐ ⇒ c ≥ b2

slide-57
SLIDE 57

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Properties in the general case

Always γ2k < b and c b < γ2 For k ≥ 1 it holds γ2 − 1 2 < c b k = 0 ⇐ ⇒ c ≥ b2 For k ≥ 1 it holds f 2 = c 4b

  • .
slide-58
SLIDE 58

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Proof of Theorem B

Theorem If c ≥ b2 then c > 16b3.

slide-59
SLIDE 59

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Proof of Theorem B

Theorem If c ≥ b2 then c > 16b3. As k = 0, one has r = f2u0, s = f2(v0 + fu0), with 1 ≤ v0 < f1

  • f + 1

2 , 0 ≤ |u0| < f1

  • 2(f + 1)
slide-60
SLIDE 60

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Proof of Theorem B

Theorem If c ≥ b2 then c > 16b3. As k = 0, one has r = f2u0, s = f2(v0 + fu0), with 1 ≤ v0 < f1

  • f + 1

2 , 0 ≤ |u0| < f1

  • 2(f + 1)

f 2

1 > 2u2 0f = 2u2 0f1f2 =

⇒ f1 > 2u2

0f2 = 2u0r

= ⇒ f = f1f2 > 2u0rf2 = 2r 2

slide-61
SLIDE 61

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Proof of Theorem B

Theorem If c ≥ b2 then c > 16b3. As k = 0, one has r = f2u0, s = f2(v0 + fu0), with 1 ≤ v0 < f1

  • f + 1

2 , 0 ≤ |u0| < f1

  • 2(f + 1)

f 2

1 > 2u2 0f = 2u2 0f1f2 =

⇒ f1 > 2u2

0f2 = 2u0r

= ⇒ f = f1f2 > 2u0rf2 = 2r 2 Put f = 2r 2 + δ in the cardinal equation to get a quadratic polynomial in s whose discriminant is square only for δ = 2r + 1 or ≥ 4r + 2

slide-62
SLIDE 62

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Where we started from

100 200 300 400 500 2 3 4 5 6 log10c logbc

slide-63
SLIDE 63

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

Where are we right now

30 60 90 120 150 2 3 4 log10c logbc

slide-64
SLIDE 64

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

References 1

  • A. Baker, H. Davenport, The equations 3x2 − 2 = y 2 and

8x2 − 7 = z2, Quart. J. Math. Oxford Ser. (2) 20 (1969), 129–137.

  • M. Bliznac Trebjeˇ

sanin, A. Filipin, Nonexistence of D(4)-quintuples, J. Number Theory, 194 (2019), 170-217.

  • N. C. Bonciocat, M. Cipu, M. Mignotte, On

D(−1)-quadruples, Publ. Math., 56 (2012), 279–304.

  • E. Brown, Sets in which xy + n is always a square, Math.
  • Comp. 45 (1985), 613–620.
  • A. Dujella, There are only finitely many Diophantine

quintuples, J. Reine Angew. Math. 566 (2004), 183–224.

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SLIDE 65

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

References 2

  • A. Dujella, Bounds for the size of sets with the property

D(n), Glas. Mat. Ser. III 39 (2004), 199–205.

  • A. Dujella, Diophantine m-tuples,

http://web.math.pmf.unizg.hr/ duje/dtuples.html

  • A. Dujella, F. Luca, Diophantine m-tuples for primes,
  • Intern. Math. Research Notices 47 (2005), 2913–2940.
  • A. Dujella, A. Filipin, C. Fuchs, Effective solution of the

D(−1)-quadruple conjecture, Acta Arith. 128 (2007), 319–338.

  • A. Dujella, C. Fuchs, Complete solution of a problem of

Diophantus and Euler, J. London Math. Soc. 71 (2005), 33–52.

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SLIDE 66

D(−1)- quadruples Mihai Cipu Prologue

Terminology

Main problems

Existence A conjecture

Classical approach to find quadi

Starting point

Alternative approach

Different viewpoint A particular case The general case

References

References 3

  • A. Filipin, There does not exist a D(4)-sextuple, J. Number

Theory 128 (2008), 1555-1565.

  • A. Filipin, Y. Fujita, The relative upper bound for the third

element of a D(−1)–quadruple, Math. Commun. 17 (2012), 13–19.

  • H. Gupta, K. Singh, On k-triad sequences, Internat. J.
  • Math. Math. Sci. 5 (1985), 799–804.
  • B. He, A. Togb´

e, V. Ziegler, There is no Diophantine quintuple, Trans. Amer. Math. Soc. 371 (2019), 6665–6709.

  • S. P. Mohanty, A. M. S. Ramasamy, On Pr,k sequences,

Fibonacci Quart. 23 (1985), 36–44.