Physics 115
General Physics II Session 33
AC: RL vs RC circuits Phase relationships RLC circuits
6/2/14 1
- R. J. Wilkes
- Email: phy115a@u.washington.edu
- Home page: http://courses.washington.edu/phy115a/
Physics 115 General Physics II Session 33 AC: RL vs RC circuits - - PowerPoint PPT Presentation
Physics 115 General Physics II Session 33 AC: RL vs RC circuits Phase relationships RLC circuits R. J. Wilkes Email: phy115a@u.washington.edu Home page: http://courses.washington.edu/phy115a/ 6/2/14 1 Lecture Schedule Today
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Today
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EXAM 3: Scores back from scan shop, should be posted soon AVG: 66
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2 1 2 2 RMS 2
( ) 2
R R
I P I R R I R ⎛ ⎞ = = = ⎜ ⎟ ⎝ ⎠
RMS
2
R
I I ≡
RMS
2
R
V V ≡
RMS
2
R
≡ E E
2 2 RMS RMS RMS RMS
R
source RMS RMS
“RMS” stands for “root-mean-square”
P is proportional to I2 , so RMS gives us the equivalent DC voltage in terms of power: DC voltage that would dissipate the same power in the resistor (same joules/sec heating effect)
IR and VR = peak values
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For AC current iR through an inductor: The changing current produces an induced EMF = voltage vL. vL = L ΔiL Δt For the AC circuit as shown, Kirchhoff’s loop law tells us: ΔVsource + ΔVL = E − vL = 0
E (t) = E0 cosωt = vL
Notice: the inductor current iL lags the voltage vL by π/2 radians =900, so that iL peaks T/4 later than vL. ΔiL = 1 L " # $ % & 'vLΔt → iL = VL ωL sinωt = VL ωL cos ωt − π 2 " # $ % & ' = IL cos ωt − π 2 " # $ % & '
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“It can be shown” (calculus) that: For inductors, ωL acts like R in Ohm’s Law: I = V/ R à IL=V/(ωL)
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We can then use a form of Ohm’s Law to relate the peak voltage VL, the peak current IL, and the inductive reactance XL in an AC circuit:
For AC circuits we define a resistance-like quantity, measured in ohms, for inductance. It is called the inductive reactance XL:
L
and
L L L L L L
V I V I X X = =
Reactance is not the same as resistance: it depends on f (time variation), and current is not in phase with voltage!
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For AC current iC through a capacitor as shown, the capacitor voltage vC = E = E0 cos ωt = VC cos ωt. The charge on the capacitor will be q = C vC = C VC cos ωt.
cos sin
C C C
dq d i CV t CV t dt dt ω ω ω = = = −
cos( / 2)
C C
i CV t ω ω π = +
So: AC current through a capacitor leads the capacitor voltage by π/2 rad or 900.
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Again, we use a form of Ohm’s Law to relate the peak voltage VC, the peak current IC, and the capacitive reactance XC in an AC circuit:
For AC circuits we also define a resistance-like quantity, measured in ohms, for capacitance. It is called the capacitive reactance XC :
C
and
C C C C C C
V I V I X X = =
Capacitive vs inductive reactance: XL is proportional to f and L XC is proportional to 1/f and 1/C Current leads in capacitors, lags in inductors
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A 10 µF capacitor is connected to a 1000 Hz oscillator with a peak emf of 5.0 V. What is the peak current in the capacitor?
C
(5.0 V) 0.314 A (15.9 )
C C C
V I X = = = Ω
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AC current through a capacitor leads the capacitor voltage by π/ 2 rad or 900. This is analogous to the behavior of the position and velocity of a mass-and- spring harmonic oscillator.
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A charged capacitor is analogous to a stretched spring : stores energy even when the charge is not moving. An inductor resembles a moving mass (remember the flywheel), stores energy only when charge is in motion. Mass + spring = an oscillator. What about a capacitor + inductor? When the switch is closed in the circuit shown in the diagram:
its energy is conserved.
energy must now be stored in the inductor’s B field.
And so on …
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In the circuit above, the frequency is initially f Hz If the generator’s frequency is doubled, to 2f, what happens to the inductor’s reactance XL ?