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Periodic quantum graphs in magnetic fields Differential Operators on - - PowerPoint PPT Presentation

Periodic quantum graphs in magnetic fields Differential Operators on Graphs and Waveguides Graz 2019 Simon Becker Cambridge Consider a lattice Z 2 or the honeycomb lattice. Consider a lattice Z 2 or the honeycomb lattice. We study quantum


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Periodic quantum graphs in magnetic fields Differential Operators on Graphs and Waveguides – Graz 2019

Simon Becker

Cambridge

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Consider a lattice Z2 or the honeycomb lattice.

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Consider a lattice Z2 or the honeycomb lattice. We study quantum graphs with magnetic field and randomness:

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Consider a lattice Z2 or the honeycomb lattice. We study quantum graphs with magnetic field and randomness: B := B dx1 ∧ dx2

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Consider a lattice Z2 or the honeycomb lattice. We study quantum graphs with magnetic field and randomness: B := B dx1 ∧ dx2 = dA, A = 1

2B (−x2 dx1 + x1 dx2) .

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Consider a lattice Z2 or the honeycomb lattice. We study quantum graphs with magnetic field and randomness: B := B dx1 ∧ dx2 = dA, A = 1

2B (−x2 dx1 + x1 dx2) .

(HBλ,ωψ)e := (DBDBψ)e+V ψe+Vωψe, (DBψ)e := −iψ′

e−Aeψe

v ∈ ∂e1 ∩ ∂e2 ⇒ ψe1(v) = ψe2(v),

  • ∂e∋v

(DBψ)e(v) = 0.

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SLIDE 7

Consider a lattice Z2 or the honeycomb lattice. We study quantum graphs with magnetic field and randomness: B := B dx1 ∧ dx2 = dA, A = 1

2B (−x2 dx1 + x1 dx2) .

(HBλ,ωψ)e := (DBDBψ)e+V ψe+Vωψe, (DBψ)e := −iψ′

e−Aeψe

v ∈ ∂e1 ∩ ∂e2 ⇒ ψe1(v) = ψe2(v),

  • ∂e∋v

(DBψ)e(v) = 0. The Peierls substitution P : ψe → eiAetψe transforms the magnetic field into the boundary conditions:

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SLIDE 8

Consider a lattice Z2 or the honeycomb lattice. We study quantum graphs with magnetic field and randomness: B := B dx1 ∧ dx2 = dA, A = 1

2B (−x2 dx1 + x1 dx2) .

(HBλ,ωψ)e := (DBDBψ)e+V ψe+Vωψe, (DBψ)e := −iψ′

e−Aeψe

v ∈ ∂e1 ∩ ∂e2 ⇒ ψe1(v) = ψe2(v),

  • ∂e∋v

(DBψ)e(v) = 0. The Peierls substitution P : ψe → eiAetψe transforms the magnetic field into the boundary conditions: ΛB := P−1HBP, (ΛBψ)e = −ψ′′

e + V ψe

∂±e1 = ∂±e2 =: v = ⇒ eiδ+±Ae1ψe1(v) = eiδ+±Ae2ψe2(v),

  • ∂±e∋v

eiδ+±Aeψ′

e(v) = 0,

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SLIDE 9

Consider a lattice Z2 or the honeycomb lattice. We study quantum graphs with magnetic field and randomness: B := B dx1 ∧ dx2 = dA, A = 1

2B (−x2 dx1 + x1 dx2) .

(HBλ,ωψ)e := (DBDBψ)e+V ψe+Vωψe, (DBψ)e := −iψ′

e−Aeψe

v ∈ ∂e1 ∩ ∂e2 ⇒ ψe1(v) = ψe2(v),

  • ∂e∋v

(DBψ)e(v) = 0. The Peierls substitution P : ψe → eiAetψe transforms the magnetic field into the boundary conditions: ΛB := P−1HBP, (ΛBψ)e = −ψ′′

e + V ψe

∂±e1 = ∂±e2 =: v = ⇒ eiδ+±Ae1ψe1(v) = eiδ+±Ae2ψe2(v),

  • ∂±e∋v

eiδ+±Aeψ′

e(v) = 0,

Br¨ uning–Geyler–Pankrashkin ’07

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SLIDE 10

Roughly speaking, Krein’s formula reduces the study of an

  • perator on the graph to the study of an operator on Z2

(Qh

u)(γ) = 1 4 (τ0 + τ ∗ 0 + τ1 + τ ∗ 1 ) u(γ)

(Qh u)(γ) = 1

3

  • 1 + τ0 + τ1

1 + τ ∗

0 + τ ∗ 1

  • u(γ)
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Roughly speaking, Krein’s formula reduces the study of an

  • perator on the graph to the study of an operator on Z2

(Qh

u)(γ) = 1 4 (τ0 + τ ∗ 0 + τ1 + τ ∗ 1 ) u(γ)

(Qh u)(γ) = 1

3

  • 1 + τ0 + τ1

1 + τ ∗

0 + τ ∗ 1

  • u(γ)

with translations given by τ 0(u)(γ) := u(γ1 − 1, γ2) τ 1(u)(γ) := eihγ1u(γ1, γ2 − 1),

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SLIDE 12

Roughly speaking, Krein’s formula reduces the study of an

  • perator on the graph to the study of an operator on Z2

(Qh

u)(γ) = 1 4 (τ0 + τ ∗ 0 + τ1 + τ ∗ 1 ) u(γ)

(Qh u)(γ) = 1

3

  • 1 + τ0 + τ1

1 + τ ∗

0 + τ ∗ 1

  • u(γ)

with translations given by τ 0(u)(γ) := u(γ1 − 1, γ2) τ 1(u)(γ) := eihγ1u(γ1, γ2 − 1), here h is the flux through a fundamental cell.

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Roughly speaking, Krein’s formula reduces the study of an

  • perator on the graph to the study of an operator on Z2

(Qh

u)(γ) = 1 4 (τ0 + τ ∗ 0 + τ1 + τ ∗ 1 ) u(γ)

(Qh u)(γ) = 1

3

  • 1 + τ0 + τ1

1 + τ ∗

0 + τ ∗ 1

  • u(γ)

with translations given by τ 0(u)(γ) := u(γ1 − 1, γ2) τ 1(u)(γ) := eihγ1u(γ1, γ2 − 1), here h is the flux through a fundamental cell. The above operators are equivalent to operators on Z with c(θ) = 1 + e−2πiθ and v(θ) = 2 cos(2πθ) (Hu)(n) = u(n + 1) + u(n − 1) + v(k + n h

2π)u(n)

(Hu)(n) = c(k + n h

2π)u(n + 1) + c(k + (n − 1) h 2π)u(n − 1)

+ v(k + n h

2π)u(n).

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SLIDE 14

Roughly speaking, Krein’s formula reduces the study of an

  • perator on the graph to the study of an operator on Z2

(Qh

u)(γ) = 1 4 (τ0 + τ ∗ 0 + τ1 + τ ∗ 1 ) u(γ)

(Qh u)(γ) = 1

3

  • 1 + τ0 + τ1

1 + τ ∗

0 + τ ∗ 1

  • u(γ)

with translations given by τ 0(u)(γ) := u(γ1 − 1, γ2) τ 1(u)(γ) := eihγ1u(γ1, γ2 − 1), here h is the flux through a fundamental cell. The above operators are equivalent to operators on Z with c(θ) = 1 + e−2πiθ and v(θ) = 2 cos(2πθ) (Hu)(n) = u(n + 1) + u(n − 1) + v(k + n h

2π)u(n)

(Hu)(n) = c(k + n h

2π)u(n + 1) + c(k + (n − 1) h 2π)u(n − 1)

+ v(k + n h

2π)u(n).

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SLIDE 15

Theorem (Helffer-Sj¨

  • strand+ B.-Han-Jitomirskaya)

The spectrum of Qh

  • r Qh

for

h 2π ∈ Q is band spectrum and a.c..

If

h 2π ∈ R\Q the spectrum is a Cantor set (closed, nowhere dense,

no isolated points) of Lebesgue measure zero and s.c..

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Theorem (Helffer-Sj¨

  • strand+ B.-Han-Jitomirskaya)

The spectrum of Qh

  • r Qh

for

h 2π ∈ Q is band spectrum and a.c..

If

h 2π ∈ R\Q the spectrum is a Cantor set (closed, nowhere dense,

no isolated points) of Lebesgue measure zero and s.c.. The proof- roughly -relies on three main ideas:

◮ Exclude point spectrum from regularity properties of the

density of states.

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Theorem (Helffer-Sj¨

  • strand+ B.-Han-Jitomirskaya)

The spectrum of Qh

  • r Qh

for

h 2π ∈ Q is band spectrum and a.c..

If

h 2π ∈ R\Q the spectrum is a Cantor set (closed, nowhere dense,

no isolated points) of Lebesgue measure zero and s.c.. The proof- roughly -relies on three main ideas:

◮ Exclude point spectrum from regularity properties of the

density of states.

◮ Get estimates on the Lebesgue measure of the spectrum (as a

set) for rational flux

h 2π ∈ Q.

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SLIDE 18

Theorem (Helffer-Sj¨

  • strand+ B.-Han-Jitomirskaya)

The spectrum of Qh

  • r Qh

for

h 2π ∈ Q is band spectrum and a.c..

If

h 2π ∈ R\Q the spectrum is a Cantor set (closed, nowhere dense,

no isolated points) of Lebesgue measure zero and s.c.. The proof- roughly -relies on three main ideas:

◮ Exclude point spectrum from regularity properties of the

density of states.

◮ Get estimates on the Lebesgue measure of the spectrum (as a

set) for rational flux

h 2π ∈ Q. ◮ Prove that the spectrum is H¨

  • lder continuous and

approximate irrationals by rationals.

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Theorem (Helffer-Sj¨

  • strand+ B.-Han-Jitomirskaya)

The spectrum of Qh

  • r Qh

for

h 2π ∈ Q is band spectrum and a.c..

If

h 2π ∈ R\Q the spectrum is a Cantor set (closed, nowhere dense,

no isolated points) of Lebesgue measure zero and s.c.. The proof- roughly -relies on three main ideas:

◮ Exclude point spectrum from regularity properties of the

density of states.

◮ Get estimates on the Lebesgue measure of the spectrum (as a

set) for rational flux

h 2π ∈ Q. ◮ Prove that the spectrum is H¨

  • lder continuous and

approximate irrationals by rationals.

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This is a plot of the spectrum of HB for the hexagonal graph:

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This is a plot of the spectrum of HB for the hexagonal graph:

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We know what kind of spectrum there is, but now we want to know: Where is the spectrum?-Are there spectral gaps?

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We know what kind of spectrum there is, but now we want to know: Where is the spectrum?-Are there spectral gaps?

  • Therefore, we study the density of states
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We know what kind of spectrum there is, but now we want to know: Where is the spectrum?-Are there spectral gaps?

  • Therefore, we study the density of states
  • tr f (HB

λ,ω) := lim R→∞

tr 1B(R)f (HB

λ,ω)

vol(B(R))

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SLIDE 25

We know what kind of spectrum there is, but now we want to know: Where is the spectrum?-Are there spectral gaps?

  • Therefore, we study the density of states
  • tr f (HB

λ,ω) := lim R→∞

tr 1B(R)f (HB

λ,ω)

vol(B(R)) =

  • R

f (E)dρλ(E).

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SLIDE 26

We know what kind of spectrum there is, but now we want to know: Where is the spectrum?-Are there spectral gaps?

  • Therefore, we study the density of states
  • tr f (HB

λ,ω) := lim R→∞

tr 1B(R)f (HB

λ,ω)

vol(B(R)) =

  • R

f (E)dρλ(E). The limit does exist and is a.s. non random-just like the spectrum

  • f HB

λ,ω.

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SLIDE 27

We know what kind of spectrum there is, but now we want to know: Where is the spectrum?-Are there spectral gaps?

  • Therefore, we study the density of states
  • tr f (HB

λ,ω) := lim R→∞

tr 1B(R)f (HB

λ,ω)

vol(B(R)) =

  • R

f (E)dρλ(E). The limit does exist and is a.s. non random-just like the spectrum

  • f HB

λ,ω.

Our next goal is to understand this object in the non-random setting first.

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We know what kind of spectrum there is, but now we want to know: Where is the spectrum?-Are there spectral gaps?

  • Therefore, we study the density of states
  • tr f (HB

λ,ω) := lim R→∞

tr 1B(R)f (HB

λ,ω)

vol(B(R)) =

  • R

f (E)dρλ(E). The limit does exist and is a.s. non random-just like the spectrum

  • f HB

λ,ω.

Our next goal is to understand this object in the non-random setting first. The key property is that for γ := (1, 0) and δ := (0, 1) τ −h

γ τ −h δ

= e−ihτ −h

δ

τ −h

γ .

This is a version of the canonical commutation relation.

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SLIDE 29

We know what kind of spectrum there is, but now we want to know: Where is the spectrum?-Are there spectral gaps?

  • Therefore, we study the density of states
  • tr f (HB

λ,ω) := lim R→∞

tr 1B(R)f (HB

λ,ω)

vol(B(R)) =

  • R

f (E)dρλ(E). The limit does exist and is a.s. non random-just like the spectrum

  • f HB

λ,ω.

Our next goal is to understand this object in the non-random setting first. The key property is that for γ := (1, 0) and δ := (0, 1) τ −h

γ τ −h δ

= e−ihτ −h

δ

τ −h

γ .

This is a version of the canonical commutation relation. In semiclassical Weyl quantization (Opw

h (a)u)(x) := 1 2πh

  • R
  • R e

i h x−y,ξa

x+y

2 , ξ

  • u(y) dy dξ, the

same commutation relation is satisfied by Opw

h

  • eix

Opw

h

  • eiξ

= e−ih Opw

h

  • eiξ

Opw

h

  • eix

.

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SLIDE 30

We know what kind of spectrum there is, but now we want to know: Where is the spectrum?-Are there spectral gaps?

  • Therefore, we study the density of states
  • tr f (HB

λ,ω) := lim R→∞

tr 1B(R)f (HB

λ,ω)

vol(B(R)) =

  • R

f (E)dρλ(E). The limit does exist and is a.s. non random-just like the spectrum

  • f HB

λ,ω.

Our next goal is to understand this object in the non-random setting first. The key property is that for γ := (1, 0) and δ := (0, 1) τ −h

γ τ −h δ

= e−ihτ −h

δ

τ −h

γ .

This is a version of the canonical commutation relation. In semiclassical Weyl quantization (Opw

h (a)u)(x) := 1 2πh

  • R
  • R e

i h x−y,ξa

x+y

2 , ξ

  • u(y) dy dξ, the

same commutation relation is satisfied by Opw

h

  • eix

Opw

h

  • eiξ

= e−ih Opw

h

  • eiξ

Opw

h

  • eix

.

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SLIDE 31

In order to understand (Qh

u)(γ) = 1 4 (τ0 + τ ∗ 0 + τ1 + τ ∗ 1 ) u(γ)

(Qh u)(γ) = 1

3

  • 1 + τ0 + τ1

1 + τ ∗

0 + τ ∗ 1

  • u(γ)
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SLIDE 32

In order to understand (Qh

u)(γ) = 1 4 (τ0 + τ ∗ 0 + τ1 + τ ∗ 1 ) u(γ)

(Qh u)(γ) = 1

3

  • 1 + τ0 + τ1

1 + τ ∗

0 + τ ∗ 1

  • u(γ)

we therefore study ΨDOs

  • Q = 1

2 (cos(x) + cos(hDx))

  • Q = 1

3

  • 1 + e−ix + e−ihDx

1 + eix + eihDx

  • .
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SLIDE 33

In order to understand (Qh

u)(γ) = 1 4 (τ0 + τ ∗ 0 + τ1 + τ ∗ 1 ) u(γ)

(Qh u)(γ) = 1

3

  • 1 + τ0 + τ1

1 + τ ∗

0 + τ ∗ 1

  • u(γ)

we therefore study ΨDOs

  • Q = 1

2 (cos(x) + cos(hDx))

  • Q = 1

3

  • 1 + e−ix + e−ihDx

1 + eix + eihDx

  • .

Why does that help?

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SLIDE 34

In order to understand (Qh

u)(γ) = 1 4 (τ0 + τ ∗ 0 + τ1 + τ ∗ 1 ) u(γ)

(Qh u)(γ) = 1

3

  • 1 + τ0 + τ1

1 + τ ∗

0 + τ ∗ 1

  • u(γ)

we therefore study ΨDOs

  • Q = 1

2 (cos(x) + cos(hDx))

  • Q = 1

3

  • 1 + e−ix + e−ihDx

1 + eix + eihDx

  • .

Why does that help? Taylor expansion of cos(x) + cos(ξ) at (π, π) shows that 1

2(cos(x) + cos(ξ)) = −1 + 1 4

  • x2 + ξ2

+ O(x4 + ξ4).

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SLIDE 35

In order to understand (Qh

u)(γ) = 1 4 (τ0 + τ ∗ 0 + τ1 + τ ∗ 1 ) u(γ)

(Qh u)(γ) = 1

3

  • 1 + τ0 + τ1

1 + τ ∗

0 + τ ∗ 1

  • u(γ)

we therefore study ΨDOs

  • Q = 1

2 (cos(x) + cos(hDx))

  • Q = 1

3

  • 1 + e−ix + e−ihDx

1 + eix + eihDx

  • .

Why does that help? Taylor expansion of cos(x) + cos(ξ) at (π, π) shows that 1

2(cos(x) + cos(ξ)) = −1 + 1 4

  • x2 + ξ2

+ O(x4 + ξ4). Hence, the spectrum should be localized to eigenvalues −1 + nh

2

where n ∈ N.

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SLIDE 36

The determinant of the symbol Q is given by −|1 + eix + eiξ|2/9, and it vanishes at (x, ξ) ∈ Z2

∗ ±

3 , − 2π 3

  • ,

that is, at the Dirac points.

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SLIDE 37

The determinant of the symbol Q is given by −|1 + eix + eiξ|2/9, and it vanishes at (x, ξ) ∈ Z2

∗ ±

3 , − 2π 3

  • ,

that is, at the Dirac points. In small neighbourhoods of ±( 2π

3 , − 2π 3 ) we can make a symplectic

change of variables: y = a(x + ξ), η = b

  • ξ − x ± 4π

3

  • ,

2ab = 1,

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SLIDE 38

The determinant of the symbol Q is given by −|1 + eix + eiξ|2/9, and it vanishes at (x, ξ) ∈ Z2

∗ ±

3 , − 2π 3

  • ,

that is, at the Dirac points. In small neighbourhoods of ±( 2π

3 , − 2π 3 ) we can make a symplectic

change of variables: y = a(x + ξ), η = b

  • ξ − x ± 4π

3

  • ,

2ab = 1, and find that 1 + eix + eiξ = c(η ∓ iy) + O(y2 + η2), 1 + e−ix + e−iξ = c(η ± iy) + O(y2 + η2), where c = 3

1 4 2− 1 2 by choosing a = ±2− 3 4 3− 1 4 and b = ±2− 1 4 3 1 4 .

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SLIDE 39

This is a plot of the first two bands of the spectrum of HB=0 on the hexagonal lattice (cf. Kuchment-Post):

  • 4.5
  • 3.5
  • 2.5

Energy

  • 1.5

2 2

  • 2
  • 2

Dirac point Dirac point

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SLIDE 40

Theorem[B.-Zworski ’18] For I a neighbourhood of a Dirac energy, ED, ∆(ED) = 0, and f ∈ C α

c (I),

α > 0,

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SLIDE 41

Theorem[B.-Zworski ’18] For I a neighbourhood of a Dirac energy, ED, ∆(ED) = 0, and f ∈ C α

c (I),

α > 0,

  • f (E)dρ(E) =

h π |b1 ∧ b2|

  • n∈Z

f (En(h)) + Of Cα(h∞) ∆(En(h)) = κ(nh, h)

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SLIDE 42

Theorem[B.-Zworski ’18] For I a neighbourhood of a Dirac energy, ED, ∆(ED) = 0, and f ∈ C α

c (I),

α > 0,

  • f (E)dρ(E) =

h π |b1 ∧ b2|

  • n∈Z

f (En(h)) + Of Cα(h∞) ∆(En(h)) = κ(nh, h) F(κ(ζ, h)2, h) = ζ, F(ω, h) ∼

  • j=0

hjFj(ω), Fj ∈ C ∞(R),

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SLIDE 43

Theorem[B.-Zworski ’18] For I a neighbourhood of a Dirac energy, ED, ∆(ED) = 0, and f ∈ C α

c (I),

α > 0,

  • f (E)dρ(E) =

h π |b1 ∧ b2|

  • n∈Z

f (En(h)) + Of Cα(h∞) ∆(En(h)) = κ(nh, h) F(κ(ζ, h)2, h) = ζ, F(ω, h) ∼

  • j=0

hjFj(ω), Fj ∈ C ∞(R), F0(ω) = 1 4π

  • γω

ξdx, γω =

  • (x, ξ) ∈ R2/2πZ2 : |1 + eix + eiξ|2

9 = ω

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SLIDE 44
  • f (E)dρ(E) = B

π

  • n∈Z

f (En), En := sign(n)vF

  • |n|B
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SLIDE 45
  • f (E)dρ(E) = B

π

  • n∈Z

f (En), En := sign(n)vF

  • |n|B

F(κ(ζ, h)2, h) = ζ, F(ω, h) ∼

  • j=0

hjFj(ω), Fj ∈ C ∞(R),

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SLIDE 46
  • f (E)dρ(E) = B

π

  • n∈Z

f (En), En := sign(n)vF

  • |n|B

F(κ(ζ, h)2, h) = ζ, F(ω, h) ∼

  • j=0

hjFj(ω), Fj ∈ C ∞(R), F0(ω) = 1 4π

  • γω

ξdx, γω =

  • (x, ξ) ∈ R2/2πZ2 : |1 + eix + eiξ|2

9 = ω

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SLIDE 47
  • f (E)dρ(E) = B

π

  • n∈Z

f (En), En := sign(n)vF

  • |n|B

F(κ(ζ, h)2, h) = ζ, F(ω, h) ∼

  • j=0

hjFj(ω), Fj ∈ C ∞(R), F0(ω) = 1 4π

  • γω

ξdx, γω =

  • (x, ξ) ∈ R2/2πZ2 : |1 + eix + eiξ|2

9 = ω

  • 1.8

2 2.2 2.4 2.6 2.8 3 3.2 Energy 2 4 6 8 10 12 14 16 18 20 Landau level Landau levels

geometric Landau levels perfect cone Landau levels

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SLIDE 48

Transferring everything to the discrete setting:

For operators A ∈ L(ℓ2(Z2, Cn)) given by A(s)(γ) :=

  • β∈Z2

k(γ, β)s(β) with possibly matrix-valued k(γ, β) := δγ, Aδβ ∈ Cn×n,

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SLIDE 49

Transferring everything to the discrete setting:

For operators A ∈ L(ℓ2(Z2, Cn)) given by A(s)(γ) :=

  • β∈Z2

k(γ, β)s(β) with possibly matrix-valued k(γ, β) := δγ, Aδβ ∈ Cn×n, we define

  • trA := lim

R→∞ 1 |B(R)|

  • γ∈Z2∩B(R)

trCn k(γ, γ) provided the limit exists.

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SLIDE 50

Transferring everything to the discrete setting:

For operators A ∈ L(ℓ2(Z2, Cn)) given by A(s)(γ) :=

  • β∈Z2

k(γ, β)s(β) with possibly matrix-valued k(γ, β) := δγ, Aδβ ∈ Cn×n, we define

  • trA := lim

R→∞ 1 |B(R)|

  • γ∈Z2∩B(R)

trCn k(γ, γ) provided the limit exists.The density of states for the discrete

  • perators is
  • trf (Qh) =

h (2)π

  • n∈Z

f (En(h)) + Of Cα(h∞).

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SLIDE 51

Quantum Hall effect

For projections P, Q such that P − Q is compact we define ind(P, Q) := dim ker(P − Q − 1) − dim ker(Q − P − 1).

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SLIDE 52

Quantum Hall effect

For projections P, Q such that P − Q is compact we define ind(P, Q) := dim ker(P − Q − 1) − dim ker(Q − P − 1). Let P = 1I(Qh) be a projection onto an interval I such that ∂I is in a spectral gap of Qh :

◮ Streda: σ = d dh

tr(P).

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SLIDE 53

Quantum Hall effect

For projections P, Q such that P − Q is compact we define ind(P, Q) := dim ker(P − Q − 1) − dim ker(Q − P − 1). Let P = 1I(Qh) be a projection onto an interval I such that ∂I is in a spectral gap of Qh :

◮ Streda: σ = d dh

tr(P).

◮ Bellissard: σ = −i

tr (P[[P, x1], [P, x2]]) .

slide-54
SLIDE 54

Quantum Hall effect

For projections P, Q such that P − Q is compact we define ind(P, Q) := dim ker(P − Q − 1) − dim ker(Q − P − 1). Let P = 1I(Qh) be a projection onto an interval I such that ∂I is in a spectral gap of Qh :

◮ Streda: σ = d dh

tr(P).

◮ Bellissard: σ = −i

tr (P[[P, x1], [P, x2]]) .

◮ Avron, Seiler, Simon: (Uaψ)(x) := e−iθa(x)ψ(x) with

θa(x) := arg(x − a) ∈ (−π, π]. σ =

1 2π ind(P, UaPU∗ a) = 1 2π tr(P − UaPU∗ a)3.

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SLIDE 55

Would like to use σ = d

dh

tr1I(Qh) but only have

  • trf (Qh) =

h (2)π

  • n∈Z

f (En(h)) + Of Cα(h∞).

slide-56
SLIDE 56

Would like to use σ = d

dh

tr1I(Qh) but only have

  • trf (Qh) =

h (2)π

  • n∈Z

f (En(h)) + Of Cα(h∞). There are two problems

◮ Don’t know anything about spectral gaps.

slide-57
SLIDE 57

Would like to use σ = d

dh

tr1I(Qh) but only have

  • trf (Qh) =

h (2)π

  • n∈Z

f (En(h)) + Of Cα(h∞). There are two problems

◮ Don’t know anything about spectral gaps. ◮ It is unclear whether formula is actually differentiable.

slide-58
SLIDE 58

Would like to use σ = d

dh

tr1I(Qh) but only have

  • trf (Qh) =

h (2)π

  • n∈Z

f (En(h)) + Of Cα(h∞). There are two problems

◮ Don’t know anything about spectral gaps. ◮ It is unclear whether formula is actually differentiable.

Way out:

slide-59
SLIDE 59

Would like to use σ = d

dh

tr1I(Qh) but only have

  • trf (Qh) =

h (2)π

  • n∈Z

f (En(h)) + Of Cα(h∞). There are two problems

◮ Don’t know anything about spectral gaps. ◮ It is unclear whether formula is actually differentiable.

Way out:

◮ Use results on spectral theory to conclude the existence of

large spectral gaps between Landau levels.

slide-60
SLIDE 60

Would like to use σ = d

dh

tr1I(Qh) but only have

  • trf (Qh) =

h (2)π

  • n∈Z

f (En(h)) + Of Cα(h∞). There are two problems

◮ Don’t know anything about spectral gaps. ◮ It is unclear whether formula is actually differentiable.

Way out:

◮ Use results on spectral theory to conclude the existence of

large spectral gaps between Landau levels.

◮ Use results from non-commutative geometry:

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SLIDE 61

On ℓ2(Z2) we define the rotation algebra A as the operator norm closure of A :=   T ∈ L(ℓ2(Z2; Cn)); ∃n ∈ N, cγ ∈ C : T =

  • |γ|≤n

cγτ h

γ

   where τ h

δ (f )(γ) := e−i h

2 σsymp(γ,δ)f (γ − δ).

slide-62
SLIDE 62

On ℓ2(Z2) we define the rotation algebra A as the operator norm closure of A :=   T ∈ L(ℓ2(Z2; Cn)); ∃n ∈ N, cγ ∈ C : T =

  • |γ|≤n

cγτ h

γ

   where τ h

δ (f )(γ) := e−i h

2 σsymp(γ,δ)f (γ − δ). From results by

Voiculescu-Pimser and Rieffel it follows that for any projection P ∈ A

  • tr(P) = γ1

tr(id)+γ2 tr(PR) = γ1+γ2 h 2π ∈

  • Z + h

2π mod 1 Z

  • ∩[0, 1]

with γ ∈ Z2.

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SLIDE 63

On ℓ2(Z2) we define the rotation algebra A as the operator norm closure of A :=   T ∈ L(ℓ2(Z2; Cn)); ∃n ∈ N, cγ ∈ C : T =

  • |γ|≤n

cγτ h

γ

   where τ h

δ (f )(γ) := e−i h

2 σsymp(γ,δ)f (γ − δ). From results by

Voiculescu-Pimser and Rieffel it follows that for any projection P ∈ A

  • tr(P) = γ1

tr(id)+γ2 tr(PR) = γ1+γ2 h 2π ∈

  • Z + h

2π mod 1 Z

  • ∩[0, 1]

with γ ∈ Z2. Combining this with the semiclassical analysis shows that σ(HB

) =

n 2π, n ≥ 1

σ(HB

) =

  • 2n+1

n ≥ 0

2n−1 2π

n < 0.

slide-64
SLIDE 64

The proof of delocalization is then based on the following ideas (cf. Germinet, Klein, Schenker):

◮ Show that the Hall conductivity is constant in regions of

strong dynamical localization.

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SLIDE 65

The proof of delocalization is then based on the following ideas (cf. Germinet, Klein, Schenker):

◮ Show that the Hall conductivity is constant in regions of

strong dynamical localization.

◮ Hall conductivity jumps in the non-random setting. Use index

theoretic approach to show universality of Hall conductance under disorder.

slide-66
SLIDE 66

The proof of delocalization is then based on the following ideas (cf. Germinet, Klein, Schenker):

◮ Show that the Hall conductivity is constant in regions of

strong dynamical localization.

◮ Hall conductivity jumps in the non-random setting. Use index

theoretic approach to show universality of Hall conductance under disorder. We conclude:

Theorem

Between each of the Landau levels of the random Schr¨

  • dinger
  • perator HB

λ,ω with B and λ sufficiently small there exists a

mobility edge, i.e. an energy at which delocalization occurs.

slide-67
SLIDE 67
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SLIDE 68

Dynamical delocalization is characterized in terms of Mh

λ,ω(p, ζ, t) =

  • xp/2e−itHh

λ,ωζ(Hh

λ,ω)δ0

  • 2

HS

where ζ ∈ C ∞

c,+(R). We also consider the averaged expression

Mh

λ(p, ζ, T) = 1

T ∞ E

  • Mh

λ,ω(p, ζ, t)

  • e−t/T dt.

The (lower) transport exponent is defined by βh

λ(p, ζ) = lim inf T→∞

log+ Mh

λ(p, ζ, T)

p log(T) , for p > 0, ζ ∈ C ∞

c,+(R)

and from this one defines the p-th local transport exponent βh

λ(p, E) = inf I∋E

sup

ζ∈C ∞

c,+(I)

βh

λ(p, ζ) ∈ [0, 1].

The local lower transport exponent is then defined as βh

λ(E) := sup p>0

βh

λ(p, E).

The exponent βh

λ(E) is a measure of transport associated with the

energy E.

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SLIDE 69

One then defines two complementary regions, the (relatively open) region of dynamical localization or insulator region Σh,DL

λ

=

  • E ∈ R; βh

λ(E) = 0

  • (1)

and the (relatively closed) region of dynamical delocalization or metallic transport Σh,DD

λ

=

  • E ∈ R; βh

λ(E) > 0

  • .

(2)