Path integrals on Riemannian Manifolds
Bruce Driver
Department of Mathematics, 0112 University of California at San Diego, USA http://math.ucsd.edu/∼bdriver Nelder Talk 1. 1pm-2:30pm, Wednesday 29th October, Room 340, Huxley Imperial College, London
Path integrals on Riemannian Manifolds Bruce Driver Department of - - PowerPoint PPT Presentation
Path integrals on Riemannian Manifolds Bruce Driver Department of Mathematics, 0112 University of California at San Diego, USA http://math.ucsd.edu/ bdriver Nelder Talk 1. 1pm-2:30pm, Wednesday 29th October, Room 340, Huxley Imperial
Department of Mathematics, 0112 University of California at San Diego, USA http://math.ucsd.edu/∼bdriver Nelder Talk 1. 1pm-2:30pm, Wednesday 29th October, Room 340, Huxley Imperial College, London
Bruce Driver 2
t ih ˆ
Hψ0
Bruce Driver 3
T i ˆ
Hψ0
i h
T
0 (K.E. - P
.E.)(t)dtψ0 (ω (T)) d vol (ω)
i h
T
0 (K.E.)(t)dtd vol (ω) .
Bruce Driver 4
Hf
0 E(ω(t), ˙
ω(t))dtf(ω(T))Dω”
2m |v|2 + V (x) is the classical energy and
2
T
0 | ˙
ω(t)|2dtDω”.
Bruce Driver 5
n→∞
A ne B n
Bruce Driver 6
2∆;
T n∆/2e−T nV n
n
n(x0, x1)e−T nV (x1) . . . pT n(xn−1, xn)e−T nV (xn)f(xn)dx1 . . . dxn
− n
2T n
|xi−xi−1|2−T
n n
V (xi)
0 [1 2|ω′(s)|2+V (ω(s+))]dsf(ω (T))dmHn (ω)
Bruce Driver 7
nTn k=0 , and
Bruce Driver 8
Hψ0
0 E(ω(t), ˙
ω(t))dtψ0(ω(T))Dω
2
T
0 | ˙
ω(t)|2dtDω”.
Bruce Driver 9
HP(Rd) exp
2
0 | ˙
1 ZP exp
2
0 | ˙
Bruce Driver 10
2 |v|2 + V (x) where V is a nice potential, then
0 V (ω(s))dsdµ (ω)
Hf
|P|→0
0 V (ω(s))dsf (ω (T)) dµ (ω) .
Bruce Driver 11
Bruce Driver 12
Bruce Driver 13
?
Bruce Driver 14
Hψ0
0 E(σ(t), ˙
σ(t))dtψ0(σ(T))Dσ
Bruce Driver 15
0 [1 2| ˙
σ(t)|2+V (σ(t))]dtDσ.
2
1
0 | ˙
σ(t)|2dtψ0 (σ (1)) Dσ.
Bruce Driver 16
Bruce Driver 17
Bruce Driver 18
ε (0)
ε (0)
Bruce Driver 19
0 g
dt , ∇X(t) dt
Bruce Driver 20
Bruce Driver 21
Bruce Driver 22
P(X, Y ) := n
P(X, Y ) := n
Bruce Driver 23
P (σ) = 1
2
1
0 | ˙
σ(t)|2dtd volG∗
P (σ) for ∗ ∈ {0, 1} .
|P|→0
P(σ) =
|P|→0
P(σ)
6
1
0 Scal(σ(s))dsdν(σ)
Bruce Driver 24
Hf(x0) = 1
0 E(σ(t), ˙
σ(t))dtf(σ(T))Dσ
Bruce Driver 25
Bruce Driver 26
P(σ) = 1
2
1
0 | ˙
σ(t)|2dtd volG1|HP(M) (σ) .
|P|→0
P(σ)
6
1
0 Scal(σ(s)) ds
Bruce Driver 27
d
Bruce Driver 28
P(σ) = 1
2
1
0 | ˙
σ(t)|2dtd volG0|HP(M) (σ) ,
|P|→0
P(σ) =
√ 3 20 √ 3
1
0 Scal(σ(s)) dsdν(σ).
Bruce Driver 29
Bruce Driver 30
s 2∆F)(x) = lim
n→∞(Qn s/nF)(x).
P is essentially product measure on M n.
s/nF)(x) ∼
1 6
1
0 S(σ(s))dsF (σ (s)) dν0
P(σ)
Bruce Driver 31
/s(σ)z(s) = k′(s),
n
si(σ)
n
Bruce Driver 32
· (σ) ∈ TσHP(M) such that
s (σ)
s
n
P = 0.
P = − n
P.
Bruce Driver 33
P =
n
P.
|P|→0
P =
|P|→0
n
P =
Bruce Driver 34
s (σ) = //s(σ)h(s) for s ∈ [0, 1].
Bruce Driver 35
Bruce Driver 36
T→0
− T
ds
Bruce Driver 37