Some analytic and geometric aspects of the p -Laplacian on Riemannian - - PowerPoint PPT Presentation
Some analytic and geometric aspects of the p -Laplacian on Riemannian - - PowerPoint PPT Presentation
Some analytic and geometric aspects of the p -Laplacian on Riemannian manifolds Stefano Pigola Universit dellInsubria Convegno Nazionale di Analisi Armonica Bardonecchia, 15-19 Giugno 2009 Prob. 1 Detect the topology of a given Riemannian
- Prob. 1 Detect the topology of a given Riemannian manifold N from the study
- f the space of smooth maps M ! N. Here M is a suitably chosen manifold.
- Prob. 2 Suppose we are given a domain M and a target N. Characterize
homotopically trivial maps among smooth maps M ! N. Recall: two continuous maps f; g : M ! N are homotopic if there is a continuous deformation H : M [0; 1] ! N of H (x; 0) = f (x) into H (x; 1) = g (x) : Special case: g (x) const: = ) f is homotopically trivial. Strategy: Take f : M ! N. Construct a somewhat “canonical” representa- tive u : M ! N in the homotopy class of f. Then u satis…es some system of
- PDEs. Make some analysis on u and derive information on the original f.
A further natural important question arises
- Prob. 3 How many “canonical” representatives u are there in the homotopy
class of f? This last problem will be considered later.
Notation
M, N are Riemannian manifolds, without boundary, either compact or complete. MRiem, MRic are the Riemann and the Ricci (covariant) tensors of M: MRiem
()
q means MRiemx
- ei; ej; ei; ej
()
q (x), 8x 2 M, and for every orthonormal ei; ej 2 TxM. MRic
()
q means MRicx (v; v)
()
q (x), 8x 2 M, and 8v 2 TxM, with jvj = 1.
Canonical representatives and topology via PDEs
- Ex. 1 (1-dimensional domains) Given a compact N, let f : S1 ! N be a
smooth loop. Suppose f is not homotopically trivial. Hilbert = ) 9 : S1 ! N :
Z
S1 j _
j2 = min
Z
S1 j _
j2 : homotopic to f
- :
The loop satis…es the equation := D _ = 0 i.e. is a smooth closed geodesic. Suppose that there are no energy min- imizer geodesic loops (a kind of Liouville type result). Then N has trivial fundamental group 1 (N) = 0. For instance, we have
- Th. 1 (Synge) N compact, orientable, NRiem > 0, dim N = 2m =
) “Liouville” for energy minimizers= ) 1 (N) = 0.
- Ex. 2 (compact m-dim. domains) Let N be a compact target, NRiem
- 0. Let f : M ! N be a smooth map. If M is compact then
Hartman Eells-Sampson =
) 9u : M ! N :
Z
M jduj2 = min
Z
M jdhj2 : h homotopic to f
- :
The minimizer u satis…es the (system of) equations u := div (du) = 0 i.e. u is a harmonic map. Note: u is smooth by elliptic regularity. Suppose, for some choice of M, the validity of a Liouville type result u = 0 = ) u = const: Then f is trivial from the topological viewpoint. For instance, we have the following
- Th. 2 (Eells-Sampson) M compact, MRic 0 and N compact, NRiem
- 0. If MRicp0 > 0 for some p0 2 M =
) Liouville for harmonic maps = ) every smooth f : M ! N is homotopically trivial.
An application: Cartan theorem. N cmpt, NRiem 0. Every element of 1 (N) has in…nite order. Proof (geometric rigidity of groups). Set Zk := Z=kZ and, by contra- diction, suppose 9Zk 1 (N), for some k 2. Consider the lens space M = S3=Zk. Then MRiem > 0 and 1 (M) ' Zk. Fix any injective ho- momorphism : 1 (M) ' Zk ! 1 (N). Since NRiem 0, by the general theory of Eilenberg-McLane spaces = ) there exists a smooth map f : M ! N which induces , say = f#. Applying the Theorem = ) f homotopically trivial = ) f# = 0 = ) is the trivial homomorphism. Contradiction.
- Rem. 1 Similar arguments can be used to prove Preissman thm and its gen-
eralizations such as Lawson-Yau ‡at torus theorems and so on...
- Ex. 3 (Noncompact domains) Let N be compact, NRiem 0. Let f :
M ! N be a smooth map. Suppose M complete, non-compact(!). Prescribe asymptotic behaviour at in…nity, say jd fj 2 L2 (M) (…nite energy). Schoen-Yau = ) 9u : M ! N :
8 > < > :
u = 0 jduj 2 L2 u homotopic to f: Suppose, for some choice of M, the validity of a Liouville type result u = 0 = ) u = const: Then f is trivial from the topological viewpoint. Liouville for MRic 0 was proved by Schoen-Yau. But an amount of negative curvature is allowed
- Th. 3 ([P.-Rigoli-Setti, J.F.A. 2005]) M complete, non-compact, MRic
q (x) with q(x)
1
(M) 0 and N compact, NRiem 0 = ) Liouville for …nite energy harmonic maps = ) every …nite energy smooth f : M ! N is homotopically trivial.
Proof (Sketch). Starting point: Bochner formula+re…ned Kato (RHS) (*) jduj jduj + q (x) jduj2 1 m jr jdujj2 : By assumption q(x)
1
(M) = inf
'2C1
c (M)
R
jr'j2q(x)'2
R
'2
0: (**) FischerColbrie-Schoen = ) 9v > 0 : v + q (x) v = 0: In the spirit of the generalized maximum principle: w = jduj v = ) div
- v2rw
- 0, 0 w 2 L2
M; v2dvol
- :
L2-Liouville for di¤usion operators= ) w = const:
();()
= ) jduj = const: and
MRic 0 =
) jduj = 0.
What about higher energies?
Natural candidates as “canonical” representatives are p-harmonic maps.
- Def. 1 The p-Laplacian (or p-tension …eld) of a manifold valued u : M ! N,
(possibly N = R) is de…ned by pu = div
- jdujp2 du
- ;
where du 2 1 TM; u1TN
- is a 1-form with values in u1TN, jduj is
the Hilbert-Shmidt norm of du, and div is the formal adjoint of the exterior di¤erential d with respect to the L2-inner product on 1.
- Def. 2 A map u : M ! N is p-harmonic if pu = 0: In case N = R, u is
p-subharmonic if pu 0 and p-superharmonic if pu 0.
- Th. 4 (W.S. Wei) Assume that (M; h; iM) is complete and that (N; h; iN)
is compact with NRiem 0. Fix a smooth map f : M ! N with …nite p-energy jd fjp 2 L1 (M), p 2. Then, in the homotopy class of f, there exists a p-harmonic map u : M ! N, u 2 C1;, with jdujp 2 L1 (M). Therefore, to prove that f is homot.-trivial we use the following very general
- Th. 5 ([P.-Veronelli, Geom. Ded. 2009]) Let (M; h; iM) be complete man-
ifold such that MRic q (x). Let (N; h; i) be a complete(!) manifold with
NRiem 0: Let u : M ! N be a p(> 2)-harmonic map, u 2 C1, such that
Z
BR
jduj
p = o (R) ; R ! +1;
for some p p. If Hq(x)
1
(M) 0; for some H > p2=4 ( p 1), then u is constant.
About the proof. Again we start with a Bochner-type inequality jduj jduj + q (x) jduj2 hdu; dui ; where, since u is p-harmonic, u = (p 2) du (r log jduj) : However: (a) The RHS is not so nice as in the case p = 2 (no sign, no re…ned Kato). The previous technique cannot be applied. We need manipulations in integral form and a direct use of the spectral assumption with suitably chosen test-functions. (b) u is not smooth. We use of a version of the approximation procedure by Duzaar-Fuchs. Idea: C1-approximate u on M+ = fjduj > 0g by smooth uk (not p-harmonic). Prove an L
p-Caccioppoli type inequality fo uk. The
Caccioppoli contains an extra term that vanishes as k ! +1. Take limits to get a Caccioppoli for u. Duzaar-Fuchs teach us how to extend this inequality from M+ to M.
Uniqueness of the “canonical” representative
Good targets for uniqueness are complete manifolds N with NRiem 0: Let f : M ! N be a smooth map. Let u : M ! N be a p-harmonic representative in the homotopy class of f. Assume u (M) nondegenerate, i.e., u (M) 6 a geodesic of N. Then, u is unique in the following situations. Linear case p = 2. (a) (Hartman) M; N compact manifolds, NRiem < 0. (b) (Schoen-Yau) M; N complete manifolds, vol (M) < +1, NRiem < 0, and jduj2 2 L1 (M). Nonlinear case p > 1. (a) (S.W. Wei) M; N compact manifolds, NRiem < 0:
- Rem. 2 In the nonlinear situation p 6= 2, the case of complete, non-compact
manifolds M; N is far from being understood. As a …rst attempt in this direction we consider uniqueness in the homotopy class of a constant map. We have the following result in the spirit of Schoen- Yau’s.
- Th. 6 ([P.-Rigoli-Setti, Math. Z. 2008]) Let (M; h; iM) and (N; h; iN) be
complete Riemannian manifolds. Assume that M satis…es the volume growth condition vol(@Br)1 = 2 L
1 p1 (+1) ;
for some p 2, and that N has NRiem 0. If u : (M; h; iM) ! (N; h; iN) is a p-harmonic map homotopic to a constant and with energy density jdujp 2 L1 (M), then u is a constant map.
Schoen-Yau argument, p = 2
Let u : M ! N be a harmonic map (freely) homotopic to a costant map, say c u (x0). To simplify the exposition, assume N simply connected, hence Cartan-Hadamard. Otherwise, lift u to a 1-equivariant harmonic map
e
u : f M ! f N between universal coverings. Consider (x) = distN (u (x) ; c) : M ! R0. Since N is Cartan-Hadamard then (x) is a convex function. Harmonic maps pull-back convex functions to subharmonic functions. Therefore 0. Consider w =
q
1 + 2: Then, w 0. Moreover, jruj2 2 L1 = ) jrwj2 2 L1 (M). Now use a Liouville-type theorem to deduce w const. This implies const., but (x0) = 0, so that u u (x0) :
- Rem. 3 The same proof works for 2 (u; v) with u; v : M ! N homotopic,
harmonic maps, v 6 const.. We then obtain (u; v) const.
p-harmonic case If p 6= 2, Schoen-Yau argument cannot be applied because of the following
- Th. 7 ([Veronelli, preprint 2009]) There exist Riemannian manifolds M, N,
a convex function H : N ! R and a p-harmonic map u : M ! N, for some p > 2, such that H u : M ! R is not p-subharmonic. Both the manifolds and the (smooth) p-harmonic map are rotationally symmet-
- ric. The proof shows that, for every increasing, rotationally symmetric convex
function H, it holds lim infx!1 p (H u) (x) < 0. To overcome the di¢culty we shall pass from function to a vector …eld related to u. This inspires to previous work by [S. Kawai, Geom. Ded. 1999].
Non-linear potential theory and Lq-vector …elds
- Def. 3 (M; h; i) is said to be p-parabolic if for any real-valued function u 2
W 1;p
loc \ C0,
(
pu 0 supM u < +1 = ) u const: Geometric conditions insuring p-parabolicity rely on volume growth assump-
- tions. Let vol(Br) and vol(@Br) denote the volume and the area of the geo-
desic ball and sphere of redius r , respectively. Then (special case of [Rigoli- Setti, Revista Mat. Iberoam. 2001]) r vol(Br) = 2 L
1 p1 (+1) =
)
6( =
1 vol(@Br) = 2 L
1 p1 (+1) =
)
6( = p-parabolicity.
- Th. 8 (V. Gol’dshtein and M. Troyanov) (M; h; i) is p-parabolic if and only
the following holds. Let X be a vector …eld on M such that: (a) jXj 2 L
p p1 (M), (b) 0
R
M divX +1
(c) divX 2 L1
loc (M) and min (divX; 0) = (divX) 2 L1 (M)
Then
R
M divX = 0:
- Cor. 1 Let (M; h; i) be a p-parabolic manifold. If u satis…es pu 0 and
jrujp 2 L1 (M), then u const:
- Rem. 4 Making use of (the p = 2 version of) the above corollary one can
considerably improve the …nite volume condition, vol (M) < +1; in Schoen- Yau uniqueness result.
As a matter of fact, the above corollary is a very special case of the next analytic result.
- Th. 9 ([P.-Veronelli, preprint 2009]) Suppose that, for some p > 2, M is
p-parabolic. Then, for u; v : M ! R, the following comparison principle holds:
(
pu pv jrujp ; jrvjp 2 L1 (M) = ) u v const:
- Rem. 5 In case u; v : M ! Rn one can prove a similar comparison, namely
(
pu = pv jdujp ; jdvjp 2 L1 (M) = ) u v const: Note that, since Rn is contractible, every map is homotopic to a constant. Therefore, in case pu = 0 = pv, the vector-valued comparison follows from
- ur uniqueness Theorem. The proof of the general vector-valued comparison is
- btained using a re…ned version of the next arguments.
- Proof. The following inequality can be derived from some work by Lindqvist
and resambles Mikljukov inequality for the mean curvature operator:
D
jrujp2 ru jrvjp2 rv; ru rv
E
C jru rvjp : Now, take : R ! [0; 1] such that 0 0 and consider the vector …eld X = (u v)
- jrujp2 ru jrvjp2 rv
- :
(a) X 2 L
p p1 (M)
(b) div X C0 (u v) jru rvjp 0. Gol’dshtein-Troyanov criterion = ) div X = 0 = ) 0 (u v) jru rvjp = 0. Set A = u (x0) v (x0) and choose such that (t) = t on t 2 [A"; A+"]: Then r (u v) = 0 on the connected component of the set fA " < u v < A + "g s.t. x0 2 . Whence, it easily follows u v A
- n = M.
Outline of the proof of the uniqueness result
Let u : M ! N be a p-harmonic map with jdujp 2 L1 (M). Assume that u is homotopic to a constant map u (x0) = y0 2 N. Fix e x0 2 f M over x0 and
f
y0 2 f N over y0. Let e u :
f
M ! f N be the lifting of u such that e u (f x0) = f y0. Then, e u is p-harmonic. Moreover, u homotopic to a constant implies the equivariant property
e
u ( (e x)) = e u (e x) , 8 2 1 (M; x0) : Let k 2 C2 ([0; +1)) be such that k0 0, k00 0 and k (t) =
(
At2 + B if 0 t << 1 t if t 1;
for suitable constants A; B > 0. Let r (e y) = distN (e y; f y0) and de…ne h (e y) = k (r (e y)) :
f
N Cartan-Hadamard= ) h convex on f N and strictly convex near f y0. By the equivariant property of e u it is well de…ned the vector …eld on M Xx = jde
xe
ujp2 f
Mre x (h e
u) ; x 2 M where e x is any point in the …ber over x. It can be veri…ed that (a) jXj 2 L
p p1,
(b) divM (X) 0: and, furthermore, (c) divM (X) (x) = 0 = ) jdu (x)jp2 trf
M
n
Hess e
N (h) (de xe
u; de
xe
u)
- = 0.
Now vol(@Br)1 = 2 L
1 p1 (+1) =
) p-parabolicity K.N.R. crit. = )
(a)+(b)
divM (X) 0: By (c) jdu (x)j = 0 on
n
x 2 M : Hess e
N (h) (e
u (e x)) > 0
- :
Since h is strictly convex near f y0, then u must be constant in a neighborhood
- f x0. Thus u is locally constant, hence a constant map.