On partition identities of Capparelli and Primc
Jehanne Dousse
CNRS and Universit´ e Lyon 1
FPSAC 2019 Ljubljana, 4 July 2019
Jehanne Dousse (CNRS) Partition identities of Capparelli and Primc FPSAC 2019 1 / 30
On partition identities of Capparelli and Primc Jehanne Dousse CNRS - - PowerPoint PPT Presentation
On partition identities of Capparelli and Primc Jehanne Dousse CNRS and Universit e Lyon 1 FPSAC 2019 Ljubljana, 4 July 2019 Jehanne Dousse (CNRS) Partition identities of Capparelli and Primc FPSAC 2019 1 / 30 Introduction: partition
CNRS and Universit´ e Lyon 1
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Introduction: partition identities
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Introduction: partition identities
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Introduction: partition identities
k=0(1 − aqk), n ∈ N ∪ {∞}.
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Introduction: partition identities
1qk′
1; qN′ 1)∞ · · · (z′
rqk′
r ; qN′ r )∞
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Introduction: partition identities
∞
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Introduction: partition identities
∞
1 -modules of level 3
1 -modules constructed from
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Introduction: partition identities
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Capparelli’s identity
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Capparelli’s identity
2 :
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Capparelli’s identity
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Capparelli’s identity
D(n; i, j, k)aibjckqn =
aibjq2(
i+1 2 )+2( j+1 2 )(−q; q)i+j(−cqi+j+1, q)∞
(q2; q2)i(q2; q2)j .
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Capparelli’s identity
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Primc’s identity
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Primc’s identity
1 .
1 (q;q)∞ .
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Primc’s identity
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Primc’s identity
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Primc’s identity
k (q; a, b, c, d) (resp. E P k (q; a, b, c, d)) to be the generating
kd(q; a, b, c, d) − G P kc(q; a, b, c, d) = E P kd(q; a, b, c, d)
kc(q; a, b, c, d) + E P ka(q; a, b, c, d) + G P (k−1)c(q; a, b, c, d)).
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Primc’s identity
k (q; a, b, c, d).
kd = 1 − bcq2k
(k−1)d
(k−2)d + adq2k−1
(k−3)d.
kd(q; a, b, c, d)
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Primc’s identity
k→∞ Hk(q; a, 1, c, d) = (−aq; q2)∞(−dq; q2)∞
k→∞ G P k (q; a, 1, c, d) = (−aq; q2)∞(−dq; q2)∞
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Primc’s identity
k (q; a, b, c, d) =
2 )
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Connection between the two identities
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Connection between the two identities
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Connection between the two identities
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Connection between the two identities
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Connection between the two identities
k (q; a, b, c, d) is the generating function for coloured
k (q; a, c, d) is the generating function for coloured
k (q; a, c, d)
k (q; a, c, c, d).
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Connection between the two identities
kd − G C kc = E C kd = dqk
ka + G C (k−1)c
kc − G C ka = E C kc = cqkG C (k−1)c,
ka − G C (k−1)d = E C ka = aqkG C (k−2)d.
kd =
(k−1)d +
(k−2)d
(k−3)d.
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Connection between the two identities
kd =
(k−1)d +
(k−2)d
(k−3)d.
kd(q; a, b, c, d)
kd(q; a, c, d)
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The bijection
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The bijection
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The bijection
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The bijection
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The bijection
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The bijection
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The bijection
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