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Mole Calculations

Slide 3 / 158 Table of Contents

· Avogadro's Number · Molar Mass · Emperical Formula · Molar Volume · Percent Composition

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Avogadro's Number

Slide 5 / 158 Atomic Mass

Recall an atom's atomic mass is equal to the number of protons plus the number of neutrons in the atom.

C 6 12.01

Atomic Number

• r number of

protons (Z) Average Atomic Mass in amu

The unit for atomic mass is amu. Carbon-12 has 6 protons and 6 neutrons. One amu is equal to 1/12 the mass of carbon-12 or approximately the mass of one proton or neutron mass of 1 proton = 1 amu mass of 1 neutron = 1 amu

Slide 6 / 158 Atomic Mass

What if you wanted to measure the mass of one atom in the laboratory? Would it be possible? A single atom has a very small mass. One carbon atom has a mass of about 2.0 x 10-23 grams.

Slide 7 / 158 The Mole

It takes a lot of atoms to give us enough material to directly measure in a lab. Hydrogen has a mass of 1 amu. How many atoms of hydrogen would be needed to make a 1 gram sample of hydrogen?

602,200,000,000,000,000,000,000

The amount 6.02x10

23 is called Avogadro's number or a

mole. How big is a mole?

Slide 8 / 158 Calculating Avogadro's Number

The atomic mass of one carbon atom is 12.01 amu or 2x10-23 g. How many carbon atoms would it take to get 12.01 grams of carbon? Givens: mass of 1 carbon atom = 2x10-23 g total mass of carbon atoms = 12.01 g 2x10-23 g x ? of atoms = 12.01 g ? of atoms 12.01 g = 2x10-23 g ? of atoms 6.02 x 1023 atoms =

Slide 9 / 158 Holy Mole-y!

If you were able to count at the rate

• f 1 million numbers a second, it

would take about 20 billion years to count out one mole!

1 mole of pennies could be distributed to all the currently-living people of the world so that they could spend a million dollars per hour every hour (day and night) for the rest of their lives!

One mole of marbles would cover the entire Earth (oceans included) for a depth of two miles!

Slide 10 / 158 The Mole

A mole is just a grouping of numbers...like dozen, ream, etc. A dozen means 12 of something. A mole means 6.02 x 10

23 of something.

Common Grouping Quantities 1 dozen = 12 1 gross =144 1 ream = 500 1 mole = 6.02 x 1023

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1 How many eggs are in two dozen eggs? A 12 B 24 C 0.0833 D 2 E 6.02 x 10

23

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1 How many eggs are in two dozen eggs? A 12 B 24 C 0.0833 D 2 E 6.02 x 10

23 [This object is a pull tab]

Answer B

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2 How many eggs are in half a dozen eggs? A 12 B 24 C 6 D 0.5 E 6.02 x 1023

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2 How many eggs are in half a dozen eggs? A 12 B 24 C 6 D 0.5 E 6.02 x 1023

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Answer C

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3 How many particles of sand are in 0.5 moles of sand? A 1.5 x 1023 B 3.01 x 1023 C 6.02 x 1023 D 1.2 x 1024 E 6.02 x 1024

1 mole = 6.02 x 1023

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3 How many particles of sand are in 0.5 moles of sand? A 1.5 x 1023 B 3.01 x 1023 C 6.02 x 1023 D 1.2 x 1024 E 6.02 x 1024

1 mole = 6.02 x 1023

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Answer B

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4 How many pieces of gold dust are in 2 moles of gold dust? A 1.5 x 1023 B 3.01 x 1023 C 6.02 x 1023 D 1.2 x 1024 E 6.02 x 1024

1 mole = 6.02 x 1023

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4 How many pieces of gold dust are in 2 moles of gold dust? A 1.5 x 1023 B 3.01 x 1023 C 6.02 x 1023 D 1.2 x 1024 E 6.02 x 1024

1 mole = 6.02 x 1023

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Answer D

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5 How many dozen eggs are in a container of 6 eggs? A 4 B 0.5 C 1 D 2 E 6.02 x 1023

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5 How many dozen eggs are in a container of 6 eggs? A 4 B 0.5 C 1 D 2 E 6.02 x 1023

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Answer C

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6 How many dozen eggs are in a container of 18 eggs? A 1.5 B 3 C 0.67 D 2 E 6.02 x 1023

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6 How many dozen eggs are in a container of 18 eggs? A 1.5 B 3 C 0.67 D 2 E 6.02 x 1023

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Answer A

Slide 17 / 158 Dimensional Analysis

How many eggs are in 47 dozen eggs? The number 47 makes this question a bit more difficult to calculate mentally. In chemistry, it is common practice to use equalities and dimensional analysis to solve problems. Equalities are two quantities that are identical in value but use different units. Examples of equalities include:

1 dozen = 12 1 meter = 1000 millimeters 1 hour = 60 minutes 1 mole = 6.02x1023

Slide 18 / 158 Dimensional Analysis

1 dozen eggs = 12 eggs

How many eggs are in 47 dozen eggs? To solve the above problem:

• 1. Choose the equality with the correct dimensions or units:
• 2. Turn the equality into a fraction.

Since 1 dozen and 12 are equal quantities 1 dozen = 12 can also be written as a fraction:

1 dozen eggs 12 eggs = 1 = 12 eggs = 1 dozen eggs

Slide 19 / 158 Dimensional Analysis

How many eggs are in 47 dozen eggs?

• 3. Start with your given:

Use dimensional analysis! Choose the fraction that has the appropriate dimensions or units to convert from your given dimensions to your unknown dimensions.

• 4. Multiply your given by your chosen fraction and cancel out

the units:

1 dozen 12 eggs

• r

12 eggs 1 dozen

unknown dimension is in the numerator

47 dozen 47 dozen x 12 eggs = 1 dozen 564 eggs

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7 The Milky Way Galaxy may have up to 400 billion (4 x 1014 stars). How many moles of stars does it have? A 1.5 x 10

9

B 6.7 x 10

• 10

C 10 D 0.5 E 6.02 x 1023

1 mole of stars = 6.02 x 1023 stars 6.02 x 1023 stars 1 mole of stars 6.02 x 1023 stars 1 mole of stars

• r

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7 The Milky Way Galaxy may have up to 400 billion (4 x 1014 stars). How many moles of stars does it have? A 1.5 x 10

9

B 6.7 x 10

• 10

C 10 D 0.5 E 6.02 x 1023

1 mole of stars = 6.02 x 1023 stars 6.02 x 1023 stars 1 mole of stars 6.02 x 1023 stars 1 mole of stars

• r

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Answer A

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8 Mathematicians estimate Earth's beaches contain nearly 5.6 x 1021 grains of sand. How many moles of sand are on Earth's beaches? A 1.5 B 9.3 x 10

• 3

C 10.0 D 107.5 E 6.02 x 1023

1 mole = 6.02 x 1023

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8 Mathematicians estimate Earth's beaches contain nearly 5.6 x 1021 grains of sand. How many moles of sand are on Earth's beaches? A 1.5 B 9.3 x 10

• 3

C 10.0 D 107.5 E 6.02 x 1023

1 mole = 6.02 x 1023

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Answer D

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Measuring Matter with Moles

The mole is the SI unit for measuring the amount of particles in a chemical substance.

1 mole of Carbon

One mole (mol) of a substance is 6.02 x 10

23 representative

particles of that substance.

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How many moles of Gold are there in a sample containing 3.01 x 1023 atoms of Gold?

Measuring Matter with Moles

1 mol = 6.02 x1023 atoms Given quantity: 3.01 x 1023 Au atoms 1 mol Au 6.02 x1023 Au atoms Equalities:

• r

1 mol Au 6.02 x1023 Au atoms 3.01 x 1023 Au atoms x 1 mol Au 6.02 x1023 Au atoms = Solve and cancel units: 0.5 mol Au

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9 How many atoms of titanium are in a sample containing 0.5 mole of titanium? A 1.5 x 1023 B 3.01 x 1023 C 6.02 x 1023 D 1.2 x 1024 E 6.02 x 1024

1 mol = 6.02 x 1023

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9 How many atoms of titanium are in a sample containing 0.5 mole of titanium? A 1.5 x 1023 B 3.01 x 1023 C 6.02 x 1023 D 1.2 x 1024 E 6.02 x 1024

1 mol = 6.02 x 1023

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Answer B

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10How many atoms of sodium are in a sample containing 2.0 moles of sodium? A 1.5 x 1023 B 3.01 x 1023 C 6.02 x 1023 D 1.2 x 1024 E 6.02 x 1022

1 mol = 6.02 x 1023

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10How many atoms of sodium are in a sample containing 2.0 moles of sodium? A 1.5 x 1023 B 3.01 x 1023 C 6.02 x 1023 D 1.2 x 1024 E 6.02 x 1022

1 mol = 6.02 x 1023

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Answer D

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11 How many moles of potassium are in a sample

containing 3.01 x 1023 atoms of potassium? A 1.0 B 2.0 C 0.5 D 0.75 E 6.02 x 1024

1 mol = 6.02 x 1023

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11 How many moles of potassium are in a sample

containing 3.01 x 1023 atoms of potassium? A 1.0 B 2.0 C 0.5 D 0.75 E 6.02 x 1024

1 mol = 6.02 x 1023

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Answer C

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12 How many moles of potassium are in a sample containing 1.2 x 1024 atoms of potassium? B 0.50 mol C 1.0 mol D 2.0 mol E 3.0 mol A 0.25 mol

1 mol = 6.02 x 1023

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12 How many moles of potassium are in a sample containing 1.2 x 1024 atoms of potassium? B 0.50 mol C 1.0 mol D 2.0 mol E 3.0 mol A 0.25 mol

1 mol = 6.02 x 1023

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Answer D

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13 How many moles of tungsten atoms are there in a sample containing 1.8 x 1024 atoms of tungsten? A 0.33 mol B 0.50 mol C 1.0 mol D 1.5 mol E 3.0 mol

1 mol = 6.02 x 1023

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13 How many moles of tungsten atoms are there in a sample containing 1.8 x 1024 atoms of tungsten? A 0.33 mol B 0.50 mol C 1.0 mol D 1.5 mol E 3.0 mol

1 mol = 6.02 x 1023

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Answer E

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14 How many moles of silver are there in a pure sample containing 1.5 x 1023 atoms of silver? A 0.10 mol B 0.25 mol C 0.50 mol D 1.0 mol E 1.5 mol

1 mol = 6.02 x 1023

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14 How many moles of silver are there in a pure sample containing 1.5 x 1023 atoms of silver? A 0.10 mol B 0.25 mol C 0.50 mol D 1.0 mol E 1.5 mol

1 mol = 6.02 x 1023

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Answer B

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15 How many atoms are there in 5.00 mol of hafnium? A 6.02 x10

23 atoms

B 1.20 x 10

23 atoms

C 1.20 x 10

22 atoms

D 3.43 x 10

23 atoms

E 3.01 x 1024 atoms

1 mol = 6.02 x 1023

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15 How many atoms are there in 5.00 mol of hafnium? A 6.02 x10

23 atoms

B 1.20 x 10

23 atoms

C 1.20 x 10

22 atoms

D 3.43 x 10

23 atoms

E 3.01 x 1024 atoms

1 mol = 6.02 x 1023

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Answer E

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A mole of ANY substance contains Avogadro’s number of representative particles, or 6.02 x 1023 representative particles. 1 mole of C atoms = 6.02 X 1023 atoms of C 1 mole of bicycles = 6.02 x 1023 bicycles The term representative particle refers to the species or types of particles in the substance For Example: atoms, molecules, formula units, ions

Measuring Matter with Moles

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In 1 mole of water there are 6.02 x 10

23 water molecules.

In 1 mole of NaCl there are 6.02 x 1023 formula units. In 1 mole of carbon there are 6.02 x 10

23 carbon atoms.

molecule of H2O 18.0 amu Avagadro's number of molecules (6.02 x1023) 1 mol H2O (18.0 g) laboratory sample size

H O H

Measuring Matter with Moles

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16 Formula units refer to particles of __________ compounds and molecules refer to particles of __________ compounds. A molecular/covalent, ionic B ionic, molecular/covalent C atoms, molecular D atoms, ionic E ionic, atomic

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16 Formula units refer to particles of __________ compounds and molecules refer to particles of __________ compounds. A molecular/covalent, ionic B ionic, molecular/covalent C atoms, molecular D atoms, ionic E ionic, atomic

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Answer B

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17 How many molecules are there in 2.10 mol CO2? A 3.79 x 1024 B 3.49 x 10-24 C 1.05 x 10-23 D 2.53 x 1024 E 1.26 x 1024

1 mol CO2 = 6.02 x 1023 CO2 molecules

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17 How many molecules are there in 2.10 mol CO2? A 3.79 x 1024 B 3.49 x 10-24 C 1.05 x 10-23 D 2.53 x 1024 E 1.26 x 1024

1 mol CO2 = 6.02 x 1023 CO2 molecules

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Answer E

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18 How many moles of helium atoms are there in a pure sample containing 6.02 x 1024 atoms of helium? A 2.0 mol B 4.0 mol C 6.0 mol D 10.0 mol E 2.4 x 1024 mol

1 mol He = 6.02 x 1023 He atoms

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18 How many moles of helium atoms are there in a pure sample containing 6.02 x 1024 atoms of helium? A 2.0 mol B 4.0 mol C 6.0 mol D 10.0 mol E 2.4 x 1024 mol

1 mol He = 6.02 x 1023 He atoms

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Answer D

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19 How many moles of NaCl are there in a pure sample containing 6.02 x 1023 formula units of sodium chloride, NaCl? A 1.0 mol B 2.0 mol C 4.0 mol D 6.0 mol E 6.02 x 1023 mol

1 mol NaCl = 6.02 x 1023 NaCl formula units

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19 How many moles of NaCl are there in a pure sample containing 6.02 x 1023 formula units of sodium chloride, NaCl? A 1.0 mol B 2.0 mol C 4.0 mol D 6.0 mol E 6.02 x 1023 mol

1 mol NaCl = 6.02 x 1023 NaCl formula units

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Answer A

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20 How many formula units of Pb(NO

3)2 are there in

0.5 mole of Pb(NO3)2? A 0.5 formula units B 2.0 formula units C 3.01 x 1023 formula units D 1.2 x 1024 formula units E 6.02 x 1023 formula units

1 mol Pb(NO3)2 = 6.02 x 1023 Pb(NO3)2 formula units

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20 How many formula units of Pb(NO

3)2 are there in

0.5 mole of Pb(NO3)2? A 0.5 formula units B 2.0 formula units C 3.01 x 1023 formula units D 1.2 x 1024 formula units E 6.02 x 1023 formula units

1 mol Pb(NO3)2 = 6.02 x 1023 Pb(NO3)2 formula units

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Answer C

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Calcium deficiency can cause osteoporosis (weakening of the bones). The minimum amount of calcium in 1 mL of blood should be around 1.3 x 1018 atoms. A patient has her blood tested and the lab finds there are 3 x 10-5 moles of calcium in the blood. Is this patient at risk for

• steoporosis?

(6.02 x 1023 atoms/mole) x (3 x 10-5 moles) = 1.8 x 1023 atoms Ca This exceeds the normal range so they are OK!

Real World Application

slide for answer

Slide 39 / 158 Review: Ionic and Molecular Compounds

Ionic Compounds Molecular Compounds

H2O

2 hydrogen atoms 1 oxygen atom

C6H6

6 carbon atoms 6 hydrogen atoms

NaCl

1 Na+ ion 1 Cl- ion

K2CrO4

2 K+ ions 1 CrO42- ion

Sn(OH)2

1 Sn 2+ ion 2 OH- ions The total number of atoms or ions in a compound depends on electronegativity and bonding.

Slide 40 / 158 Review: Ionic and Molecular Compounds

Chemicals are composed of more than one molecule or formula unit. To indicate more than one molecule or formulat unit, add a coefficient in front of the compound. Example: six molecules of carbon dioxide = 6CO2. 6 atoms of carbon and 12 atoms of oxygen Move to reveal answer How many atoms of carbon and oxygen are in 6CO2?

Slide 41 / 158 Review: Ionic and Molecular Compounds

Ionic Compounds - Fill in Molecular Compounds - Fill in

H2O

__hydrogen atoms __oxygen atom

6 C6H6

__carbon atoms __hydrogen atoms

NaCl

__ Na+ ions __ Cl- ions

3

3 3

K2CrO4

__K+ ions __CrO42- ions

2 Sn(OH)2

__Sn 2+ ions __OH- ions

4 Slide 42 / 158 Converting Moles to Number of Particles

In one mole of water molecules there are:

molecule of H2O 18.0 amu Avagadro's number of molecules (6.02 x10

23 )

1 mol H2O (18.0 g) laboratory sample size

H O H

H2O

2 moles of hydrogen atoms 1 mole of

• xygen atoms

2 x 6.02x1023 atoms

• f hydrogen

1 x 6.02x1023 atoms

• f oxygen

Slide 43 / 158 Converting Moles to Number of Particles

In 3 moles of sodium chloride formula units there are:

3NaCl

3 moles of Na+ ions 3 moles of Cl- ions

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21 How many hydrogen atoms are in six molecules of

ethylene glycol, the major component in antifreeze? The formula for ethylene glycol is: HOCH2CH2OH. A 6 atoms of H B 36 atoms of H C 6 x 6.02 x 10

23 atoms of H

D 36 x 6.02 x 10

23 atoms of H

E 6.02 x 1023 atoms of H

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21 How many hydrogen atoms are in six molecules of

ethylene glycol, the major component in antifreeze? The formula for ethylene glycol is: HOCH2CH2OH. A 6 atoms of H B 36 atoms of H C 6 x 6.02 x 10

23 atoms of H

D 36 x 6.02 x 10

23 atoms of H

E 6.02 x 1023 atoms of H

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Answer B

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22 How many CO32- ions are in one formula unit of

CaCO3? A 1 ion B 3 ions C 6 x 6.02 x 10

23 ions

D 36 x 6.02 x 10

23 ions

E 6.02 x 1023 ions

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22 How many CO32- ions are in one formula unit of

CaCO3? A 1 ion B 3 ions C 6 x 6.02 x 10

23 ions

D 36 x 6.02 x 10

23 ions

E 6.02 x 1023 ions

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Answer A

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23 How many K+ ions are there in two formula units of potassium hydroxide, 2KOH? A 1 K+ ion B 2 K+ ions C 1 x 6.02 x10

23 ions of K +

D 2 x 6.02 x 10

23 ions of K+

E 3.12 x 1023 ions of K+

Slide 46 (Answer) / 158

23 How many K+ ions are there in two formula units of potassium hydroxide, 2KOH? A 1 K+ ion B 2 K+ ions C 1 x 6.02 x10

23 ions of K +

D 2 x 6.02 x 10

23 ions of K+

E 3.12 x 1023 ions of K+

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Answer B

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24 How many sulfide ions (S2- ) are there in 2.0 moles of ammonium sulfide,(NH4)2S? A 2.0 ions B 1.2 x 1024 ions C 2.4 x 1024 ions D 6.02 x 1023 ions E none

1 mol (NH4)2S = 6.02 x 1023 (NH4)2S formula units *Use two equalities to solve: 1 (NH4)2S formula unit = 1 S2- ion

Slide 47 (Answer) / 158

24 How many sulfide ions (S2- ) are there in 2.0 moles of ammonium sulfide,(NH4)2S? A 2.0 ions B 1.2 x 1024 ions C 2.4 x 1024 ions D 6.02 x 1023 ions E none

1 mol (NH4)2S = 6.02 x 1023 (NH4)2S formula units *Use two equalities to solve: 1 (NH4)2S formula unit = 1 S2- ion

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Answer B

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25 How many ammonium ions (NH4 + ) are there in 2.0 moles of ammonium sulfide, (NH4)2S? A 2.0 ions B 1.2 x 1024 ions C 2.4 x 1024 ions D 6.02 x 10 23 ions E 8.0 ions

1 mol (NH4)2S = 6.02 x 1023 (NH4)2S formula units *Use two equalities to solve: 1 (NH4)2S formula unit = 2 NH4+ ions

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25 How many ammonium ions (NH4 + ) are there in 2.0 moles of ammonium sulfide, (NH4)2S? A 2.0 ions B 1.2 x 1024 ions C 2.4 x 1024 ions D 6.02 x 10 23 ions E 8.0 ions

1 mol (NH4)2S = 6.02 x 1023 (NH4)2S formula units *Use two equalities to solve: 1 (NH4)2S formula unit = 2 NH4+ ions

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Answer C

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26 How many moles of O are in 2.4 X 1024

molecules of SO3?

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26 How many moles of O are in 2.4 X 1024

molecules of SO3?

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Answer 12 mol

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Hemoglobin is a protein that carries O2 around your body. The formula for it is approximately C2800H4800N3200O800S8Fe4. If a patient has 2 x 1016 atoms of Fe, how many moles of Hb would be present?

moles of Fe: n = N/Na --> (2 x 1016 atoms)/(6.02 x 1023 atoms/n)= 3.3 x 10-7 moles Fe moles of Hb: There are 1 Hb/4 Fe --> (3.3 x 10-7 moles Fe)/(4 moles of Fe/Hb)

= 8.2 x 10-8 moles Hb

Real World Application

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Molar Mass

Slide 52 / 158 Mass of Compounds

The total mass of a chemical compound can be calculated by using the masses on the Periodic Table. Example: Calculate the mass of the compound Magnesium Chloride (MgCl2) Mg = 24.305 amu 2Cl = (2)35.453 amu Mass of MgCl2 95.211 amu +

Slide 53 / 158 Masses of Elements/Compounds

Atomic mass Formula mass or Formula weight (FW) Molecular mass or Molecular weight used for elements (like F, V, etc..) only used for ionic compounds (like NaCl, MgO, etc..) only used for molecular compounds (like CO2, H2O, etc..) only amu Units amu amu

Slide 54 / 158

27 What is the formula weight of sodium bromide? A 79.904 amu B 102.894 amu C 205.780 amu D 300.120 amu E 605.102 amu

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27 What is the formula weight of sodium bromide? A 79.904 amu B 102.894 amu C 205.780 amu D 300.120 amu E 605.102 amu

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Answer B

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28 What is the formula weight of Pb(NO3)2? A 79.90 amu B 102.89 amu C 205.78 amu D 331.34 amu E 605.10 amu

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28 What is the formula weight of Pb(NO3)2? A 79.90 amu B 102.89 amu C 205.78 amu D 331.34 amu E 605.10 amu

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Answer 1 Pb = 207.20 amu 2 N = 2(14.07) amu 6 O = 6(16.00) amu FW = 331.34 amu D

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29 What is the molecular mass of 3H2O2? A 17 amu B 34 amu C 68 amu D 102 amu E 204 amu

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29 What is the molecular mass of 3H2O2? A 17 amu B 34 amu C 68 amu D 102 amu E 204 amu

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Answer D

Slide 57 / 158 Molar Mass (M)

The mass in grams of one mole of any substance is its molar mass (M). Each of the bars shown below equals

• ne mole of a pure element.

A mole represents the number of atoms it takes to convert from a single atomic mass in amu to the same mass in grams. 1 mole of Aluminum = 26.982 g 1 mole of Copper = 63.546 g

Slide 58 / 158 Molar Mass (M)

One mole of carbon, sulfur and silver are shown.

1 mol of Carbon atoms = 12.0 g 1 mol of sulfur atoms 32.0 g of S 1 mol of silver = 107.9 g of Ag

Slide 59 / 158

Average atomic mass of 1 atom of Kr = 83.8 amu. 1 mole (6.02 x 1023 atoms) of Kr = 83.8 grams. The atomic mass of an element expressed in grams is the mass of one mole or molar mass (M) of the element.

How is the atomic mass of an element related to the molar mass?

1 mole of Kr = 83.8 grams Molar mass of Kr = 83.8 grams or 83.8 g/mol 1 mol

Slide 60 / 158 Molar Mass

Gram atomic mass Gram formula mass or Formula weight (FW) Gram molecular mass or Molecular weight used for elements (like F, V, etc..) only used for ionic compounds (like NaCl, MgO, etc..) only used for molecular compounds (like CO2, H2O, etc..) only grams Units grams grams

The molar mass of an element or compound can be used to convert directly from masses in amu to masses in grams.

Slide 61 / 158

To convert from moles to mass, or vice versa, use dimensional analysis.

Molar Mass

How many moles of Helium are in 8.0 grams of Helium? Given quantity: 8.0 g He 1 mol He 4.0 g He

• r

4.0 g He 1 mol He Equalities: 8.0 g He x 1 mol He 4.0 g He = 2 mol He Solve and cancel units: Molar mass of He = 4.0 g/mol

Slide 62 / 158

30 How many moles are in a 64-gram sample of

pure sulfur?

*Molar mass (M) of S = ? g/mol

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30 How many moles are in a 64-gram sample of

pure sulfur?

*Molar mass (M) of S = ? g/mol

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Answer 2 mol

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31 How many moles are in a 72-gram sample of pure

magnesium?

*Molar mass (M) of Mg = ? g/mol

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31 How many moles are in a 72-gram sample of pure

magnesium?

*Molar mass (M) of Mg = ? g/mol

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Answer 3 mol

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32 What is the mass, in grams, of 2 moles of carbon?

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32 What is the mass, in grams, of 2 moles of carbon?

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Answer 24 g

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33 What is the mass, in grams, of 5 moles of iron?

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33 What is the mass, in grams, of 5 moles of iron?

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Answer 280 g

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34 How many grams is 2.0 mol neon atoms?

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34 How many grams is 2.0 mol neon atoms?

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Answer 40 g

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Diatomic Molecules

(Recall the seven diatomic molecules: HONClBrIF) The molar mass of these molecules will be twice their atomic mass. Examples: M of hydrogen gas: H

2 = (2 x 1) = 2 g/mol

M of bromine liquid: Br

2 = (2 x 79.9) = 159.8 g/mol

M of fluorine molecules: F

2 = (2 x 19) = 38 g/mol

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35 How many grams is 1.0 mole of hydrogen

molecules?

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35 How many grams is 1.0 mole of hydrogen

molecules?

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Answer 2 g

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36 How many grams is 0.50 mol of oxygen molecules?

Slide 69 (Answer) / 158

36 How many grams is 0.50 mol of oxygen molecules?

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Answer 16 g

Slide 70 / 158

The molar mass of a compound is the sum of the molar masses of all the elements in the compound.

Molar Mass of a Compound

To calculate the molar mass of a compound, find the number of grams of each element in one mole of the compound. Then add the masses of the elements in the compound.

32.065 g/mol + 3(16.000) g/mol = 80.650 g/mol

Molar mass of SO3 = 80.650 g/mol

Slide 71 / 158 Molar Mass of a Compound

Note the different molar masses of these two compounds.

18 g of H2O = 1 mole H

2O

180 g of glucose (C

6H12 O6)

= 1 mole glucose

Slide 72 / 158

37 What is the molar mass of K2O, potassium oxide?

[*]

Slide 72 (Answer) / 158

37 What is the molar mass of K2O, potassium oxide?

[*]

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Answer 94 g/mol

Slide 73 / 158

38 What is the molar mass of CaCO3, calcium carbonate found in eggshells? A 50 amu B 50 grams/mol C 100 amu D 100 grams/mol

Slide 73 (Answer) / 158

38 What is the molar mass of CaCO3, calcium carbonate found in eggshells? A 50 amu B 50 grams/mol C 100 amu D 100 grams/mol

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Answer D

Slide 74 / 158

39 What is the molar mass of carbon dioxide? A 28 amu B 28 grams/mol C 44 amu D 44 grams/mol

Slide 74 (Answer) / 158

39 What is the molar mass of carbon dioxide? A 28 amu B 28 grams/mol C 44 amu D 44 grams/mol

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Answer D

Slide 75 / 158

40 What is the molar mass of ammonia, NH3? A 17 amu B 17 grams/mol C 45 amu D 45 grams/mol

Slide 75 (Answer) / 158

40 What is the molar mass of ammonia, NH3? A 17 amu B 17 grams/mol C 45 amu D 45 grams/mol

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Answer B

Slide 76 / 158

Molar mass is the mass of 1 mole of a substance (measured in g/mol). The atomic mass will be the same number as the molar mass (measured in amu). The difference is that the atomic mass refers to only one representative particle and molar mass refers to one mole (6.02 x 1023 ) of representative particles.

Summary of Molar Mass Slide 77 / 158

41 What is the mass of one formula unit of NaCl? A 17 amu B 17 grams/mol C 58.5 amu D 58.5 grams/mol

Slide 77 (Answer) / 158

41 What is the mass of one formula unit of NaCl? A 17 amu B 17 grams/mol C 58.5 amu D 58.5 grams/mol

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Answer C

Slide 78 / 158

42 What is the mass of one molecule of water? A 18 amu B 18 grams/mol C 8 amu D 8 grams/mol

Slide 78 (Answer) / 158

42 What is the mass of one molecule of water? A 18 amu B 18 grams/mol C 8 amu D 8 grams/mol

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Answer A

Slide 79 / 158

43 The chemical formula of aspirin is C9H8O4.

What is the mass of 0.200 moles of aspirin?

Slide 79 (Answer) / 158

43 The chemical formula of aspirin is C9H8O4.

What is the mass of 0.200 moles of aspirin?

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Answer 36 g

Slide 80 / 158

44 The molar mass of oxygen (O2) is: A equal to the mass of one mole of oxygen atoms. B 16.0 g/mol C 32.0 g/mol D none of the above E equal to the mass of one oxygen atom.

Slide 80 (Answer) / 158

44 The molar mass of oxygen (O2) is: A equal to the mass of one mole of oxygen atoms. B 16.0 g/mol C 32.0 g/mol D none of the above E equal to the mass of one oxygen atom.

[This object is a pull tab]

Answer C

Slide 81 / 158

45 There are more moles of CO2 in a 44 g sample of carbon dioxide gas than there are moles of helium atoms in a box containing 2 x 1023 atoms of He.

True False

Slide 81 (Answer) / 158

45 There are more moles of CO2 in a 44 g sample of carbon dioxide gas than there are moles of helium atoms in a box containing 2 x 1023 atoms of He.

True False

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Answer True

Slide 82 / 158

How many grams of iron are in a 68 gram sample of Fe2O3? M of Fe2O3 = 160 g/mol M of Fe = 56g/mol 69 g Fe2O3 x 1 mol Fe2O3 x 2 mol Fe x 56g Fe = 48 g Fe 160g Fe2O3 1 mol Fe2O3 1 mol Fe

Move to see answer

Slide 83 / 158

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Molar Volume

Slide 84 / 158 The Mole and the Volume of a Gas

The volume of a gas varies with temperature and pressure. But comparisons between gases can be made by designating a standard temperature and pressure (STP).

Slide 85 / 158 STP (Standard Temperature and Pressure)

Standard Temperature (T) is considered 0°C (273 K), the temperature at which water freezes. Standard Pressure (P) is considered 1 atmosphere (101.3 kPa),

• r the pressure of the atmosphere at sea level.

At STP, 1 mole of gas occupies a volume of 22.4 liters (L) Vm = 22.4 L For the time being, we will treat all gases as if they are at STP.

Slide 86 / 158 The Mole and the Volume of a Gas

The volume occupied by one mole of gas is called the molar volume and has the symbol, Vm. It is the same for all gases.

At STP; Vm = 22.4 liters (L).

1 mole of gas = 6.02 x 1023 particles = 22.4 L

Notice that this statement does not depend on the type of gas. It's true of all gases.

Slide 87 / 158 The Mole and the Volume of a Gas At STP; Vm = 22.4 liters (L).

This is true because in a gas the molecules are so far apart that they take up almost no space...the volume of a gas is mostly empty space, regardless of the type of gas. So when it comes to volume (at STP) all gases are created equal. 1 mole of He gas occupies 22.4 L @STP 1 mole of HCl gas occupies 22.4 L @STP

Slide 88 / 158

46 Which of the following must be true about 2 moles of H2 gas vs. 2 moles of CO2 gas at the same temperature and pressure?

A Each sample will have the same density B The same # of atoms will be present in each

sample

C Each sample will have the same mass D Each sample will occupy the same volume E None of these are true

Slide 88 (Answer) / 158

46 Which of the following must be true about 2 moles of H2 gas vs. 2 moles of CO2 gas at the same temperature and pressure?

A Each sample will have the same density B The same # of atoms will be present in each

sample

C Each sample will have the same mass D Each sample will occupy the same volume E None of these are true

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Answer D

Slide 89 / 158

At STP, 1 mole or, 6.02 x 1023 representative particles, of any gas occupies a volume of 22.4 L. The quantity 22.4 L is called the molar volume of a gas.

The Mole and the Volume of a Gas

Given quantity: 11.2 L of CO2 1 mol CO2 22.4 L CO2 Equalities:

• r

11.2 L CO2 x 1 mol CO2 22.4 L CO2 = 0.5 mol CO2 Solve and cancel units: At STP, how many moles of CO

2 are there in 11.2 L of CO 2?

1 mol CO2 22.4 L CO2 1 mole of gas = 22.4 L gas

Slide 90 / 158

47 How many moles are there in 44.8 liters (at STP)

• f fluorine gas?

* At STP 1 mol = 22.4 L

Slide 90 (Answer) / 158

47 How many moles are there in 44.8 liters (at STP)

• f fluorine gas?

* At STP 1 mol = 22.4 L

[This object is a pull tab]

Answer 2 mol

Slide 91 / 158

48 How many moles of atoms are there in 22.4 liters

(at STP) of Xenon?

Slide 91 (Answer) / 158

48 How many moles of atoms are there in 22.4 liters

(at STP) of Xenon?

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Answer 1 mol

Slide 92 / 158

49 What is the volume (in liters at STP) of 1.00 mole

• f sulfur dioxide?

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49 What is the volume (in liters at STP) of 1.00 mole

• f sulfur dioxide?

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Answer 22.4 L

Slide 93 / 158

50 What is the volume (in liters at STP) of 2.50 moles

• f carbon monoxide?

Slide 93 (Answer) / 158

50 What is the volume (in liters at STP) of 2.50 moles

• f carbon monoxide?

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Answer 56 L

Slide 94 / 158

51 What is the volume (in liters at STP) of 4.00

moles of Nitrogen?

Slide 94 (Answer) / 158

51 What is the volume (in liters at STP) of 4.00

moles of Nitrogen?

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Answer 89.6 L

Slide 95 / 158 Real World Application

An inflated airbag requires 60 L of nitrogen gas (N2) at STP in order to protect the occupant of the vehicle. How many moles of nitrogen gas would need to be created in 40 milliseconds to inflate the airbag?

Slide 96 / 158 Mole Calculations

Sometimes multiple steps must be used in mole calculations. To solve these problems use dimensional analysis and the appropriate mole conversions. Here's an example: How many atoms of carbon are present in a 24 g sample

• f pure carbon?

To solve convert from: grams moles atoms

Slide 97 / 158

How many atoms of carbon are present in a 24 g sample? Start with your given: Choose the correct equality to convert from grams to moles: Choose the correct equality to convert from moles to atoms: Solve and cancel out units:

24 g C

M of C = 12g/mol 1 mole = 6.02 x 1023 24 g C x 1 mol C 6.02 x 1023 atoms C x 12 g C 1 mol C = 1.2 X 1024 atoms C

1 mol C 12 g C

• r

1 mol C 12 g C

6.02 x 1023 atoms C 1 mol C 6.02 x 1023 atoms C 1 mol C

• r

Mole Calculations Slide 98 / 158 Mole Road Map

moles

1 mol = 6.02 x 1023 particles Particles: atoms, ions, molecules, etc.

V

Molar Volume (V

M)

1 mol = 22.4 L

(Volume)

m (mass)

Molar mass (M) 1 mol = ___ grams found using the Periodic Table

Slide 99 / 158

52 How many molecules are there in 44.8 liters

(at STP) of oxygen gas?

1 mol O2 molecules = 6.02 x 1023 O2 molecules 1 mol O2 gas = 22.4 L O2

Slide 99 (Answer) / 158

52 How many molecules are there in 44.8 liters

(at STP) of oxygen gas?

1 mol O2 molecules = 6.02 x 1023 O2 molecules 1 mol O2 gas = 22.4 L O2

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Answer 1.2 x 10

24 molecules

Slide 100 / 158

53 How many atoms are there in 11.2 liters (at STP)

• f molecular oxygen ( oxygen gas)?

Slide 100 (Answer) / 158

53 How many atoms are there in 11.2 liters (at STP)

• f molecular oxygen ( oxygen gas)?

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Answer 6.0 x 10

23 atoms

Slide 101 / 158

54 What is the mass of 44.8 liters (at STP) of

molecular oxygen?

Slide 101 (Answer) / 158

54 What is the mass of 44.8 liters (at STP) of

molecular oxygen?

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Answer 64 g

Slide 102 / 158

55 What is the volume (at STP) of 3.0 x 1023

molecules of fluorine?

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55 What is the volume (at STP) of 3.0 x 1023

molecules of fluorine?

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Answer 11.2 L

Slide 103 / 158

56 What is the volume (at STP) of 240 g of

nitrogen gas?

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56 What is the volume (at STP) of 240 g of

nitrogen gas?

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Answer 192 L

Slide 104 / 158

57 How many atoms are present in 30 g of boron ?

M of Boron= 10.8 g/mol or 1 mol = 10.8 g 1 mol B = 6.02 x 1023 atoms B

Slide 104 (Answer) / 158

57 How many atoms are present in 30 g of boron ?

M of Boron= 10.8 g/mol or 1 mol = 10.8 g 1 mol B = 6.02 x 1023 atoms B

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Answer 1.6 x 10

24 atoms

Slide 105 / 158

58 What is the mass of a pure sample of lead

which contains 3.0 x 1024 atoms?

Slide 105 (Answer) / 158

58 What is the mass of a pure sample of lead

which contains 3.0 x 1024 atoms?

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Answer 1040 g

Slide 106 / 158

59 How many moles are there in 11.2 liters (at STP)

• f chlorine?

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59 How many moles are there in 11.2 liters (at STP)

• f chlorine?

[This object is a pull tab]

Answer 0.5 mol

Slide 107 / 158

60 What volume will 6.0x1024 molecules of oxygen gas

• ccupy at STP?

Slide 107 (Answer) / 158

60 What volume will 6.0x1024 molecules of oxygen gas

• ccupy at STP?

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Answer 224 L

Slide 108 / 158

61 How many molecules are in a 32g sample of SO2 ?

Slide 108 (Answer) / 158

61 How many molecules are in a 32g sample of SO2 ?

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Answer 3 x 10

23 molecules

Slide 109 / 158

62 Determine the volume occupied by 216g of N2O5 at STP?

Slide 109 (Answer) / 158

62 Determine the volume occupied by 216g of N2O5 at STP?

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Answer 44.8 L

Slide 110 / 158

63 What volume will 5.0x1024 atoms of krypton occupy at

STP?

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63 What volume will 5.0x1024 atoms of krypton occupy at

STP?

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Answer 187 L

Slide 111 / 158

64 What is the mass of 224 L of hexene (C6H12 ) at STP?

Slide 111 (Answer) / 158

64 What is the mass of 224 L of hexene (C6H12 ) at STP?

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Answer 840 g

Slide 112 / 158

65 What is the volume occupied by 6.0x1023 atoms of

Hydrogen at STP?

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65 What is the volume occupied by 6.0x1023 atoms of

Hydrogen at STP?

[This object is a pull tab]

Answer 22.4 L

Slide 113 / 158

66 How many atoms of C are in a 30 milligram sample of calcium cyanide. (Hint: you must remember that milli means 1/1000 and you must first write the proper formula for calcium cyanide)

Slide 113 (Answer) / 158

66 How many atoms of C are in a 30 milligram sample of calcium cyanide. (Hint: you must remember that milli means 1/1000 and you must first write the proper formula for calcium cyanide)

[This object is a pull tab]

Answer 3.9 x 10

20 atoms

Slide 114 / 158

67 What is the mass of 44.8L of Argon gas at STP?

Slide 114 (Answer) / 158

67 What is the mass of 44.8L of Argon gas at STP?

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Answer 80 g

Slide 115 / 158

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Percent Composition

Slide 116 / 158 Identify an Unknown Substance

We have been able to calculate the molar mass of a material if we know its formula already. However, what if we encounter an unidentified substance? Using the tools we already have, we are able to determine the composition of a substance if we have certain pieces of information.

Slide 117 / 158 Percent Composition

Potassium chromate, K2 CrO4 Potassium dichromate, K2 Cr2 O7

One such piece of information is the percent composition, or the percentage of a compound's mass, made up by its various elements.

Slide 118 / 158

% element = (number of atoms)(atomic weight) (FW of the compound) x 100

Percent Composition

The percent by mass of an element in a compound is the number of grams of the element divided by the mass in grams of the compound, multiplied by 100%.

Slide 119 / 158

= 80.0% %C = (2)(12.0 amu) 30.0 amu x 100 %H = (6)(1.0 amu) 30.0 amu = 20.0% x 100

The percent composition of carbon and hydrogen in ethane, (C2H6) is…

Percent Composition of Ethane

Since ethane is made of only Carbon and Hydrogen, if the percent composition of Carbon was 80%, the remaining percent must be Hydrogen. A nother method to calculate the %H is: %H = 100% - %C %H = 100% - 80% %H = 20%

Slide 120 / 158

%H = 20% and %C = 80%

The percent composition of ethane, (C2H6) is… Note that even though there are more ATOMS of hydrogen in ethane, there is a much less percentage of mass in the compound than that of carbon. This is because 1 carbon atom (12 amu) is much more massive than 1 hydrogen atom (1 amu). Therefore, carbon accounts for a much greater percentage of the mass of ethane than hydrogen does.

Percent Composition of Ethane Slide 121 / 158

68 In water (H2O), which element do you think accounts for more mass? A Hydrogen B Oxygen C Hydrogen and Oxygen account for the same percent of mass D Carbon

Slide 121 (Answer) / 158

68 In water (H2O), which element do you think accounts for more mass? A Hydrogen B Oxygen C Hydrogen and Oxygen account for the same percent of mass D Carbon

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Answer B

Slide 122 / 158

69 What is the mass percentage of oxygen in water?

Slide 122 (Answer) / 158

69 What is the mass percentage of oxygen in water?

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Answer 88.8%

Slide 123 / 158

70 What is the percent by mass of carbon in acetone, C3H6O?

Slide 123 (Answer) / 158

70 What is the percent by mass of carbon in acetone, C3H6O?

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Answer 62%

Slide 124 / 158

71 What is the percent of Ba in Ba(NO3)2

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71 What is the percent of Ba in Ba(NO3)2

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Answer 52%

Slide 125 / 158

72 Iron (II) oxide has a smaller % of iron by mass than iron (III) oxide.

True False

Slide 125 (Answer) / 158

72 Iron (II) oxide has a smaller % of iron by mass than iron (III) oxide.

True False

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Answer False

Slide 126 / 158 Real World Application

Aluminum is used in soda cans, aircraft frames, and automobile

• engines. Worldwide aluminum demand

is increasing. Aluminum is isolated from an ore called bauxite which is roughly 12% aluminum by mass. How much bauxite ore (in grams) must be mined to provide enough aluminum to make a car engine requiring 100 kg of aluminum?

bauxite ore Al block engine

100 kg x (1000 g/kg) x (100 g of ore/12 gram of Al) = 830,000 g Al

move for answer

Slide 127 / 158

73 A 2.00 sample of a compound containing only potassium and oxygen is heated. The oxygen gas leaves and the resulting mass of the potassium is 1.66 grams. What is the % by mass of oxygen in the compound?

A 17% B 70% C 30% D 45% E Cannot be determined from the information

Slide 127 (Answer) / 158

73 A 2.00 sample of a compound containing only potassium and oxygen is heated. The oxygen gas leaves and the resulting mass of the potassium is 1.66 grams. What is the % by mass of oxygen in the compound?

A 17% B 70% C 30% D 45% E Cannot be determined from the information

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Answer A

Slide 128 / 158

74 What is the % by mass of water in the CaSO4*2H2O crystal?

A 10% B 21% C 19% D 50% E 75%

Slide 128 (Answer) / 158

74 What is the % by mass of water in the CaSO4*2H2O crystal?

A 10% B 21% C 19% D 50% E 75%

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Answer B

Slide 129 / 158

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Empirical Formula

Slide 130 / 158 Calculating Empirical Formulas

Now that we are able to calculate the percent of a compound by mass of each element, we can begin to identify unknown

• substances. First, we must identify the ratio of the number of

moles of each element in the substance This formula, based on whole-number ratio, is called an empirical formula.

Slide 131 / 158 Calculating Empirical Formulas

Empirical formula: The formula that indicates the molar ratio of elements present in a molecular compound reduced to the least common denominator. For instance, the empirical formula for benzene (C6H6) is CH.

Mass % elements Grams of each element Moles of each element Empirical formula Assume 100g sample use molar mass Calculate mole ratio

Slide 132 / 158 Calculating Empirical Formulas

Empirical formula: There is only one empirical formula for a substance, but two different substances can have the same empirical formula. That is because an empirical formula is always based on the ratio

• f the elements given in their lowest common denominator.

Example: Substance Hydrogen peroxide Hydroxide Molecular Formula Emperical Formula

H2O2 OH OH OH Slide 133 / 158

75 The empirical formula for C6H4(NO3)2 is C3H2N2O3 True False

Slide 133 (Answer) / 158

75 The empirical formula for C6H4(NO3)2 is C3H2N2O3 True False

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Answer False

Slide 134 / 158

76 Which of the following has an empirical formula that is the same as its molecular formula? (1) NH4Cl (2) (NH4)2CO3 (3) CH2Cl2 (4) CHCl2Br A 1 and 3 only B 1, 2 and 4 only C 1 and 4 only D all of them

Slide 134 (Answer) / 158

76 Which of the following has an empirical formula that is the same as its molecular formula? (1) NH4Cl (2) (NH4)2CO3 (3) CH2Cl2 (4) CHCl2Br A 1 and 3 only B 1, 2 and 4 only C 1 and 4 only D all of them

[This object is a pull tab]

Answer D

Slide 135 / 158 Calculating Empirical Formulas

The compound para-aminobenzoic acid (listed as PABA in bottles of sunscreen) is composed of the following elements (by mass): carbon (61.31%), hydrogen (5.14%), nitrogen (10.21%), and oxygen (23.33%). Find the empirical formula of PABA.

Mass % elements

Slide 136 / 158

Step 1: convert the mass percentages to mole amounts in a hypothetical 100 g sample. Assume a 100.00 g amount of PABA to represent the mass of each element: C: 61.31% x 100g = 61.31 g H: 5.14 % x 100g = 5.14 g N: 10.21% x 100g = 10.21 g O: 23.33 % x 100g = 23.33 g

Mass % elements Grams of each element Assume 100g sample

Calculating Empirical Formulas

Slide 137 / 158

Step 2: Now that we know the representative mass, we can use the molar mass of each element to calculate the number

• f moles that would be present.

C: 61.31 g x = 5.105 mol H: 5.14 g x = 5.09 mol N: 10.21 g x = 0.7288 mol O: 23.33 g x = 1.456 mol 1 mol 12.01 g 1 mol 14.01 g 1 mol 1.01 g 1 mol 16.00 g

Calculating Empirical Formulas

Mass % elements Grams of each element Moles of each element Assume 100g sample use molar mass

Slide 138 / 158 Calculating Empirical Formulas

Step 3: Calculate the mole ratio by dividing each mole value by the smallest number of moles. In this case, by that of nitrogen. Divide them all by 0.7288. C: 5.105 mol H: 5.09 mol N: 0.7288 mol O: 1.456 mol 0.7288 mol 0.7288 mol 0.7288 mol 5.105 mol 5.09 mol 0.7288 mol 1.456 mol = 7.005 # 7 = 6.984 # 7 = 1.00 = 1 = 2.001 # 2 0.7288 mol

Mass % elements Grams of each element Moles of each element Empirical formula Assume 100g sample use molar mass Calculate mole ratio

The empirical formula for PABA is C

7H7NO2

Slide 139 / 158

C: 62.1 g x = 5.17 mol = 5.17 mol = 3.01 3 H: 13.8 g x = 13.8 mol = 13.8 mol = 7.96 8 N: 24.1 g x = 1.72 mol = 1.72 mol = 1.00 = 1 1 mol 14.01 g 1 mol 12 .0 g 1 mol 1.0 g 1.72 mol 1.72 mol 1.72 mol # #

The empirical formula is C3H8N

1,6 - diaminohexane is used in making nylon. It is 62.1% C, 13.8% H and 24.1% N. What is the empirical formula?

Calculating Empirical Formulas Slide 140 / 158

77 What is the empirical formula for a compound with

the following percent composition? A C H4 B C2 H5 C C3 H6 D C3 H8

C: 74.9 % H: 25.1 %

Slide 140 (Answer) / 158

77 What is the empirical formula for a compound with

the following percent composition? A C H4 B C2 H5 C C3 H6 D C3 H8

C: 74.9 % H: 25.1 %

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Answer A

Slide 141 / 158

78 What is the empirical formula for a compound with

the following percent composition? A C2 H O B C H2 O C C H O2 D C2 H3 O2

C: 40.0 % H: 6.7 % O: 53.0 % Slide 141 (Answer) / 158

78 What is the empirical formula for a compound with

the following percent composition? A C2 H O B C H2 O C C H O2 D C2 H3 O2

C: 40.0 % H: 6.7 % O: 53.0 %

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Answer B

Slide 142 / 158

The molar ratio works very well for most compounds. However, in some cases the math leaves us without whole numbers: For Example: iron (?) oxide Fe: 69.92% -> 69.92g = 1.25 mol = 1 O: 30.08% -> 30.08g = 1.88 mol = 1.5

Mass % elements Grams of each element Moles of each element Assume 100g sample use molar mass Calculate mole ratio

55.85 g/mol 16.00g/mol 1.25 mol 1.25 mol

FeO1.5 Special Cases Slide 143 / 158 Special Cases

In these cases, it is necessary to multiply the results by an integer to ensure the ratio is a whole number ratio... The empirical formula is Fe2O3

x 2 = 2 x 2 = 3

The name of the compound is iron (III) oxide

Slide 144 / 158

79 What is the empirical formula for a compound with

the following percent composition? A V O1.67 B V2 O5 C V3 O5 D V3 O8

V: 56.02 % O: 43.98 %

Slide 144 (Answer) / 158

79 What is the empirical formula for a compound with

the following percent composition? A V O1.67 B V2 O5 C V3 O5 D V3 O8

V: 56.02 % O: 43.98 %

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Answer B

Slide 145 / 158

80 A 4.68 gram sample of a sulfur oxide is heated releasing oxygen gas and leaving behind solid sulfur. If the mass of the sulfur left behind was 2.34 grams, what must be the empirical formula of the compound?

A SO B SO2 C S2O D S2O3 E SO3

Slide 145 (Answer) / 158

80 A 4.68 gram sample of a sulfur oxide is heated releasing oxygen gas and leaving behind solid sulfur. If the mass of the sulfur left behind was 2.34 grams, what must be the empirical formula of the compound?

A SO B SO2 C S2O D S2O3 E SO3

[This object is a pull tab]

Answer B

Slide 146 / 158 Hydrated Crystals

Many ionic compounds have a fixed quantity of water molecules bound within their structure. The mole ratio of water to the dry CuSO4 crystal is 5:1 CuSO4 * 5H2O

Slide 147 / 158 Finding the formula of a hydrate

One can find the formula of a hydrate by heating the crystal to remove the water. Then find the mole ratio between the dry crystal and the water just as you would when finding an empirical formula. g CuSO4

• -> n CuSO4

CuSO4 * ? H2O g H2O --> n H2O

HEAT

Find mole ratio!

Slide 148 / 158 Finding the formula of a hydrate

After heating, a hydrate of MgSO4 was found to be roughly 51.3% water by mass. What is the formula of the hydrate? Step 1: Find the % of the crystal and water and express in grams. 100 - 51.3% water = 48.7 % MgSO4 = 48.7 g MgSO4 & 51.3 g of water Step 2: Convert to moles 48.7 g MgSO4 = 0.405 mol MgSO4 51.3 g H2O = 2.85 mol H2O 120 g/mol 18 g/mol

Slide 149 / 158

Step 3: Find the mole ratio of the water to the dry crystal 0.405 mol MgSO4 = 1 2.85 mol H2O = 7 0.405 mol 0.405 mol .....the formula is MgSO4*7H2O

Finding the formula of a hydrate Slide 150 / 158

81 When a 2.4 g sample of a hydrated crystal of BaCl2 is heated, the dry anhydrous crystal has a mass of 2.08 grams after heating. What is the formula of the hydrate?

A BaCl2*H2O B BaCl2*2H2O C BaCl2*3H2O D BaCl2*4H2O E BaCl2*5H2O

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81 When a 2.4 g sample of a hydrated crystal of BaCl2 is heated, the dry anhydrous crystal has a mass of 2.08 grams after heating. What is the formula of the hydrate?

A BaCl2*H2O B BaCl2*2H2O C BaCl2*3H2O D BaCl2*4H2O E BaCl2*5H2O

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Answer B

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A molecular formula indicates the number of atoms of each element present in the molecule. The molecular formula of a compound is either the same as its experimentally determined empirical formula, or it is a simple whole-number multiple of its empirical formula

Molecular Formulas

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Molecular Formulas

Formula Name Type of Formula Molar Mass

CH C2H2 Ethyne C6H6 Benzene CH2O Methanal C2H4O2 Ethanoic Acid C6H12O6 Glucose Empirical Molecular Molecular Empirical & Molecular Molecular Molecular 13 (13x2 =) 26 (13x6 =) 78 30 (30x2 =) 60 (30x6 =) 180

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To find the actual molecular formula you need one other piece of information...the molecular weight (mass) of the molecule.

If

you know the ratio of the elements in a molecule

and you know the total mass of the molecule then you can determine the molecular formula. Molecular Formulas

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To find the molecular formula: Step 1: Determine the molar mass of the empirical formula. Step 2: Divide the molecular mass by the empirical mass Step 3: Multiply the Empirical Formula by the resulting integer

Molecular Formulas

What is the molecular formula of a compound with an empirical formula of CH

2O that has a mass of 180 g/mol?

Molar mass of CH2O = 30 g/mol Molecular mass = 180 g/mol = 6 Empirical mass 30 g/mol 6 x CH2O = C6H12O6

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82 The molecular mass of Benzene is 78. If the empirical formula of benzene is CH, what is its molecular formula? A C2H2 B CH C C6H6 D C2H4

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82 The molecular mass of Benzene is 78. If the empirical formula of benzene is CH, what is its molecular formula? A C2H2 B CH C C6H6 D C2H4

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Answer C

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Maleic acid is an organic compound composed of 41.39 % carbon, 3.47% hydrogen, and the rest is oxygen. It has a molecular mass of 116 g/mole.

Molecular Formulas

Determine the empirical formula for Maleic acid. Then determine the molecular formula for Maleic acid.

Slide 157 / 158 Real World Application

Clenbuterol is a steroid drug that is illegally used in cattle and in sports like cycling to help the cattle or athlete lose fat and gain lean muscle

• mass. It can be detected by

mass spectroscopy. What is the empirical and molecular formula for clenbuterol if when a 10.0 g sample is combusted in air, it is found it contains 4.60 g of carbon, 0.613 g of H, 0.51 g of oxygen with the rest being chlorine? The molecular weight is 313 g/mol.

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