Models of ice sheet dynamics and meltwater lubrication Ian Hewitt, - - PowerPoint PPT Presentation

models of ice sheet dynamics and meltwater lubrication
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Models of ice sheet dynamics and meltwater lubrication Ian Hewitt, - - PowerPoint PPT Presentation

Models of ice sheet dynamics and meltwater lubrication Ian Hewitt, University of Oxford Thanks to: Christian Schoof, Mauro Werder, Gwenn Flowers, John Fell Fund, ERC Antarctica B B ' West Antarctica 4,000 Ellsworth Ice Elevation (m)


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Models of ice sheet dynamics and meltwater lubrication

Ian Hewitt, University of Oxford Thanks to: Christian Schoof, Mauro Werder, Gwenn Flowers, John Fell Fund, ERC

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30°W 60°W 60°W 60°W 90°W 120°W 120°E 120°E 120°E 90°E 90°E 90°E 7 ° S 8 ° S 60°E 60°E 60°E 30°E 0°E 150°W 150°E 150°E 150°E 180°E

Ice velocity (m year–1)

1,000 100 10 <1.5

B B' C' C

Ocean Ice Land 4,000 2,000 (MSL) 0

  • 2,000

Elevation (m) West Antarctica

B' B

Ronne Ice Shelf Ellsworth Mountains Bentley Subglacial Trench Ross Ice Shelf Vertical exaggeration x80 Gunnerus Bank

  • 2,000

(MSL) 0 2,000 4,000

Elevation (m)

C C'

Gamburtsev Subglacial Mountains Vincennes Subglacial Basin Astrolabe Subglacial Basin

East Antarctica

Vertical exaggeration x80 Vostok Subglacial Highlands Aurora Subglacial Basin

Antarctica

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Ice sheets in climate models

Most climate models have a static ice sheet The ice sheet stores and releases water according to surface energy balance Some interesting feedbacks are (at least potentially!) not captured

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Models of ice sheet dynamics

Stokes flow

r · u ∂τij ∂xj ∂p ∂xi = ρgi r · u = 0

Ice Bedrock

pni + τijnj = 0 ◆

x z Dij = 1 2 ✓∂ui ∂xj + ∂uj ∂xi ◆ n ⇡ 3 ⇡ A = A(T)

Rheology

q τij = A−1/nD1/n−1Dij ✓ D = q

1 2DijDij

τ b = f(Ub)ub Ub

surface bed Boundary conditions bed

pni + τijnj = 0 ◆

surface

(δij ninj)τjknk = f(Ub)(δij ninj)ui Ub z = s z = b ∂s ∂t + u∂s ∂x + v ∂s ∂y = w + a u ∂b ∂x + v ∂b ∂y = w − m

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Reduced models (depth-integrated)

  • ∂H

∂t + r · (Hu) = a m Z ∂s ∂t r ·

  • (s b)n+2|rs|n−1rs
  • = a m

Shallow ice approximation Shallow stream approximation

z = s z = b z = b z = s f(Ub) u Ub = ρgH ∂s ∂x + ∂ ∂x  ηH ✓ 4∂u ∂x + 2∂v ∂y ◆ + ∂ ∂y  ηH ✓∂u ∂y + ∂v ∂x ◆ f(Ub) v Ub = ρgH ∂s ∂y + ∂ ∂x  ηH ✓∂u ∂y + ∂v ∂x ◆ + ∂ ∂y  ηH ✓ 2∂u ∂x + 4∂v ∂y ◆

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Inverse methods

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Inversion for basal slipperiness (frozen-time problem)

f(Ub) = βUb

Assume a linear friction law Basal boundary condition Forward problem: given geometry, temperature & basal slipperiness, determine ice velocity

τ b = β(x)ub

Inverse problem: use observed ice velocity to infer basal slipperiness

J (β) = 1 2 Z |u − uobs|2 dV + R(β)

Stokes flow

r · u ∂τij ∂xj ∂p ∂xi = ρgi r · u = 0

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Isaac et al 2015

Inferred basal slipperiness Observations Model Surface velocity

Inversion for basal slipperiness

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−500 500 1,000 2,000 1,500 Bed elevation (m) 6 ° N 65° N 70° N 75° N 80° N 70° W 60° W 50° W 40° W 3 ° W 300 km 20 km 20 km 50 km

c b a d e f

30 km 30 km 20 km

Inversion for bed topography (assumes steady state)

Morlighem et al 2014

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Future

Assimilate time-dependent observations Make use of more observations - eg. internal radar layers

Duncan Young / UTIG

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Sliding

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Microscopic view of a ‘hard’ bed

β ub τ b

A film of water exists between ice and the underlying bedrock, allowing slip Resistance comes from the roughness of the bedrock

β ub τ b =

‘Cavitation’ occurs in the lee of bumps

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Nye’s sliding theory

Take Fourier transform

⇤ k∗ = ρiL 4kCη ⇥1/2

  • 4ψ = 0

  • τb = ηiUb

k2

π ⇤ ∞ ˆ Zb(k)k3 k2 + k2

dk

Stokes flow

ν 1

Fourier transform of bed profile, i.e. power spectrum

  • ˆ

Zb(k) = lim

M→∞

1 M

  • ⌅ M

−M

Zb(x)eikx dx

  • Nye 1969, Fowler 1986, Schoof 2005
  • 4ψ = 0

Stokes flow

ν 1 ⌅

Theory can be extended to account for cavitation Riemann-Hilbert problem

→∞

τb = Nf ⇥Ub N ⇤ ⇥ ⇤

Newtonian ice

2T = 0

Heat equation

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β ub τ b β ub

Sliding laws

Hard bedrock Cavities Soft sediments

β ub τ b τ b

τb = RU 1/m

b

τb = µN

⇧b = µN

  • Ub

Ub + ⇤AN n ⇥1/n

⇥ τb/N Ub/N n ⇥ τb/N Ub/N n τb Ub

(plastic)

τb = CN qU p

b

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Subglacial water

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A distributed drainage model

h ∂h ∂t + r · q = m + r φ = ρgb + pw q = K(h)rφ z = s z = b φ ⇡ ρgs + (ρw ρ)gb

Basal water ‘Water table’ Ice surface

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10 m

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Turbulent dissipation causes channelisation

S

h

‘Wormholing’ Mechanical erosion Chemical erosion (eg limestone caves) Analogues

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Cordillera Blanca, Peru

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Creep Melting

Subglacial conduits

Röthlisberger 1972, Nye 1976

Cross-sectional area evolution

M = 1 ρwL ⇤ ⇤ ⇤ ⇤Q∂φ ∂s ⇤ ⇤ ⇤ ⇤ ⇤ ⇤ ∂S ∂t = ρw ρi M − 2A nn S|N|n−1N ⇤ ⇤

Melting

∂S ∂t + ∂Q ∂s = M + qin

Mass conservation Energy

T ≈ 2.5 K

Flux

⇤ ⇤ ⇤ ⇤ ⇤ ⇤ ⇤ ⇤ Q = −KcSα ⇤ ⇤ ⇤ ⇤ ∂φ ∂s ⇤ ⇤ ⇤ ⇤

−1/2 ∂φ

∂s

z = s z = b ⇡

  • φ = ρgs + (ρw ρ)gb N

gH ⇠ cpT ⇠ gH ⇠ φL ⇠ H ⇡ 1 km ⇡ φ ⇡ 0.03

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Creep Melting

∂S ∂t C2S α > 1

Unstable equilibrium Mass conservation prevents unbounded growth ... but neighbouring channels compete with one other

Q ∂S ∂t = C1SαΨ3/2 C2SN n

Subglacial conduits

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Schoof 2010

a

Melt Creep closure

b

Sliding Creep closure j i

  • Conduits

Conduit network

  • Water flow

Increasing steady input

∂t

  • ∂S

∂t = C1SαΨ3/2 C2SN n + C3Ub

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S

h

A hybrid sheet-conduit drainage model

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5 10 15 20

t = 50d

a

4 8 8

10 20 30 40 50 5 10 15 20

t = 500d

c

4 8 x (km)

5 10 15 20

t = 150d

b

4 8 y (km)

60 10 20 30 40 50 60

Werder et al 2013 Water flow

A hybrid sheet-conduit drainage model

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Meltwater lubrication

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Seasonal ice velocity modulation

Sole et al 2013

Time Ice speed

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Runoff [ mm / d ] Time J A J O J

Subglacial drainage model coupled to ice flow model

Annual cycle of surface melt runoff routed into moulins τb = CUbN

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Time Ice speed Subglacial discharge (areal m2/s)

Hewitt 2013, EPSL

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Landforms

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Bridgenorth Esker

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Storrar et al 2014

Eskers beneath Laurentide ice sheet

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Summary Lots of interesting fluid phenomena going on in ice sheets! Inverse methods increasingly useful for fitting models to data

  • assimilating over time is the next step

Forecasting models still do not resolve important feedbacks

  • detailed studies of these needed
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Temperature

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Ice temperature

✓ ◆ ρwL ✓∂φ ∂t + u · rφ ◆ + ρwLr · j = τij ˙ εij, T = Tm, φ > 0 ρc ✓∂T ∂t + u · rT ◆ = r · (krT) + τij ˙ εij, φ = 0, T  Tm ✓ ◆

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T [ C ] φ [ % ]

  • 10
  • 5

2 4

T [ C ] φ [ % ]

  • 10
  • 5

2 4

‘Standard’ enthalpy gradient model Compaction pressure model

Polythermal ice