Mechanical Engineering Drawing / MECH 211/M
- Lecture #5; Chapter 19
; p
- Dr. John Cheung
Mechanical Engineering Drawing MECH 211/M / Lecture #5; Chapter 19 - - PowerPoint PPT Presentation
Mechanical Engineering Drawing MECH 211/M / Lecture #5; Chapter 19 ; p Dr. John Cheung Lecture 4 summary Lecture 4 summary Dihedral angle Line true length point view. ed a a g e e t ue e gt po t e . Plane
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Viewing parallel to TL ‐ Point
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Fi d T l th P j t ll l t TL P i t
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Find True length. Project parallel to TL – Point. Find the minimum distance between point and true length.
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1 D f ldi li b i 1. Draw folding line, obtain true length line 1‐2. 2. Draw FL perpendicular to true length obtain point true length, obtain point view of Line 1‐2. 3. Draw perpendicular line from Point 1,2 to line 3‐4. from Point 1,2 to line 3 4. This line = shortest distance between the two skew lines.
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g ‘A’ and intersecting two skew lines.
3 T L of Line 1 2 then point
view of line 1‐2.
view 1‐2 and A to Line 3‐4, form Line C‐A‐B.
to Auxiliary 1, Front and Top views Top views.
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2 3 7
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1. Given line 4‐5 in top view. 2. Lines 4‐5 and 1‐2 not parallel, hence must intersect at Point 6. 3. Extend line 4‐5 until it crosses line 2‐3, then yield Point 7. 4 Cutting plane method Project 4. Cutting plane method – Project Point 6 to Line 1‐2 and Point 7 to Line 2‐3 in front view. 5 Joining points 4 5 6 and 7 to 5. Joining points 4, 5, 6 and 7 to form the corresponding Line 4‐5 in front view.
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Locate Point 4 in Top View in Plane 1 2 3
Locate Point 4 in Top View in Plane 1‐2‐3
intersects Line 1‐2 in Front view, then yield Point 5.
1‐2 in Top view.
view.
3 5 in Front View to 3‐5 in Front View to Line 3‐5 in Top view. The intersection is Point 4 in Top View
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Point 4 in Top View.
ll l parallel to Line 2‐3 in Front view. Intersection = P5.
Top View yields the corresponding P5 Top View yields the corresponding P5 in TV.
to Line 2‐3 in TV to Line 2 3 in TV.
starting with P5. Intersection = P4 in TV.
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10mm above P2 and 12mm behind P3.
Point P is somewhere along Line 4‐5.
P is somewhere along he line along he line 12mm behind P3.
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g p Use Line 4‐5 in Front view as Cutting plane.
and P5 to Line 2 3 in and P5 to Line 2‐3 in TV .
view.
behind P3) as CP.
and P7 to Line 1‐3 in and P7 to Line 1‐3 in FV.
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4‐5 and 6‐7 is Point P.
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1. Given Plane 1‐2‐3 and Li 4 5 Line 4‐5. 2. Find piercing point between Line 4‐5 and Plane 1 2 3 Plane 1‐2‐3.
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1. Using edge view h d method. 2. Find TL in Front view. 3. Draw auxiliary view parallel to TL i e Edge parallel to TL, i.e. Edge view of Plane 1‐2‐3. 4. Extend Line 4‐5 until it crosses Plane EV. The crosses Plane EV. The intersection = piercing point.
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1. Using edge view h d method. 2. Project piercing point back to Front View and Top view Top view. 3. Check distance D1 between the auxiliary and Top views for and Top views for accuracy.
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1. Using CP method. 2 C i l AA 2. Cutting plane AA containing Line 4‐5. 3. Cutting Line 6‐7 in Plane 1 2 3 Plane 1‐2‐3. 4. Line 6‐7 and Line 4‐5 in the sane plane – must intersect. intersect. 5. Project P6 and P7 to Front View. Draw Line 6‐7. 6. Intersection between Line 4‐5 and 6‐7 in FV = Piercing point.
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7. Project piercing point to TV.
1. Using CP method. 2 D i h i ibili f 2. Determine the visibility of line and plane using the skew lines method learnt in Lecture 4
A B
in Lecture 4. 3. View A, looking down to FV, see Line 2‐3 first, So, Line 2‐3 on top in TV .
A B
Line 2 3 on top in TV . 4. View B, looking up to TV, see Line 2‐3 first, so Line 2‐3 is above and Line 4‐5 hidden in FV.
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3 d Pl 4 5 3 and Plane 4‐5‐ 6.
straight line containing all points common points common to the two planes.
p and follow with its EV.
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points = Piercing points.
3 d Pl 4 5 3 and Plane 4‐5‐ 6.
piercing points piercing points to TV and FV.
connecting the connecting the two piercing points.
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3 d Li 5 6 3 and Line 5‐6.
True size method method.
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