Lecture 2.5: Linear differential equations Matthew Macauley - - PowerPoint PPT Presentation

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Lecture 2.5: Linear differential equations Matthew Macauley - - PowerPoint PPT Presentation

Lecture 2.5: Linear differential equations Matthew Macauley Department of Mathematical Sciences Clemson University http://www.math.clemson.edu/~macaule/ Math 2080, Differential Equations M. Macauley (Clemson) Lecture 2.5: Linear differential


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Lecture 2.5: Linear differential equations

Matthew Macauley Department of Mathematical Sciences Clemson University http://www.math.clemson.edu/~macaule/ Math 2080, Differential Equations

  • M. Macauley (Clemson)

Lecture 2.5: Linear differential equations Math 2080, ODEs 1 / 8

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Motivation

Recall

A first order ODE is linear if it can be written as y ′(t) + a(t)y(t) = f (t) , and moreover, is homogeneous if f (t) = 0. Linear differential equations and their solutions have a lot of structure. Understanding the structure helps demystify these objects and reveals their simplicity. We will see two “Big Ideas” in this lecture, and these will re-appear when we study 2nd order ODEs. Along the way, we will uncover a neat short-cut for solving ODEs that is usually not covered in a differential equation course.

  • M. Macauley (Clemson)

Lecture 2.5: Linear differential equations Math 2080, ODEs 2 / 8

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Big idea #1: homogeneous ODEs

Big idea 1

Suppose a homogeneous ODE y ′ + a(t)y(t) = 0 has solutions y1(t) and y2(t). Then C1y1(t) + C2y2(t) is a solution for any constants C1 and C2.

  • M. Macauley (Clemson)

Lecture 2.5: Linear differential equations Math 2080, ODEs 3 / 8

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Big idea #2: inhomogeneous ODEs

Big idea 2

Consider an inhomogeneous ODE y ′ + a(t)y(t) = f (t). If yp(t) is any particular solution, and yh(t) is the general solution to the related “homogeneous equation”, y ′ + a(t)y = 0, then the general solution to the inhomogeneous equation is y(t) = yh(t) + yp(t) .

  • M. Macauley (Clemson)

Lecture 2.5: Linear differential equations Math 2080, ODEs 4 / 8

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A nice shortcut

Applications of y = yh + yp

Solving for yh(t) is usually easy (separate variables). Sometimes, it’s easy to find some yp(t) by inspection. When this happens, we automatically have the general solution!

Example 1

Solve T ′ = k(72 − T).

  • M. Macauley (Clemson)

Lecture 2.5: Linear differential equations Math 2080, ODEs 5 / 8

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Exploiting our shortcut

Example 2

Solve y ′ = 2y + t.

  • M. Macauley (Clemson)

Lecture 2.5: Linear differential equations Math 2080, ODEs 6 / 8

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Exploiting our shortcut

Example 3

Solve y ′ = 2y + e3t.

  • M. Macauley (Clemson)

Lecture 2.5: Linear differential equations Math 2080, ODEs 7 / 8

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An interesting observation

  • M. Macauley (Clemson)

Lecture 2.5: Linear differential equations Math 2080, ODEs 8 / 8