Independence
- f
Characters
I :
Fixed
fields
- f
subgroups
Lattimer subsets of Art IE ) field function for Fixed & sub - - PowerPoint PPT Presentation
of Characters Independence fields Fixed of I : subgroups Lattimer subsets of Art IE ) field function for Fixed & sub extensions of E subsets et Aut ( E ) lie , inclusion reversing ) " contravariant " not too small ) (
Independence
Characters
Fixed
fields
subgroups
Lattimer
Fixed
field
function
for
subsets of Art IE)
&
subextensions of E
subsets et Aut ( E)→
" contravariant "lie , inclusion reversing)
→ [ E
: EG ) 3141(fixed feild, not too small)
necessary
tool
: ifEr . .
. ., rn) EAT LE) , then99 .
. -son)are
" EWut happens
when
we stty
fixed
fields
subgroups
→
can
we
say
more
about
IE
: EG) andIGI ?
→
is
fixed field function
subgraph
" injective " ?theorem
( Bigness
matches
her subgroups)
Suppose
GE Atle )
. ThenIE : EG)
= IGI .PI
Wc already
know
CE
: EG)> IGI
.For
contradiction
,assume
CE : EG)
> 1Gt
.lets
write
G
, so
1Gt - n
.By
assumption
we
have
{ e , .
. ., Ent . ) E Ethat
are
EG
we'll
create
a
linear system of equations :
L
=Tile
;
) x , t
legit
,)xnt , = Orace ,)x , t
.lentil xnt,
= 0Since there
are
more
variables
than equations
in
. £ ,we
know
he
has
a
non
solution
.Let
r
be
The
minimal
number of
nonzero
elements
in
a
nontrvinl
solution
to
ye
.let's
create
a
" nice "solution
to
L
with
r may
nonzero
components
.By
rearranging
columns of Lo
, we
can
assume
we have
a
solution
( x,,
.. . .,Xr , O,with all xito . Scaling by
Xi
'still
produces
a
solution
( l, ya ,
. . ., yr , q .with
all
gi to
.w
Xzxi
'Focus
row
corresponding
to
idq
,
we see
idle , ) Lt idler) yzt
id Cena) yay .
If
all
git EG
, This
violates
EG
So :
some
yi
has
yi
Ef EG
After
carrying
columns
,
can
assume
yr # EG
.Hence , there
exists
some
ri EG
with
rilyr) t yr
.let
ri
act
each
row
L
to
create
a
new
system
grid
: {tri ( T , (4) Xi
t
i.
to , lentil xnti )
=D
Oi ( Tale,)x, t
=D
= {circle .)oi(x ,) t;
(e.) ri (a) t
① (x . ,
. - . xut.)solves L
iff
( rlx . ) .
. . .ir/xutiDsohesriL② since
GEAVHE)
,Erin ,
. - i , rion) :{r, , . . ., on)Hence
we
have
( x . .
. . , Xu , )solves L
iff
(rilx .) ,
. . ., rilxnti))solves
L
In
particular
( l , ya,
rilyr) , rill, rill)
⇐ ( O , yaL
.to since
It
has
too few
non
terms
. →←TIX
Ouranginalypictre
G
HH et Aut ( E)
subextensions of E
subgroup'
properties
. contravariantCos ( Fixed field function is injection
If
it
, Ge Aut CE)have
E
't = EG
, then H=G .
PI
claim
E
"
gives
E " "
"
= E "( you
can
prove This
as
"funexercise
")So
:htt = IE
: E't)
= ( E : E"")
> I Hv G)
So
GE H
.Run the
same argument
but
reverse
the
roles of
H & G ,
we get
HEG
.µ
Ouronginalypictre
G
HH et Aut ( E)
subextensions of E
subgroup'
properties
. contravariant