h h h h C 3 = H ( M ) IV= C 0 C 1 C 2 C 3 256 1 Davis-Meyer 2 - PowerPoint PPT Presentation

May 09, 2023 •306 likes •365 views

MerkleDamgrd Hash Pad( M ) determines M |Pad( M )| is a positive multiple of n | M |=| M | |Pad( M )|=|Pad( M )| | M || M | last(Pad( M )) last(Pad( M )) 100 512 M 1 M 2 M 3 M 4 Pad 512 10*| M | M 1 M 2 M 3 M 4 h

Merkle–Damgård Hash Pad( M ) determines M |Pad( M )| is a positive multiple of n | M |=| M ′| ⇒ |Pad( M )|=|Pad( M ′)| | M |≠| M ′| ⇒ last(Pad( M )) ≠ last(Pad( M ′)) 100 512 M 1 M 2 M 3 M 4 Pad 512 10*| M | M 1 M 2 M 3 M 4 h h h h C 3 = H ( M ) IV= C 0 C 1 C 2 C 3 256 1
Davis-Meyer 2
algorithm SHA256BC (w, a b c d e f g h) // blockcipherunderlying SHA-256 (k[0],…, k[63]) ← constants Regard w as words w[0]...w[15] for i ← 16 to 63 s0 ← (w[i-15] >>> 7) ⊕ (w[i-15] >>> 18) ⊕ (w[i-15] >>> 3) s1 ← (w[i-2] >>> 17) ⊕ (w[i-2] >>> 19) ⊕ (w[i-2] >>> 10) w[i] ← w[i-16] + s0 + w[i-7] + s1 for i ← 0 to 63 S1 ← (e >>> 6) ⊕ (e >>> 11) ⊕ (e >>> 25) ch ← (e ∧ f) ⊕ (~e ∧ g) temp1 ← h + S1 + ch + k[i] + w[i] S0 ← (a >>> 2) ⊕ (a >>> 13) ⊕ (a >>> 22) maj ← (a ∧ b) ⊕ (a ∧ c) ⊕ (b ∧ c) temp2 ← S0 + maj (a,b,c,d,e,f,g,h) ← (temp1+temp2,a,b,c,d+temp1,e,f,g) return a || b || c || d || e || f || g || h 3
One round (of 64) of the blockcipher sha256 underlying SHA256 4
SHA-3 – Keccak [Guido Bertoni, Joan Daemen, Michaël Peeters, Gilles Van Assche] r=1088 bits c=512 bits 5

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