Gov 51: Bayes Rule
Matthew Blackwell
Harvard University
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Gov 51: Bayes Rule Matthew Blackwell Harvard University 1 / 8 - - PowerPoint PPT Presentation
Gov 51: Bayes Rule Matthew Blackwell Harvard University 1 / 8 QAnon You meet a man named Steve and he tells you that he is a Republican. You have been interested in meeting someone who believes in the QAnon conspiracy theory. Given what you
Matthew Blackwell
Harvard University
1 / 8
You meet a man named Steve and he tells you that he is a Republican. You have been interested in meeting someone who believes in the QAnon conspiracy theory. Given what you know about Steve, would you guess that he believes in QAnon or not?
be Republicans.
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You meet a man named Steve and he tells you that he is a Republican. You have been interested in meeting someone who believes in the QAnon conspiracy theory. Given what you know about Steve, would you guess that he believes in QAnon or not?
be Republicans.
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You meet a man named Steve and he tells you that he is a Republican. You have been interested in meeting someone who believes in the QAnon conspiracy theory. Given what you know about Steve, would you guess that he believes in QAnon or not?
be Republicans.
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Qanon nonbelievers
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Qanon nonbelievers Qanon believers
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Qanon nonbelievers Qanon believers Qanon Republicans
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Qanon nonbelievers Qanon believers Qanon Republicans non-Qanon Republicans
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Chance a random Republican believes QAnon =
Qanon nonbelievers Qanon believers Qanon Republicans non-Qanon Republicans
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Chance a random Republican believes QAnon =
Qanon nonbelievers Qanon believers Qanon Republicans non-Qanon Republicans
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Chance a random Republican believes QAnon =
Qanon nonbelievers Qanon believers Qanon Republicans non-Qanon Republicans
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Chance a random Republican believes QAnon =
Qanon nonbelievers Qanon believers Qanon Republicans non-Qanon Republicans ℙ(혘)
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Chance a random Republican believes QAnon =
Qanon nonbelievers Qanon believers non-Qanon Republicans ℙ(혙∣혘) ℙ(혘)
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ℙ(혙∣혘)ℙ(혘) + ℙ(혙∣혘)ℙ(혘)
Chance a random Republican believes QAnon =
Qanon nonbelievers Qanon believers non-Qanon Republicans ℙ(혙∣혘) ℙ(혘)
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ℙ(혙∣혘)ℙ(혘) + ℙ(혙∣혘)ℙ(혘)
Chance a random Republican believes QAnon =
Qanon nonbelievers Qanon believers non-Qanon Republicans ℙ(혙∣혘) ℙ(not 혘) ℙ(혘)
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ℙ(혙∣혘)ℙ(혘) + ℙ(혙∣혘)ℙ(혘)
Chance a random Republican believes QAnon =
Qanon nonbelievers Qanon believers ℙ(혙∣혘) ℙ(혙∣not 혘) ℙ(not 혘) ℙ(혘)
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ℙ(혙∣not 혘)ℙ(not 혘) ℙ(혙∣혘)ℙ(혘) + ℙ(혙∣혘)ℙ(혘)
Chance a random Republican believes QAnon =
Qanon nonbelievers Qanon believers ℙ(혙∣혘) ℙ(혙∣not 혘) ℙ(not 혘) ℙ(혘)
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ℙ(𝘉 ∣ 𝘊) = ℙ(𝘊 ∣ 𝘉)ℙ(𝘉) ℙ(𝘊) = ℙ(𝘊 ∣ 𝘉)ℙ(𝘉) ℙ(𝘊 ∣ 𝘉)ℙ(𝘉) + ℙ(𝘊 ∣ not 𝘉)ℙ(not 𝘉)
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ℙ(𝘉 ∣ 𝘊) = ℙ(𝘊 ∣ 𝘉)ℙ(𝘉) ℙ(𝘊) = ℙ(𝘊 ∣ 𝘉)ℙ(𝘉) ℙ(𝘊 ∣ 𝘉)ℙ(𝘉) + ℙ(𝘊 ∣ not 𝘉)ℙ(not 𝘉)
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ℙ(𝘉 ∣ 𝘊) = ℙ(𝘊 ∣ 𝘉)ℙ(𝘉) ℙ(𝘊) = ℙ(𝘊 ∣ 𝘉)ℙ(𝘉) ℙ(𝘊 ∣ 𝘉)ℙ(𝘉) + ℙ(𝘊 ∣ not 𝘉)ℙ(not 𝘉)
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ℙ(QAnon ∣ Republican)
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ℙ(QAnon ∣ Republican)
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ℙ(QAnon ∣ Republican)
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ℙ(QAnon ∣ Republican)
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ℙ(QAnon ∣ Republican)
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ℙ(QAnon ∣ Republican)
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ℙ(QAnon ∣ Republican)
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ℙ(QAnon ∣ Republican)
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ℙ(𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) + ℙ(𝘘𝘜|not 𝘋)ℙ(not 𝘋) = (𝟣.𝟪 × 𝟣.𝟣𝟣𝟤) + (𝟣.𝟣𝟨 × 𝟣.𝟬𝟬𝟬) = 𝟣.𝟣𝟨𝟤
ℙ(𝘋 ∣ 𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) ℙ(𝘘𝘜) = 𝟣.𝟪 × 𝟣.𝟣𝟣𝟤 𝟣.𝟣𝟨𝟤 ≈ 𝟣.𝟣𝟤𝟧
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ℙ(𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) + ℙ(𝘘𝘜|not 𝘋)ℙ(not 𝘋) = (𝟣.𝟪 × 𝟣.𝟣𝟣𝟤) + (𝟣.𝟣𝟨 × 𝟣.𝟬𝟬𝟬) = 𝟣.𝟣𝟨𝟤
ℙ(𝘋 ∣ 𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) ℙ(𝘘𝘜) = 𝟣.𝟪 × 𝟣.𝟣𝟣𝟤 𝟣.𝟣𝟨𝟤 ≈ 𝟣.𝟣𝟤𝟧
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ℙ(𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) + ℙ(𝘘𝘜|not 𝘋)ℙ(not 𝘋) = (𝟣.𝟪 × 𝟣.𝟣𝟣𝟤) + (𝟣.𝟣𝟨 × 𝟣.𝟬𝟬𝟬) = 𝟣.𝟣𝟨𝟤
ℙ(𝘋 ∣ 𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) ℙ(𝘘𝘜) = 𝟣.𝟪 × 𝟣.𝟣𝟣𝟤 𝟣.𝟣𝟨𝟤 ≈ 𝟣.𝟣𝟤𝟧
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ℙ(𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) + ℙ(𝘘𝘜|not 𝘋)ℙ(not 𝘋) = (𝟣.𝟪 × 𝟣.𝟣𝟣𝟤) + (𝟣.𝟣𝟨 × 𝟣.𝟬𝟬𝟬) = 𝟣.𝟣𝟨𝟤
ℙ(𝘋 ∣ 𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) ℙ(𝘘𝘜) = 𝟣.𝟪 × 𝟣.𝟣𝟣𝟤 𝟣.𝟣𝟨𝟤 ≈ 𝟣.𝟣𝟤𝟧
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ℙ(𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) + ℙ(𝘘𝘜|not 𝘋)ℙ(not 𝘋) = (𝟣.𝟪 × 𝟣.𝟣𝟣𝟤) + (𝟣.𝟣𝟨 × 𝟣.𝟬𝟬𝟬) = 𝟣.𝟣𝟨𝟤
ℙ(𝘋 ∣ 𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) ℙ(𝘘𝘜) = 𝟣.𝟪 × 𝟣.𝟣𝟣𝟤 𝟣.𝟣𝟨𝟤 ≈ 𝟣.𝟣𝟤𝟧
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ℙ(𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) + ℙ(𝘘𝘜|not 𝘋)ℙ(not 𝘋) = (𝟣.𝟪 × 𝟣.𝟣𝟣𝟤) + (𝟣.𝟣𝟨 × 𝟣.𝟬𝟬𝟬) = 𝟣.𝟣𝟨𝟤
ℙ(𝘋 ∣ 𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) ℙ(𝘘𝘜) = 𝟣.𝟪 × 𝟣.𝟣𝟣𝟤 𝟣.𝟣𝟨𝟤 ≈ 𝟣.𝟣𝟤𝟧
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ℙ(𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) + ℙ(𝘘𝘜|not 𝘋)ℙ(not 𝘋) = (𝟣.𝟪 × 𝟣.𝟣𝟣𝟤) + (𝟣.𝟣𝟨 × 𝟣.𝟬𝟬𝟬) = 𝟣.𝟣𝟨𝟤
ℙ(𝘋 ∣ 𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) ℙ(𝘘𝘜) = 𝟣.𝟪 × 𝟣.𝟣𝟣𝟤 𝟣.𝟣𝟨𝟤 ≈ 𝟣.𝟣𝟤𝟧
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ℙ(𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) + ℙ(𝘘𝘜|not 𝘋)ℙ(not 𝘋) = (𝟣.𝟪 × 𝟣.𝟣𝟣𝟤) + (𝟣.𝟣𝟨 × 𝟣.𝟬𝟬𝟬) = 𝟣.𝟣𝟨𝟤
ℙ(𝘋 ∣ 𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) ℙ(𝘘𝘜) = 𝟣.𝟪 × 𝟣.𝟣𝟣𝟤 𝟣.𝟣𝟨𝟤 ≈ 𝟣.𝟣𝟤𝟧
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ℙ(𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) + ℙ(𝘘𝘜|not 𝘋)ℙ(not 𝘋) = (𝟣.𝟪 × 𝟣.𝟣𝟣𝟤) + (𝟣.𝟣𝟨 × 𝟣.𝟬𝟬𝟬) = 𝟣.𝟣𝟨𝟤
ℙ(𝘋 ∣ 𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) ℙ(𝘘𝘜) = 𝟣.𝟪 × 𝟣.𝟣𝟣𝟤 𝟣.𝟣𝟨𝟤 ≈ 𝟣.𝟣𝟤𝟧
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ℙ(𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) + ℙ(𝘘𝘜|not 𝘋)ℙ(not 𝘋) = (𝟣.𝟪 × 𝟣.𝟣𝟣𝟤) + (𝟣.𝟣𝟨 × 𝟣.𝟬𝟬𝟬) = 𝟣.𝟣𝟨𝟤
ℙ(𝘋 ∣ 𝘘𝘜) = ℙ(𝘘𝘜 ∣ 𝘋)ℙ(𝘋) ℙ(𝘘𝘜) = 𝟣.𝟪 × 𝟣.𝟣𝟣𝟤 𝟣.𝟣𝟨𝟤 ≈ 𝟣.𝟣𝟤𝟧
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