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First-Principles Prediction of Acidities in the Gas and Solution Phase
- Prof. Michelle Coote and Dr Junming Ho
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First-Principles Prediction of Acidities in the Gas and Solution - - PDF document
First-Principles Prediction of Acidities in the Gas and Solution Phase Prof. Michelle Coote and Dr Junming Ho 1 Why are Chemists interested in p K a s? 2 1 Chemical Speciation Oxicams (polyprotic acids) are non-steroidal anti-
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S N O O CH3 OH N H O S N O O CH3 O N H O S N O O CH3 OH N H O zwitterion (O) neutral product S N O O CH3 OH N O zwitterion (N) N H S N S N H S N H S S N O O CH3 O N H O N S CATION NEUTRAL ANION Ka1 Ka2 K1ZO K1N K1ZN K2ZO K2N K2ZN KT1 KT2 CH3 CH3 CH3 CH3 CH3
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N NH2 NH2 H2N 1+ 2+ 3+ 4+ ???
fA = 1 Do ; fHA+ = [H+] K1Do ; fHA2
2+ = [H+]2
K1K2Do ; fHA3
3+ =
[H+]3 K1K2K3Do ; fHA4
4+ =
[H+]4 K1K2K3K4Do
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*
!Gsoln
!Gsolv(HA) !Gsolv(H+) !Gsolv(A-) !Ggas
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j
i
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gas to standard state of 1 mol L-1
*
°
pressure (or concentration) of the ideal gas changes
HA (aq) H+(aq) + A-(aq)
!G*soln
HA (g)
!G*solv(HA) !G*solv(H+) !G*solv(A-) !Gogas
H+(g) + A-(g)
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!GS
* (HF) = "31.7 kJ/mol
!GS
* (F") = "439.3 kJ/mol
!GS
* (H+) = "1112.5 kJ/mol
HF(g) # H+(g)+F-(g); !Go=1529 kJ/mol
pKa = !Gsoln
*
RT ln(10)
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!GS
* (HF) = "31.7 kJ/mol
!GS
* (F") = "439.3 kJ/mol
!GS
* (H+) = "1112.5 kJ/mol
HF(g) # H+(g)+F-(g); !Go=1529 kJ/mol
pKa = !Gsoln
*
RT ln(10) !Gsoln
*
= !Ggas
* (F ") + !GS "(H +) " !GS * (HF) +RT ln( %
RT) =17.1 kJ mol-1 pKa = !Gsoln
*
RT ln(10) = 2.9
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!Gacid
= Go(H +) + E(A-) - E(HA) + Gcorr (A") "Gcorr (HA)
Ideal gas partition functions Electronic energies From MOT or DFT methods (Single-point; high level) Thermal corrections (including ZPVE) based on the harmonic
model (opt + freq; low level)
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Calculated gas phase acidities using different levels of theory for electronic energies. Calculations were based on B3LYP/6-31+G(d) geometries and corresponding thermal corrections
0.0 10.0 20.0 30.0 40.0 50.0 60.0 BP86 B971 B3LYP BMK M05-2X HF MP2 G3MP2+ CBS-QB3
MAD (neutrals) ADmax (neutrals) MAD (cations) ADmax (cations)
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Molecular dynamics simulations are expensive Continuum models are much more cost effective and can deliver comparable, if not better accuracy.
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Main parameters: (1) Level of theory – HF? DFT? MP2? Basis set?
(2) Choice of radii {rH, rC, rN, rO etc}
* = !GES + !Gcav + !Gdisp"rep
Almost all continuum models contain parameters, e.g. {ri}, which have been
Semi-empirical nature of these models means that it is important to adhere to parameterization protocol for best accuracy.
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The Conductor-like Polarisable Continuum Model. (1) Level of theory: HF/6-31G(d) for neutrals and HF/6-31+G(d) for ions (2) UAHF: The radius of each atom contains additional parameters which takes into account the formal charge and hybridisation of the atom. (3) Accuracy: ~ 4 kJ mol-1 for neutrals and 15 kJ mol-1 for ions.
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Variational PCM results ======================= <psi(0)| H |psi(0)> (a.u.) = -76.010631 <psi(0)|H+V(0)/2|psi(0)> (a.u.) = -76.021150 <psi(0)|H+V(f)/2|psi(0)> (a.u.) = -76.022089 <psi(f)| H |psi(f)> (a.u.) = -76.009608 <psi(f)|H+V(f)/2|psi(f)> (a.u.) = -76.022097 Total free energy in solution: with all non electrostatic terms (a.u.) = -76.020988
(Unpolarized solute)-Solvent (kcal/mol) = -6.60 (Polarized solute)-Solvent (kcal/mol) = -7.84 Solute polarization (kcal/mol) = 0.64 Total electrostatic (kcal/mol) = -7.19
Cavitation energy (kcal/mol) = 4.45 Dispersion energy (kcal/mol) = -5.15 Repulsion energy (kcal/mol) = 1.40 Total non electrostatic (kcal/mol) = 0.70 What we want! ΔG*s DeltaG (solv) (kcal/mol) = -6.50
This is ΔG*s(H2O)
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The above example calculates the solvation free energy by performing BOTH solvent and gas phase calculation on the solution-optimised geometry. Provided that solution and gas phase geometries are very similar, this is a reasonable approximation. For conformationally flexible molecules, where solution phase and gas phase geometries differ significantly, effects of geometrical relaxation needs to be added into ΔGs. !Gsolv
*
" !Gsolv
*
(soln geom) + !Erelax = !Gsolv
*
(soln geom) + (Egas//soln - Egas//gas)
Example 2. Given the experimental gas phase acidity acetic acid (CH3COOH) and acetone (CH3COCH3) are 1427 and 1514 kJ mol-1 respectively, calculate the aqueous pKa values of each acid using solvation energies obtained from the CPCM-UAHF model at the HF/6-31G(d) level
Tip: Start with the gas phase optimized geometry and use it as the input geometry for your solvation calculation.
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*
RTln(10) !Gsolv
*
(H+) = "1112.5 kJ / mol 20
H H C H H C O C H HMOLDEN MOLDEN MOLDEN MOLDEN MOLDEN MOLDEN MOLDEN MOLDEN MOLDEN MOLDEN MOLDEN MOLDEN MOLDEN MOLDEN MOLDEN MOLDEN
H H C H C O O H H H C H H C O C HMOLDEN MOLDEN MOLDEN
H H C H C O O21
Example 2. Given the experimental gas phase acidity acetic acid (CH3COOH) and acetone (CH3COCH3) are 1427 and 1514 kJ mol-1 respectively, calculate the aqueous pKa values of each acid using solvation energies obtained from the CPCM-UAHF model at the HF/6-31G(d) level
ΔG*s(acetone) = -3.8 kcal mol-1or -15.8 kJ mol-1 ΔG*s(enolate) = -63.9kcal mol-1or -267.4 kJ mol-1 ΔG*s(acetic) = -7.6 kcal mol-1or -31.6 kJ mol-1 ΔG*s(acetate) = -77.2 kcal mol-1or -323.1 kJ mol-1 ΔG*soln(acetone) = 1514 + (-267.4) + (-1112.5) - (-15.8) + 7.9 = 157.8 kJ mol-1 ΔG*soln(acetic) = 1427 + (-323.1) + (-1112.5) – (-31.6) + 7.9 = 30.9 kJ mol-1 pKa(acetone) = 27.6 cf. expt (19.2) pKa(acetic acid) = 5.4 cf. expt (4.8) 22
– Neutrals (error ~ 5 kJ mol-1) – Ions (Error >= 15 kJ mol-1)
therefore the good agreement is not surprising.
much larger.
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Isodesmic proton exchange method – Relies on structural similarity with HRef to maximise error cancellation in ΔGgas and ΔΔGsolv. – No need for ΔGs(H+)
HA(aq, 1M) + Ref-(aq, 1M) HRef(aq, 1M) + A-(aq, 1M)
!G*soln !G*gas "!G*solv(HA) !G*solv(HRef) !G*solv(A-)
HA(g, 1M) + Ref-(g, 1M) HRef(g, 1M) + A-(g, 1M)
"!G*solv(Ref-)
pKa(HA) = !Gsoln
*
RTln(10) + pKa(HRef)
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Example 3. Using a proton exchange scheme to improve the accuracy
Provided below are some organic molecules and their experimental gas phase and aqueous acidities (acidic proton in bold).
Acid !Go
acid(kJ/mol)
pKa CH3COOH 1427 4.8 HCN 1433 9.4 CH3COOCH3 1528 25 CH3NO2 1467 10.3 CH3OH 1569 15.5
(a) From the above Table, identify the acid that you would use to set up an isodesmic proton exchange reaction for calculating the pKa of acetone. (b) Construct a thermodynamic cycle for the proton exchange reaction and use it to calculate the pKa of acetone. You should use the CPCM-UAHF model for your solvation calculations (at the HF/6-31G(d) level of theory) and the gas phase acidity of acetone provided in the previous example.
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Example 3. Using a proton exchange scheme to improve the accuracy of a pKa calculation. Pick methylacetate!
O O O O O O (aq) (aq) (aq) (aq)
!G*soln !G*solv !G*solv !G*solv !G*solv
O O O O O O (g) (g) (g) (g)
!Gogas
ΔG*s(acetone) = -3.8 kcal mol-1or -15.8 kJ mol-1 ΔG*s(enolate) = -63.9kcal mol-1or -267.4 kJ mol-1 ΔG*s(methylacetate) = -3.5 kcal mol-1or -14.8 kJ mol-1 ΔG*s(enolate) = -62.1kcal mol-1or -259.9 kJ mol-1 ΔG*
soln = -20.5 kJ mol-1
pKa(HA) = !Gsoln
*
RTln(10) + pKa(HRef) = 21.4 26
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NH R1 R2 R3 R4 N R1 R2 R3 R4 + H+ !E (G3)
ONIOM APPROXIMATION !E(G3) " !ECORE(G3)+!EEX (MP2/L)
NH N + H !ECORE (G3) NH R1 R2 R3 R4 N + NH N R1 R2 R3 R4 + !EEX (MP2/L)