Cutting a part from many measures Nevena Pali 6th BMS Student - - PowerPoint PPT Presentation

cutting a part from many measures
SMART_READER_LITE
LIVE PREVIEW

Cutting a part from many measures Nevena Pali 6th BMS Student - - PowerPoint PPT Presentation

Cutting a part from many measures Nevena Pali 6th BMS Student Conference Nevena Pali Cutting a part from many measures 23.02.2018 1 / 16 Equivariant Topological Combinatorics Equivariant Topological Combinatorics Equivariant


slide-1
SLIDE 1

Cutting a part from many measures

Nevena Palić 6th BMS Student Conference

Nevena Palić Cutting a part from many measures 23.02.2018 1 / 16

slide-2
SLIDE 2

Equivariant Topological Combinatorics

slide-3
SLIDE 3

Equivariant Topological Combinatorics

slide-4
SLIDE 4

Equivariant Topological Combinatorics

slide-5
SLIDE 5

Equivariant Topological Combinatorics

slide-6
SLIDE 6

Equivariant Topological Combinatorics

slide-7
SLIDE 7

Equivariant Topological Combinatorics

G G

G

G G

slide-8
SLIDE 8

Equivariant Topological Combinatorics

G

G

G

slide-9
SLIDE 9

Equivariant Topological Combinatorics

G

G

G

slide-10
SLIDE 10

First example

Theorem (Ham Sandwich theorem, Banach 1938)

Any collection of d finite absolutely continuous measures in Rd can be simultaneously cut into two parts by one hyperplane cut in such a way that each part captures exactly one half of each measure.

Figure: from Curiosa Mathematica

Nevena Palić Cutting a part from many measures 23.02.2018 2 / 16

slide-11
SLIDE 11

First example

H H+ H− Rd

Nevena Palić Cutting a part from many measures 23.02.2018 3 / 16

slide-12
SLIDE 12

First example

H H+ H− Rd N S H Rd Rd+1

Nevena Palić Cutting a part from many measures 23.02.2018 3 / 16

slide-13
SLIDE 13

First example

Proof.

Sd \ {N, S} − → Rd p − → (µ1(H+

p ) − µ1(H− p ), . . . , µd(H+ p ) − µd(H− p ))

Nevena Palić Cutting a part from many measures 23.02.2018 4 / 16

slide-14
SLIDE 14

First example

Proof.

Sd − → Rd p − → (µ1(H+

p ) − µ1(H− p ), . . . , µd(H+ p ) − µd(H− p ))

Nevena Palić Cutting a part from many measures 23.02.2018 4 / 16

slide-15
SLIDE 15

First example

Proof.

Sd − → Rd p − → (µ1(H+

p ) − µ1(H− p ), . . . , µd(H+ p ) − µd(H− p ))

Assume that there is no solution, i.e., for every hyperplane H there is some 1 ≤ i ≤ d such that µi(H+) = µi(H−).

Nevena Palić Cutting a part from many measures 23.02.2018 4 / 16

slide-16
SLIDE 16

First example

Proof.

Sd − → Rd p − → (µ1(H+

p ) − µ1(H− p ), . . . , µd(H+ p ) − µd(H− p ))

Assume that there is no solution, i.e., for every hyperplane H there is some 1 ≤ i ≤ d such that µi(H+) = µi(H−). Sd − → Rd \ {0} − → Sd−1

Nevena Palić Cutting a part from many measures 23.02.2018 4 / 16

slide-17
SLIDE 17

First example

Proof.

Sd − → Rd p − → (µ1(H+

p ) − µ1(H− p ), . . . , µd(H+ p ) − µd(H− p ))

Assume that there is no solution, i.e., for every hyperplane H there is some 1 ≤ i ≤ d such that µi(H+) = µi(H−). Sd − → Rd \ {0} − → Sd−1 Group action! Sd − →Z2 Sd−1

Nevena Palić Cutting a part from many measures 23.02.2018 4 / 16

slide-18
SLIDE 18

First example

Let G be a group that acts on topological spaces X and Y . A map f : X − → Y is G-equivariant if f(g · x) = g · f(x) for every x ∈ X and every g ∈ G.

Nevena Palić Cutting a part from many measures 23.02.2018 5 / 16

slide-19
SLIDE 19

First example

Let G be a group that acts on topological spaces X and Y . A map f : X − → Y is G-equivariant if f(g · x) = g · f(x) for every x ∈ X and every g ∈ G.

Theorem (Borsuk-Ulam)

There is no Z2-equivariant map Sd → Sd−1.

Nevena Palić Cutting a part from many measures 23.02.2018 5 / 16

slide-20
SLIDE 20

First example – discrete version

Theorem (Discrete Ham Sandwich theorem, Matoušek)

Let A1, . . . , Ad ⊂ Rd be disjoint finite point sets in general position. Then there exists a hyperplane H that bisects each set Ai, such that there are exactly ⌊ 1

2|Ai|⌋ points from the set Ai in each of the open

half-spaces defined by H, for every 1 ≤ i ≤ d.

Nevena Palić Cutting a part from many measures 23.02.2018 6 / 16

slide-21
SLIDE 21

First example – discrete version

Theorem (Discrete Ham Sandwich theorem, Matoušek)

Let A1, . . . , Ad ⊂ Rd be disjoint finite point sets in general position. Then there exists a hyperplane H that bisects each set Ai, such that there are exactly ⌊ 1

2|Ai|⌋ points from the set Ai in each of the open

half-spaces defined by H, for every 1 ≤ i ≤ d.

Nevena Palić Cutting a part from many measures 23.02.2018 6 / 16

slide-22
SLIDE 22

Partitions and measures

Definition

Let d ≥ 1 and n ≥ 1 be integers. An ordered collection of closed subsets (C1, . . . , Cn) of Rd is called a partition of Rd if (1) n

i=1 Ci = Rd,

(2) int(Ci) = ∅ for every 1 ≤ i ≤ n, and (3) int(Ci) ∩ int(Cj) = ∅ for all 1 ≤ i < j ≤ n. A partition (C1, . . . , Cn) is called convex if all subsets C1, . . . , Cn are convex.

Nevena Palić Cutting a part from many measures 23.02.2018 7 / 16

slide-23
SLIDE 23

Partitions and measures

Definition

Let d ≥ 1 and n ≥ 1 be integers. An ordered collection of closed subsets (C1, . . . , Cn) of Rd is called a partition of Rd if (1) n

i=1 Ci = Rd,

(2) int(Ci) = ∅ for every 1 ≤ i ≤ n, and (3) int(Ci) ∩ int(Cj) = ∅ for all 1 ≤ i < j ≤ n. A partition (C1, . . . , Cn) is called convex if all subsets C1, . . . , Cn are convex. We consider finite absolutely continuous Borel measures.

Nevena Palić Cutting a part from many measures 23.02.2018 7 / 16

slide-24
SLIDE 24

Motivation

Conjecture (Holmsen, Kynčl, Valculescu, 2017)

d ≥ 2, ℓ ≥ 2, m ≥ 2 and n ≥ 1 integers, m ≥ d and ℓ ≥ d, X ⊆ Rd, |X| = ℓn, X in general position, X is colored with at least m different colors. a partition of X into n subsets of size ℓ such that each subset contains points colored by at least d colors.

Nevena Palić Cutting a part from many measures 23.02.2018 8 / 16

slide-25
SLIDE 25

Motivation

Conjecture (Holmsen, Kynčl, Valculescu, 2017)

d ≥ 2, ℓ ≥ 2, m ≥ 2 and n ≥ 1 integers, m ≥ d and ℓ ≥ d, X ⊆ Rd, |X| = ℓn, X in general position, X is colored with at least m different colors. a partition of X into n subsets of size ℓ such that each subset contains points colored by at least d colors. Then there exists such a partition of X that in addition has the property that the convex hulls of the n subsets are pairwise disjoint.

Nevena Palić Cutting a part from many measures 23.02.2018 8 / 16

slide-26
SLIDE 26

Motivation

d = 2, m = 3, n = 6, l = 3

Nevena Palić Cutting a part from many measures 23.02.2018 9 / 16

slide-27
SLIDE 27

Motivation

d = 2, m = 3, n = 6, l = 3

Nevena Palić Cutting a part from many measures 23.02.2018 9 / 16

slide-28
SLIDE 28

Cutting a part from many measures

Theorem (Blagojević, P., Ziegler, 2017)

d ≥ 2, m ≥ 2, and c ≥ 2 integers, n = pk a prime power, m ≥ n(c − d) + dn

p − n p + 1,

µ1, . . . , µm positive finite absolutely continuous measures on Rd.

Nevena Palić Cutting a part from many measures 23.02.2018 10 / 16

slide-29
SLIDE 29

Cutting a part from many measures

Theorem (Blagojević, P., Ziegler, 2017)

d ≥ 2, m ≥ 2, and c ≥ 2 integers, n = pk a prime power, m ≥ n(c − d) + dn

p − n p + 1,

µ1, . . . , µm positive finite absolutely continuous measures on Rd. Then there exists a convex partition (C1, . . . , Cn) such that

Nevena Palić Cutting a part from many measures 23.02.2018 10 / 16

slide-30
SLIDE 30

Cutting a part from many measures

Theorem (Blagojević, P., Ziegler, 2017)

d ≥ 2, m ≥ 2, and c ≥ 2 integers, n = pk a prime power, m ≥ n(c − d) + dn

p − n p + 1,

µ1, . . . , µm positive finite absolutely continuous measures on Rd. Then there exists a convex partition (C1, . . . , Cn) such that #{j : 1 ≤ j ≤ m, µj(Ci) > 0} ≥ c and µm(C1) = · · · = µm(Cn) = 1 nµm(Rd), for every 1 ≤ i ≤ n.

Nevena Palić Cutting a part from many measures 23.02.2018 10 / 16

slide-31
SLIDE 31

Cutting a part from many measures

Example

n = 5 c = 4 d = 3 m = 8

Nevena Palić Cutting a part from many measures 23.02.2018 11 / 16

slide-32
SLIDE 32

CS/TM scheme

EMP(µm, n) – all convex partitions of Rd into n convex pieces that equipart the measure µm

Nevena Palić Cutting a part from many measures 23.02.2018 12 / 16

slide-33
SLIDE 33

CS/TM scheme

EMP(µm, n) – all convex partitions of Rd into n convex pieces that equipart the measure µm f : EMP(µm, n) − → R(m−1)×n ∼ = (Rm−1)n (C1, . . . , Cn) − →      µ1(C1) µ1(C2) . . . µ1(Cn) µ2(C1) µ2(C2) . . . µ2(Cn) . . . . . . ... . . . µm−1(C1) µm−1(C2) . . . µm−1(Cn)     

Nevena Palić Cutting a part from many measures 23.02.2018 12 / 16

slide-34
SLIDE 34

CS/TM scheme

EMP(µm, n) – all convex partitions of Rd into n convex pieces that equipart the measure µm f : EMP(µm, n) − → R(m−1)×n ∼ = (Rm−1)n (C1, . . . , Cn) − →      µ1(C1) µ1(C2) . . . µ1(Cn) µ2(C1) µ2(C2) . . . µ2(Cn) . . . . . . ... . . . µm−1(C1) µm−1(C2) . . . µm−1(Cn)      f is Sn-equivariant.

Nevena Palić Cutting a part from many measures 23.02.2018 12 / 16

slide-35
SLIDE 35

CS/TM scheme

V =

  • (yjk) ∈ R(m−1)×n :

n

  • k=1

yjk = µj(Rd) for every 1 ≤ j ≤ m − 1

= R(m−1)×(n−1)

Nevena Palić Cutting a part from many measures 23.02.2018 13 / 16

slide-36
SLIDE 36

CS/TM scheme

V =

  • (yjk) ∈ R(m−1)×n :

n

  • k=1

yjk = µj(Rd) for every 1 ≤ j ≤ m − 1

= R(m−1)×(n−1) f : EMP(µm, n) − → V ⊆ R(m−1)×n (C1, . . . , Cn) − →      µ1(C1) µ1(C2) . . . µ1(Cn) µ2(C1) µ2(C2) . . . µ2(Cn) . . . . . . ... . . . µm−1(C1) µm−1(C2) . . . µm−1(Cn)     

Nevena Palić Cutting a part from many measures 23.02.2018 13 / 16

slide-37
SLIDE 37

CS/TM scheme

Arrangement A = A(m, n, c) of all subspaces of V ⊂ R(m−1)×n that have at least m − c + 1 zeros in some column.

Nevena Palić Cutting a part from many measures 23.02.2018 14 / 16

slide-38
SLIDE 38

CS/TM scheme

Arrangement A = A(m, n, c) of all subspaces of V ⊂ R(m−1)×n that have at least m − c + 1 zeros in some column. If there is NO solution, then f : EMP(µm, n) − →Sn

  • A

Nevena Palić Cutting a part from many measures 23.02.2018 14 / 16

slide-39
SLIDE 39

CS/TM scheme

Arrangement A = A(m, n, c) of all subspaces of V ⊂ R(m−1)×n that have at least m − c + 1 zeros in some column. If there is NO solution, then f : EMP(µm, n) − →Sn

  • A

Theorem (Blagojević, P., Ziegler, 2017)

There is no Sn-equivariant map f : EMP(µm, n) − →Sn

  • A.

Nevena Palić Cutting a part from many measures 23.02.2018 14 / 16

slide-40
SLIDE 40

Proof of the topological result

We construct these Sn-equivariant maps:

EMP(µm, n)

f

A

β

hocolimP (A) C

γ

hocolimQ′ D

δ

hocolimQ′ E

η

  • Conf(Rd, n)

α

  • g:=η◦δ◦γ◦β◦f◦α

X

Nevena Palić Cutting a part from many measures 23.02.2018 15 / 16

slide-41
SLIDE 41

Proof of the topological result

We construct these Sn-equivariant maps:

EMP(µm, n)

f

A

β

hocolimP (A) C

γ

hocolimQ′ D

δ

hocolimQ′ E

η

  • Conf(Rd, n)

α

  • g:=η◦δ◦γ◦β◦f◦α

X

Conf(Rd, n) := {(x1, . . . , xn) ∈ (Rd)n | xi = xj for all 1 ≤ i < j ≤ n}

Nevena Palić Cutting a part from many measures 23.02.2018 15 / 16

slide-42
SLIDE 42

References

[1] Pavle V.M. Blagojević, Nevena Palić and Günter M. Ziegler, Cutting a part from many measures, arXiv:1710.05118. [2] Andreas F. Holmsen, Jan Kynčl and Claudiu Valculescu, Near equipartitions of colored point sets, Computational Geometry 65 (2017), 35–42. [3] Jirží Matoušek, Using the Borsuk-Ulam theorem, Lectures on Topological Methods in Combinatorics and Geometry, Springer Publishing Company, Incorporated 2007.

Nevena Palić Cutting a part from many measures 23.02.2018 16 / 16