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Prepared with SEVI SLIDES Competition Policy - Spring 2005 Monopolization practices I Antonio Cabrales & Massimo Motta May 25, 2005 Summary Some definitions Efficiency reasons for tying


  1. Prepared with SEVI SLIDES Competition Policy - Spring 2005 Monopolization practices I Antonio Cabrales & Massimo Motta May 25, 2005 ➪ ➪ ➲

  2. ➟ ➠ ➪ Summary • Some definitions ➟ ➠ • Efficiency reasons for tying ➟ ➠ • Tying as a price discrimination device: Bundling ➟ ➠ • Requirements tying ➟ ➠ • Exclusionary tying ➟ ➠ • Strategic behavior in network industries ➟ ➠ ➪ ➲ ➪ ➟ ➠

  3. ➣➟ ➪ Some definitions (1/2) • Tie-in sales (tying) : Whenever a good is offered under the condition that another good is bought with it. • Bundling (or package tie-in) : Different goods are sold together in fixed proportions (e.g., shoes and laces, cars and tyres, laptop and OS software and so on.) • Mixed-bundling : When the consumer is also given the choice to buy the goods separately. • Requirements tying : Whenever two goods are sold together in vari- able proportions (e.g., copy machine and toner, cell phone and sub- scription and so on.) ➪ ➪ ➟ ➣ ➥ ➲ 1 31

  4. ➟ ➠ ➪ Efficiency reasons for tying • Consumers save on assembling costs and transaction costs: If they buy the bundle (e.g., shoes and laces, different car parts) rather than separate goods • Scale economies due to division of labour: Else, each of us should learn how to assemble a car. • Solving problems of asymmetric information: And guaranteeing highest quality, by ensuring that different components work well together (but quality problems might also be solved in other ways, e.g. with quality control, minimum quality standards, certifications.) ➟ ➠ ➪ ➪ ➟➠ ➲ 2 31

  5. Tying as a price discrimination device: Bundling ➣➟ ➠ ➪ (1/3) • Bundling might be used to extract more surplus from consumers (espe- cially when preferences for different goods are negatively correlated.) • Example: See Table next page. • A monopolist obtains higher profits by bundling two products than selling them separately to the two consumers. • Ambiguous effects on welfare (same as with price discrimination.) ➟ ➪ ➪ ➟➠ ➣ ➥ ➲ 3 31

  6. Tying as a price discrimination device: Bundling ➢ ➣➟ ➠ ➪ (2/3) • By selling A, B separately, firm earns 4(2)+5(2)=18. • By bundling them, it makes 12+12=24. 1’s willingness to pay 2’s willingness to pay Good A 7 4 Good B 5 8 Goods A and B 12 12 ➟ ➪ ➪ ➟➠ ➥ ➢ ➣ ➥ ➲ 4 31

  7. ➣➟ ➠ ➪ Requirements tying (1/9) • Requirements tying might act as a metering device. • If a product can be used with different intensities, a firm would like to charge more to consumers with higher intensity of use (i.e., with higher valuation.) • By keeping low price of basic product (e.g. copy machine, cellular handset) and high price of complementary products (toner cartridges, calls), firm charges according to intensity of use. • Welfare higher, if under tying more consumers buy. • Welfare lower, if all consumers buy absent tying or with it (same effects as with price discrimination.) ➟ ➠ ➪ ➪ ➟➠ ➣ ➥ ➲ 5 31

  8. ➢ ➣➟ ➠ ➪ Requirements tying (2/9) A model of requirements tying A consumer is type i = h, l and buys one unit of good A and q units of B. U i = q − q 2 2 v i Proportion of type l (lower intensity) is λ. Good A is monopolized by firm 1 and market B has several suppliers (including 1.) Constant marginal cost c A , c B < 1 . No fixed cost. ➟ ➠ ➪ ➪ ➟➠ ➥ ➢ ➣ ➥ ➲ 6 31

  9. ➢ ➣➟ ➠ ➪ Requirements tying (3/9) No tying (all buy) Suppose a consumer buys. Then his demand is: q i = v i (1 − p B ) . He will buy if U i − p A − p B q i ≥ 0, that is, if v i (1 − p B ) 2 / 2 − p A ≥ 0 . Competition implies p B = c B If firm 1 prices so that all consumers buy: = v l (1 − c B ) 2 p NT A 2 In this case l consumers have no surplus and h consumers have CS NT = h ( v h − v l )(1 − c B ) 2 / 2 . Producer surplus is π NT = v l (1 − c B ) 2 / 2 − c A . Welfare is then: W NT = ((1 − λ ) v h + λv l )(1 − c B ) 2 − c A . 2 ➟ ➠ ➪ ➪ ➟➠ ➥ ➢ ➣ ➥ ➲ 7 31

  10. ➢ ➣➟ ➠ ➪ Requirements tying (4/9) No tying (Only high types buy) If firm 1 prices so that only h consumers buy: = v h (1 − c B ) 2 p NTh A 2 In this case all consumers have no surplus CS NTh = 0 . � � Producer surplus is π NTh = (1 − λ ) v h (1 − c B ) 2 / 2 − c A = W NTh . This strategy is profitable if π NTh ≥ π NT , which is true if: λ ≤ ( v h − v l )(1 − c B ) 2 v h (1 − c B ) 2 − 2 c A ➟ ➠ ➪ ➪ ➟➠ ➥ ➢ ➣ ➥ ➲ 8 31

  11. ➢ ➣➟ ➠ ➪ Requirements tying (5/9) Tying If firm 1 requires consumers who want good A also to buy good B from it (and can enforce it.) π = ( p B − c B )[ λv l (1 − p B ) + (1 − λ ) v h (1 − p B )] + p A − c A . Which implies B = (1 − λ )( v h − v l ) + c B [ λv l + (1 − λ ) v h ] p T > c B 2 v h − v l − 2 λ ( v h − v l ) Price of A is chosen so that v i (1 − p T B ) 2 / 2 − p A ≥ 0 , thus: A = (1 − c B ) 2 v l [ λv l + (1 − λ ) v h ] 2 p T 2[2 v h − v l − 2 λ ( v h − v l )] 2 The price p T A acts like the fixed part of a two-part tariff, and allows to screen between types. ➟ ➠ ➪ ➪ ➟➠ ➥ ➢ ➣ ➥ ➲ 9 31

  12. ➢ ➣➟ ➠ ➪ Requirements tying (6/9) π T = (1 − c B ) 2 [ λv l + (1 − λ ) v h ] 2 − c A . 2[2 v h − v l − 2 λ ( v h − v l )] Consumers of type l have no surplus and: h = (1 − c B ) 2 ( v h − v l )[ λv l + (1 − λ ) v h ] 2 CS T 2[2 v h − v l − 2 λ ( v h − v l )] 2 Thus: W T = (1 − c B ) 2 [ λv l + (1 − λ ) v h ] 2 [1 + (1 − λ )( v h − v l )] − c A 2[2 v h − v l − 2 λ ( v h − v l )] 2 ➟ ➠ ➪ ➪ ➟➠ ➥ ➢ ➣ ➥ ➲ 10 31

  13. ➢ ➣➟ ➠ ➪ Requirements tying (7/9) Comparisons of equilibria 1. First assume that it is optimal to serve all under no tying. Then: (1 − c B ) 2 ( v h − v l ) 2 π T − π NT = 2[2 v h − v l − 2 λ ( v h − v l )] > 0 . W NT − W T = (1 − c B ) 2 (1 − λ )( v h − v h ) 2 [(1 + λ − 2 λ 2 ) v h + 2 λ 2 v l ] > 0 . 2[2 v h − v l − 2 λ ( v h − v l )] 2 Consumers do not buy any more at marginal cost good B. ➟ ➠ ➪ ➪ ➟➠ ➥ ➢ ➣ ➥ ➲ 11 31

  14. ➢ ➟ ➠ ➪ Requirements tying (8/9) 2. Now assume that it is optimal to serve only the h types under no tying. Simple to see as under no tying consumer surplus is zero and now positive. Profits have to be higher or else it would not be done. 3. To check that tying will indeed be profitable consider c A = c B = 0 , v h = 2 , v l = 1 . Without tying firm 1 will serve only h if λ < 1 / 2 . Then π T − π NTh > 0 if λ > 1 − √ 3 / 3 . ➟ ➠ ➪ ➪ ➟➠ ➥ ➢ ➲ 12 31

  15. ➣➟ ➠ ➪ Exclusionary tying (1/15) • Whinston, 1990: tying as a commitment to compete aggressively, thus forcing a rival out of the market. • Two independent products, A and B . Firm 1 monopolist on A , firms 1 and 2 both sell good B . • If 1 commits to bundle A and B , it will price more aggressively, because it knows that every consumer who buys B will not buy A , on which firm 1 has a high margin ( A is a monopoly) • Fierce competition decrease both firms profits: knowing it, rival exits if cannot cover fixed costs. ➟ ➠ ➪ ➪ ➟➠ ➣ ➥ ➲ 13 31

  16. ➢ ➣➟ ➠ ➪ Exclusionary tying (2/15) A model of exclusionary tying with differenti- ated goods • Consumers uniformly distributed in [0 , 1] consume one unit (at most) of A, valued at v > c A and one of B, valued at U Bi = w − t i | x − x Bi |− p Bi , where w > max( c B 1 , c B 2 ) and x B 1 = 0 , x B 2 = 1 . • Firm 1first decides whether to bundle A and B 1 (irreversibly.) Then both firms decide whether to enter market B (and if so, pay F. ) Then pricing ( � p for the bundle if there is one, otherwise p A , p B 1 and p B 2 . ) ➟ ➠ ➪ ➪ ➟➠ ➥ ➢ ➣ ➥ ➲ 14 31

  17. ➢ ➣➟ ➠ ➪ Exclusionary tying (3/15) Independent Pricing (no tying) A consumer will buy B 1 rather than B 2 if U B 1 > U B 2 or w − t 1 x − p B 1 ≥ w − t 2 (1 − x ) − p B 2 . Both firms sell at equilibrium if: ( A 1) 0 < v − c A < t 2 + 2 t 1 + c B 1 − c B 2 ( A 2) v − c A > − 2 t 2 − t 1 + c B 1 − c B 2 x 12 ( p B 1 , p B 2 ) ≡ t 2 + p B 2 − p B 1 . t 2 + t 1 ➟ ➠ ➪ ➪ ➟➠ ➥ ➢ ➣ ➥ ➲ 15 31

  18. ➢ ➣➟ ➠ ➪ Exclusionary tying (4/15) q B 1 = x 12 ( p B 1 , p B 2 ) , q B 2 = 1 − x 12 ( p B 1 , p B 2 ) . π B 1 = ( p B 1 − c B 1 ) t 2 + p B 2 − p B 1 ; π B 2 = ( p B 2 − c B 2 ) t 1 + p B 1 − p B 2 t 2 + t 1 t 2 + t 1 R B 1 : p B 1 = t 2 + c B 1 + p B 2 ; R B 2 : p B 1 = 2 p B 2 − c B 2 − t 1 2 Thus � � 2 t i + 2 t j + c Bj + 2 c Bi Bi = t i + 2 t j + c Bj + 2 c Bi p ∗ ; π ∗ Bi = 3 9( t i + t j ) ➟ ➠ ➪ ➪ ➟➠ ➥ ➢ ➣ ➥ ➲ 16 31

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