Causality of fluid dynamics for high-energy nuclear collisions
Eduardo Grossi ITP Heidelberg University
Cold Quantum Coffee, Heidelberg, 21/11/2017
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with S. Floerchinger arXiv:1711.06687
Causality of fluid dynamics for high-energy nuclear collisions - - PowerPoint PPT Presentation
Causality of fluid dynamics for high-energy nuclear collisions Eduardo Grossi ITP Heidelberg University with S. Floerchinger arXiv:1711.06687 Cold Quantum Coffee, Heidelberg, 21/11/2017 1 Relativistic Hydrodynamics The equation of
Eduardo Grossi ITP Heidelberg University
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with S. Floerchinger arXiv:1711.06687
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✦ Energy conservation ✦ Charge conservation ✦ Euler equation
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( + p)uµ energy density four-velocity stress tensor bulk viscous pressure
figure from [Rezzolla, Zanotti “Relativistic Hydrodynamics”]
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δQ = δQ0eikx+Γt Γ+ (c2 + p)c2 T For k=0 we will have a growing mode and a damping mode in the transverse direction Consider a traverse perturbation around equilibrium with the fluid at rest. If we neglect the heat conductivity we obtain the diffusive mode like in non relativistic theory Γ = − k2 + p
[W. Hiscock et al. PRD (1985)]
δQ = δQ0eik(−γvt+γx)+Γ(γt−vγx) Γ+ (c2 + p)c2 v2
[W. Hiscock et al. PRD (1985)]
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[R. Baier et al. JHEP 0804 (2008)] [P. Romatschke Class.Quant.Grav. 27 (2010)] [S. Bhattacharyya et al., JHEP 0802 (2008)]
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[Muller 1967, Israel, Stewart 1976] [Hiscock 1983]
New transport coefficient, the relaxation time
A more general theory will have more terms in the equation for the stress tensor. This equation can be derive from Kinetic theory in consistent way. ✦ Energy conservation and Euler equation ✦ Relaxation equation for shear tensor ✦ Relaxation equation for bulk pressure
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[G. S. Denicol et al. Phys. Rev. D (2012)]
✦ boost invariance along the z direction ✦ rotational and translation invariance in the transverse plane. ✦
Figure from W. van der Schee, (2014).
Every quantity depend
Describe only the central rapidity region, no radial velocity.
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✦ boost invariance along the z direction ✦ rotational invariance in the transverse plane. ✦ Temperature ✦ Four velocity
This simplified setup nevertheless can be used to modeling the hydro evolution of an ultra central collision, where the initial energy profile is almost rotational invariant.
✦ Shear and bulk
Picture stolen from C. Shen et al. (2016)
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∂0Φi + Mij∂1Φj + Si = 0 This type of equation are called hyperbolic when is possible to diagonalize the matrix M w(m)
j
λ(m) dJ(m) = w(m)
j
dΦj ∂0J(m) + λ(m)∂1J(m) + w(m)
j
Sj = 0 Left eigenvector Eigenvalue With this variables we can partially diagonalized the system of pde. Riemann Invariants:
1 c2
sT
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x1 x0
Cl Cr P(x0,x1) Pr Pl Ar Al Γ x0=t x0=0
[Courant and Hilbert, (1953)]
5 10 15 20 25 30 r [fm] 0.1 0.2 0.3 0.4 T [GeV]
✦ Initial vanish
✦ Initial stress tensor
✦ No bulk
s(τ0, r) = s0 1 − x 2 nW N(r) + xnBC(r)
0.0 0.1 0.2 0.3 0.4 0.5 0.6 T [GeV] 5 10 15 20 25 30 τshear
0.1 0.2 0.3 0.4 0.5 0.6 T [GeV] 0.05 0.10 0.15 0.20 0.25 0.30 cs2
0.1 0.2 0.3 0.4 0.5 0.6 T [GeV] 0.2 0.4 0.6 0.8 1.0 1.2 η/s
[ N. Christianse et al. PRL (2015)] [ S. Borsanyi et al., Nature (2016) ]
φ = πη η = 0
πη
η + 2η
3 1 τ0 + 4 3τshearπη
η
1 2τ0 = 0 πη
η = −2η
3 1 τ0 πφ
φ = η
3 1 τ0
5 10 15 0.6 0.7 0.8 0.9 1.0 1.1 1.2 r [fm] c
τ=0.6 fm/c τ=4 fm/c τ=15 fm/c
5 10 15 0.6 0.7 0.8 0.9 1.0 1.1 1.2 r [fm] c
τ=1.5 fm/c τ=4 fm/c τ=15 fm/c
5 10 15 0.6 0.7 0.8 0.9 1.0 1.1 1.2 r [fm] c
τ=1.5 fm/c τ=4 fm/c τ=15 fm/c
5 10 15 0.6 0.7 0.8 0.9 1.0 1.1 1.2 r [fm] c
τ=1.5 fm/c τ=4 fm/c τ=15 fm/c
2 4 6 8 10 12 14 2 4 6 8 10 12 14 r [fm] τ [fm/c]
λ(1) λ(3) λ(2)
T=0.145 GeV
Γd Γi x
Γi λ(1) = v + ˜ c 1 + ˜ cv λ(2) = v − ˜ c 1 − ˜ cv λ(3) = v Maximal velocity Minmal velocity Fluid velocity Domain of dependence Domain of influence
0.0 0.5 1.0
10 20 x h(x) [fm]
R=15 α=3
0.0 0.2 0.4 0.6 0.8 1.0 0.0 0.2 0.4 0.6 0.8 1.0 ρ σ
+ i0 i+
r=const. τ=const
0.0 0.2 0.4 0.6 0.8 1.0 0.0 0.2 0.4 0.6 0.8 1.0 ρ σ
+ i0 i+ Σ0
T=0.15 GeV T=0.20 GeV T=0.25 GeV
λ(3)
0.0 0.2 0.4 0.6 0.8 1.0 0.0 0.2 0.4 0.6 0.8 1.0 ρ σ
+ i0 i+ Σ0
T=0.15 GeV T=0.20 GeV T=0.25 GeV
λ(1)
0.0 0.2 0.4 0.6 0.8 1.0 0.0 0.2 0.4 0.6 0.8 1.0 ρ σ
+ i0 i+ Σ0
T=0.15 GeV T=0.20 GeV T=0.25 GeV
λ(2)
λ(1) = v + ˜ c 1 + ˜ cv λ(2) = v − ˜ c 1 − ˜ cv λ(3) = v
2 4 6 8 10 12 14
0.0 0.5 1.0 τ [fm/c] Pη/Pr 2 4 6 8 10 12 14
0.0 0.5 1.0 τ [fm/c] Pη/Pr
shear = 3
shear = 30
✦ The dissipative hydro equation are hyperbolic partial
differential equation.
✦ The causal structure is given by the characteristic
velocity
✦ The characteristic velocity in general are state
dependents
✦ It is possible to use the causality bound to constrain
the allowed initial condition and the transport coefficient.
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