ax 2 bx c
play

ax 2 + bx + c Product of a & c Fill the 2 empty sides with 2 - PowerPoint PPT Presentation

D AY 139 X-BOX F ACTORING X- B OX Trinomial (Quadratic Equation) ax 2 + bx + c Product of a & c Fill the 2 empty sides with 2 numbers that are factors of ac and add to b give you b. X- B OX Trinomial (Quadratic


  1. D AY 139 – X-BOX F ACTORING

  2. X- B OX Trinomial (Quadratic Equation) ax 2 + bx + c Product of a & c Fill the 2 empty sides with 2 numbers that are factors of ‘a·c’ and add to b give you ‘b’.

  3. X- B OX Trinomial (Quadratic Equation) x 2 + 9x + 20 20 5 Fill the 2 empty sides 4 with 2 numbers that are factors of ‘a·c’ and add to 9 give you ‘b’.

  4. X- B OX Trinomial (Quadratic Equation) 2x 2 -x - 21 -42 Fill the 2 empty sides -7 6 with 2 numbers that are factors of ‘a·c’ and add to -1 give you ‘b’.

  5. X- BOX F ACTORING  This is a guaranteed method for factoring quadratic equations — no guessing necessary!  We will learn how to factor quadratic equations using the x-box method

  6. LET’S TRY IT! Students apply basic factoring techniques to second- and simple third-degree polynomials. These techniques include finding a common factor for all terms in a polynomial, recognizing the difference of two squares, and recognizing perfect squares of binomials. Objective: I can use the x-box method to factor non-prime trinomials.

  7. F ACTOR THE X - BOX WAY Example: Factor x 2 -3x -10 (1)(-10)= x -5 -10 x 2 -5x x GCF -5 2 -3 -10 2x +2 GCF GCF GCF x 2 -3x -10 = (x-5)(x+2)

  8. F ACTOR THE X - BOX WAY y = ax 2 + bx + c Base 1 Base 2 Product First and ac=mn 1st Last Factor GCF Term Coefficients n n m Middle Last Factor b=m+n Height term m Sum

  9. F ACTOR THE X - BOX WAY Example: Factor 3x 2 -13x -10 x -5 -30 3x 3x 2 -15x 2 -15 -13 -10 2x +2 3x 2 -13x -10 = (x-5)(3x+2)

  10. E XAMPLES Factor using the x-box method. 1. x 2 + 4x – 12 x +6 a) b) -12 x 2 6x x 6 -2 4 -2 -2x -12 Solution: x 2 + 4x – 12 = (x + 6)(x - 2)

  11. E XAMPLES CONTINUED 2. x 2 - 9x + 20 x -4 a) b) 20 x 2 -4x x -4 -5 -5x 20 -5 -9 Solution: x 2 - 9x + 20 = (x - 4)(x - 5 )

  12. E XAMPLES CONTINUED 3. 2x 2 - 5x - 7 2x -7 a) b) -14 2x 2 -7x x -7 2 -5 +1 2x -7 Solution: 2x 2 - 5x – 7 = (2x - 7)(x + 1 )

  13. E XAMPLES CONTINUED 3. 15x 2 + 7x - 2 3x +2 a) b) -30 15x 2 10x 5x 10 -3 7 -3x -2 -1 Solution: 15x 2 + 7x – 2 = (3x + 2)(5x - 1 )

  14. E XTRA P RACTICE x 2 +4x -32 1. 4x 2 +4x -3 2. 3x 2 + 11x – 20 3.

  15. R EMINDER !! Don’t forget to check your answer by multiplying!

Download Presentation
Download Policy: The content available on the website is offered to you 'AS IS' for your personal information and use only. It cannot be commercialized, licensed, or distributed on other websites without prior consent from the author. To download a presentation, simply click this link. If you encounter any difficulties during the download process, it's possible that the publisher has removed the file from their server.

Recommend


More recommend