Slide 1 / 126
AP Chemistry
Compounds
2015-09-14 www.njctl.org
Slide 2 / 126
Table of Contents: Compounds Pt. B
· States of Matter · Molecular Geometry
Click on the topic to go to that section
AP Chemistry Compounds 2015-09-14 www.njctl.org Slide 3 / 126 - - PDF document
Slide 1 / 126 Slide 2 / 126 AP Chemistry Compounds 2015-09-14 www.njctl.org Slide 3 / 126 Table of Contents: Compounds Pt. B Click on the topic to go to that section Molecular Geometry Intermolecular Forces States of Matter
Click on the topic to go to that section
Return to Table
VSEPR theory assigns a 3-digit code to each molecular shape. To determine this code we must first sketch the Lewis structure.
the total number of electron-domains around the central atom. That means the total number of bonds and lone
count as 1 electron domain. 3 6
Electron Domain Geometries
"AB" Designation (# of bonds) # of unbonded pairs of electrons on "A" atom Shape Bond Angles Example
AB2 linear 180 AB3 trigonal planar 120 AB4 tetrahedral 109.5 AB5 trigonal bypyramidal 90, 120, 180 AB6
90, 180
**Note: Pi bonds act with the sigma bonds to contribute to the repulsions that result in the molecular shape, however they do not act as a separate constituent around the "A" atom.
1 What is the electron domain geometry of CH
4?
1 What is the electron domain geometry of CH
4?
[This object is a pull tab]
2 What is the EDG of H 2O?
2 What is the EDG of H 2O?
[This object is a pull tab]
3 What is the EDG of CO2?
3 What is the EDG of CO2?
[This object is a pull tab]
Students type their answers here
Students type their answers here
[This object is a pull tab]
3 - Trigonal Planar
4 - Square Planar
3 - Bent
117
Elements Bonds & Electrons
Draw a Lewis Structure and determine the electron domain geometry (EDG) and the molecular geometry (MG). For Ions
Elements Bonds & Electrons
Draw a Lewis Structure and determine the electron domain geometry (EDG) and the molecular geometry (MG). For Ions
[This object is a pull tab]
4 3 1 EDG: tetrahedral MG: trigonal pyramidal
Elements Bonds & Electrons
Draw a Lewis Structure and determine the electron domain geometry (EDG) and the molecular geometry (MG).
For Ions
Elements Bonds & Electrons
Draw a Lewis Structure and determine the electron domain geometry (EDG) and the molecular geometry (MG).
For Ions
[This object is a pull tab]
4 4 0 EDG: tetrahedral MG: tetrahedral
Elements Bonds & Electrons
Draw a Lewis Structure and determine the electron domain geometry (EDG) and the molecular geometry (MG).
For Ions
Elements Bonds & Electrons
Draw a Lewis Structure and determine the electron domain geometry (EDG) and the molecular geometry (MG).
For Ions
[This object is a pull tab]
6 5 1 EDG: octahedral MG: square pyramidal
Elements Bonds & Electrons
Draw a Lewis Structure and determine the electron domain geometry (EDG) and the molecular geometry (MG).
For Ions
Elements Bonds & Electrons
Draw a Lewis Structure and determine the electron domain geometry (EDG) and the molecular geometry (MG).
For Ions
[This object is a pull tab]
3 2 1 EDG: trigonal planar MG: bent
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
Dipole moment = 1.85 D Dipole moment = 0.97 D
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
Return to Table
*Note: Intermolecular forces are much weaker than intramolecular forces due to the greater distance between charges which diminishes the Coulombic attractions.
e- e- e- e- e- e- e- e- e- e- e- e- e- e- e- e-
Normal Polarized
e- e- e- e- e- e- e- e-
e- e- e- e- e- e- e- e-
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
isobutane n-butane
isobutane n-butane
[This object is a pull tab]
H Cl + - H Cl + - dipole-dipole force
H F + - H F + -
dipole-dipole force
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
Substance LDF Rank H-Bonds DDF Rank MP @1 atm BP @ 1 atm Heat of Vaporization H2O 3 Yes 1 0 C 100 C 40.6 kJ/mol I2 1 No 3 114 C 184 C 41.6 kJ/mol CH3COCH3 2 No 2
56 C 29 kJ/mol
*When comparing properties of molecular compounds, first determine if the molecule is polar. If it is, dipole-dipole forces will be part of the
When evaluating properties such as boiling point, one must consider the forces present in each substance. Although LDF's are in general weaker than dipole-dipole forces (DDF's), large non-polar molecules can have higher boiling points than smaller polar molecules, even those with hydrogen bonding.
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
Return to Table
Note: Water is unique in that its liquid state is more dense than the solid state.
Students type their answers here
Students type their answers here
[This object is a pull tab]
Melting Point Conductivity Malleability
*Note: Recall LDF stands for London Dispersion Forces
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
*Note: Even at low temperatures, some of the gas molecules have as much energy as the average energy of the gas molecules at a much higher temperature. # of gas molecules Molecular speeds Temperatures
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
Mass of cylinder initially = 110.400 grams Mass of cylinder after dispensing gas = 110.273 grams Volume of gas dispensed @ 15 C = 100.3 mL Pressure of gas collected @ 15 C = 763 mm Hg
Mass of cylinder initially = 110.400 grams Mass of cylinder after dispensing gas = 110.273 grams Volume of gas dispensed @ 15 C = 100.3 mL Pressure of gas collected @ 15 C = 763 mm Hg
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
valve 2 L of He @ 2atm 0.8 L of Ar @1 atm
valve 2 L of He @ 2atm 0.8 L of Ar @1 atm
[This object is a pull tab]
(1/2) or 1.41 x slower.
2 or 4x lighter.
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
Temp: 20 C 20 C 20 C Gas: N2 O2 He Pressure: 1 atm 2 atm 1 atm Volume: 5 L 5 L 5 L
Temp: 20 C 20 C 20 C Gas: N2 O2 He Pressure: 1 atm 2 atm 1 atm Volume: 5 L 5 L 5 L
[This object is a pull tab]
[This object is a pull tab]
[This object is a pull tab]
Return to Table
Students type their answers here
Students type their answers here
[This object is a pull tab]
Students type their answers here
Students type their answers here
[This object is a pull tab]
[This object is a pull tab]