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D AY 77 G RAPHING SYSTEM OF INEQUALITIES P ROBLEM Libby is making a window frame for etched glass. The frame will be for a window that is square on the bottom with an isosceles triangle on top. The perimeter of the window must be no more


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SLIDE 1

DAY 77 – GRAPHING SYSTEM OF

INEQUALITIES

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SLIDE 2

PROBLEM

Libby is making a window frame for etched glass. The frame will be for a window that is square on the bottom with an isosceles triangle on top. The perimeter of the window must be no more than 15 feet. What are some possible dimensions of the window?

b mx y  

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SLIDE 3
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SLIDE 4
  • 1. Let x represent the length of each side of

the square, and let y represent the length of one of the two congruent sides

  • f the isosceles triangle.
  • 2. The perimeter of the window must be no

more than 15 feet. Write an inequality for the perimeter using the variables x and y.

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SLIDE 5

ANSWER #1 AND #2

1. 2.

15 2 3   y x

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SLIDE 6
  • 3. The sum of two sides of a triangle is

always greater than the third side. Use this fact to write the second inequality.

  • 4. Write the system of inequalities. Solve

each inequality for y.

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SLIDE 7

ANSWER #3 AND #4

3. 4.

      x y y x 2 15 2 3

x y  2

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SLIDE 8

Recall that you can use a graph to find the solutions. All of the points that lie in the solution region of both inequalities are in the solution of the

  • system. Remember that the

dimensions of the windows must be positive, so the reasonable domain and range are contained in the first quadrant.

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SLIDE 9
  • 5. Graph the boundary lines. Is one or both
  • f the boundary lines solid or dashed?

Why?

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SLIDE 10
  • 6. Notice that the boundary lines divide

the first quadrant into four regions. Points A, B, C and D are each placed in

  • ne of these four regions. In the

following table the coordinates of each point in both inequalities, and complete the table.

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SLIDE 11

Point Is the inequality true? Is the inequality true? Are both inequalities true? A (3 , 1) No B (2 , 2) yes C (4 , 4) no D (6 , 1) no

no ; 3 ) 1 ( 2 

x y  2

yes ; 15 ) 1 ( 2 ) 3 ( 3  

no ; 3 ) 1 ( 2 

yes ; 15 ) 2 ( 2 ) 2 ( 3   no ; 15 ) 2 ( 2 ) 4 ( 3   no ; 15 ) 1 ( 2 ) 6 ( 3  

yes ; 2 ) 2 ( 2  yes ; 4 ) 4 ( 2  no ; 6 ) 1 ( 2 

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SLIDE 12
  • 7. On your graph, shade the region

containing the point that makes both inequalities true. Do either of the boundary lines contain points that are solutions to this system of linear inequalities? Explain

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SLIDE 13

ANSWER TO #7

The line 3x + 2y ≤ 15 contains points that are solutions to the system because of the (≤ ) equal.

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SLIDE 14

SOLVE BY GRAPHING 1

        4 10 y x y x

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SLIDE 15

SOLVE BY GRAPHING 1

Graph x + y > 10. Any point in half-plane E is a solution of x + y >10. Note that the graph of x + y = 10 is dashed to show that it is not included in the half- plane.

E x + y > 10

        4 10 y x y x

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SLIDE 16

SOLVE BY GRAPHING 1

Graph x - y > -4. Any point in half-plane F is a solution of x - y > -4. Note that the points

  • n the graph of

X – y = -4 are not included in the half- plane

F x – y > - 4

        4 10 y x y x

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SLIDE 17

SOLVE BY GRAPHING 1

Any point in the intersection of the half- planes E and F (double shading) is a solution of x + y > 10 and x – y > - 4 Thus, all points in the darkest region (but no points on the lines) are solutions of the system.

F E

        4 10 y x y x

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SLIDE 18

SOLVE BY GRAPHING 2

       5 4 2 y x x y

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SLIDE 19

SOLVE BY GRAPHING 2

Graph y ≥ 2x - 4. Any point in half-plane E or

  • n the line y = 2x – 4

(edge of half-plane E) is a solution of y ≥ 2x – 4.

E y = 2x - 4

       5 4 2 y x x y

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SLIDE 20

SOLVE BY GRAPHING 2

Graph x + y ≤ 5. Any point in half-plane F or

  • n the line x + y = 5

(edge of half-plane F) is a solution of x + y ≤ 5.

F x + y = 5

       5 4 2 y x x y

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SLIDE 21

SOLVE BY GRAPHING 2

Any point in the intersection of half- planes E and F (double- shading) and any point

  • n the lines that

border the intersection is a solution of y ≥ 2x – 4 and x + y ≤ 5

F E

       5 4 2 y x x y

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SLIDE 22

CONSUMERISM

  • Mrs. Fuentes wants to buy at least 10
  • books. Each paperback costs an average of $10,

and each hardcover book costs an average of $20.

  • Mrs. Fuentes is planning to spend less than $250
  • n books.

a.Write a system of linear inequalities that represents this

  • situation. Then graph the solution of the system.
  • b. Based on you graph, name three possible combinations
  • f paperback and hardcover books Mrs. Fuentes could

buy.

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SLIDE 23

CONSUMERISM

  • a. Let x represent the number of paperback

books and y represent the number of hardcover

  • books. The number of books Mrs. Fuentes wants

to buy is x + y ≥ 10. The amount she plans to spend is 10x + 20y < 250. So, the system of inequalities that represents the situation is

       20 20 10 10 y x y x

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SLIDE 24

Graph x + y = 10 with a solid

  • line. Test points on either

side of the line, such as (0,0) and (10,10), to see which half-plane to shade. Shade above the line, because the point (10,10) is above the line and makes x + y ≥ 10 true. Then graph 10x + 20y = 250 with a dashed line. Testing points above and below the line shows that the half-plane below the line should be shaded. The solution is the double- shaded region.

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SLIDE 25
  • b. Select any three points in the double-

shaded region. The points representing 12 paperback books and 6 hardcover books, 16 paperback books and 0 hardcover books, and 0 paperback books and 10 hardcover books are all within the double- shaded region