DAY 77 – GRAPHING SYSTEM OF
INEQUALITIES
1. Let x represent the length of each side of the square, and let y - - PowerPoint PPT Presentation
D AY 77 G RAPHING SYSTEM OF INEQUALITIES P ROBLEM Libby is making a window frame for etched glass. The frame will be for a window that is square on the bottom with an isosceles triangle on top. The perimeter of the window must be no more
DAY 77 – GRAPHING SYSTEM OF
INEQUALITIES
PROBLEM
Libby is making a window frame for etched glass. The frame will be for a window that is square on the bottom with an isosceles triangle on top. The perimeter of the window must be no more than 15 feet. What are some possible dimensions of the window?
b mx y
ANSWER #1 AND #2
1. 2.
15 2 3 y x
ANSWER #3 AND #4
3. 4.
x y y x 2 15 2 3
x y 2
Point Is the inequality true? Is the inequality true? Are both inequalities true? A (3 , 1) No B (2 , 2) yes C (4 , 4) no D (6 , 1) no
no ; 3 ) 1 ( 2
x y 2
yes ; 15 ) 1 ( 2 ) 3 ( 3
no ; 3 ) 1 ( 2
yes ; 15 ) 2 ( 2 ) 2 ( 3 no ; 15 ) 2 ( 2 ) 4 ( 3 no ; 15 ) 1 ( 2 ) 6 ( 3
yes ; 2 ) 2 ( 2 yes ; 4 ) 4 ( 2 no ; 6 ) 1 ( 2
ANSWER TO #7
SOLVE BY GRAPHING 1
SOLVE BY GRAPHING 1
Graph x + y > 10. Any point in half-plane E is a solution of x + y >10. Note that the graph of x + y = 10 is dashed to show that it is not included in the half- plane.
E x + y > 10
SOLVE BY GRAPHING 1
Graph x - y > -4. Any point in half-plane F is a solution of x - y > -4. Note that the points
X – y = -4 are not included in the half- plane
F x – y > - 4
SOLVE BY GRAPHING 1
Any point in the intersection of the half- planes E and F (double shading) is a solution of x + y > 10 and x – y > - 4 Thus, all points in the darkest region (but no points on the lines) are solutions of the system.
F E
SOLVE BY GRAPHING 2
SOLVE BY GRAPHING 2
Graph y ≥ 2x - 4. Any point in half-plane E or
(edge of half-plane E) is a solution of y ≥ 2x – 4.
E y = 2x - 4
SOLVE BY GRAPHING 2
Graph x + y ≤ 5. Any point in half-plane F or
(edge of half-plane F) is a solution of x + y ≤ 5.
F x + y = 5
SOLVE BY GRAPHING 2
Any point in the intersection of half- planes E and F (double- shading) and any point
border the intersection is a solution of y ≥ 2x – 4 and x + y ≤ 5
F E
CONSUMERISM
and each hardcover book costs an average of $20.
a.Write a system of linear inequalities that represents this
buy.
CONSUMERISM
books and y represent the number of hardcover
to buy is x + y ≥ 10. The amount she plans to spend is 10x + 20y < 250. So, the system of inequalities that represents the situation is
Graph x + y = 10 with a solid
side of the line, such as (0,0) and (10,10), to see which half-plane to shade. Shade above the line, because the point (10,10) is above the line and makes x + y ≥ 10 true. Then graph 10x + 20y = 250 with a dashed line. Testing points above and below the line shows that the half-plane below the line should be shaded. The solution is the double- shaded region.