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What happens when it rains stream(t) = only-surface(t)+sometime-in-ground(t) precip(t) = infil(t)+only-surface(t) infil(t) = sometime-in-ground(t)+all-time-in-ground(t) out(t) = stream(t)+all-time-in-ground(t) precip(t) = out(t) ()


  1. What happens when it rains stream(t) = only-surface(t)+sometime-in-ground(t) precip(t) = infil(t)+only-surface(t) infil(t) = sometime-in-ground(t)+all-time-in-ground(t) out(t) = stream(t)+all-time-in-ground(t) precip(t) = out(t) () August 2, 2017 4 / 25

  2. What happens when it rains Rain Infiltration Overland Baseflow Time stream(t) = only-surface(t)+sometime-in-ground(t) precip(t) = infil(t)+only-surface(t) infil(t) = sometime-in-ground(t)+all-time-in-ground(t) out(t) = stream(t)+all-time-in-ground(t) precip(t) = out(t) () August 2, 2017 5 / 25

  3. Immediate Runoff () August 2, 2017 6 / 25

  4. Stream-flow and Base-flow The stream flow is largely baseflow for most of the year. Only in the monsoon is there a run-off component. A simple exponential flow model: flow = Ae − α t + B where A , B and α are parameters of the watershed. A small α signifies good health. If flow is negative, assume it to signify that the stream is dry. Monsoons Runoff Baseflow Baseflow Time () August 2, 2017 7 / 25

  5. Infiltration and Stream-flow Infiltration This is the part of precipitation which flows out of the watershed through rivers and streams. Overall Indian average is about 43% , in Konkan its above 93 % . The difference ◮ is stored in reservoirs and tanks. ◮ recharges ground-water. ◮ evaporates or is consumed. Stram-flow is a function of rain-intensity, slope, land-conditions, forest-cover, existing soil-moisture and many other things. How do I estimate stream-flow and infiltration? How do I modify these? () August 2, 2017 8 / 25

  6. Slope Both stream-flow and infiltration depend greatly on the slope. Slope-maps are an important input for developing Stream-flow and infiltration models for the water-shed. Infiltration models are easier and depend on point conditions. Stream-flow models are more difficult and also must model drainage and thus, floods. Standard models for watersheds must be developed and calibrated. () August 2, 2017 9 / 25

  7. Computing flows-A Model Regions S1 S2 S3 S4 S5 Area Ha. 220 330 510 430 290 Capacity (TCM) 13 34 100 70 30 Storage (TCM) 2 8 12 12 20 Infiltration α 0.4 0.5 0.6 0.3 0.5 ET b (mm) 3 5 6 6 7 storage i ( n + 1) = (1 − β ) ∗ storage i ( n ) + overflow i − 1 ( n ) − ∆ i ( n ) overflow i ( n + 1) = A ∗ ( f i ( n ) − b ) ∗ (1 − α ) + ∆ i ( n ) Rain f (mm) S1 S2 S3 S4 S5 Day 1 11 11 9 9 9 Day 2 0 0 0 0 0 Day 3 2 2 2 3 2 () August 2, 2017 10 / 25

  8. Measuring Rain (wikipedia) Standard : Funnel-top, and Tipping bucket : Funnel, with water a measuring cylinder. falling on a see-saw. Pulse generated every 0.2mm. Now standard in India. () August 2, 2017 11 / 25

  9. Estimating Data Frequent Situation: Data observed at discrete points p i . Estimate to be made for another point q . r4 r1 r6 r3 r2 r5 p1 p2 p3 p4 q p5 p6 Two simple options. Constant and Linear interpolation. Linear Interpolation Constant Approximation r4 r1 r6 r3 r2 r5 p1 p2 p3 p4 q p5 p6 () August 2, 2017 12 / 25

  10. MyWatershed -estimating total rainfall MyWatershed Shown here is my watershed with the Rain−gauges locations of rain-gauges. Estimate the total rainfall over my watershed ( in cubic-meters . () August 2, 2017 13 / 25

  11. The Voronoi perpendicular a bisector c d b region(c) : All points for which c is the closest. Note that it depends on the presence of other points. () August 8, 2017 14 / 30

  12. The Domain decomposition () August 8, 2017 15 / 30

  13. MyWatershed -estimating total rainfall MyWatershed Shown here is my watershed with the Rain−gauges locations of rain-gauges. Estimate the total rainfall over my watershed ( in cubic-meters . Question: What should I assume as the rainfall at point p ? Heuristic: Assign to each point p , the rainfall at the closest gauge. () August 2, 2017 13 / 25

  14. MyWatershed -the construction MyWatershed Draw your watershed on a graph-paper. Let g ( i ) be a gauge and let the reading at g ( i ) be r ( i ). A(i) We want to find all points p for g(i) which the closest point is g ( i ). () August 2, 2017 14 / 25

  15. MyWatershed -the construction MyWatershed Draw your watershed on a graph-paper. Let g ( i ) be a gauge and let the reading at g ( i ) be r ( i ). A(i) We want to find all points p for g(i) which the closest point is g ( i ). Compute the polygon P ( i ) by the method of bisectors. Let A ( i ) be the fraction of the area lying inside my waterhsed. () August 2, 2017 14 / 25

  16. MyWatershed -the construction MyWatershed Draw your watershed on a graph-paper. Let g ( i ) be a gauge and let the reading at g ( i ) be r ( i ). A(i) We want to find all points p for g(i) which the closest point is g ( i ). Compute the polygon P ( i ) by the method of bisectors. Let A ( i ) be the fraction of the area lying inside my waterhsed. The area A ( i ) belongs to g ( i ). () August 2, 2017 14 / 25

  17. MyWatershed -the construction MyWatershed Measure A ( i ) using the graph paper. Ignore area outside the watershed. The sum � i A ( i ) = A the total A(i) area of the watershed. g(i) Average rainfall Ignore � A ( i ) r ( i ) r = � A ( i ) Finally... Total Volumne= A . r () August 2, 2017 15 / 25

  18. Domain Decomposition Division of the domain into non-overlapping triangles () August 8, 2017 18 / 30

  19. Internal Section Formula a x 1−x c q p 1−y r y b f ( p ) = (1 − x ) · f ( a ) + x · ( y · f ( c ) + (1 − y ) · f ( b )) () August 8, 2017 19 / 30

  20. Delaunay-Voronai Dual Decomposition () August 8, 2017 20 / 30

  21. Other Options MyWatershed a,f(a) A(i) g(i) x,f(x) c,f(c) b,f(b) x=u1.a+u2.b+u3.c u1+u2+u3=1 f(x)=u1.f(a)+u2.f(b)+u3.f(c) () August 2, 2017 16 / 25

  22. Measuring Stream-flows V-notch weir. Suitable for small streams. A V-notch is inserted in the stream so that there is sufficient head behind the V-notch. Measurements are taken on the height of the For a 90-degree stream-level on the V -notch: Q = 2 . 5 H 5 / 2 where V-notch. Q in cu.ft/s, and H is ht. of Flow: cu.m./s is given head above crest. Example: by an empirical If H = 0 . 25 ft then relationship. Q = 0 . 078 cu.ft/s. () August 2, 2017 17 / 25

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