Geometry Trigonometry of Right Triangles 2014-06-05 www.njctl.org - - PDF document

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Geometry Trigonometry of Right Triangles 2014-06-05 www.njctl.org - - PDF document

Slide 1 / 240 New Jersey Center for Teaching and Learning Progressive Mathematics Initiative This material is made freely available at www.njctl.org and is intended for the non-commercial use of students and teachers. These materials may not be


slide-1
SLIDE 1

This material is made freely available at www.njctl.org and is intended for the non-commercial use of students and teachers. These materials may not be used for any commercial purpose without the written permission of the owners. NJCTL maintains its website for the convenience of teachers who wish to make their work available to other teachers, participate in a virtual professional learning community, and/or provide access to course materials to parents, students and others.

Click to go to website: www.njctl.org New Jersey Center for Teaching and Learning Progressive Mathematics Initiative

Slide 1 / 240

www.njctl.org 2014-06-05

Geometry Trigonometry of Right Triangles

Slide 2 / 240

Table of Contents Pythagorean Theorem Special Right Triangles Trigonometric Ratios Solving Right Triangles Angles of Elevation and Depression Area of an Oblique Triangle

Click on a Topic to go to that section

Similarity in Right Triangles Law of Sines and Law of Cosines

Slide 3 / 240

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SLIDE 2

Pythagorean Theorem

Return to the Table of Contents

Slide 4 / 240

Before learning about similar right triangles and trigonometry, we need to review the Pythagorean Theorem and the Pythagorean Theorem Converse.

Slide 5 / 240

Recall that a right triangle is a triangle with a right angle. The sides form that right angle are the legs. The side opposite the right angle is the hypotenuse. The hypotenuse is also the longest side.

leg hypotenuse leg

Slide 6 / 240

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SLIDE 3

In a right triangle, the sum of the squares of the lengths

  • f the legs is equal to the square of the length of the

hypotenuse. leg2 + leg2 = hypotenuse2

  • r

a2 + b2 = c2 a b c

Pythagorean Theorem Slide 7 / 240

Example: Find the length of the missing side of the right triangle.

x 9 12

Is the missing side a leg or the hypotenuse of the right triangle? Answer

Slide 8 / 240

92 + 122 = x2 81 + 144 = x2 225 = x2 15 = x

  • 15 is a extraneous solution, a distance

can not equal a negative number. x = 15

x

9

12

Solve for x:

Slide 9 / 240

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SLIDE 4

x 28 20

Is the missing side a leg or the hypotenuse

  • f the right triangle?

Example: Find the length of the missing side

  • f the right triangle.

Answer

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1 The missing side is the ________ of the right triangle.

A leg B

hypotenuse

6 9 x

Answer

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2 Find the length of the missing side.

6 9 x

Answer

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SLIDE 5

3 The missing side is the _________ of the right triangle.

A leg B

hypotenuse

x 15 36

Answer

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4 Find the length of the missing side.

x 15 36

Answer

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The safe distance of the base of the ladder from a wall it leans against should be one-fourth of the length of the ladder.

28 feet 7 feet

?

Thus, the bottom of a 28-foot ladder should be 7 feet from the wall. How far up the wall will a ladder reach?

Real World Application Slide 15 / 240

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SLIDE 6

28 feet 7 feet

?

The ladder will reach feet up the wall safely. Answer Solve using a + b = c

2 2 2

Slide 16 / 240

84 50

x

The dimensions of a high school basketball court are 84' long and 50' wide. What is the length from one corner of the court to the opposite corner?

Real World Application

Answer

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5 A NBA court is 50 feet wide and the length from

  • ne corner of the court to the opposite corner is

106.5 feet. How long is the court?

A 94.03 feet B

117.7 feet

C

118 feet

D

94 feet

(Round the answer to the nearest whole number) Answer

Slide 18 / 240

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SLIDE 7

Pythagorean Theorem Applications

The Pythagorean Theorem can also be used in figures that contain right angles.

Slide 19 / 240

Example Find the perimeter of the square. note: Before finding the perimeter of the square, we need to first find the length

  • f each side.

18 cm

Psq = 4s

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18 cm

x Remember, in a square all sides are congruent. Answer Start here: x + x = 18

2 2 2

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SLIDE 8

Example Find the area of the triangle. The base of the triangle is given, but we need to find the height of the triangle. A = bh

1 2

13 feet 10 feet 13 feet

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By definition, the altitude (or height) of an isosceles triangle is the perpendicular bisector of the base.

13 feet 5 feet 13 feet

h

5 feet

Answer

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Try this... Find the perimeter of the rectangle.

Prect = 2l + 2w

8 in 10 in

Answer

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SLIDE 9

6 Find the area of the rectangle.

A 120 square feet B 84 square feet C

46 square inches

D

46 square feet

8 feet 1 7 f e e t

Answer

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7 Find the perimeter of the square. (Round to the nearest tenth)

A 12.8 cm B

25.5 cm

C

25.6 cm

D

36 cm

9 c m

Answer

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8 Find the area of the triangle.

7 inches 10 inches 7 inches

Answer

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SLIDE 10

9 Find the area of the triangle.

7 inches 4 inches 7 inches

Answer

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If the square of the longest side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is a right triangle. If c2 = a2 + b2, then ABC is a right triangle.

a b c

A B C

Converse of the Pythagorean Theorem Slide 29 / 240

Example Tell whether the triangle is a right triangle.

Remember c is the longest side

D E F 7 24 25

Answer

Slide 30 / 240

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SLIDE 11

If the square of the longest side of a triangle is greater than the sum of the squares of the other two sides, then the triangle is obtuse. If c2 > a2 + b2, then ABC is obtuse.

A B C a b c

Theorem Slide 31 / 240

If the square of the longest side of a triangle is less than the sum of the squares of the other two sides, then the triangle is acute. If c2 < a2 + b2 , then ABC is acute.

a b c A B C

Theorem Slide 32 / 240

Example Classify the triangle as acute, right, or obtuse.

17 15 13

Answer

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SLIDE 12

10 Classify the triangle as acute, right, obtuse, or not a triangle.

A acute B

right

C

  • btuse

D

not a triangle 11 12 15

Answer

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11 Classify the triangle as acute, right, obtuse, or not a triangle.

A acute B

right

C

  • btuse

D

not a triangle

6 3 5

Answer

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12 Classify the triangle as acute, right, obtuse, or not a triangle.

A acute B

right

C

  • btuse

D

not a triangle

25 19 20

Answer

Slide 36 / 240

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SLIDE 13

13 Tell whether the lengths 35, 65, and 56 represent the sides of an acute, right, or obtuse triangle.

A acute B

right

C

  • btuse

Answer

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14 Tell whether the lengths represent the sides of an acute, right, or obtuse triangle.

A acute triangle B

right triangle

C

  • btuse triangle

Answer

Slide 38 / 240 Review

If c2 = a2 + b2, then triangle is right. If c2 < a2 + b2, then triangle is acute. If c2 > a2 + b2, then triangle is obtuse.

Slide 39 / 240

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SLIDE 14

Similarity in Right Triangles

Return to the Table of Contents

Slide 40 / 240

There are many proofs to the Pythagorean Theorem. How many do you know? Triangle similarity can be used to prove the Pythagorean Theorem. How?

Slide 41 / 240

Theorem The altitude of a right triangle divides the triangle into two smaller triangles that are similar to the original triangle and each other. CD is the altitude of ABC

ABC~ ACD~ CBD

A C B D

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SLIDE 15

click for Lab 1 - Similar Right Triangles Therefore, the altitude of a right triangle divides the triangle into two smaller triangles that are similar to the

  • riginal triangle and similar to each other.

click

To prove this,

click

Teacher Notes

Slide 43 / 240

A C B D

ABC~ ACD~ CBD

Let's prove the Theorem.

The altitude of a right triangle divides the triangle into two smaller triangles that are similar to the original triangle and each other. Given: Prove: ABC is a right triangle is the altitude of ABC Statements Reasons

ABC is a right triangle is a right angle is a right angle is a right angle

ABC ~ ACD ABC ~ CBD ABC~ ACD~ CBD

Given Given

Def of Perp Lines. 2 lines that form a rt angle Def of Altitude All rt angles are Reflexive Prop of AA~ Def of Perp Lines All rt angles are Reflexive Prop of AA~ Transitive Prop of ~ click click click click click click click click click click click click

Slide 44 / 240

Let's sketch the 3 triangle's separately, with the same orientation.

A C D

B C D

B A C Match up the angles.

Helpful tip: If you set , then you can assign all the angles a value and easily find the matches.

60 30

A C D

30 60 B C D 60 30

B A C

60 30 30 60

A C B D

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SLIDE 16

d e c b a

Because the triangles are similar the corresponding sides are proportional.

c B

A C

a b

A C D

d b

B C D

e a

ABC~ ACD~ CBD

Assign lengths to all the segments. Let the lengths of the segments on the hypotenuse be d and e. Label the sides of a triangle with the lower case letter of the opposite angle.

ABC~ ACD ABC~ CBD

Slide 46 / 240

Statements Reasons

d e c b a

To prove the Pythagorean Theorem, use the proportions.

Given: Prove:

ABC is a right triangle.

is an altitude. ABC~ ACD ABC~ CBD

Using the multiplication property of equality, multiply the equation by bc. simplify Using the multiplication property of equality, multiply the equation by ac simplify Altitude of a rt triangle theorem. Altitude of a rt triangle theorem. Definition of similar triangles. Definition of similar triangles. (1) (2) click click click click click click click click

Slide 47 / 240

Statements Reasons

d e c b a

To prove the Pythagorean Theorem, use the proportions (continued).

Given: Prove:

ABC is a right triangle.

is an altitude.

Distributive Property Simplify Using the addition property

  • f equality, add equation (1)

and equation (2) together. Given Substitution click click click click click

Slide 48 / 240

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SLIDE 17

Example Find the length of the altitude KI?

H I J K 12 5 13

Slide 49 / 240

It maybe helpful to sketch the 3 triangle's separately, with the same orientation.

J K I 5

H I K 12

H J K 5 12 13

H I J K 12 5 13

Because the triangles are similar the corresponding sides are proportional.

13x = 60 x ≈ 4.62

x x x

Slide 50 / 240

5 P S Q 4 3 R

S Q 4

5 P R S x P Q R S 5 4 3 x

Try this... Find the length of RS. Answer

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SLIDE 18

15 Which ratio is the ratio of corresponding sides?

A B C D

H I J K

Answer

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16 Find KJ.

H I J K 7 24 25

Answer

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The next two theorems are Geometric Mean Theorems. What is a mean? An average. Usually when we ask to find the mean, we are asking for the arithmetic mean. What is an arithmetic mean? The sum of n values divided by the number of values (n). What is a geometric mean? The nth root of a product of n

  • values. It is defined for only positive numbers (no

negative numbers, no zero) For more information click on this link: Arithmetic Mean vs Geometric Mean

Slide 54 / 240

slide-19
SLIDE 19

The geometric mean of two positive numbers a and b is the positive number x that satisfies a x x b x2 = ab x = = Visually, the geometric mean answers this question: given a rectangle with sides a and b, find the side of the square whose area equals that of the rectangle.

Slide 55 / 240

Example Find the geometric mean of 8 and 14. x2 = 8(14) x2 = 112

(only the positive value)

Slide 56 / 240

17 Find the geometric mean of 7 and 56. Write the answer is simplest radical form. A B C D

Answer

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SLIDE 20

18 Find the geometric mean of 3 and 48.

Students type their answers here

Answer

Slide 58 / 240

Corollary The altitude drawn to the hypotenuse of a right triangle divides the the hypotenuse into two segments. The altitude is the geometric mean of the two segments formed. CD2 = AD(DB) CD is the altitude of ABC

Since, ACD~ CBD

A C B D

Slide 59 / 240

8 z 6

Example Find z. Answer

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slide-21
SLIDE 21

Example Find z.

18 z 6

Answer

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y 9 12

2)

18 8 y

1)

Try this... Find y. Answer

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19 Find x.

A B

100

C

20

D

50

5

x

10

Answer

Slide 63 / 240

slide-22
SLIDE 22

20 Find x.

A 99 B C D

11 9 x

Answer

Slide 64 / 240

Corollary If the altitude drawn to the hypotenuse of a right triangle, divides the hypotenuse into two segments. The length of each leg of the original triangle is the geometric mean of the lengths of the hypotenuse and the segment of the hypotenuse that is adjacent to the leg. AD AC AC AB = AB BC BC DB = CD is the altitude of ABC

A C B D

Since, ABC~ ACD~ CBD ABC~ ACD ABC~ CBD

Slide 65 / 240

R

S T U 4

9 x

Example Find x. Answer

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slide-23
SLIDE 23

D E F G 4 6 x

Example Find x. Answer

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21 Is PR a geometric mean between QR and SR?

True False

P Q R S

Answer

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22 Is the geometric mean correct?

True False

P Q R S

Answer

Slide 69 / 240

slide-24
SLIDE 24

23 Which proportion is correct?

A B C D

J

K L M

Answer

Slide 70 / 240

24 Find y.

A B

20

C

5

D

12

9 16 y

Answer

Slide 71 / 240

25 Find y.

A 3 B

18

C

24

D

None of the above

27 9

x y

Answer

Slide 72 / 240

slide-25
SLIDE 25

26 Find x.

5 8 x

Answer

Slide 73 / 240 Special Right Triangles

Return to the Table of Contents

Slide 74 / 240

In this section you will learn about the properties of the two special right triangles.

45o 45o 90o 30o 60o 90o

45-45-90 30-60-90

Slide 75 / 240

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SLIDE 26

A 45-45-90 triangle is an isosceles right triangle, where the hypotenuse is √2 times the length of the leg. hypotenuse = leg(√2) 45o 45o

x√2

x x

45-45-90 Triangle Theorem

Can you prove this? Answer

Slide 76 / 240

Example Find the length of the missing sides. Write the answer in simplest radical form. P Q R x y 45o 45o

6

Answer

Slide 77 / 240

Example Find the length of the missing sides of the right triangle.

S T V 18 x y

Answer

Slide 78 / 240

slide-27
SLIDE 27

Try this... Find the length of the missing sides.

x y 8

Answer

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27 Find the value of x.

A 5 B

5√2

C

(5√2)/2

x y 5

Answer

Slide 80 / 240

28 Find the value of y.

A 5 B

5√2

C

(5√2)/2

x y 5

Answer

Slide 81 / 240

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SLIDE 28

29 What is the length of the hypotenuse of an isosceles right triangle, if the length of the legs is 8 √2 inches.

Answer

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30 What is the length of each leg of an isosceles, if the length of the hypotenuse is 20 cm.

Answer

Slide 83 / 240

In a 30-60-90 right triangle, the hypotenuse is twice the length of the shorter leg and the longer leg is √3 times the length of the shorter leg. hypotenuse = 2(shorter leg) longer leg = √3(shorter leg) x x√3 2x 30o 60o

30-60-90 Triangle Theorem Slide 84 / 240

slide-29
SLIDE 29

This can be proved using an equilateral triangle. x x√3 2x 30o 60o

A C 60 60 30 30 c=2x 2x a=x x D b B

For right triangle ABD, BD is a perpendicular bisector. let a = x, c = 2x and b= BD

Slide 85 / 240

Example Find the length of the missing sides

  • f the right triangle.

F G H 60o x y

30o

5

Slide 86 / 240

F G H

60o x y

30o

5

Recall triangle inequality, the shortest side is

  • pposite the smallest angle and the longest

side is opposite the largest angle. HF is the shortest side GF is the longest side (hypotenuse) GH is the 2nd longest side HF < GH < GF Answer

Slide 87 / 240

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SLIDE 30

M A T 30o 60o x y 9 Example Find the length of the missing sides

  • f the right triangle.

Answer

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Example Find the area of the triangle.

14 ft

Slide 89 / 240

14 ft h

? ? The altitude (or height) divides the triangle into two 30o-60o-90o triangles. The length of the shorter leg is 7 ft. The length of the longer leg is 7√3 ft. A = b(h) = 14(7√3) A ≈ 84.87 square ft

Slide 90 / 240

slide-31
SLIDE 31

Try this... Find the length of the missing sides of the right triangle.

15

30o 60o

x y

Answer

Slide 91 / 240

30o 9 ft

Try this... Find the area of the triangle. Answer

Slide 92 / 240

30o 60o

x 7

31 Find the value of x.

A 7 B

7√3

C

(7√2)/2

D

14

Answer

Slide 93 / 240

slide-32
SLIDE 32

32 Find the value of x.

A 7 B

7√3

C

(7√2)/2

D

14

7√2 x

Answer

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33 Find the value of x.

A 7 B

7√3

C

(7√2)/2

D

14

30o 60o

x

7√3

Answer

Slide 95 / 240

34 The hypotenuse of a 30

  • -60o-90o triangle is 13 cm.

What is the length of the shorter leg?

Answer

Slide 96 / 240

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SLIDE 33

35 The length the longer leg of a 30

  • -60o-90o triangle is

7 cm. What is the length of the hypotenuse?

Answer

Slide 97 / 240

The wheelchair ramp at your school has a height of 2.5 feet and rises at angle of 30o. What is the length of the ramp?

Real World Example Slide 98 / 240

30o 2.5 ?

The triangle formed by the ramp is a 30

  • -60o-90o right
  • triangle. The length of the ramp is the hypotenuse.

hypotenuse = 2(shorter leg) hypotenuse = 2(2.5) hypotenuse = 5 The ramp is 5 feet long.

Slide 99 / 240

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SLIDE 34

36 A skateboarder constructs a ramp using plywood. The length of the plywood is 3 feet long and falls at an angle of 45 . What is the height of the ramp? Round to the nearest hundredth.

45o 3 feet ?

Answer

Slide 100 / 240

37 What is the length of the base of the ramp? Round to the nearest hundredth.

45o 3 feet ?

Answer

Slide 101 / 240

38 The yield sign is shaped like an equilateral triangle. Find the length of the altitude.

20 inches

Answer

Slide 102 / 240

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SLIDE 35

39 The yield sign is shaped like an equilateral

  • triangle. Find the area of the sign.

20 inches

Answer

Slide 103 / 240 Trigonometric Ratios

Return to the Table of Contents

Slide 104 / 240

Right triangle trigonometry is the study of the relationships between the sides and angles of right triangles.

a b c A B C

Slide 105 / 240

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SLIDE 36

Leaning Tower of Pisa, Bell Tower in Pisa, Italy

Ever since the construction of the Bell Tower in the 1100's, it has slowly tilted south and is at risk of falling

  • ver. If the angle of slant ever fall's

below 83 degrees, it is feared the tower will collapse.

Slide 106 / 240

A B C D F angle of slant GE

ABC~ DBE~ FBG WHY? Engineers can measure the angle of slant using any of the right triangles constructed below. Engineers very carefully measure the perpendicular distance from a tower window (points A, D or F) to the ground (points G, E or C). Then they measure the distance from the tower to points C, E or G. Answer

Slide 107 / 240

Triangle Height Base Ratio Height / Base ABC AC=50m BC=5m 50/5=10 DBE DE=30m BE=3m 30/3=10 FBG FG=20m BG=2m 20/2=10

Let's calculate the ratio's of the height to the base for each right triangle. Notice that all of the ratios are the same. WHY? The ratio of height/base is also called the slope ratio (rise/run) or tangent ratio. Answer

Slide 108 / 240

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SLIDE 37

When the triangle is dilated (pull scale), how does the angle change? What happens to the slope ratio? What happens to the ratio when the angle increases? What happens to the ratio when the angle decreases? Click for interactive website to investigate.

Slide 109 / 240

a b c A B C

To learn right triangle trigonometry, first you need to be able to identify the sides of a right triangle. In a right triangle, there are 2 acute

  • angles. In the triangle to the left,

A and B are the acute angles.

Label the sides of a triangle with the lower case letter of the opposite angle.

Slide 110 / 240

Let's look at A, when A is the reference angle, the side opposite A is a. the side adjacent (or next to) A is b. and the hypotenuse is c.

a b c A B C

When B is the reference angle, the side opposite B is b. the side adjacent (or next to) B is a. and the hypotenuse is c.

a b c A B C

  • pp

adj hyp

  • pp

adj hyp

Slide 111 / 240

slide-38
SLIDE 38

40 What is the side opposite to J?

A JL B

LK

C

KJ

J K L

Answer

Slide 112 / 240

41 What is the hypotenuse of the triangle?

A JL B

LK

C

KJ

J K L

Answer

Slide 113 / 240

42 What is the side adjacent to J?

A JL B

LK

C

KJ

J K L

Answer

Slide 114 / 240

slide-39
SLIDE 39

43 What is the side opposite K? A JL B LK C KJ

J K L

Answer

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44 What is the side adjacent to K? A JL B LK C KJ

J K L

Answer

Slide 116 / 240

A trigonometric ratio is the ratio of the two sides of a right triangle. There are 3 ratios for each acute angle

  • f a right triangle.

The ratios are called sine, cosine, and tangent (abbreviated sin, cos, and tan).

a b c A B C

Trigonometric Ratios Slide 117 / 240

slide-40
SLIDE 40

sinθ =

  • pposite side

hypotenuse cosθ =

adjacent side hypotenuse

tanθ =

  • pposite side

adjacent side a b c A B C

The 3 Trigonometric Ratios

This spells....

SOHCAHTOA

  • r

which is a pneumonic to help you remember the sides of a right triangle (you'll need to remember the spelling).

θ

Slide 118 / 240

Click for a SOHCAHTOA song on youtube.com "Gettin' Triggy Wit It".

Slide 119 / 240

Example Find the sin F, cos F, and tan F.

D E F 6 8 10

Since F is your reference angle, label the sides of the triangle opposite, adjacent and hypotenuse. Use the pneumonic to find the trig ratios. sinF = opp

hyp 6 10

=

3 5

= cosF = adj

hyp 8 10 = 4 5

= tan F = opp

adj 6 8

=

3 4

=

D E F 6 8 10

  • pp

adj hyp

Always reduce fractions to lowest terms.

Slide 120 / 240

slide-41
SLIDE 41

Example Find the sin D, cos D, and tan D.

D E F 6 8 10

Since D is your reference angle, label the sides of the triangle opposite, adjacent and hypotenuse. Use the pneumonic to find the trig ratios. sinD =opp

hyp 8 10 4 5

= = cosD = adj

hyp 6 10 = 3 5

= tanD = opp

adj 8 6

=

4 3

=

D E F 6 8 10

  • pp

adj hyp

Always reduce fractions to lowest terms.

Slide 121 / 240

45 What is the sin R? A 20/29 B 21/20 C 21/29

D 20/21 Answer

Slide 122 / 240

46 What is the cosR?

A 20/29 B

21/20

C

21/29

D

20/21

Answer

Slide 123 / 240

slide-42
SLIDE 42

47 What is the tanR?

A 20/21 B

21/20

C

20/29

D

21/29

Answer

Slide 124 / 240

48 What is the sinQ? A 20/29 B 21/20 C 21/29 D 29/20

Answer

Slide 125 / 240

49 What is the cosQ? A 20/29 B 21/20 C 21/29 D 29/21

Answer

Slide 126 / 240

slide-43
SLIDE 43

50 What is the tanQ? A 20/29 B 21/20 C 21/29 D 20/21

Answer

Slide 127 / 240

The angle of slant of the Tower of Pisa is 84.3

A B C D F angle of slant

To find the trigonometric ratio of an angle, use a calculator or a trig table. Check that your calculator is set for degrees (not radians) and round your answer to the ten thousandth place (4 decimal places). Find the following: sin 84.3 = .9951 cos 84.3 = .0993 tan 84.3 = 10.0187

click click click

Slide 128 / 240

51 Evaluate sin 60. Round to the nearest ten thousandth. A 0.5 B 0.8660 C 1.7321 D 0.5774

Answer

Slide 129 / 240

slide-44
SLIDE 44

52 Evaluate cos 60. Round to the nearest ten thousandth. A 0.5 B 0.8660 C 1.7321 D 0.5774

Answer

Slide 130 / 240

53 Evaluate tan 60. Round to the nearest ten thousandth. A 0.5 B 0.8660 C 1.7321 D 0.5774

Answer

Slide 131 / 240

Trig tables were used by early mathematicians and astronomers to calculate distances that they were unable to measure directly. Today, calculators are usually used.

x

Slide 132 / 240

slide-45
SLIDE 45

How do you find an unknown side measure in a right triangle when you are given an acute angle and one side?

  • pp

adj You need to identify the correct trig function that will find the missing side. Use SOHCAHTOA to help. B is your angle of reference. Label the given and unknown sides of your triangle

  • pp, adj, or hyp. Identify the trig funtion that uses

B, the unknown side and the given side. Using , I am looking for

  • and I have a, so

the ratio is o/a which is tangent. now you can solve for x, the missing side.

Slide 133 / 240

B C

x

12 30o

A

Example Find the trig equation that will find x. Answer

Slide 134 / 240

B C

x

12 30o

A

Example Find the trig equation that will find x. Answer

Slide 135 / 240

slide-46
SLIDE 46

B C

x

12 30o

A

Example Find the trig equation that will find x. Answer

Slide 136 / 240

54 Using B, which is the correct trig equation needed to solve for x.

A sin40 = 12/x B

cos40 = x/12

C

tan40 = 12/x

D

sin40 = x/12

B E x 12 40o D

Answer

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55 Using D, which is the correct trig equation needed to solve for x.

A sin50 = 12/x B

cos50 = x/12

C

tan50 = 12/x

D

sin50 = x/12

B E x 12 50o D

Answer

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SLIDE 47

56 Using J, which is the correct trig equation needed to solve for x.

A tan32 = x/11 B

cos32 = x/11

C

tan32 = 11/x

D

sin32 = 11/x

J L K x 32o 11 Answer

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57 Using K, which is the correct trig equation needed to solve for x.

A tan58 = x/11 B

cos58 = x/11

C

tan58 = 11/x

D

sin 58 = 11/x

J L K x 58o 11 Answer

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Finding the Missing Side of a Right Triangle

  • pp

adj Now, you can solve for x, the missing side. Round your answer to the nearest tenth.

Using your calculator, find the tan 84.3 Round your answer to 4 decimal places. You can rewrite 10.0187 with a denominator

  • f 1 and use the cross product property or

multiply both sides of the equation by 5 using the multiplication property of equality (see next slide).

Slide 141 / 240

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SLIDE 48

Finding the Missing Side of a Right Triangle

  • pp

adj Now, you can solve for x, the missing side. Round your answer to the nearest tenth.

Multiply both sides of the equation by 5 using the multiplication property of equality.

Slide 142 / 240

12 G E M 25o x

Example Find x. Round your answer to the nearest hundredth. Answer

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12 G E M 65o x Example Find x. Round your answer to the nearest hundredth. Answer

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SLIDE 49

C A E y 10 20o

Example Find y. Round your answer to the nearest hundredth. Answer

Slide 145 / 240

58 Find the length of LM. Round your answer to the nearest tenth. L M P 12 68o

Answer

Slide 146 / 240

59 Find the length of LP. Round your answer to the nearest tenth. L M P 12 68o

Answer

Slide 147 / 240

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SLIDE 50

Explain and use the relationship between the sine and cosine of complementary angles.

Slide 148 / 240

Find the measure of A?

Slide 149 / 240

To find the measure of A... The sum of the interior angles of any triangle is equal to 180 degrees. A and B are complementary angles. Complementary angles are two angles whose sum of their measures is 90 degrees. The acute angles of a right triangle are always complementary.

Slide 150 / 240

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SLIDE 51

60 For right triangle ABC, what is the measure of B? A 30 degrees B 50 degrees C 60 degrees D cannot be determined A C B 30o

Answer

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61 If the , find the complementary angle? A 20 degrees B 70 degrees C 160 degrees D none of the above

Answer

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A C B

53.1 36.9 4 5 3

Let's compare the sine and cosine of the acute angles of a right triangle. In a right triangle, the acute angles are

  • complementary. m A + m B = 90

53.1 + 36.9 = 90 sin A = 4/5 sin 53.1 = .7997 cos B = 4/5 cos 36.9 = .7997 sin A = cos B sin 53.1 = cos 36.9 The sine of an angle is equal to the cosine of its complement. cos A = 3/5 cos 53.1 = .6004 sin B = 3/5 sin 36.9 = .6004 cos A = sin B cos 53.1 = sin 36.9 The cosine of an angle is equal to the sine of its complement.

Slide 153 / 240

slide-52
SLIDE 52

L M P 12 68o 22o x

First, find the measure of LP using the sine function. Then, find the measure of LP using the cosine function. sine function cosine function Sine and Cosine are called co-functions of each other. Co-functions of complementary angles are equal.

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62 Given that sin 10 = .1736, write the cosine of a complementary angle. A sin 10 = .1736 B sin 80 = .9848 C cos 10 = .9848 D cos 80 = .1736

Answer

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63 Given that cos 50 = .6428, write the sine of a complementary angle. A sin 50 = .7660 B sin 40 = .6428 C cos 50 = .6428 D cos 40 = .7660

Answer

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slide-53
SLIDE 53

64 Given that cos 65 = .4226, write the sine of a complementary angle. A sin 25 = .4226 B cos 25 = .9063 C sin 65 = .9063 D cos 65 = .4226

Answer

Slide 157 / 240

65 What can you conclude about the sine and cosine of 45 degrees?

Students type their answers here

Answer

Slide 158 / 240 Solving Right Triangles

Return to the Table of Contents

Slide 159 / 240

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SLIDE 54

To solve a right triangle means to find all 6 values in a triangle. The lengths of all 3 sides and the measures of all 3 angles.

a b c A B C

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Let's solve a right triangle given the length of one side and the measure of one acute an gle (AAS). You need to find the 3 missing parts.

C A B 15

x y z

64o

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C A B 15

x y z

64o

First, let's find the measure of A. Answer

Slide 162 / 240

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SLIDE 55

C A B 15

26 y z

64o

Then, let's find the measure of AB. Answer

Slide 163 / 240

Then, let's find the measure of BC.

C A B 15

26 13.48

64o

z

Answer

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Try this... Find the missing parts of the triangle.

R E D 37o

11

Answer

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SLIDE 56

Let's solve a right triangle given the length of two sides (SSA).

9 15 A B C

x y z

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First, find the length of BC since we know how to do that. But, how do you find the measure of A and C?

9 15 A B C

x y z

Answer

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You will need to use the inverse trig functions. If sinθ = , θ = sin-1 If cosθ = , θ = cos-1 If tanθ = , θ = tan-1

a b c A B C

θ

With the sine, cosine and tangent trig functions, if you know the angle θ and the measure of one leg, then you can find the measure of a leg of a triangle. With the inverse sine, inverse cosine and inverse tangent trig functions, if you know the measures of 2 legs of a triangle, you can find the measure of the angle.

Pronounced inverse sine, inverse cosine, and inverse tangent.

Slide 168 / 240

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SLIDE 57

θ = sin-1( )

  • pposite side

hypotenuse θ = cos-1( ) adjacent side hypotenuse θ = tan-1( )

  • pposite side

adjacent side a b c A B C θ

The 3 Inverse Trigonometric Ratios

Use the inverse trig function to find the unknown angle measure when you know the length of 2 sides.

Remember:

Slide 169 / 240

66 Find sin

  • 10.8. Round the angle measure to the

nearest hundredth.

Answer

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67 Find tan

  • 12.3. Round

the angle measure to the nearest hundredth.

Answer

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SLIDE 58

68 Find cos

  • 10.45. Round

the angle measure to the nearest hundredth.

Answer

Slide 172 / 240

9 15 A B C

θ

To find an unknown angle measure in a right triangle, You need to identify the correct trig function that will find the missing value. Use SOHCAHTOA to help. A is your angle of reference. Label the two given sides

  • f your triangle opp, adj, or hyp.

Identify the trig funtion that uses A, and the two sides. Using , I have a and h, so the ratio is a/h which is cosine. now you can solve for A, the missing angle using the inverse trig function. adj hyp How are you going to calculate the measure of C? Answer

Slide 173 / 240

B C

7

12

A

θ

Example Find the trig equation that will find θ. Answer

Slide 174 / 240

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SLIDE 59

B C 10

12

A

θ Example Find the trig equation that will find θ. Answer

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B C

9

12

A θ

Example Find the trig equation that will find θ. Answer

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69 Which is the correct trig equation to solve for A B C D

B E 7 12 D

Answer

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SLIDE 60

70 Which is the correct trig equation to solve for A B C D

B E 5 12 D

Answer

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71 Which is the correct trig equation to solve for A B C D

J L K 9 11 Answer

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Try this... Solve the right triangle. Round your answers to the nearest hundredth.

Q R

S 7

24

Answer

Slide 180 / 240

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SLIDE 61

72 Find CE.

C D E 8 5 Answer

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73 Find m C.

C D E 8 5 Answer

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74 Find the m E.

C D E 8 5 Answer

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SLIDE 62

75 Find the m G. L

A G

18 20o Answer

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76 Find AL. L A G

18 20o

Answer

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77 Find the m P.

A 49.19o B

33.69o

C

41.81o

D

56.31o

P E N 12 18 Answer

Slide 186 / 240

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SLIDE 63

78 Find RT.

A 10.44 B

12.45

C

11.47

D

9.53 40o S R T 8

Answer

Slide 187 / 240 Angle of Elevation and Depression

Return to the Table of Contents

Slide 188 / 240

How can you use trigonometric ratios to solve word problems involving angles of elevation and depression?

Slide 189 / 240

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SLIDE 64

When you look up at an

  • bject, the angle your line
  • f sight makes with a line

drawn horizontally is the angle of elevation.

Slide 190 / 240

When you look down at an

  • bject, the angle your line
  • f sight makes with a line

drawn horizontally is the angle of depression.

Slide 191 / 240

The angle of elevation and the angle of depression are both measured relative to parallel horizontal lines, they are equal in meaure.

Slide 192 / 240

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SLIDE 65

79 How can you describe the angle relationship between the angle of elevation and the angle of depression? A corresponding angles B alternate interior angles C alternate exterior angles D none of the above

Answer

Slide 193 / 240

Example Amy is flying a kite at an angle of 58o. The kite's string is 1 58 feet long and Amy's arm is 3 feet off the ground. How high is the kite off the ground?

58o 1 5 8 f e e t

x 3 feet

Slide 194 / 240

sinθ = sin58 = .8480 = x = 134

x 158 x 158 x 158

Now, we must add in Amy's arm height. 134 + 3 = 137 The kite is about 137 feet off the ground.

158ft x 58o

Slide 195 / 240

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SLIDE 66

30o 6 ft 5306 ft

x Example You are standing on a mountain that is 5306 feet high. You look down at your campsite at angle of 30

  • . If you are 6 feet

tall, how far is the base of the mountain from the campsite?

Slide 196 / 240

30o

x

5312 ft

tan30 = .5774 = .5774x = 5312 x ≈ 9,200 ft

5312 x 5312 x

The campsite is about 9,200 ft from the base of the mountain.

Slide 197 / 240

Try this... You are looking at the top of a tree. The angle of elevation is 55o. The distance from the top of the tree to your position (line of sight) is 84 feet. If you are 5.5 feet tall, how far are you from the base of the tree?

Answer

Slide 198 / 240

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SLIDE 67

80 When you look down at an object, the angle your line of sight makes with a line drawn horizontally is the angle of _______.

A elevation B

depression

Answer

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81 Katherine looks down out of the crown of the statue

  • f liberty to an incoming ferry about 345 feet. The

distance from crown to the ground is about 250 feet. What is the angle of depression?

Answer

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82 What is the distance from the ferry to the base of the statue?

Answer

Slide 201 / 240

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SLIDE 68

Law of Sines and Law of Cosines

Return to the Table of Contents

Slide 202 / 240

How can you solve a non-right triangle ? How can you find the side lengths and angle measures of non-right triangles? The Law of Sines and Law of Cosines can be used to solve any triangle. You can use the Law of Sines when you are given -

  • 1. Two angle measures and any side length (AAS or ASA)
  • 2. Two side lengths and the measure of a non-included angle

(SSA) when the angle is a right angle or an obtuse angle. The Law of Sines has a problem dealing with SSA when the angle is acute. There can be zero, one or two solutions. Click on: Khan Academy Video "More On Why SSA Is Not A Postulate" for more info. You can use the Law of Cosines when you are given -

  • 3. Three side lengths (SSS)
  • 4. Two side lengths and the measure of an

included angle (SAS)

Slide 203 / 240 Law of Sines

If ABC has sides of length a, b, and c, then sin A = sinB = sinC a b c To use the Law of Sines, 2 angles and 1 side must be given. a c A B C b

Slide 204 / 240

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SLIDE 69

Let's prove the Law of Sines

Given: Prove: ABC has sides of length a, b, and c

Statements Reasons

Given

Def of Altitude

If ABC has sides of length a, b, and c, then sin A = sinB = sinC a b c sin A = sinB = sinC a b c

a A C b c B

h Draw an altitude from C to side AB Let h be the length of the altitude ABC with side lengths a, b, and c

Def of sine Multiply by b. Mult Prop of =. Substitution Prop of = Divide by ab. Division Prop of = Multiply by a. Mult Prop of =. click click click click click click click

Slide 205 / 240

Prove the Law of Sines (continued)

Given: Prove: ABC has sides of length a, b, and c

Statements Reasons

Def of Altitude

sin A = sinB = sinC a b c

Draw an altitude from B to side AC Let g be the length of the altitude

Def of sine Multiply by c. Mult Prop of =. Substitution Prop of = Divide by ac. Division Prop of = Multiply by a. Mult Prop of =.

a A b c B

g

C

Substitution Prop of = click click click click click click click

a A C b c B

h

Slide 206 / 240

Use the Law of Sines to solve the triangle. A B

C 10 65o 70o a b

Select the ratios based on the given information. Given: m B, m C and BA (side c) (AAS) Which ratios must be used first? Why? sin A = sinB = sinC a b c Answer

Slide 207 / 240

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SLIDE 70

A B C 10 65o 70o a b

sinB = sinC b c sin70 = sin65 b 10 First we can find the length side b. Answer

Slide 208 / 240

Before we find the length of side a , we find the m A .

A B 10 65o 70o a b=10.37 C

Triangle Sum Theorem m A + m B + m C = 180o Answer

Slide 209 / 240

A C 10 65o 70o a b=10.37 =45o B sinA = sinC a c Now we find the length side a. Answer

Slide 210 / 240

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SLIDE 71

Try this... Use the Law of Sines to find the length of side b (ASA).

a b 9 85o 29o A B C Since the length of the side opposite <C is given, find the m<C first.

hint

Answer

Slide 211 / 240

Example... Find the length of side b (SSA with an obtuse angle).

2.8

101o

A B 8 b C Answer

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83 Find the m A.

A 19o B

31o

C

29o

D

28o

A B C 10 70o 81o b c

Answer

Slide 213 / 240

slide-72
SLIDE 72

84 Which ratio must be used to find the length of b or c?

A sinA

a

B

sinA b

C

sinB b

D

sinC c

A B C 10 70o 81o b c

Answer

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85 What is the length of b?

A B C 10 70o 81o b c

Answer

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86 What is the length of c?

A B C 10 70o 81o b c

Answer

Slide 216 / 240

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SLIDE 73

a c A B C b

If ABC has sides of length a, b, and c, then: To use the Law Cosines, you must be given the length of 3 sides (SSS) or the length of 2 sides and the measure of the included angle (SAS).

Law of Cosines Slide 217 / 240

Let's prove the Law of Cosines

Given: Prove: ABC has sides of length a, b, and c

Statements Reasons

Given Def of Altitude

If ABC has sides of length a, b, and c, then

a A C b

h

D x c-x B c

Draw an altitude CD from C to side

  • AB. Let h be the length of the alt.

ABC with side lengths a, b, and c

Segment Addition Postulate Multiply by b. Mult Prop of =. Simplify Substitution, equation (2)

a A C b c B

Let x be the length of AD. Then (c-x) is the length of DB. In ADC, cosA = x/b x=b(cosA)

Definition of cosine

In ADC,

Pythagorean Theorem

In CDB,

Pythagorean Theorem

(1) (2)

Associative Prop of Addition Substitution, equation (1)

(similar reasoning shows that ) click click click click click click click click click click click

Slide 218 / 240

a is opposite <A b is opposite <B c is opposite <C

Example Use the Law of Cosines to solve the right triangle.

A B C c=27 a=16 b=23

The formula you choose depends on which angle you are solving for first.

Slide 219 / 240

slide-74
SLIDE 74

To find the m A, a2 = b2 + c2 - 2bc(cosA) 162 = 232 + 272 - 2(23)(27)(cosA) 256 = 529 + 729 - 1242(cosA) 256 = 1258 - 1242(cosA)

  • 1002 = -1242(cosA)

.8068 = cosA A = cos-1(.8068) m A ≈ 36.22o

A B C c=27 a=16 b=23

Slide 220 / 240

To find the m B, b2 = a2 + c2 -2ac(cosB) 232 = 162 + 272 - 2(16)(27)(cosB) 529 = 256 + 729 - 864(cosB) 579 = 985 - 864(cosB)

  • 406 = -864(cosB)

.4699 = cosB B=cos-1(.4699) m B ≈ 61.97o

A B C c=27 a=16 b=23 36.22

  • r

Using 2 different methods, the answers are slightly different because of rounding.

Slide 221 / 240

To find the m C, Use the Triangle Sum Theorem.

A B C c=27 a=16 b=23 36.22

61.97

Answer

Slide 222 / 240

slide-75
SLIDE 75

Try this... Use the Law of Cosines to find the m<B (SSS).

A B C 5 6 7

Answer

Slide 223 / 240

87 In the triangle the length of c is...

A 8 B

9

C

15

A B C 8 9 15

Answer

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88 In the triangle the length of a is...

A 8 B

9

C

15

A B C 8 9 15

Answer

Slide 225 / 240

slide-76
SLIDE 76

89 Which formula would you use to find the m<A?

A a2 = b2 + c2 - 2ac(cosA) B

a2 = b2 + c2 - 2bc(cosA)

C

b2 = a2 + c2 - 2ac(cosB)

D

c2 = a2 + b2 - 2ab(cosC)

Answer

Slide 226 / 240

90 What is the m A?

A B C 8 9 15

Answer

Slide 227 / 240

91 What is the m C?

A B C 8 9 15

Answer

Slide 228 / 240

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SLIDE 77

92 What is the measure of B (ASA)?

Students type their answers here

Answer

B A C 4 8 50

Slide 229 / 240

93 The Law of Sines and Cosines is used to solve...

A right triangles B

acute triangles

C

  • btuse triangles

D

all triangles

Answer

Slide 230 / 240

Return to the Table of Contents

Area of an Oblique Triangle Slide 231 / 240

slide-78
SLIDE 78

Do you remember this? Previously, we found the area of a triangle when we were given 3 sides. Find the area of the triangle.

13 feet 10 feet 13 feet

Slide 232 / 240

b is the base of the triangle b = 10. h is the altitude (or height). It is the perpendicular bisector of the base in an isosceles triangle.

13 feet 5 feet 13 feet

h

5 feet

Find h, using the pythagorean theorem - A = bh

1 2

Slide 233 / 240

What formula can you use to find the area of a triangle if you know the length of two sides and the measure of an included angle (SAS)? Find the area of the triangle.

10 feet 13 feet

67.38

Slide 234 / 240

slide-79
SLIDE 79

10 feet 13 feet

h

67.38

Since A = bh and b = 10, we need to find h.

1 2

Slide 235 / 240

Let's derive the formula for an oblique triangle.

Given: Prove:

Statements Reasons

Given

Def of Altitude

ABC has sides of length a, b, and c. Altitude h.

a A C b c B

h Draw an altitude from B to side AC Let h be the length of the altitude ABC with side lengths a, b, and c

Def of sine Substitution Prop of =

  • Definition. Formula for

the area of a triangle. Multiply by a. Mult Prop of =. Commutative Prop of Multiplication click click click click click click click

Slide 236 / 240

94 Which of the following expressions can be used to find the area of the triangle below? Select all that apply. A B C D E F Answer

Slide 237 / 240

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SLIDE 80

95 Find the area of the triangle to the nearest tenth.

Students type their answers here

Answer

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96 Find the area of the triangle to the nearest tenth.

Students type their answers here

Answer

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97 Find the area of the triangle to the nearest tenth.

Students type their answers here

Answer

Slide 240 / 240